I suuuuuck at regex and can't even begin to figure out how to remove everything from #edit to the end which contains a veriable of the url from this kind of URL:
https://docs.google.com/presentation/d/1aa_xpsyJtslFJsg4UndsjDvlCe7Vu97_i6Q8zSKofy4/edit?usp=sharing
Any help would be greatly appreciated!
Thanks!
Using strstr() with the third parameter set to true will be the cleanest, most direct non-regex approach. ...and you won't have to sweat your "suuuuucky" regex skills ;) This will isolate the substring from start of the string to the character before your search substring.
Code: (Demo)
$url = 'https://docs.google.com/presentation/d/1aa_xpsyJtslFJsg4UndsjDvlCe7Vu97_i6Q8zSKofy4/edit?usp=sharing';
echo strstr($url, '/edit', true); // https://docs.google.com/presentation/d/1aa_xpsyJtslFJsg4UndsjDvlCe7Vu97_i6Q8zSKofy4
echo "\n";
echo strstr($url, '/edit?', true); // https://docs.google.com/presentation/d/1aa_xpsyJtslFJsg4UndsjDvlCe7Vu97_i6Q8zSKofy4
*note: If the querystring (beginning witih ?) will always exist after /edit, adding the ? to the search substring can only improve accuracy.
Why is this the best function to call? It doesn't leverage the overhead of calling the regex engine, it doesn't generate any temporary arrays, and it is a single function call as opposed to substr()-strrpos().
If your use cases are a bit more complex and this approach is letting you down, calling parse_url() should stabilize things sufficiently to allow you extract the appropriate url components.
Code: (Demo)
$url = 'https://docs.google.com/presentation/d/1aa_xpsyJtslFJsg4UndsjDvlCe7Vu97_i6Q8zSKofy4/edit?usp=sharing';
$components = parse_url($url);
echo $components['scheme'], '://', $components['host'], strstr($components['path'],'/edit',true);
I believe you are trying to parse the query parameters at the end of the url. You can do so by using the explode function:
$url = "https://docs.google.com/presentation/d/1aa_xpsyJtslFJsg4UndsjDvlCe7Vu97_i6Q8zSKofy4/edit?usp=sharing";
print(explode('/edit', $url)[1]);
which will print
?usp=sharing
Related
Hi all i know preg_replace can be used for formatting string but
i need help in that concerned area
my url will be like this
www.example.com/en/index.php
or
www.example.com/fr/index.php
what i want is to get
result as
www.example.com/index.php
i need it in php code so as to set in a session
can anyone please explain how ?
preg_replace('/www.example.com\/(.+)\/index.php/i', "www.example.com/index.php?lang=$1", $url); will do the thing
This is one way to do it:-
$newurl = preg_replace('/\/[a-z][a-z]\//', '/', $url);
Note that the search string appears with quotes and forward slashes ('/.../') and that the forward slashes in the URL then have to be escaped (\/). The language code is then matched with '[a-z][a-z]', but there are several other ways to do this and you may want something more liberal in case there are ever 3 letter codes, or caps. Equally you may need to do something tighter depending on what other URL schemes might appear.
I suspect in this instance it would be faster simply to use str_replace as follows:
$cleanedData = str_replace(array('www.example.com/en/', 'www.example.com/fr/'), '', $sourceData);
Finally i got a method my thanks to Purpletoucan
$newurl = preg_replace('/\/(en|esp|fr)\//', '/', $url);
it's working now i think!
I’m working on a small hoppy project where I want to replace a specific page on a URL. Let me explain:
I’ve got the URL
http://www.example.com/article/paragraph/low/
I want to keep the URL but replace the last segment /low/ with /high/ so the new URL is:
http://www.example.com/article/paragraph/high/
I’ve tried different explode, split and splice but I just can’t seem to wrap my head around it and make it work. I can change the entire URL but not just the last segment and save it in a new variable.
