I am using the following code:
<p><?php esc_html_e( 'It looks like nothing was found at this location. Maybe try one of the navigation links above or a search? Or it is possible you are trying to access a restricted page without being logged in to gain access.', 'shapely' ); ?></p>
Which ends up being displayed as follows:
It looks like nothing was found at this location. Maybe try one of the navigation links above or a search? Or it is possible you are
trying to access a restricted page without being logged in to gain
access.
What I want to display is this:
It looks like nothing was found at this location.
Maybe try one of the navigation links above or a search?
Or it is possible you are trying to access a restricted page without
being logged in to gain access.
So what I want is a way to break the line. I tried <br /> and \n, and neither work. Is there a way to add line breaks in the esc_html_e() function?
I know this a older question, I wanted to to point out that there is no need to use the output buffering functions in PHP. You can simplify this code by calling the WordPress function esc_html__() instead of esc_html_e(). This function will return the escaped value instead of echoing it out.
https://developer.wordpress.org/reference/functions/esc_html__/
echo nl2br( esc_html__("Line1\nLine2\nLine3", 'shapely') );
First off you can't use \n inside single quotes. Also, line breaks won't be rendered as such on on a webpage. From the looks of things esc_html_e() actually echoes the output so to capture & process it you'd need to do something like this:
ob_start();
esc_html_e("Line1\nLine2\nLine3");
$output = ob_get_contents();
ob_end_clean();
echo nl2br($output);
But this seems like an awful lot to go through and probably the wrong way to go about it. If you need to output html you probably don't be using esc_html_e() to begin with. Really hard to say without more context.
Related
I've searched around and struggled to come up with a solution to this.
I've inherited a project with several thousand php files, each of which has multiple links in the form of:
<a href="_link.php?[RANDOMSTRING]">
Trouble is, I don't have the _link.php file.
I'm assuming its some kind of redirect script, as it is supposed to send the user to
RANDOMSTRING.php
when clicked.
It doesn't do anything nice like use a variable name like
_link.php?url=[RANDOMSTRING]
What code do I need to put into _link.php to just get it working for now. Its a hacky job and I'm planing a major overall and sticking all of this content into a database, but for now I just need the flatfile version running.
Cheers for your help.
Assuming that there are not actual [], then a hack is to create the file _link.php and inside, either redirect:
<?php
header("location: {$_SERVER['QUERY_STRING']}.php");
exit;
Or possibly include if that would work:
<?php
include("{$_SERVER['QUERY_STRING']}.php");
If there are actual [] then just trim them:
trim($_SERVER['QUERY_STRING'], '[]');
functions/SkriptParser.php
<?php
$text = file_get_contents(basename($_SERVER['PHP_SELF']));
preg_match_all("/{(.*?)}/", $text, $matches);
var_dump($matches[0]);
echo str_replace($matches[0],"Test",$text);
?>
Is my current code, this is called from my index page which is here:
index.php
require_once 'functions/SkriptParser.php';
When i open index.php it replace the correct strings [ It'll replace any string inside {} however, it seems to be replacing <?php and I have no clue why.
Any ideas?
I'm not sure I fully understand what you are trying to do.
This line $text = file_get_contents(basename($_SERVER['PHP_SELF']));resolves to a local filename which will be the name of the script it's included in.
It won't load the page which that script would output, it will load the file without executing the code. The contents of $text will be a string containing the pure php content.
When I run your code from the command line and use "Here is a test of {your code}" as my string the output is:
{your code}<?php
require_once 'includetest.php';
print_r(basename($_SERVER['PHP_SELF']));
echo "Here's a test of Test";
If I run it from a browser and view the source I see that too, but the browser escapes the php so it isn't rendered on the page. So (for me at least), your concept kinda works. However, the fact the code isn't executed means it will never do what you intend.
Here's what I don't really understand though. In essence within index.php what you are telling your code to do is load a script which will load another copy of index.php and replace content within it.
If you want to change the behaviour of index.php then alter the code within index.php, don't generate unsuitable output and then load another script in an attempt to parse it before returning it. Just output it the way you want the first time.
Where is the content within the {} that you want to remove coming from? Why do you want/need to remove it? If you can clarify exactly what your aim is then it will be easier to suggest a solution.
To put my question into context, I'm working on an entirely static website where 'post' pages are created by myself manually - there's no CMS behind it. Each page will require a <pre> <code> block to display code as text in a styled block. This could be very few - several which is why I'm trying to do this for ease.
Here's what I've done -
function outputCode($code) {
return "<pre class='preBlock'><code class='codeBlock'>".htmlentities($code)."</code></pre>";
}
The code works as expected and produces an expected outcome when it's able to grab code. My idea is to somehow wrap the code for the code block with this function and echo it out for the effect, fewer lines and better readability.
As I'm literally just creating pages as they're needed, is there even a way to create the needed code blocks with such function to avoid having to manually repeat all the code for each code block? Cheers!
EDIT:
I was previously using this function and it was working great as I was pulling code from .txt documents in a directory and storing the code for code blocks in a variable with file_get_contents(). However, now, I'm trying to get the function to work by manually inputting the code into the function.
Well. Wrapping the function input in ' ' completely slipped my mind! It works just fine now!
