PHP insert function not working [duplicate] - php

Question

This question already has answers here:
Reference: What is variable scope, which variables are accessible from where and what are "undefined variable" errors?
(3 answers)
Why does this PDO statement silently fail?
(2 answers)
Closed 5 years ago.
I'm trying to make some insert function, but something is wrong, and can find where is the problem. Basically o just set some informations, and this same should be insert in database. The message errors are:
Notice: Undefined variable: conn in /Applications/AMPPS/www/teste/index.php on line 21
Fatal error: Call to a member function query() on a non-object in /Applications/AMPPS/www/teste/index.php on line 21
ini_set('display_errors',1);
ini_set('display_startup_erros',1);
error_reporting(E_ALL);
$dbtype = "mysql";
$dbhost = "XXXXXXXXXX";
$dbname = "XXXXXXXXXX";
$dbuser = "XXXXXXXXXX";
$dbpass = "XXXXXXXXXX";
$conn = new PDO("mysql:host=$dbhost;dbname=$dbname",$dbuser,$dbpass);
function Insertdata($table,$field,$data){
$field_values= implode(',',$field);
$data_values=implode(',',$data);
$sql = "INSERT into". " ".$table." ".$field_values. "VALUES(".$data_values.")";
$result = $conn->query($sql);
}
$table="teste";
$field_values=array("nome","idade","email","cidade");
$data_values=array("Teste","14","teste#yahoo.com","Rio de Janeiro");
$sample = Insertdata($table,$field_values,$data_values);
if($result)
{
echo "inserted";
}
else
{
echo "not inserted";
}

Answer 1

You didn't pass $conn to your function, you'll need to do that in order to have it in scope:
function Insertdata($table, $field, $data, $conn){
$field_values= implode(',',$field);
$data_values=implode(',',$data);
$sql = "INSERT into". " ".$table." ".$field_values. "VALUES(".$data_values.")";
$result = $conn->query($sql);
}