SQL multi order - php

Assume this array is my db table.
array('1','1','1','2','2','2','3','3','3','4','4','4','4','5','5','5','5');
in that table i have status from 1 to 5. but i want get data first with status = 2,sec 5 ... ,1,3,4.
is it possible ? if not how can i do it with php.

You may order using FIELD:
SELECT *
FROM yourTable
ORDER BY FIELD(status,2,5,1,3,4);
Demo

If you get the array from a table then you could use a CASE WHEN in the ORDER BY of your query
For example:
select num
from YourTable
order by (case when num = 2 then 1 when num = 5 then 2 else num+2 end);

Related

How select next row pagination in sql

I'm sorry I'm weak for English.
i echo 2 row in each page . how echo next 2 row
SELECT *
FROM `mzmx_post`
JOIN mzmx_post_category
WHERE mzmx_post.id = mzmx_post_category.post_id AND zmx_post_category.category_id = 5
ORDER BY id DESC
LIMIT 2
You can use the two-arguments form of LIMIT to offset the result by a given number of rows, like:
SELECT *
FROM `mzmx_post`
JOIN mzmx_post_category ON mzmx_post.id = mzmx_post_category.post_id
WHERE mzmx_post_category.category_id = 5
ORDER BY id DESC
LIMIT 2, 2 -- fetch records 3 and 4
This gives you the second page. If you want the third page, then:
LIMIT 4, 2
And so on.
Note that I modified your query so the joining condition between the tables is placed in the ON clause of the join rather than in the WHERE clause.
Better add one extra column (e.g. mzmx_post_key bigint) of Long type in each table and have sequential value on that column. Use that column to fetch data from DB from page wise.
sqL suery should look like:
SELECT *
FROM `mzmx_post`
JOIN mzmx_post_category ON mzmx_post.id = mzmx_post_category.post_id
WHERE mzmx_post_category.category_id = 5 and mzmx_post_key> ##last record key##
ORDER BY mzmx_post_key ASC
LIMIT 2
The basic idea is to use
LIMIT n,o
where n is the results per page
o is the offset from the first result
for the p-th page the offset would be
o = p * n
where p = 0,1,2,....

PHP MYSQL General Error returned when using LIMIT [duplicate]