If I understand correctly, you want to re-use your outputCode function in several different PHP files, corresponding to posts. If yes, you could put this 1 function in its own file, called outputcode.php for example, and then do
include "outputcode.php";
in every post/PHP file that needs to re-use this function. This will pull in the code, from the one common/shared file, for use in each post/PHP file that needs it. Or maybe I'm misreading your last paragraph :(
I am trying to find a way to create a simple dynamic URL, that gets its information from boxes where people enter something.
I got a google search machine and want to refer to it, so basically I wanted two boxes:
One for choosing which directory to search in (the google machine has different directories in its index I want people to be able to choose from those)
and the other for the search term they are looking for.
The URL looks like that:
http://searchengine.xx/search?q=SEARCHTERM&site=DIRECTORY&btnG=Suchen&entqr=0&ud=1&sort=date%3AD%3AL%3Ad1&output=xml_no_dtd&oe=UTF-8&ie=UTF-8
I tried it with PHP like that:
<?php
$directory = $_GET['searchterm'];
echo "http://searchengine.xx/search?q=".$searchterm."&site=directory&btnG=Suchen& entqr=0&ud=1&sort=date%3AD%3AL%3Ad1&output=xml_no_dtd&oe=UTF-8&ie=UTF-8'>URL</a>
?>
This doesnt seem to work well and I wondered if this was possible in any other way (simple HTML, JavaScript maybe?)
try to mix php and htaccess...
<?php
//get the text form the text box and put it in a variable eg.($text)
$url = 'index.php?searchterms=$text';
header("Location: $url");
?>
I think that something like this might work.
Get the text from the text box, then put the text onto a variable (i've used $text to exemplify).
Put the url that you want in a variable (i've used $url to exemplify), but in the end of the url put the text variable the way i did it.
Finally, use the header function to redirect to the url that you want.
Hope i helped
There are several problems with the PHP code in your question. $searchterm is never set and the echo statement is never ended. Try this instead:
<?php
$searchterm = $_GET['searchterm'];
$searchterm = strip_tags($searchterm);
echo "<a href='http://searchengine.xx/search?q=".$searchterm."&site=directory&btnG=Suchen&entqr=0&ud=1&sort=date%3AD%3AL%3Ad1&output=xml_no_dtd&oe=UTF-8&ie=UTF-8'>URL</a>";
?>
The strip_tags will ensure " and ' are removed so it doesn't break your link.
At the end of a page, if something occurs, it needs to be cleared, then the entire page needs to be re-parsed before serving to the client. I was going to echo out a javascript to refresh the page, but that will make them load the page and then reload it...I was wondering if there was a way to just tell the php engine to go back to the beginning and re-parse the entire page?
Thanks!
I will try to explain the problem more clearly but it is complicated and I am a terrible communicator. I on the page that lists products I am giving users the option to select fields to narrow the results. The system remembers this so they don't have to keep selected them. If they narrow a category like metal color and then go to a category that metal color is irrelevant like crystal figurines it will not show any results because none will match the metal color chosen. To generate the query to pull the products from the data-base is very complicated because different categories have different requirements to find the correct products. so once the query is generated I want to test it against mysql_num_rows() and if there is no results clear out the users choices and start over.
You're being a little vague, but if you're merely talking about reparsing the output, you could do that using output buffering.
I'm not entirely clear what the issue is, but couldn't you decide what is to be shown before creating the HTML, and then send the right thing the first time?
To generate the query to pull the products from the data-base is very complicated because different categories have different requirements to find the correct products. so once the query is generated I want to test it against mysql_num_rows() and if there is no results clear out the users choices and start over.
In that case, just put the query inside a function that returns the result, check the row count, and if it's zero clear the filters and call that function a second time.
Output buffering (ob_start and ob_clean), combined with separating the functionality at hand into a separate file and eval()'ing that should do the trick.
Oh, and recent PHP versions actually have a goto statement... although I'll always deny mentioning anything about it. :-)
I think you're going about it a little bit off.
What you should do to reparse the page is to redirect the user to the page again, using
header('Location: thepagefile.php');
however if you actually would like to reparse the file without creating a new page, you could also just include the file again:
include thepagefile.php
But you'd probably get the same result. If you want to actually parse the output of the page you'd do something like:
ob_start(); // this is at the very top of the code/page
// all the code goes here
$output = ob_get_clean();
eval($output); // WTF?
but that actually makes no sense, but I hope it helps.
I'd actually like to know what the real problem you're trying to solve really is.
I think your looking for something like this:
<?php
ob_start(); //we start output buffering, this means nothing is send to the browser
//We do some code stuff
$time = microtime();
echo "Hai \n"; //Note taht mixing logic and output in real life
echo $time; // is terribly practice
echo "\n bai"; //I do it here purely for the example
if(/*some condition */){
$anErrorHappened = true;
}
if($anEroorHappened === true){
//Load the output in a var if you need it
//Otherwise don't
$output = ob_get_clean();
//Do other code stuff
//I.E. send an error page
include('errorPage.html');
}
else{
ob_end_flush(); //Send everything the script has echo()'d, print()'ed and send to the browser in any other way (I.E. readfile(), header() etc.)
}
?>