I got to table need to combine into 1
Table 1 :
| ID | FEEDBACK_VALUE |
| 1 | EMAILS |
| 2 | WALK IN |
| 3 | SMS BLAST |
| 4 | SOCIAL MEDIA |
| 5 | NEWSPAPER |
| 6 | FAMILY & FRIEND |
| 7 | OTHERS |
Table 2 :
| ID | FEEDBACK_ID |
| 1 | 1 |
| 2 | 2 |
| 3 | 2 |
| 4 | 7 |
| 5 | 7 |
| 6 | 7 |
| 7 | 4 |
| 8 | 4 |
| 9 | 3 |
Table 3 :
| ID | FEEDBACK_VALUE | FEEDBACK_RECEIVE |
| 1 | EMAILS | 1 |
| 2 | WALK IN | 2 |
| 3 | SMS BLAST | 1 |
| 4 | SOCIAL MEDIA | 2 |
| 5 | NEWSPAPER | 0 |
| 6 | FAMILY & FRIEND | 0 |
| 7 | OTHERS | 3 |
From table 1 and 2, How can i get result like table 3 using mysql? Thanks
You could use a left jojn, and subquery with count group by
select t1.ID, t1.FEEDBACK_VALUE, ifnull( my_count,0) feedback_receive
from table1 t1
left join (
select FEEDBACK_ID, count(*) as my_count
from table 2
group by FEEDBACK_ID
) t on t1.ID = t.FEEDBACK_ID
Just use a subquery as shown below:
SELECT A.*, (SELECT COUNT(*) FROM TABLE2 B WHERE A.ID=B.FEEDBACK_ID) AS FEEDBACK_RECEIVE
FROM TABLE1 A;
See DEMO on SQL Fiddle
Or, if less code is your thing...
SELECT x.*
, COUNT(y.id) total
FROM table_1 x
LEFT
JOIN table_2 y
ON y.feedback_id = x.id
GROUP
BY x.id;
Related
I have 3 tables
Table#1: groups
|---------------|---------------|
| id_group | Name |
|-------------------------------|
| 1 | Group 1 |
--------------------------------|
| 2 | Group 2 |
--------------------------------|
| 3 | Group 3 |
--------------------------------|
Table#2: jobs
|---------------|---------------|----------------------|
| id_job | id_group | name_job |
|---------------|--------------------------------------|
| 1 | 1 | name_1 |
-------------------------------------------------------|
| 2 | 1 | name_2 |
-------------------------------------------------------|
| 3 | 2 | name_3 |
-------------------------------------------------------|
| 4 | 3 | name_4 |
-------------------------------------------------------|
| 5 | 3 | name_5 |
-------------------------------------------------------|
| 6 | 3 | name_6 |
-------------------------------------------------------|
Table#3: users
|---------------|---------------|
| user | id_job |
|-------------------------------|
| A | 1 |
--------------------------------|
| B | 1 |
--------------------------------|
| C | 4 |
--------------------------------|
| D | 6 |
--------------------------------|
If I were an user (e.g C), the result I'd look for is a page where there is a table with 2 columns (USERS | JOB).
The column USERS should be filled in with all the users who share the same group. The column JOB should be filled in with all name_job of the specific group group as follows:
LOGIN: C
|---------------|---------------|
| user | job |
|-------------------------------|
| C | name_4, |
| | name_5, |
| | name_6 |
--------------------------------|
| D | name_4, |
| | name_5, |
| | name_6 |
--------------------------------|
I tried with this code, but the result is that I can read people who share the same group with me, but I can't read the jobs.
SELECT users.* jobs.*
FROM users JOIN jobs ON users.id_job=jobs.id_job
WHERE job.id_group IN
(SELECT job.id_group
FROM users JOIN jobs ON users.id_job = jobs.id_job
WHERE users.user= '$login')
Your help is appreciated in advance.
If I follow you correctly, you want the list all jobs of the group the user belongs to. One option uses a correlated subquery and string aggregation:
select u.*,
(
select group_concat(j1.name_job order by j1.id_job)
from jobs j
inner join jobs j1 on j1.id_group = j.id_group
where j.id_job = u.id_job
) as job_names
from users u
I need help to resolve this.
