Selecting data from other columns - php

Question

I've rather new at php and mysqli and I've had some success but am currently facing a wall. Mostly because I dont know the terms to express what i'm trying to do.
I can select a row all day long but I seem to be stuck on the same row. I need to be able to select data from further down the column. Here is the code i'm working with.
$qry = "select * from products";
$rs = mysqli_query($conn,$qry);
$getRow = mysqli_fetch_row($rs);
$getRowAssoc = mysqli_fetch_assoc($rs);
echo "<img src=\"".$getRow['1'] . "\">";
i have several links to images in the picture column on my database but can't seem to figure out a simple way to display the links from other rows in that column. I may be way off base here but I dont think I am.
this is a layout of the db db pic
any help would be much appreciated

Answer 1

For each mysqli_fetch_assoc you get the result of the next row. As the index starts in -1, the first time you call it, it goes to the first row. So whenever you call it again, it goes to the next row. Use it inside of a loop and you will be all set.
while($row = mysqli_fetch_assoc($result)){
// $row will have new content each iteration
}

Answer 2

mysqli_fetch_assoc Fetch a result row as an associative array, but just 1 row, if you want to get all the result, you have to go through a loop to get everything for the result, example :
<?php
$query = 'SELECT `products`.* FROM `products`';
$mysqli = new Mysqli('localhost','test','root','password');
$result = $mysqli->query($query);
while ($row = $result->fetch_assoc()) {
echo '<img src="' . htmlentities($row['pic']) . '" /><hr />';
}
unset($row);
$result->free();
$mysqli->close();
if you want to get all the rows in 1 step for later usage, you would use mysqli::fetch_all(), example :
<?php
$query = 'SELECT `products`.* FROM `products`';
$mysqli = new Mysqli('localhost','test','root','password');
$result = $mysqli->query($query);
$products = $result->fetch_all();
$result->free();
$mysqli->close();
print_r($products);