This question already has answers here:
Implement paging (skip / take) functionality with this query
(6 answers)
Closed 1 year ago.
I have this query with MySQL:
select * from table1 LIMIT 10,20
How can I do this with SQL Server?
Starting SQL SERVER 2005, you can do this...
USE AdventureWorks;
GO
WITH OrderedOrders AS
(
SELECT SalesOrderID, OrderDate,
ROW_NUMBER() OVER (ORDER BY OrderDate) AS 'RowNumber'
FROM Sales.SalesOrderHeader
)
SELECT *
FROM OrderedOrders
WHERE RowNumber BETWEEN 10 AND 20;
or something like this for 2000 and below versions...
SELECT TOP 10 * FROM (SELECT TOP 20 FROM Table ORDER BY Id) ORDER BY Id DESC
Starting with SQL SERVER 2012, you can use the OFFSET FETCH Clause:
USE AdventureWorks;
GO
SELECT SalesOrderID, OrderDate
FROM Sales.SalesOrderHeader
ORDER BY SalesOrderID
OFFSET 10 ROWS
FETCH NEXT 10 ROWS ONLY;
GO
http://msdn.microsoft.com/en-us/library/ms188385(v=sql.110).aspx
This may not work correctly when the order by is not unique.
If the query is modified to ORDER BY OrderDate, the result set returned is not as expected.
This is how I limit the results in MS SQL Server 2012:
SELECT *
FROM table1
ORDER BY columnName
OFFSET 10 ROWS FETCH NEXT 10 ROWS ONLY
NOTE: OFFSET can only be used with or in tandem to ORDER BY.
To explain the code line OFFSET xx ROWS FETCH NEXT yy ROW ONLY
The xx is the record/row number you want to start pulling from in the table, i.e: If there are 40 records in table 1, the code above will start pulling from row 10.
The yy is the number of records/rows you want to pull from the table.
To build on the previous example: If table 1 has 40 records and you began pulling from row 10 and grab the NEXT set of 10 (yy).
That would mean, the code above will pull the records from table 1 starting at row 10 and ending at 20. Thus pulling rows 10 - 20.
Check out the link for more info on OFFSET
This is almost a duplicate of a question I asked in October:
Emulate MySQL LIMIT clause in Microsoft SQL Server 2000
If you're using Microsoft SQL Server 2000, there is no good solution. Most people have to resort to capturing the result of the query in a temporary table with a IDENTITY primary key. Then query against the primary key column using a BETWEEN condition.
If you're using Microsoft SQL Server 2005 or later, you have a ROW_NUMBER() function, so you can get the same result but avoid the temporary table.
SELECT t1.*
FROM (
SELECT ROW_NUMBER OVER(ORDER BY id) AS row, t1.*
FROM ( ...original SQL query... ) t1
) t2
WHERE t2.row BETWEEN #offset+1 AND #offset+#count;
You can also write this as a common table expression as shown in #Leon Tayson's answer.
SELECT *
FROM (
SELECT TOP 20
t.*, ROW_NUMBER() OVER (ORDER BY field1) AS rn
FROM table1 t
ORDER BY
field1
) t
WHERE rn > 10
Syntactically MySQL LIMIT query is something like this:
SELECT * FROM table LIMIT OFFSET, ROW_COUNT
This can be translated into Microsoft SQL Server like
SELECT * FROM
(
SELECT TOP #{OFFSET+ROW_COUNT} *, ROW_NUMBER() OVER (ORDER BY (SELECT 1)) AS rnum
FROM table
) a
WHERE rnum > OFFSET
Now your query select * from table1 LIMIT 10,20 will be like this:
SELECT * FROM
(
SELECT TOP 30 *, ROW_NUMBER() OVER (ORDER BY (SELECT 1)) AS rnum
FROM table1
) a
WHERE rnum > 10
SELECT TOP 10 * FROM table;
Is the same as
SELECT * FROM table LIMIT 0,10;
Here's an article about implementing Limit in MsSQL Its a nice read, specially the comments.
This is one of the reasons I try to avoid using MS Server... but anyway. Sometimes you just don't have an option (yei! and I have to use an outdated version!!).
My suggestion is to create a virtual table:
From:
SELECT * FROM table
To:
CREATE VIEW v_table AS
SELECT ROW_NUMBER() OVER (ORDER BY table_key) AS row,* FROM table
Then just query:
SELECT * FROM v_table WHERE row BETWEEN 10 AND 20
If fields are added, or removed, "row" is updated automatically.
The main problem with this option is that ORDER BY is fixed. So if you want a different order, you would have to create another view.
UPDATE
There is another problem with this approach: if you try to filter your data, it won't work as expected. For example, if you do:
SELECT * FROM v_table WHERE field = 'test' AND row BETWEEN 10 AND 20
WHERE becomes limited to those data which are in the rows between 10 and 20 (instead of searching the whole dataset and limiting the output).
In SQL there's no LIMIT keyword exists. If you only need a limited number of rows you should use a TOP keyword which is similar to a LIMIT.
Must try. In below query, you can see group by, order by, Skip rows, and limit rows.
select emp_no , sum(salary_amount) from emp_salary
Group by emp_no
ORDER BY emp_no
OFFSET 5 ROWS -- Skip first 5
FETCH NEXT 10 ROWS ONLY; -- limit to retrieve next 10 row after skiping rows
Easy way
MYSQL:
SELECT 'filds' FROM 'table' WHERE 'where' LIMIT 'offset','per_page'
MSSQL:
SELECT 'filds' FROM 'table' WHERE 'where' ORDER BY 'any' OFFSET 'offset'
ROWS FETCH NEXT 'per_page' ROWS ONLY
ORDER BY is mandatory
This is a multi step approach that will work in SQL2000.
-- Create a temp table to hold the data
CREATE TABLE #foo(rowID int identity(1, 1), myOtherColumns)
INSERT INTO #foo (myColumns) SELECT myData order By MyCriteria
Select * FROM #foo where rowID > 10
SELECT
*
FROM
(
SELECT
top 20 -- ($a) number of records to show
*
FROM
(
SELECT
top 29 -- ($b) last record position
*
FROM
table -- replace this for table name (i.e. "Customer")
ORDER BY
2 ASC
) AS tbl1
ORDER BY
2 DESC
) AS tbl2
ORDER BY
2 ASC;
-- Examples:
-- Show 5 records from position 5:
-- $a = 5;
-- $b = (5 + 5) - 1
-- $b = 9;
-- Show 10 records from position 4:
-- $a = 10;
-- $b = (10 + 4) - 1
-- $b = 13;
-- To calculate $b:
-- $b = ($a + position) - 1
-- For the present exercise we need to:
-- Show 20 records from position 10:
-- $a = 20;
-- $b = (20 + 10) - 1
-- $b = 29;
If your ID is unique identifier type or your id in table is not sorted you must do like this below.
select * from
(select ROW_NUMBER() OVER (ORDER BY (select 0)) AS RowNumber,* from table1) a
where a.RowNumber between 2 and 5
The code will be
select * from limit 2,5
better use this in MSSQLExpress 2017.
SELECT * FROM
(
SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 0)) as [Count], * FROM table1
) as a
WHERE [Count] BETWEEN 10 and 20;
--Giving a Column [Count] and assigning every row a unique counting without ordering something then re select again where you can provide your limits.. :)
One of the possible way to get result as below , hope this will help.
declare #start int
declare #end int
SET #start = '5000'; -- 0 , 5000 ,
SET #end = '10000'; -- 5001, 10001
SELECT * FROM (
SELECT TABLE_NAME,TABLE_TYPE, ROW_NUMBER() OVER (ORDER BY TABLE_NAME) as row FROM information_schema.tables
) a WHERE a.row > #start and a.row <= #end
If i remember correctly (it's been a while since i dabbed with SQL Server) you may be able to use something like this: (2005 and up)
SELECT
*
,ROW_NUMBER() OVER(ORDER BY SomeFields) AS [RowNum]
FROM SomeTable
WHERE RowNum BETWEEN 10 AND 20

