public function get_inner_refs($referral){
$query = $this->db->query("SELECT username FROM users WHERE binery_referral='$referral'");
if ($query->num_rows() > 0) {
foreach ($query->result_array() as $row){
$referral = $row['username'];
$referrals[] = $row['username'];
$this->get_inner_refs($referral, $referrals);
}
}
return $referrals;
}
here i want to return an array of all users but it returns only first value from database,
Try to create a private variable to assign to and create a get method:
private $referrals;
public function get_inner_refs($referral)
{
$query = $this->db->query("SELECT username FROM users WHERE binery_referral='$referral'");
if ($query->num_rows() > 0) {
foreach ($query->result_array() as $row){
$username = $row['username'];
$this->referrals[] = $username;
$this->get_inner_refs($username);
}
}
return $this;
}
public function getReferrals()
{
return $this->referrals;
}
Then to use:
$referrals = $ReferralClass->get_inner_refs($username)->getReferrals();
i think you can edit like this
public function get_inner_refs($referral='',$referrals = []){
$query = $this->db->query("SELECT username FROM users WHERE binery_referral='$referral'");
if ($query->num_rows() > 0) {
foreach ($query->result_array() as $row){
$referral = $row['username'];
$referrals[] = $row['username'];
$this->get_inner_refs($referral, $referrals);
}
}
return $referrals;
}
Related
i want to join the data of 2 tables in 1 table and display the data of 2 tables. I already have function that load the one table. can someone modify this function code to get the 2 tables ? im just a beginner in php.
Model_users.php
public function getUserGroup($userId = null)
{
if($userId) {
$sql = "SELECT * FROM user_group WHERE user_id = ?";
$query = $this->db->query($sql, array($userId));
$result = $query->row_array();
$group_id = $result['group_id'];
$g_sql = "SELECT * FROM groups WHERE id = ?";
$g_query = $this->db->query($g_sql, array($group_id));
$q_result = $g_query->row_array();
return $q_result;
}
}
Controller User.php
public function index()
{
if(!in_array('viewUser', $this->permission)) {
redirect('dashboard', 'refresh');
}
$user_data = $this->model_users->getUserData();
$result = array();
foreach ($user_data as $k => $v) {
$result[$k]['user_info'] = $v;
$group = $this->model_users->getUserGroup($v['id']);
$result[$k]['user_group'] = $group;
}
$this->data['user_data'] = $result;
$this->render_template('users/index', $this->data);
}
Here you go
$this->db->select("ug.*,g.*");
$this->db->from("user_group ug");
$this->db->join('groups g', 'ug.user_id = g.group_id');
$this->db->where("ug.user_id",1);
$query = $this->db->get();
if ($query->num_rows() > 0) {
$result = $query->result();
} else {
$result = null;
}
return $result;
Here are my resources first
As you can see on my database I have a Referal_Code and Referral_Link
Now what I am trying to here is I want to get all those Referral_Link that has the same value on the Referal_Code
I know I am no where near to what I am trying to do but I am trying my best really to get this done.
Here what I have tried so far
On my model
public function get_same_referral_code()
{
$this->db->select('referal_code');
$this->db->where('referal_code', 'PoVsw0Epne');
$query = $this->db->get('investor');
if ($query->num_rows() > 0) {
foreach ($query->result() as $row) {
$data[] = $row;
}
return $data;
}
}
and on my controller
public function get_all()
{
$data = array();
$data['title'] = "Rewards";
$data["data"] = $this->investor->get_all_investor();
$data["get_all_flevel"] = $this->investor->get_all_first_level();
$data["referrals"] = $this->investor->get_same_referral_code();
$this->template->load('default_layout','contents','rewards',$data);
}
and I am calling it on my view like this
<?php
echo ($referrals[0][id]);
echo ($referrals[0][firstname]);
echo ($referrals[0][referal_code]);
echo ($referrals[0][referral_link]);
?>
What my expected result should be like this
Could someone help me .
