Issue while trying to display images from display on carousel slider - php

Question

I currently trying to make it where My Database is storing image names like slider1.jpg and then I'm retrieving that from my database, but the issue is when I'm selecting * all from the table its only displaying the first link in the table. Any Ideas on how I can fix this in my code?
Heres my PHP:
<?php
//Gets Links
$stmt = $DB_con->prepare('SELECT * FROM slider');
$stmt->execute();
if($stmt->rowCount() > 0)
{
$row=$stmt->fetch(PDO::FETCH_ASSOC);
extract($row);
}
?>
And Heres my Carousel Slider.
<header>
<div id="carouselExampleIndicators" class="carousel slide" data-ride="carousel">
<ol class="carousel-indicators">
<li data-target="#carouselExampleIndicators" data-slide-to="0" class="active"></li>
<li data-target="#carouselExampleIndicators" data-slide-to="1"></li>
<li data-target="#carouselExampleIndicators" data-slide-to="2"></li>
</ol>
<div class="carousel-inner" role="listbox">
<!-- Slide One - Set the background image for this slide in the line below -->
<div class="carousel-item active" style="background-image: url('images/slider/<?php echo $row['link'];?>')">
<div class="carousel-caption d-none d-md-block">
<h3>First Slide</h3>
<p>This is a description for the first slide.</p>
</div>
</div>
<!-- Slide Two - Set the background image for this slide in the line below -->
<div class="carousel-item" style="background-image: url('images/slider/<?php echo $row['link'];?>')">
<div class="carousel-caption d-none d-md-block">
<h3>Second Slide</h3>
<p>This is a description for the second slide.</p>
</div>
</div>
<!-- Slide Three - Set the background image for this slide in the line below -->
<div class="carousel-item" style="background-image: url('images/slider/<?php echo $row['link'];?>')">
<div class="carousel-caption d-none d-md-block">
<h3>Third Slide</h3>
<p>This is a description for the third slide.</p>
</div>
</div>
</div>
<a class="carousel-control-prev" href="#carouselExampleIndicators" role="button" data-slide="prev">
<span class="carousel-control-prev-icon" aria-hidden="true"></span>
<span class="sr-only">Previous</span>
</a>
<a class="carousel-control-next" href="#carouselExampleIndicators" role="button" data-slide="next">
<span class="carousel-control-next-icon" aria-hidden="true"></span>
<span class="sr-only">Next</span>
</a>
</div>
</header>

Answer 1

You need to utilize a loop on the results so you can build each slide with a new $row from the database query:
<?php
// build a clean array of slides from the db grab
$stmt = $DB_con->prepare('SELECT * FROM slider');
$stmt->execute();
$slides = [];
if($stmt->rowCount() > 0) {
$slides = $stmt->fetchAll(PDO::FETCH_ASSOC);
}
?>
.... starter html ....
<ol class="carousel-indicators">
<?php foreach($slides as $i => $slide) { ?>
<li data-target="#carouselExampleIndicators"
data-slide-to="<?php echo $i;?>"
class="<?php echo (!$i?'active':'');?>"></li>
<?php }?>
</ol>
.... more html ....
<div class="carousel-inner" role="listbox">
<?php foreach($slides as $i => $slide) { ?>
<div class="carousel-item <?php echo (!$i?'active':'');?>"
style="background-image: url('images/slider/<?php echo $slide['link'];?>')">
<div class="carousel-caption d-none d-md-block">
<h3><?php echo $slide['slide_name'];?></h3>
<p><?php echo $slide['slide_desc'];?></p>
</div>
</div>
<?php } ?>
</div>
.... the rest of your html output ....