In phpMyAdmin, I am writing
SELECT `class` FROM `teachers` WHERE `var1`=3;
I can give results. The Results are 5,6,7,8,9,10.
I am Trying this code in Sublimetext3. code is like this :
<tr>
<?php
$classlistdata = $db->getrows("SELECT `class` FROM `teachers` WHERE `var1`=3; ");
foreach ($classlistdata as $ndcld) {
?>
<td height="25" colspan="3" ><span class="admin"><?php echo ($ndcld); ?></span></td>
<?php } ?>
</tr>
this code writing 6 times "array"
. How can I fix it. I am new PHP. thanks for your answer.
You should use echo $ndcld['class'];
I don't know whats behind the getrows method, but likely its just an normal SQL query since you get arrays. Well, in your case, ndcld is an array. An array containing all the queried attributes as an array key.
Change your code to:
$classlistdata = $db->getrows("SELECT `class` FROM `teachers` WHERE `var1`=3; ");
foreach ($classlistdata as $ndcld) {
?>
<td height="25" colspan="3" ><span class="admin"><?php echo $ndcld["class"]; ?></span></td>
<?php } ?>
That should do the job ;)
Related
I'm currently working on a table that contains 'Name', 'Info', 'Price' and 'Duration'. However the PHP-Script is connected to a database.
I want to autofill the tablecells: 'Name', 'Price', 'Duration' via the Database by using PHP and SQL and that works perfectly fine for me. Though, I want to customize the content that's in the individual Info cells (e.g. Readmore jQuery and redirect to other pages).
I tried a little bit with using tags inside the Database and other weird stuff which, obviously, didn't work.
Is there a more elegant way of solving my problem than setting up a complete normal table without PHP/SQL, where I'd have to put in every bit of data about Name,Price and Duration manually?
<table class="table table-bordered table-hover tablesorter row sortable">
<thead>
<tr>
<th class="header">Name</th>
<th class="hidden-xs">Info</th>
<th>Price (in Euro)</th>
<th>Duration</th>
</tr>
</thead>
<tbody>
<?php
//Connect to Database
$db=mysql_connect ("xxxx", "xxxx", "xxxx") or die ('Oops! Da hat wohl' . mysqli_error(). 'Mist gebaut');
//Choose Database
$mydb=mysql_select_db("massageke_de");
//Query Database
$sql="SELECT * FROM Angebote";
//-run the query against the mysql query function
$result=mysql_query($sql);
//Show Results
while($row=mysql_fetch_array($result)){
//Start table ?>
<tr>
<td class="col-sm-2"><?php echo $Name =$row['Name'] ; ?></td>
<!--In this <td>-tag I want to put long textes with links-->
<td class="hidden-xs col-sm-5">echo $Name =$row['Info'];?<</td>
<td class="col-sm-2"><?php echo $Preis =$row['Preis']; ?></td>
<td ckass="col-sm-1"><?php echo $Dauer =$row['Dauer']; ?></td>
</tr>
<?php } ?>
</tbody>
</table>
Thanks in advance for helping.
Don't bother asking me additional questions.
P.S.: I hope you can help, without needing the CSS of Bootstrap, that I used.
P.P.S.:I know that my PHP-Script is not protected against PHP-Injection
(but I want to and will learn how to secure it)
Edit: As Jester asked for it. I made it quickly with photoshop because I think an image can express much better, what I want to achieve, than my poorly coding-skills.
Get to the image
Seems to me like the easiest way would be to just edit the info column in the database for each? If you want to do it in php i'd suggest making an array using the names (ids would be better but it seems you don't have access to those?) as keys:
$info['Aroma Teilkoerper'] = "Text about aroma teilkoerper";
$info['Aroma Ganzkoerper'] = "Text about aroma ganzkoerper";
and so on until you have all. Then in the loop:
//Show Results
while($row=mysql_fetch_array($result)){
//Start table ?>
<tr>
<td class="col-sm-2"><?php echo $Name =$row['Name'] ; ?></td>
<!--In this <td>-tag I want to put long textes with links-->
<td class="hidden-xs col-sm-5">echo $Name =$info[$row['Name']];?></td>
<td class="col-sm-2"><?php echo $Preis =$row['Preis']; ?></td>
<td ckass="col-sm-1"><?php echo $Dauer =$row['Dauer']; ?></td>
</tr>
<?php } ?>
Hoping that is a workable solution for you? (also you had a syntax error in your closing php tag.
echo $Name =$row['Info'];?< // <----- should be ?> of course
I will have to mention first that I have searched for a Google and stackoverflow and anywhere else, as well as tried to use scripts given in forums and write my own ones, but nothing worked for me. I am completely stuck.
