SELECT OPTION from mysql field value - php

Question

I need to populate an html SELECT OPTION using a while loop with an sequence from 1 to the value of a integer number that is stored in a field called dummy3 inside a table from mysql database.
Example: if the dummy3 field has number 4, than the select option should display 1 2 3 4 as option values.
Here is my code, that is not working. The option values in this code version always come empty (with other code variants i tried the browser looped forever).
Here is my code:
echo 'Quantidade: '.'<select name="product_qty" id="product_qty" class="btn">';
$qt = 1;
$quantidade = "SELECT dummy3 FROM shop_products ORDER BY category ASC";
$quantidade1 = mysqli_query($conn, $quantidade) or die("database error:". mysqli_error($conn));
while($row_quantidade = mysqli_fetch_assoc($quantidade1, MYSQL_NUM)){
$row_qt = $row_quantidade['dummy3'];
while($qt <= $row_quantidade['dummy3']){
echo '<option value="'.$qt.'">'.$qt.'</option>';
}
}
echo '</select>';

Answer 1

echo 'Quantidade: '.'<select name="product_qty" id="product_qty" class="btn">';
$qt = 1;
$quantidade = "SELECT dummy3 FROM shop_products ORDER BY category ASC";
$quantidade1 = mysqli_query($conn, $quantidade) or die("database error:". mysqli_error($conn));
while($row_quantidade = mysqli_fetch_assoc($quantidade1, MYSQL_NUM)){
$row_qt = $row_quantidade['dummy3'];
for($i = 1; $i <= $row_qt; $i++) {
echo '<option value="'.$i.'">'.$i.'</option>';
}
}
echo '</select>';
Does this work?