Replace file url with query string php - php

Question

I have 1000 images in my website (running in codeingiter), which are named as
My_image_1.png, My_image_2.png ........ My_image_1000.png
and available in this url http://example.com/files/My_image_1.png
But i want the url is http://example.com/images?cid=1.png = My_image_1.png
How can i do this in php?
This is what i'm trying
if ( !function_exists('get_img_by_cid')) {
function get_img_by_cid() {
if ( isset($_GET['cid']) ) {
$cid = $_GET['cid'];
return '/path_to_image/My_image_'.$cid.'.png';
} else {
return 'Please specify compound id';
}
}
}
This function return the original path, but i need url like the example below.
In address bar or img tag wherever i use
Here is an example
https://pubchem.ncbi.nlm.nih.gov/image/imgsrv.fcgi?cid=2244
Any help or tutorial will be greatly appriciated :)

Answer 1

You can achieve it by following code.
Your URL = http://example.com/images.php?cid=1.png
write below code to images.php file
<img src="<?php echo "My_image_".$_GET['cid'];?>">
Above line will display image with named My_image_1.png
Hope this will helps you
Thanks & Regards

Answer 2

You need to write .htaccess rule :
RewriteCond %{QUERY_STRING} cid=([0-9]+) [NC]
RewriteRule ^images$ /files/My_image_%1.png [L]
Edit :
nginx configuration
location / {
if ($query_string ~* "cid=([0-9]+)"){
rewrite ^/images$ /files/My_image_%1.png break;
}
}

Answer 3

Building on the code provided by #Shishil Patel, a friend and I wrote this:
<?php
$file = "My_image_".$_GET['cid'];
$size = getimagesize($file);
$fp = fopen($file, "rb");
if ($size && $fp) {
header("Content-type: {$size['mime']}");
fpassthru($fp);
exit;
} else {
header("HTTP/1.0 404 Not Found");
}
readfile("{$file}");
?>
With this, https://example.com/?cid=1.png will display your image without any issues... as long as it's stored to index.php, otherwise your url is similar to https://example.com/index.php?cid=1.png, but with the proper php file name in the url.
EDIT:
On an additional note, $file should contain the folder path to your file, for example
$file = "/path_to_image/My_image_".$_GET['cid'];
Let me know if this was of use, your question was the same issue we had!