So, all I try to do is to write a script that will delete checked rows from MySQL table. Here is my HTML written inside of a PHP file:
<tr class="noP">
<td class="check"><input class="checkbox" name="checkbox[]" type="checkbox" value="'.$row["PID"].'"/></td>
<td class="id">'.$row['PID'].'</th>
<td>'.$row["name"].'</th>
<td>'.$row["surname"].'</th>
<td>'.$row["pcode"].'</th>
<td class="address">'.$row["address"].'</th>
<td class="email">'.$row["email"].'</th>
<td>'.$row["phone"].'</th>
<td class="education">'.$row["education"].'</th>
<td class="remarks">'.$row["remarks"].'</th>
</tr>
for here $row = mysql_fetch_assoc($qParts);, so this array is just a collector of field values from MySQL DB.
Basically, all I try to do is just a table with all the participants listed with ability to delete selected ones.
I would highly appreciate any help provided. Thank you!
This should help you:
foreach($_REQUEST['checkbox'] as $val)
$delIds = intval($val);
$delSql = implode($delIds, ",");
mysql_query("DELETE FROM table WHERE PID IN ($delSql)");
So, that takes your input array from $_GET/$_POST, sanitises it (a little), then implodes it to get a list of IDs (e.g. 5, 7, 9, 13). It then feeds that into an SQL statement, matching on those IDs using the IN operator.
Note that you should do this using prepared statements or similar. It's been a while though, so I can't write them off-hand, but this should give you the gist of it.
To do this using PDO, have a look here. It's a bit more complex, since you need to dynamically create the placeholders, but it should then work the same.
Reference - frequently asked questions about PDO
I think I can help you out. I had the same issue during my semester project. The problem can be solved using HTML and PHP alone.
I am assuming that PID is the primary key in your table. The trick here is to put the entire table in a form so that it looks like this:
<form action="/*NAME OF THIS PAGE HERE*/.php" method="POST">
<?php
if(isset($_POST['delete'])) //THE NAME OF THE BUTTON IS delete.
{
foreach ($_POST["checkbox"] as $id){
$de1 = "DELETE FROM //table-name WHERE PID='$id'";
if(mysqli_query($conn, $de1))
echo "<b>Deletion Successful. </b>";
else
echo "ERROR: Could not execute";
}
}
if(isset($_POST['delete'])){
echo"<b>Please make a selection to complete this operation.</b>";
}
?>
</br>
<!-- below you will see that I had placed an image as the delete button and stated its styles -->
<button type="submit" name="delete" value="delete" style="float:right;border:none; background:none;">
<img style="width:55px; height:55px;margin-left:10px; margin-bottom:6px; float:left;" src="images/del.png">
</button>
<table>
<thead>
<tr>
<th>#</th>
<th>PID</th>
<th>NAME</th>
<th>SURNAME</th>
<!--REST OF THE TABLE HEADINGS HERE -->
</tr>
<?php $fqn="SELECT * FROM //table-name here;
$fqn_run=mysqli_query($conn,$fqn);
while($row=mysqli_fetch_array($fqn_run)):?>
</thead>
<tbody>
<tr class="noP">
<td class="check"><input class="checkbox" name="checkbox[]" type="checkbox" value="<?php echo $row["PID"];?>"></td>
<td><?php echo $row['PID'];?></td>
<td><?php echo $row["name"];?></td>
<td><?php echo $row["surname"];?></td>
<!-- REST OF THE ROWS HERE -->
</tr><?php endwhile;?>
</tbody>
</table>
</div>
</div>
</form>
Hope this helps you.
I'm new to web development and I'm trying to create editable database interface. I have got checkboxes in every row and an edit button. I need to update table(in database) when button clicked(rows that are checked). However I can't get current values in cells. I tried contentedittable div to display attiributes.