I’m pretty confidence that it is a pretty straight forward case but I’ve never worked that much with arrays / string-manipulation in PHP so I’m pretty lost.
I guess that I have to first split the URL up in segments, using the "\" to separate it (I tried that but have problems by using explode("\", $string)) and then replace the last \low\ with \high\
Hope someone could help or point me in the right direction to what methods to use for doing this.
Sincere
Mestika
how about str_replace?
<?php
$newurl = str_replace('low', 'high', $oldurl);
?>
documentation;
http://php.net/manual/en/function.str-replace.php
edit;
Rik is right; if your domain (or any other part of the url for that matter) includes the string "low", this will mess up your link.
So: if your url may contain multiple 'low' 's, you will have to add an extra indicator in the script. An example of that would be including the /'s in your str_replace.
You took \ for /.
$url = explode('/', rtrim($url, '/'));
if (end($url) == 'low') {
$url[count($url)-1] = 'high';
}
$url = implode('/', $url) .'/';
Use parse_url to split the URL into its components, modify them as required (here you can use explode to split the path into its segments), and then rebuild the URL with http_build_url.
<?php
class TestURL extends PHPUnit_Framework_TestCase {
public function testURL() {
$URL = 'http://www.mydomain.com/article/paragraph/low/';
$explode = explode('/', $URL);
$explode[5] = 'high';
$expected = 'http://www.mydomain.com/article/paragraph/high/';
$actual = implode('/', $explode);
$this->assertEquals($expected, $actual);
}
}
--
phpunit simple-test.php
PHPUnit 3.4.13 by Sebastian Bergmann.
.
Time: 0 seconds, Memory: 4.75Mb
OK (1 test, 1 assertion)
This will probably be enough:
$url = "http://www.mydomain.com/article/paragraph/low/";
$newUrl = str_replace('/low/', '/high/', $url);
or with regular expressions (it allows more flexibility)
$url = "http://www.mydomain.com/article/paragraph/low/";
$newUrl = preg_replace('/low(\/?)$/', 'high$1', $url);
Note that the string approach will replace any low segment and only if it's followed by a /. The regex approach will replace low only if it's the last segment and it may not be followed by a /.
I'm trying to write a regex in php that in a line like
<a href="mypage.php?(some junk)&p=12345&(other junk)" other link stuff>Text</a>
and it will only return me "p=12345", or even "12345". Note that the (some junk)& and the &(otherjunk) may or may not be present.
Can I do this with one expression, or will I need more than one? I can't seem to work out how to do it in one, which is what I would like if at all possible. I'm also open to other methods of doing this, if you have a suggestion.
Thanks
Perhaps a better tactic over using a regular expressoin in this case is to use parse_url.
You can use that to get the query (what comes after the ? in your URL) and split on the '&' character and then the '=' to put things into a nice dictionary.
Use parse_url and parse_str:
$url = 'mypage.php?(some junk)&p=12345&(other junk)';
$parsed_url = parse_url($url);
parse_str($parsed_url['query'], $parsed_str);
echo $parsed_str['p'];
I am trying to get the page or last directory name from a url
for example if the url is: http://www.example.com/dir/ i want it to return dir or if the passed url is http://www.example.com/page.php I want it to return page Notice I do not want the trailing slash or file extension.
I tried this:
$regex = "/.*\.(com|gov|org|net|mil|edu)/([a-z_\-]+).*/i";
$name = strtolower(preg_replace($regex,"$2",$url));
I ran this regex in PHP and it returned nothing. (however I tested the same regex in ActionScript and it worked!)
So what am I doing wrong here, how do I get what I want?
Thanks!!!
Don't use / as the regex delimiter if it also contains slashes. Try this:
$regex = "#^.*\.(com|gov|org|net|mil|edu)/([a-z_\-]+).*$#i";
You may try tho escape the "/" in the middle. That simply closes your regex. So this may work:
$regex = "/.*\.(com|gov|org|net|mil|edu)\/([a-z_\-]+).*/i";
You may also make the regex somewhat more general, but that's another problem.
