MySQLI how to insert a form into database by language select - php

Question

Im having an issue with form method.
How can I insert a form value in the database in different table by language select.
I have in my database the tables called article_en / articles_ro ,and when I chose with select english I want the values to be inserted in the article_en
Also when I select the language its not staying selected.
And if I write something in the inputs and chose a language the inputs are being cleared.
PS:Im a newby , I am still learning.
This is the language select code
<?php
define("LANG",$_GET['lang']);
include('../db.php');
function select_langs(){
global $conn;
echo'<h2 class="box-title">Select the language where you want to the article</h2>
<select id="select_language">
<option selected disabled hidden value=""></option>';
$get_languages = mysqli_query($conn, "SELECT lang,title from `languages`") or die(mysqli_error($conn));
while($row = mysqli_fetch_array($get_languages)){
if($row['title'] == $_GET['lang']){
echo'<option value="insert_article.php?lang='.$row['lang'].'" selected>'.$row['title'].'</option>';
}
else{
echo'<option value="insert_article.php?lang='.$row['lang'].'">'.$row['title'].'</option>';
}
}
echo'</select>';
}
?>
And this is the insert code.
<?php
include('./lang.php');
include('../db.php');
define("LANG",$_GET['lang']);
select_langs();
// extract data from form; store in variable
$title = $_GET['title'];
$link = $_GET['link'];
if (!empty($title) and !empty($link ) and !empty($_GET['lang'])) {
// Define the query to inser the song request
$sql = "INSERT INTO `articles_".LANG."`(title , link)VALUES (".$title.", ".$link.")";
if (mysqli_query($conn, $sql)) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
mysqli_close($conn);
}
?>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script type="text/javascript">
$("#select_language").bind("change",function(){var n=$(this).val();return""!=n&&(window.location=n),!1});
</script>
<form action="insert_article.php" method="get">
<label id="first">title:</label><br/>
<input type="text" name="title"><br/>
<label id="first">link:</label><br/>
<input type="text" name="link"><br/>
<input type="submit" value="submit">
</form>
Thank You.

Answer 1

I think you need to use ajax to send the details to the php to insert it in your database. It's just easier.
var select_language= document.getElementById("select_language").value;
var title= document.getElementById("title").value;
var link= document.getElementById("link").value;
var data= {select_language: select_language,title: title,link:link};
$.ajax({
type: "POST",
url: "insert.php",
data: data,
cache: false,
success: function(html)
{
console.log (html);
alert("Success");
},
error: function (html)
{
console.log (html);
alert("Failure");
}
});
insert.php
include '../dbconfig.php';
$select_language= mysqli_real_escape_string($db,$_POST['select_language']);
$title = mysqli_real_escape_string($db,$_POST['title']);
$link= mysqli_real_escape_string($db,$_POST['link']);
$query = "your insert query";
mysqli_query($db, $query) or die(mysqli_error($db));
Hope this helps.