<?php while ( $rows = mysql_fetch_array($result)): ?>
<td align="center" bgcolor="#FFFFFF"><input name="need_delete[<?php echo $rows['UniqueID']; ?>]" type="checkbox" id="checkbox[<?php echo $rows['UniqueID']; ?>]" value="<?php echo $rows['UniqueID']; ?>"></td>
<td bgcolor="#FFFFFF"><div contenteditable><?php echo $rows['Timestamp']; ?></div></td>
<td bgcolor="#FFFFFF"><div contenteditable><?php echo $rows['Name']; ?></div></td>
<td bgcolor="#FFFFFF"><div contenteditable><?php echo $rows['Email']; ?></div></td>
<?php endwhile; ?>
I also tried to give unique names to divs, but it didn't work. I want to get current values from there if possible.
<?php
if( ! empty($_POST['edit']) ){
$query = 'UPDATE `asd` SET `Timestamp` = '????' WHERE `UniqueID`='.(int)$id;
mysql_query($query);
}
?>
Checkboxes work fine when I delete rows from table. Any suggestions ?
Thanks.
There are several javascript libraries that help with this problem:
x-editable http://vitalets.github.io/x-editable/ (bootstrap)
datatables https://datatables.net/ (jquery)
I had a similar issue that I solved here:
http://www.abrandao.com/2019/12/saving-contenteditable-html-using-php/
basically, it involves reading the HTML and using PHP parser to exctract the tag and the update the data
I am creating a dummy online store to illustrate some real world functionality which one of them is to search the website for items i.e.
I have written PHP code to deal with this scenario but it does not work properly. Wchat it does dough is it matches the results and the number of results but it does not display them which I of course wont it to do.
Been trying to look for answers on GOOGLE but didn't find corresponding solution or a tip to my problem.
Here am gonna list the code I am using:
PHP code (search.php):
<?php
session_start();
include('connect_mysql.php');
$product_name = 'product_name';
$product_qua = 'product_qua';
$product_price = 'product_price';
$product_image = 'product_image';
$product_des = 'product_des';
if (isset($_POST['keyword']))
{
$search = $_POST['keyword'];
if (!empty($search))
{
$query = "SELECT product_name FROM products WHERE product_name='$search'";
$query_search = mysql_query($query);
echo mysql_num_rows($query_search);
if (mysql_num_rows($query_search) >=1)
{
echo 'Results found: <br>';
while ($query_row = mysql_fetch_row($query_search))
{
echo $query_row['product_name'];
}
while($rows = mysql_fetch_array($query_search))
{ ?>
<table id='display'>
<tr><td><?php echo "<img src=$rows[$product_image] class='grow'>" ?></td></tr>
<tr>
<th></th>
<th><strong>Avalible</strong></th>
<th><strong>Price</strong></th>
<th><strong>Description</strong></th>
</tr>
<tr>
<td width='290px'><?php echo "$rows[$product_name]" ?></td>
<td width='290px'><?php echo "$rows[$product_qua]" ?></td>
<td width='290px'><?php echo "£ $rows[$product_price]" ?></td>
<td width='290px'><?php echo "$rows[$product_des]" ?></td>
</tr>
<tr>
<td><p>Please Login To purchase this item </p><br />Login</td>
</tr>
</table>
<?php
}
} else {
echo 'NO results found.';
}
}
}
?>
HTML code (index.php):
<form action="search.php" method="post">
<input type="text" name="keyword" size="20" placeholder="Search for products...."/>
<input type="submit" value="Search >>" />
</form>
Print screen of current result:
As you have have noticed it also says 3 results have been found which is correct considering i have searched for ever which is a common name of my product but drows up only two tables moreover they are empty.
website url: http://studentnet.kingston.ac.uk/~k1024026/index.php
finally my product table consists of : product_id product_name product_qua product_price product_image product_des product_type attrebiutes/columns
anyone can spot where i might be going wrong with this....?
First, try removing this
while ($query_row = mysql_fetch_row($query_search))
{
echo $query_row['product_name'];
}
I also noticed a few bad typo in your code :
table id="display" an id should be unique. If you iterate over it and still want it to be an id, put display-n instead, n being the unique id of the product for example. (or use class="display" instead of id)
You should take a look at sql injection and how to defeat them.