I have 4 tables :
Transactions
| id | cid | gt | rt |
| 1 | 6 | 2 | 5 |
| 2 | 6 | 9 | 7.5 |
| 3 | 6 | 3 | 9.7 |
| 4 | 3 | 3 | 7.0 |
| 5 | 3 | 7 | 6.8 |
| 6 | 9 | 4 | 2.5 |
| 7 | 9 | 2 | 5.4 |
Clients
| id | firstname | lastname | date |
| 1 | jean | moulin | 1987 |
| 2 | salah | fera | 1968
| 3 | marouan | youra | 2001 |
| 4 | amin | esa | 1963 |
| 5 | kamal | tara | 1789 |
| 6 | moad | mara | 2005 |
| 9 | safaa | dara | 2004 |
Produit A
| id | cid |
| 1 | 6 |
| 2 | 6 |
| 3 | 3 |
| 4 | 3 |
| 5 | 3 |
| 6 | 4 |
| 7 | 1 |
Produit B
| id | cid |
| 1 | 6 |
| 2 | 3 |
| 3 | 9 |
| 4 | 3 |
| 5 | 3 |
| 6 | 4 |
| 7 | 6 |
The result that i need is :
cid | name | date | pa | pb | gt | rt |
3 | | | | | | |
6 | | | | | | |
9 | | | | | | |
I need to select from transaction all distinct client id (pid) and select the firstname and last name (name = firstname lastname) and date from clients table and sum all values (gt) and (rt) and search in table produitA the number of products for this client by his id and the same thing for the table produitB.
What i do for this but it don't work is (suggested by Gimeniux):
SELECT
clients.id,
CONCAT(firstname, ' ', lastname) as name,
date,
count(distinct produitA.id) as pa,
count(distinct produitB.id) as pb,
sum(gt) AS gt,
sum(rt) AS rt
FROM clients
LEFT JOIN transactions ON clients.id = transactions.pid
LEFT JOIN produitA ON clients.id = produitA.cid
LEFT JOIN produitB ON clients.id = produitB.cid
where pid is not null
group by clients.id
The probleme here is that gt and rt values are true for only the first client. For the second client and third and ... there is different values that are not true.
Although is hard for me to see the logic between your tables, you can use this query to get the result you desire. But i think it won't work if there are two same 'gt' or two same 'rt' values for one client.
SELECT
clients.id,
CONCAT(firstname, ' ', lastname) as name,
date,
count(distinct produitA.id) as pa,
count(distinct produitB.id) as pb,
sum(distinct gt) AS gt,
sum(distinct rt) AS rt
FROM clients
LEFT JOIN transactions ON clients.id = transactions.pid
LEFT JOIN produitA ON clients.id = produitA.cid
LEFT JOIN produitB ON clients.id = produitB.cid
where pid is not null
group by clients.id
Row for pid=9 doesn't show because in the data you gave there is no client with id=9
Here is my data
cardNo| userName| tablename| hours | date
1 | a | a | 12 | 12-06-2015
1 | a | a | 5 | 11-06-2015
2 | b | b | 3 | 15-06-2015
1 | a | a | 8 | 12-06-2015
2 | b | b | 3 | 21-06-2015
1 | a | a | 12 | 14-06-2015
2 | b | b | 10 | 8-06-2015
cardNo is unique. I need to display all details and total hours for each card, like:
cardNo | userName | tablename | totalhours
1 | a | a | 37
2 | b | b | 16
It's simple SUM() with GROUP BY:
SELECT cardNo,sum(hours)
FROM yourtable
GROUP BY cardNo;
I left it as an exercise for the OP to include userName and tablename columns into the query
SELECT cardNo,userName, tablename, sum(hours) hours
FROM Table_1 GROUP BY cardNo,userName,tablename
I have three tables and they are the following
User Table
+---------+-----------+--------+
| user_id | user_name | branch |
+---------+-----------+--------+
| 1 | John | 1 |
| 2 | Jim | 2 |
| 3 | Jern | 3 |
| 4 | Jack | 1 |
| 5 | Jery | 2 |
| 6 | Tom | 3 |
| 7 | Sona | 1 |
| 8 | Tina | 3 |
+---------+-----------+--------+
Branch Table
+-----------+----------------+
| branch_id | branch_name |
+-----------+----------------+
| 1 | IT |
| 2 | SALES |
| 3 | Administration |
+-----------+----------------+
Enquiry Table
+------------+---------------+---------+
| enquiry_id | enquiry_name | user_id |
+------------+---------------+---------+
| 1 | enqury_test1 | 1 |
| 2 | enqury_test2 | 2 |
| 3 | enqury_test3 | 1 |
| 4 | enqury_test4 | 3 |
| 5 | enqury_test5 | 2 |
| 6 | enqury_test6 | 5 |
| 7 | enqury_test7 | 1 |
| 8 | enqury_test8 | 2 |
| 9 | enqury_test9 | 4 |
| 10 | enqury_test10 | 6 |
| 11 | enqury_test11 | 2 |
| 12 | enqury_test12 | 7 |
+------------+---------------+---------+
From the above tables its clear that, each branch contains a number of users.
