Can someone help? I am trying to do a bulk insert (400 rows), everytime it shows an error message after inserted 58 rows in the database, I tried different dataset, it behave the same way.
Warning: PDOStatement::execute(): SQLSTATE[HY093]: Invalid parameter number: number of bound variables does not match number of tokens
Here is the Code:
$rows = $_POST['myTableArray'];
$nrecuser= $_SERVER['REMOTE_ADDR'];
$ndatetime= date('Y-m-d G:i:s');
$sql = "INSERT INTO dbo.rec(ncode, nname, nprimary, ndate, nyear, nperiod,
nref, ntype, nuser, ncategorycode1, ncategorycode2,
ncategorycode3, namount, ndescription, naccount,
nmajorheadcode, ncheck, nrecuser, ndatetime)
VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)";
include_once dirname(__FILE__) . '/includes/db.inc.php';
try
{
$conn->beginTransaction();
$stmt = $conn->prepare($sql);
foreach($rows as $row)
{
array_push($row, $nrecuser, $ndatetime);
$stmt->execute($row);
}
$conn->commit();
exit();
}
catch (PDOException $e)
{
$conn->rollback();
echo $e;
exit();
}
The number of given insert query parameters is not equal values you are passing to insert
It turn out to be a server side issue, all I have to update the php.ini max_input_vars setting. Thanks for the help.
Related
I have this prepared statement and it isn't inserting into the table at all. The connection to my database is working. I am still new to this so I am unsure on what is wrong. The spelling of my table is correct also. My network tab on inspect element doesn't show any errors as if it did insert the data but the table doesn't update with said data.
$stmt = $conn->prepare("INSERT INTO usersreports (DateOfReport,Username,ReportedPostId,ReportedUser,ReportedUserId,ReportedReason,ReportedTopic,Resolved,Response,ActionTaken) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?)");
$stmt->bind_param("ssssssssss", $DateOfReport,$YourUsername,$UsersPostId,$ReportedUsername,$ReportedUserId,$ReportReason,$ReportTopic,$Resolved,$Response,$ActionTaken);
if ( $stmt === false ) {
echo $conn->error;
exit;
}
$stmt->execute();
$stmt->close();
$conn->close();
Can't insert data into DB . When i remove user_id then data is inserted. Please check below my code and help me.
function adddata($data) {
global $db;
if (is_array($data)) {
$stmt = $db->prepare('INSERT INTO `pay` (id, payment, status, itemid, time, user_id) VALUES(?, ?, ?, ?, ?, ?');
$userid = 2;
$stmt->bind_param(
'sdssss',
$data['txn_id'],
$data['payment_amount'],
$data['payment_status'],
$data['item_number'],
date('Y-m-d H:i:s'),
$userid
);
$stmt->execute();
$stmt->close();
return $db->insert_id;
}
return false;
}
It's subtle, but your SQL string is missing a closing bracket:
$stmt = $db->prepare('INSERT INTO `pay` (...) VALUES (?, ?, ?, ?, ?, ?)');
Where the VALUES list was not properly closed.
A lot of problems can be detected and resolved by enabling exceptions in mysqli so mistakes aren't easily ignored. This should show up as a SQL error in your logs.
I can conect to my database just fine, but whenever I try to insert data I get a "Call to a member function bind_param() on a non-object" error, which I know means that I must have mistyped the name of a slot, or something, but I just can't see it, I'm connecting locally, do I have to set up something in MyPhP to allow data to be added from a php file? Thanks in advance.