I might rather do this:
$query = "SELECT product_name FROM products WHERE product_name LIKE %" . $search . "%";
Hope it will help. Then use a foreach loop to run through the result like:
foreach ($search as $key => $result){
echo $result . '<br />';
}
mysql_fetch_row( $query_search) returns a plain array not an associative array but you are trying to access its values using keys - $query_row [ 'product_name' ]. Rather use _fetch_array
There are lots of syntactical errors. There is a space between function name and list of parameters.
Don't use mysql_. They are deprecated (read: dead). Use PDO instead.
I'm trying to use if-statement to change <td>-s color.
Basically, I have a simple query to retrieve information from the database.
Additionaly, I have a column there which keeps the information like if the task is accomplished or not. When I retrieve the information I get all of them, but I need the accomplished tasks to be green, and others without any color.
I've searhed for the answer, but I couldn't find anything that satisfies me.
For example:
$qry = mysql_query("select * from table");
$recs = array();
while($row = mysql_fetch_array($qry))
$recs[]=$row;
mysql_free_result($qry);
I've tried to add while statement to the code above, but I was confused and it didnt work :(
I'm printing the results using heredoc:
How to give them color here?
<?php
$last_id=0;
foreach($recs as $rec)
{
$html=<<<HTML
<tr>
<td><b>Номер</b></td>
<td>$rec[0]</td>
</tr>
<tr>
<td><b>Номер документа</b></td>
<td>$rec[1]</td>
</tr>
<tr>
<td><b>Дата регистрации</b></td>
<td>$rec[8]</td>
</tr>
<tr>
<td><b>От кого</b></td>
<td>$rec[2]</td>
</tr>
<tr>
<td><b>По</b></td>
<td>$rec[4]</td>
</tr>
<tr>
<td><b>Краткое содержание</b></td>
<td>$rec[3]</td>
</tr>
<tr>
<td><b>Исполнитель</b></td>
<td>$rec[5]</td>
</tr>
<tr>
<td><b>Срок исполнения</b></td>
<td>$rec[6]</td>
</tr>
<tr>
<td><b>Срок исполнения продлен до</b></td>
<td><b>$rec[10]</b></td>
</tr>
<tr>
<td><b>Прислан</b></td>
<td>$rec[9]</td>
</tr>
<tr>
<td><b>Примечание</b></td>
<td>$rec[7]</td>
</tr>
<tr>
<td bgcolor="#838B83"> </td>
<td bgcolor="#838B83"> </td>
</tr>
HTML;
print $html;
if($rec[0]>$last_id)
$last_id=$rec[0];
};
$new_id=$last_id+1;
?>
rather than colour use a class, so you can change it in CSS
<td<?php if($row['complete']) echo ' class="complete"'; ?>>data</td>
<table>
<tr>
<td>column heading</td>
</tr>
<?php
$qry=mysql_query("select * from table");
while($row=mysql_fetch_array($qry)) {
if($row['urcolumnn']==1)
{
echo "<tr bgcolor=green>";
}
else
{
echo "<tr>";
}
?>
<td>
<?php echo $row['urcolumn']; ?>
</td>
</tr>
<?php } ?>
</table>
This is an example code. think this will help you. here i give the background color to <tr> like this if u want to give color to <td> use this <td style="background-color:green;">
I would suggest you to use ternary operator, rather than using IF statement, or your could use another workaround to use arrays to define colors, this would help you to define various colors for each status value globally, please find an example below:
$aryColor = array(
'complete' => 'green',
'incomplete' => "red",
'pending' => 'orange'
.....
);
//you can specify values for all of your status, or leave them blank for no color, the keys in the array are the possible values from your status field
foreach($recs as $rec) {
echo '<tr bgcolor="'.$aryColor[$rec['status_field']].'">
<td>'.$rec['title_field'].'</td>
</tr>';
}
I hope this helps you out, and you can easily edit this for HEREDOC.
first you should change your column values change its structure to int and set default value as "0".so when your task is complete the field value should be change to "1".
now come to your code:
$qry = mysql_query("select * from table");
while($row = mysql_fetch_assoc($qry)){
if($row['status']==1){
echo "<td color="green">Data</td>"
}
else{
echo "<td color="white">Data</td>";
}
}
Hence you can get the rows in green which status is==1 means complete and white for incomplete.