I would like to update a column row inside MYSQL by adding 50 to the last current number.Means column named sum was 200 and after query, it will update to 250.
I can do this by using two query as follow:
$add1 = 50;
$sql = "SELECT sum FROM table_name WHERE id = '$id' ";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
$row = mysqli_fetch_assoc($result);
$add2 = $row['sum'] + $add1 ;
}
$sql1 = "UPDATE tabel_name SET sum = '$add2' WHERE id = '$id' ";
$result1 = $conn->query($sql1);
However, is there a better way to do this with less code or by one go?
Thanks
You can calculate values directly in UPDATE queries.
$add1 = 50;
$sql1 = "UPDATE tabel_name SET sum = sum + $add1 WHERE id = '$id';";
In case the type of your column sum is not numeric, but contians a string of the given number, you can use the MySQL CAST function to cast it to a number, calculate it and cast it back to a string again:
$sql1 = "UPDATE tabel_name SET sum = CAST((CAST(sum as INT(11)) + $add1) as VARCHAR(11)) WHERE id = '$id';";
Why dont you try By
$sql1 = "UPDATE tabel_name SET sum = sum + 'YOUR VALUE' WHERE id = '$id'
You can do it using UPDATE for this, just change your query like:
$sql = "UPDATE table_name SET sum=sum+value_you_want WHERE id = '$id' ";
Please use this sql query:
$sql1 = "UPDATE tabel_name SET sum = sum + 50 WHERE id = '$id' ";
Related
I need to count the number of columns that have a specific value (1) in a specific row (250). The value of the row is variable according to the query.
I tried the code below, but it didn't work.
$total_r = mysqli_query($con, "SELECT * FROM registers WHERE ID = '$ID' AND 1 IN (column1, column2, column3, column4)";
$total = mysqli_num_rows($total_r);
echo $total;
I need the result as a number, lets say "2 columns" or something like that.
In MySQL Booleans become 0 or 1 in numerical context. So you could add expressions checking for a column to be equal to 1.
SELECT (column1 = 1)
+ (column2 = 1)
+ (column3 = 1)
+ (column4 = 1)
FROM registers
WHERE id = ?;
Check with below query
SELECT COUNT(*) TOT FROM registers WHERE ID = '$ID' AND column1='1' AND column2='1' AND column3='1' AND column4='1'
What finally did was a general query and then fetch and save every column value into a variable. Then i just added them, because the value of each column could be 0 or 1. Here is the code:
$query = mysqli_query($con, "SELECT * FROM registers WHERE ID = '$ID'");
$result = mysqli_fetch_array($query);
$column1 = $result['column1'];
$column2 = $result['column2'];
$column3 = $result['column3'];
$total = $column1 + $column2 + $column3;
If the column has a value = 0, will not be considered into the count.
I am writing a code for MySQL to fetch the 1st row with status is "inactive" and make them "active", but whenever I tried to update the column and make it "active" my query updates multiple rows rather than the single row.
date_default_timezone_set('Asia/Kolkata');
$d = time ();
$date = date("Y-m-d", $d);
$customer_id="1470831854";
$member_details="SELECT * FROM login_update WHERE customer_id ='$customer_id' AND status='inactive' ORDER BY id ASC LIMIT 1 ";
$member = mysql_query($member_details);
while($list = mysql_fetch_array($member)){
$status = $list['status'];
$id = (int)$list['id'];
}
$date_update = "UPDATE login_update SET status='active' WHERE id = '$id'";
$enter_date = mysql_query($date_update);
I think your code should be change as follow
while($list = mysql_fetch_array($member)){
$status = $list['status'];
$customerId = (int)$list['customer_id'];
}
$date_update = "UPDATE login_update SET status='active' WHERE id = '$customerId'";
$enter_date = mysql_query($date_update);
becasue if you get $list['id'] it is always return only 1 unique value from the database then update only one record. I assumed id is your primary key.
table 1
two column >> paid - order_num1
table 2
two column >> order_num2
I want get order_num2 value from table 2 and
update paid(insert paid = 1) in table one with same order_num value
If order_num1=order_num2 then paid = 1 in table 1
$q = mysql_query("select order_num2 from table2 where samevalue = samevalue ");
$x = mysql_fetch_row($q);
mysql_query("update table1 set paid=1 where order_num1='$x['order_num2']'");
But it does not work!