<?php
include 'connect.php';
if (isset($_POST['Slot1'])) {
$Slot1 = $_POST['Slot1'];
}
if (isset($_POST['Slot2'])) {
$Slot2 = $_POST['Slot2'];
}
if (isset($_POST['Slot3'])) {
$Slot3 = $_POST['Slot3'];
}
if (isset($_POST['Slot4'])) {
$Slot4 = $_POST['Slot4'];
}
if (isset($_POST['Slot5'])) {
$Slot5 = $_POST['Slot5'];
}
if (isset($_POST['Slot6'])) {
$Slot6 = $_POST['Slot6'];
}
if (isset($_POST['Slot7'])) {
$Slot7 = $_POST['Slot7'];
}
$stmt = $db->prepare("INSERT INTO `tabel` (Slot1, Slot 2, Slot3, Slot4,Slot5,
Slot6, Slot7)
VALUES (?, ?, ?, ?, ?, ?,?");
$stmt->bind_param('sssssss',$Slot1,$Slot2,$Slot3,$Slot4,$Slot5,$Slot6,$Slot7);
$stmt->execute();
$stmt->close();
header("Location: Display.php")
?>
You have missed one end parenthese
Replace
$stmt = $db->prepare("INSERT INTO `tabel` (Slot1, Slot 2, Slot3, Slot4,Slot5,
Slot6, Slot7)
VALUES (?, ?, ?, ?, ?, ?,?");
To
$stmt = $db->prepare("INSERT INTO `tabel` (Slot1, Slot 2, Slot3, Slot4,Slot5,
Slot6, Slot7)
VALUES (?, ?, ?, ?, ?, ?,?)");
Try to change your query to
$stmt = $db->prepare("INSERT INTO `tabel` (Slot1, Slot 2, Slot3, Slot4,Slot5,Slot6, Slot7)VALUES (?, ?, ?, ?, ?, ?,?)");
I'm trying out using prepared statements for the first time and running into the following issue with the below code
Error :
Warning: mysqli_stmt_bind_param() expects parameter 1 to be
mysqli_stmt, boolean given
Code :
$stmt = mysqli_prepare($db, "INSERT INTO fragrances(name, description, essentialoils, topnotes, middlenotes, basenotes, reference, year, type, price, fragrancehouse, triangle, extractname, extractreference, extractprice, extractfragrancehouse, disccolour, collarcolour, actuatorcolour)
VALUES(?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)");
mysqli_stmt_bind_param($stmt, 'sssssssssssssssssss', $name, $description, $essentialoils, $topnotes, $middlenotes, $basenotes, $reference, $year, $type, $price, $fragrancehouse, $triangle, $extractname, $extractreference, $extractprice, $extractfragrancehouse, $disccolour, $collarcolour, $actuatorcolour);
mysqli_stmt_execute($stmt);
I've looked at many different questions on here and none of their solutions seem to apply for my problem, does anyone know what the issue is?
$stmt becomes a boolean only when mysqli_prepare returns false.
When this happens it means it failed to prepare the query therefore you need to check for errors:
$stmt = mysqli_stmt_init($db);
if (mysqli_stmt_prepare($stmt, 'INSERT INTO fragrances VALUES...')) {
//it's all good bind and execute here
}else{
//we have a problem
printf("Errormessage: %s\n", mysqli_error($db));
}
The error message means your mysqli_prepare returned a boolean (and for your case, it returned false).
You need to replace all your field name by the character ? to make your prepared statement. This is how it works.
See example in the official documentation
EDIT See also mysqli_error , which will detail your error. In fact, you should always check a variable before using it:
$stmt = mysqli_prepare($db, "....");
if(!$stmt)
echo mysqli_error($db); // display error only for debug. Avoid this in production
It means your SQL was invalid because the prepare is returning false;
Your SQL should be;
$stmt = mysqli_prepare($db, "INSERT INTO fragrances VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ? )");
Each ? is to show where each parameter needs to be bound respectively.
Your INSERT statement is invalid: VALUES clause must be with ? in parantheses (and after field names in parentheses). Also good practice is to check $stmt after assigning:
$stmt = mysqli_prepare($db,
"INSERT INTO fragrances (name, description, essentialoils, topnotes, middlenotes, basenotes, reference, year, type, price, fragrancehouse, triangle, extractname, extractreference, extractprice, extractfragrancehouse, disccolour, collarcolour, actuatorcolour)
VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)");
if ($stmt) {
mysqli_stmt_bind_param($stmt, 'sssssssssssssssssss', $name, $description, $essentialoils, $topnotes, $middlenotes, $basenotes, $reference, $year, $type, $price, $fragrancehouse, $triangle, $extractname, $extractreference, $extractprice, $extractfragrancehouse, $disccolour, $collarcolour, $actuatorcolour);
mysqli_stmt_execute($stmt);
// ...
} else
printf("Error: %s\n", mysqli_error($db));
First of all sorry for my bad English..
I have this function in a model:
function insertUser($data){
$sql = "INSERT INTO USERS VALUES (?, ?, ?, ?, ?, ?, ?, ?)";
$query = $this->db->query($sql, array(
$data["uname"],
$data["nome"],
$data["dnuser"],
$data["muser"],
$data["fruser"],
$data["cpuser"],
$data["euser"],
md5($data["passu"])
));
//return $this->db->_error_number();
}
I have one primary key and when data is correct the function works but when is inserted a duplicate key the function doesn’t work. But how can i know that? i mean how can i catch the error ORA-00001 ??
BTW the commented line doesn’t work..
Thank you very much!!
You can use try catch block...
function insertUser($data){
$sql = "INSERT INTO USERS VALUES (?, ?, ?, ?, ?, ?, ?, ?)";
try{
$this->db->trans_start();
$query = $this->db->query($sql, array(
$data["uname"],
$data["nome"],
$data["dnuser"],
$data["muser"],
$data["fruser"],
$data["cpuser"],
$data["euser"],
md5($data["passu"])
));
$this->db->trans_commit();
}
catch(Exception $ex){
$this->db->trans_rollback();
echo "Error:".$ex;
}
}
You can check the following article..
http://ellislab.com/codeigniter/user-guide/database/transactions.html