These users post multiple enquiries.
I need to get the total number of enquiries in each branch as
branch id => number of enquiries
I have tried various queries. But i couldn't get the result. Any one can help?
I am using MySQL and i need a single query to do this.
Thanks in advance
You need count and group by
select
b.branch_id,
count(e.user_id) as `total_enq`
from Branch b
left join User u on u.branch = b.branch_id
left join Enquiry e on e.user_id = u.user_id
group by b.branch_id
The query you have to perform to get you desired result is like this :-
$query = "SELECT u.branch, COUNT(u.user_id) AS `total_enquires`
FROM enquiry e INNER JOIN user u ON e.user_id = u.user_id
GROUP BY u.branch"
This will help you,and i think you don't need to join branch table as user table already contain branch_id.
This is the query
SELECT `branch`,`branch_name`,count(`user`.`user_id`),count(`enquiry_id`) FROM `user` inner join `branch` on `user`.`branch`=`branch`.`branch_id` inner join `enquiry` on `user`.`user_id`=`enquiry`.`user_id` group by `branch`
try it here
http://sqlfiddle.com/#!9/cf3eb/1
SELECT
bt.branch_id
,COUNT(enquiry_id) AS total_enquiry
FROM
enquiry_table et
INNER JOIN user_table ut on ut.user_id = et.user_id
INNER JOIN branch_table bt ON bt.branch_id = ut.branch
WHERE
1=1
GROUP BY
bt.branch_id
you can try this
I have two tables:
table pin_info:
id | member_id | look_week | look_name | is_pinned | date
1 | 1 | 3 | the improviser | yes | 2013-11-19 21:57:04
2 | 1 | 2 | destined for stardom | yes | 2013-11-19 21:56:00
3 | 1 | 1 | fashinably corporate | no | 2013-11-19 21:54:00
table arrow_rating:
id | member_id | look_week | look_name | rating |
1 | 1 | 3 | the improviser | 3 |
2 | 1 | 2 | destined for stardom | 4 |
3 | 2 | 1 | fashinably corporate | 5 |
I want is_pinned(from pin_info) and rating(from rating) .I will be having parameter member_id and look_week. (assume 1 and 2 respectively)
What I have done:
SELECT p_i.is_pinned,a_r.rating
FROM pin_info p_i,arrow_rating a_r
WHERE p_i.look_week=a_r.look_week AND p_i.member_id='1'
I am sure this is not the correct way.Any help?
Try this:
SELECT pin_info.is_pinned, arrow_rating
FROM pin_info INNER JOIN arrow_rating
ON pin_info.look_week = arrow_rating.look_week
WHERE pin_info.id = '1';
SELECT is_pinned, rating
FROM pin_info
LEFT JOIN arrow_rating USING (look_week, member_id)
WHERE pin_info.member_id = 1
AND pin_info.look_week = 2
That will select where both member_ids equal 1, and look_week equals 2
The result set for the above is:
is_pinned | rating
------------------
yes | 4