PHP List items in json data in a table - php

Question

I am doing some requests using php i am getting this json data from the url i am requesting from and i need to list the name and tag category of each different set of brackets or item out in html how would i go about this see my code below
<?php
$query = $_POST['query'];
$cSession = curl_init();
curl_setopt($cSession,CURLOPT_URL,"https://api.spiget.org/v2/search/resources/" + $query);
curl_setopt($cSession,CURLOPT_RETURNTRANSFER,true);
curl_setopt($cSession,CURLOPT_HEADER, false);
$result = curl_exec($cSession);
curl_close($cSession);
$json = json_decode($result);
foreach ($json['items'] as $data)
{
echo "<h3>". $json['name']."</h3>";
echo "<h4>". $json['tag']."</h3>";
echo "\n";
echo "\n";
echo "\n";
};?>
JSON DATA
Warning: A non-numeric value encountered in C:\xampp\htdocs\request.php on line 7
Warning: A non-numeric value encountered in C:\xampp\htdocs\request.php on line 7
Warning: Invalid argument supplied for foreach() in C:\xampp\htdocs\request.php on line 14
Those are the errors i get when the file is run

Answer 1

You define in your json loop as $data so you need to use it in displaying
<?php
$query = $_POST['query'];
$cSession = curl_init();
curl_setopt($cSession,CURLOPT_URL,"https://api.spiget.org/v2/search/resources/" + $query);
curl_setopt($cSession,CURLOPT_RETURNTRANSFER,true);
curl_setopt($cSession,CURLOPT_HEADER, false);
$result = curl_exec($cSession);
curl_close($cSession);
$json = json_decode($result);
foreach ($json['items'] as $data)
{
echo "<h3>". $data['name']."</h3>";
echo "<h4>". $data['tag']."</h3>";
echo "\n";
echo "\n";
echo "\n";
};?>