EDIT
I've tried again this way to get what I want .
First I tried to get all the referal_code
public function get_same_referral_code()
{
$this->db->select('referal_code');
$query = $this->db->get('investor');
if ($query->num_rows() > 0) {
foreach ($query->result() as $row) {
$data[] = $row;
}
return $data;
}
}
and now I will going to use this method get_same_referral_code() to check if
referral_link has the same value on the referal_code
public function get_same_referral_link()
{
$this->db->select('referral_link');
$this->db->where('referral_link','get_same_referral_code();');
$query = $this->db->get('investor');
if($query->num_rows() > 0)
{
foreach($query->result() as $row)
{
$data[] = $row;
}
return $data;
}
}
but the problem is that I got this error now
Message: Invalid argument supplied for foreach()
i think sub query will help you
$SQL= "SELECT * FROM tableName WHERE referal_code EXISTS (SELECT DISTINCT Referral_Link FROM tableName)";
$query = $this->db->query($SQL);
return $query->result_array();
or
$SQL= "SELECT * FROM investor WHERE referral_link IN (SELECT DISTINCT referal_code FROM investor)";
$query = $this->db->query($SQL);
return $query->result_array();
This question already has answers here:
return inside foreach php and laravel
(2 answers)
Closed 3 years ago.
Im fairly new to OOP way of coding and I want to fetch a record of users in my DB
This is my code below:
$con = new mysqli('localhost', 'root', '', 'goldpalace');
class User {
public $connect;
public function get_users() {
$sql = "SELECT * from users";
$result = $this->connect->query($sql);
$num_rows = $result->num_rows;
if ($num_rows > 0) {
while ($row = $result->fetch_assoc()) {
$data[] = $row;
return $data;
}
}
}
}
$obj = new User();
$obj->connect = $con;
$user_data = $obj->get_users();
foreach ($user_data as $value) {
echo $value['name']."<br>";
}
I have a lot of records in my DB but it only returns the first row.
That's because you return the value of $data immediately after you retrieve one row. return will return that value and stop execution of that method. You need to return that value after you are done retrieving your values.
class User {
public $connect;
public function get_users() {
$sql = "SELECT * from users";
$result = $this->connect->query($sql);
$num_rows = $result->num_rows;
$data = [];
if ($num_rows > 0) {
while ($row = $result->fetch_assoc()) {
$data[] = $row;
}
}
return $data;
}
}
FYI, you can use fetch_all() here to make this a bit simpler:
class User {
public $connect;
public function get_users() {
$sql = "SELECT * from users";
$result = $this->connect->query($sql);
$num_rows = $result->num_rows;
$data = [];
if ($num_rows > 0) {
$data = $result->fetch_all(MYSQLI_ASSOC);
}
return $data;
}
}
For you return in the first cycle in while
while ($row = $result->fetch_assoc()) {
$data[] = $row;
return $data;
}
just move the return out of while loop
while ($row = $result->fetch_assoc()) {
$data[] = $row;
}
return $data;
I am trying to get all categories with related parent ID with a recursive function.
If i print that array its showing me all data but if i want to return this is not working. I am sure i am doing some mistake.
My code for recursive function is:
public function get_child($id,$level=0){
//$level=0;
$this->db->select('*');
$this->db->from('whole_category');
$this->db->where('parent_id',$id);
$this->db->order_by("id", "ASC");
$query = $this->db->get();
if ($query->num_rows() > 0) {
$res= $query->result();
echo $current_node_id=$res[0]->id;
$level++;
$this->get_child($current_node_id,$level);
$cat["level".$level][] =$res;
return $cat;
}else{
return $cat;
}
}
Calling it like:
public function getcategories(){
echo "<pre>";
$a=$this->get_child(1);
var_dump($a);
}
I had created a Recursive function for a Multi level Marketing Project
Please try it.