First get from one table and update paid from another table if order_num have same value
Try
$table2 = mysqli_query("SELECT * FROM table2");
$row = mysqli_fetch_array($table2);
$num2 = $row['order_num2'];
$table1 = mysqli_query("SELECT * from table1");
$roww = mysqli_fetch_array($table1);
$num1 = $row['order_num1'];
if ($num2 == $num1) {
$updateDB = mysqli_query("UPDATE table1 SET paid = 1 WHERE order_num1 = '$num2'");
} else {
//Not equal so the paid column wont get updated
}
I want to update the database of the sort order column to increase its value by one if the the new value inserted into the database clashes with the value that is already in the database. May I know how should I go about doing it? Please help! Thanks!
Below is my code (I am not sure whether am I on the right track):
$result = mysql_query("SELECT sortorder FROM information ORDER BY id ASC;");
if($result >= 1 ){
$i=1;
while ($initialorder = mysql_fetch_assoc($result))
{
$initialorder = $initialorder["sortorder"];
if ($sortorder == $initialorder ){
$result6 = mysql_query("SELECT * FROM information
WHERE `sortorder` = '$sortorder'");
$row6 = mysql_fetch_array($result6);
$removethis1 = $row6['id'];
$result7 = mysql_query("UPDATE information
SET `sortorder`= ((SELECT `sortorder`
FROM (SELECT MAX(`sortorder`) AS
'$initialorder' FROM information) AS '$initialorder') + 1)
WHERE id='$removethis1'");
}
$query = "INSERT INTO `information`
(`id`,`page`,`description`,`status`,`sortorder`,`keyword`,`date_added`)
VALUES
('$id','$title','$description','$status',
'$sortorder','$keyword','$date_added')";
$result = mysql_query($query, $conn);
header('Location: index.php?status=1&title='.$title);
$i++; }
}
You can do this:
INSERT INTO ON `information`
...
DUPLICATE KEY UPDATE
sortorder = '".$sortorder + 1." '
Here is my code:
$query1 = "select user, sum(column) as total1 from table1 GROUP BY user";
$result = mysql_query(query1);
$row_query1 = mysql_fech_assoc($result);
do{
$user = $row_query1['user'];
$query2 = "select names, sum(column1) as total2 from table2 WHERE names ='$user' GROUP BY names";
$result2 = mysql_query($query2);
$row_query2 = mysql_fetch_assoc($result2);
$sum = $row_query1['total1'] + $row_query2['total1'];
<tr> <?php echo $sum; ?></tr>
}while($row_query1 = mysql_fech_assoc($result));
I need to get the highest value of $sum from this loop. Can anyone help?
You can do like this.. take a temporary variable($temp) which can have check upon the sum variable($sum).
$query1 = "select user, sum(column) as total1 from table1 GROUP BY user";
$result = mysql_query(query1);
$row_query1 = mysql_fech_assoc($result);
$temp = 0;
do{
$user = $row_query1['user'];
$query2 = "select names, sum(column1) as total2 from table2 WHERE names ='$user' GROUP BY names";
$result2 = mysql_query($query2);
$row_query2 = mysql_fetch_assoc($result2);
$sum = $row_query1['total1'] + $row_query2['total1'];
if($temp < $sum)
$temp = sum;
echo "<tr>$sum</tr>";
}while($row_query1 = mysql_fech_assoc($result));
echo "maximum sum :".$temp;
I would advice doing a JOIN instead of performing the sub queries yourself:
select user, sum(column) + sum(column1) as total
from table1
INNER JOIN table2 ON names = user
GROUP BY user
The rest should be straightforward in code.