I'm building an app with Laravel 5.5. and I need to customize the pagination. I have to apply css class on the page link elements. Where I find the template to override?
You have to launch this command from terminal:
php artisan vendor:publish --tag=laravel-pagination
This creates the views in the resources/views/vendor/pagination directory.
Now you can apply your classes in the view: default.blade.php.
Read the documentation here: https://laravel.com/docs/5.6/pagination#customizing-the-pagination-view
You can specify your own pagination view:
{{ $paginator->links('view.name') }}
From the docs:
By default, the views rendered to display the pagination links are compatible with the Bootstrap CSS framework. However, if you are not using Bootstrap, you are free to define your own views to render these links. When calling the links method on a paginator instance, pass the view name as the first argument to the method
Or you can customize the default view.
From the docs:
However, the easiest way to customize the pagination views is by exporting them to your resources/views/vendor directory using the vendor:publish command:
php artisan vendor:publish --tag=laravel-pagination
This command will place the views in the resources/views/vendor/pagination directory. The default.blade.php file within this directory corresponds to the default pagination view. Edit this file to modify the pagination HTML.
Or, if you've just modified default Bootstrap classes, you can just load CSS after Bootstrap is loaded.
You need to publish the views first with php artisan vendor:publish --tag=laravel-pagination then they will appear in your resources/views/vendor/pagination folder and you can override them. Here is the reference
This command will place the views in the resources/views/vendor/pagination directory. The default.blade.php file within this directory corresponds to the default pagination view. Simply edit this file to modify the pagination HTML.
Related
I want to make a component in Laravel 8 by this command: php artisan make:component forms.input --view that means i want a component with only a Blade template and no class.
But i m Getting this ERROR: The "--view" option does not exist. Thanks for the tips
well, you may create a sub-directory under components let's say ...components/buttons.
Then just create a blade file representing your component for example round.blade.php.
use this component in any template like so <x-buttons.round /> and your component will be rendered correctly in your template.
I have a site under Laravel based on a template uploaded on Themeforest. I use the CSS proposed by this template. I would like to set up custom CSS rules but I have the impression that Laravel has a cache. No CSS changes are displayed. I have the problem in two cases: if I make a new CSS file or even if I modify an existing CSS file.
I tried to clear my browser's cache.
I tried to clear Laravel's cache with artisan views:clear and artisan cache:clear.
I also checked that my CSS files were included in my Blade file.
This is strange because if I put CSS directives directly into my Blade file as HTML (style=""") it works. But once it's in an external file it doesn't work.
Do you have any leads ?
Please try this code for the bootstrap cache clear.
php artisan cache:clear
php artisan config:cache
or
php artisan optomize
I try to make my own version of a vendor blade template.
I dont want to extends the controller with the reference of the view.
So in my AppServiceProvider I add this line:
// Custom views for passport
$this->loadViewsFrom(__DIR__.'/../../resources/views/oauth/passport', 'passport');
I created a file named authorize.blade.php in /resources/views/oauth/passport
In the vendor controller method we can see this:
return $this->response->view('passport::authorize');
The problem is when I call the vendor controller method it loads his version of authorize.blade.php. I would like mine to be loaded and I expected the new line I added to AppServiceProvider to do that.
Passport comes with VUE components and views you need to publish first to override them. From the Laravel Passport page:
"If you would like to customize the authorization approval screen, you may publish Passport's views using the vendor:publish Artisan command."
All you need to do is run php artisan vendor:publish --tag=passport-views and the vendor views will be place in resources/views/vendor/passport, where you can edit them.
Use can use php artisan vendor:publish --tag=passport-views this will copy the views to your views folder for you to change.
So in my AppServiceProvider I add this line:
// Custom views for passport
$this->loadViewsFrom(DIR.'/../../resources/views/oauth/passport',
'passport');
You can use this option only by placing it in registry () instead of boot(). And then you can use your Views regardless of whether they were published in Vendor or not
I'm using Symfony2.8 and when ever I use the command line for generating controllers and twig templates the templates are created under
MyBundle/Resources/views/home/home.html.twig
I want to follow the best practices suggested by symfony docs and have it inside of the
app/Resources/views/home/home.html.twig
I could just cut and paste the twig file and then change the {% extends %} if necessary, but then I would have lesser hair on my head because I would be pulling it out.
So what do I type in the prompt so that it generates the controller in the MyBundle as usual BUT the twig files would be under the global app/Resources/views folder
Thanks!
Edit: new extended question
After playing a little with the path for template generation i succeeded in placing the twig file inside the app/Resources/views/ folder.
Assuming that you have the standard architecture of a symfony2 app:
You could write the following path for the template when generator asks to specify the Templatename
Templatename (optional) [AppBundle:Post:get.html.twig]: ::../../../../app/Resources/views/Post/get.html.twig
I am new to Zend Framework, and i am attempting to remove an action using ZF command line tools. However, i am not able to do so. Basically, there's a function to an action in my controller that i wish to remove. I created the action using the following command:
Action
zf create action name controller-name[=Index] view-included[=1] module
Is there a command to remove it?
There is no command in Zend_Tool for that. You need to do that manually, by removing the action method in the controller and deleting the view script. You have also to edit the .zfproject.xml in the root of your project.
If you remove any controller or action manually, you have to also edit .zfproject.xml file on the root of your project, otherwise it will not allow you to create that controller or action in future again with zend tool.
Go to your application root and edit .zfproject.xml file. This is the file, where zf command will create each controller and action log. remove those actions from there and from controller files and also the views.