public function getSubMembers($memberID, $tableName = 'member_master') {
$data = arra[enter image description here][1]y();
$strQuery = "select MEMBER_ID,LOGIN_NAME,FIRSTNAME,LASTNAME,SPONSOR,PARENT_ID,PAYMENT_STATUS from member_master where SPONSOR='" . $memberID . "' order by POSITION ";
$result = mysqli_query($this->conn, $strQuery);
if (mysqli_field_count($this->conn)) {
while ($row = mysqli_fetch_assoc($result)) {
$data[$row['LOGIN_NAME']] = $row;
foreach ($data as $values) {
$data[$values['LOGIN_NAME']]['SUB'] = $this->getSubMembers($values['LOGIN_NAME']);
}
}
}
return $data;
}
my problem is i whenever i input fname and mname i got an error from the database. i just want to search both of fname and mname in search field.
my search controller function
public function search()
{
$li = $this->session->userdata('logged_in');
$id = $this->session->userdata('idnumber');
if($li == TRUE)
{
$this->load->model('users_model');
$this->load->helper('smiley');
$this->load->library('table');
$image_array = get_clickable_smileys('http://localhost/efg/images/smileys', 'status');
$col_array = $this->table->make_columns($image_array, 8);
$image_array2 = get_clickable_smileys('http://localhost/efg/images/smileys', 'status');
$col_array2 = $this->table->make_columns($image_array2, 8);
$this->data['smiley_table1'] = $this->table->generate($col_array);
$this->data['smiley_tables'] = $this->table->generate($col_array2);
if($this->input->post())
{
$search = $this->input->post('search');
$memb = $this->users_model->search($search);
$usersearch = $this->users_model->search($search);
$grpsearch = $this->users_model->searchgrp($search);
redirect ('home/profile/'.$memb);
}
}
}
My users_model model
public function search($search)
{
$this->db->select('*');
$this->db->from('users');
$this->db->like('username',$search);
$this->db->or_like('fname',$search);
$this->db->or_like('lname',$search);
$this->db->or_like('mname',$search);
$query = $this->db->get();
foreach ($query->result_array() as $row)
{
$memb = $row['idnumber'];
}
$error = 'There is no record for the one you searched. Please go Back.';
$query1 = $this->db->query("SELECT * FROM users WHERE idnumber ='$memb'");
$hehe = $query1->result_array();
if($hehe==NULL)
{
echo $error; exit;
}
else
{
return $memb;
}
}
Always check the varibles using in condition are declared before the condition.
If it doesnt pass the condition what would be the output
public function search($search)
{
$this->db->select('*');
$this->db->from('users');
$this->db->like('username',$search);
$this->db->or_like('fname',$search);
$this->db->or_like('lname',$search);
$this->db->or_like('mname',$search);
$query = $this->db->get();
$memb = null;
foreach ($query->result_array() as $row)
{
$memb = $row['idnumber'];
}
$error = 'There is no record for the one you searched. Please go Back.';
$query1 = $this->db->query("SELECT * FROM users WHERE idnumber =$memb");
$hehe = $query1->result_array();
if($hehe==NULL)
{
return $error;
}
else
{
return $memb;
}
}
Make sure the variables that youll be using in queries are set. Trap before executing queries.
Also, use Query Builder (Active Record) when you can.
public function search($search)
{
$this->db->select('*');
$this->db->from('users');
$this->db->like('username',$search);
$this->db->or_like('fname',$search);
$this->db->or_like('lname',$search);
$this->db->or_like('mname',$search);
$query = $this->db->get();
$memb = '';
if ($query->result_array() > 0) {
foreach ($query->result_array() as $row) {
$memb = $row['idnumber'];
}
if ($memb) {
$this->db->select("*");
$this->db->where("idnumber", $memb);
$query1 = $this->db->get("users");
//$query1 = $this->db->query("SELECT * FROM users WHERE idnumber ='$memb'");
$hehe = $query1->result_array();
return ($hehe) ? $memb : false;
}
return false;
}
$error = 'There is no record for the one you searched. Please go Back.';
return $error;
}