You can use this
array_pop(explode('/', $url));
Then apply a simple regex to remove any file extension
Assuming you want to match the entire address after the domain portion:
$regex = "%://[^/]+/([^?#]+)%i";
The above assumes a URL of the format extension://domainpart/everythingelse.
Then again, it seems that the problem here isn't that your RegEx isn't powerful enough, just mistyped (closing delimiter in the middle of the string). I'll leave this up for posterity, but I strongly recommend you check out PHP's parse_url() method.
This should adequately deliver:
substr($s = basename($_SERVER['REQUEST_URI']), 0, strrpos($s,'.') ?: strlen($s))
But this is better:
preg_replace('/[#\.\?].*/','',basename($path));
Although, your example is short, so I cannot tell if you want to preserve the entire path or just the last element of it. The preceding example will only preserve the last piece, but this should save the whole path while being generic enough to work with just about anything that can be thrown at you:
preg_replace('~(?:/$|[#\.\?].*)~','',substr(parse_url($path, PHP_URL_PATH),1));
As much as I personally love using regular expressions, more 'crude' (for want of a better word) string functions might be a good alternative for you. The snippet below uses sscanf to parse the path part of the URL for the first bunch of letters.
$url = "http://www.example.com/page.php";
$path = parse_url($url, PHP_URL_PATH);
sscanf($path, '/%[a-z]', $part);
// $part = "page";
This expression:
(?<=^[^:]+://[^.]+(?:\.[^.]+)*/)[^/]*(?=\.[^.]+$|/$)
Gives the following results:
http://www.example.com/dir/ dir
http://www.example.com/foo/dir/ dir
http://www.example.com/page.php page
http://www.example.com/foo/page.php page
Apologies in advance if this is not valid PHP regex - I tested it using RegexBuddy.
Save yourself the regular expression and make PHP's other functions feel more loved.
$url = "http://www.example.com/page.php";
$filename = pathinfo(parse_url($url, PHP_URL_PATH), PATHINFO_FILENAME);
Warning: for PHP 5.2 and up.
i reposted this question because i didn't find a good answer.
i have a string which can contains text with urls.
i want a function to strip all urls from this string and just let the text.
by example the string can contains like this :
1) hey take a look here : http://xxx.xxx/545df5 this is nice!
2) hey take a look here : http://www.xxx.xxx/545df5 this is nice!
3) hey take a look here : xxx.xxx/545df5 this is nice!
4) hey take a look here : www.xxx.xxx/545df5 this is nice!
Thanks
Regular expression for URL and how to use regular expression with php should help you.
What you really need is a solid regex to find urls in a string and you can preg_replace that pattern with nothing. I can tell you though that tracking down a regex like that is not easy. Depending on the variations in the urls you're looking for (i.e. http:// vs https:// vs ftp://) You could run into real trouble trying to account for all that.
Here is a page that I found to be a good start though.
Regex is the way to go as was discussed prior. Finding one isn't that terribly hard (google: url regex pattern) One example returned is here
http://www.geekzilla.co.uk/View2D3B0109-C1B2-4B4E-BFFD-E8088CBC85FD.htm
I would also recommend you test your regex using one of the many fine online regex testers. My favorite (for non-java) is
http://www.regextester.com/
This function should do it(assuming your strings are seperated by space " "):
function isValidURL($url) {
return preg_match('|^http(s)?://[a-z0-9-]+(.[a-z0-9-]+)*(:[0-9]+)?(/.*)?$|i', $url);
}
function cleanUpUrls($urls) {
$urlArray = explode(' ',$urls);
$resultArray = array();
foreach ($urlArray as $url) {
if(!isValidURL($url)) {
$resultArray[] = $url;
}
}
return implode(' ',$resultArray);
}