Ordering the SQL query in a particular order

Say i have a table Guest and it has column g_id : values 1 to 10.
Now i want the query to return me the g_id's neither in ascending order nor in descending..
but i want the 4th then 3rd and then 5th entry, in this particular order.
Also i want just the 4th 3rd and 5th entry.
say my entries have an id and a name . ;i.e. my table Guest has these two tables.
Now my table is as following.
1 A
2 B
3 C
4 D
5 E
6 F
7 G
8 H
9 I
10 J
Now i want just the entry with 4th 3rd and 5th g_id, and in this particular order.
How do i write the SQL query?
Thanks.
Select * from Guest ___________???
Kindly fill in the gaps.
You can use a CASE statement in your ORDER BY to use a fake column to sort on and a WHERE IN clause to only return the values you need.
SELECT *
FROM Guest
WHERE g_id IN (3, 4, 5)
ORDER BY
CASE WHEN g_id = 4 THEN 1
WHEN g_id = 3 THEN 2
WHEN g_id = 5 THEN 3
END
What is the order that deteremines whether something is 4th, 3rd or 5th? Without an ORDER BY clause, the data is returned in an indeterminate order by SQL. You cannot rely on the order that rows are entered or stored in the database table itself.
You can hard-code what you are asking like this:
select *
from Guest
order by case
when g_id = 4 then 1
when g_id = 3 then 2
when g_id = 5 then 3
else 4
end
One solution is the case statement:
select g_id from (
select g_id, case g_id
when 4 then 1
when 3 then 2
when 5 then 3
else 0
end virtcol
where virtcol != 0
order by virtcol
);
I'm not sure how set your ordering will be, but you can order by specifics:
ORDER BY
g_id = 4 DESC,
g_id = 3 DESC,
g_id = 5 DESC
You may be better off selecting the entries as they are and doing something like this in your php code:
$order = array('4 ', '3 ', '5 ');
$data = array();
while ($row = $result->fetch()) {
$data["$row->g_id "] = $row;
}
$data = array_merge(array_flip($order), $data);
I think that the answer mostly depends on the DBMS you are working on.
In Oracle the query below, even though inefficient, should work
select * from
(select * , rownum as order from guest order by id asc ) b
where b.order = 4
UNION
select * from
(select * , rownum as order from guest order by id asc ) b
where b.order = 3
UNION
select * from
(select * , rownum as order from guest order by id asc ) b
where b.order = 5
Not sure if something of more efficient is possible with a simple query,
i would use the monster above only and only if the table you are querying is very small.
You also have another option if the table is big and you have to extract only the first rows. In the case you described, I would retrieve the first 5 rows and then programmatically I would extract the rows in position 4,3,5.
you can extract the first 5 rows with this query in oracle
select * from guest order by id asc where rownum < 6
This query will get you the 3rd, 5th, and 4th items (limit 2, 1 means "retrieve starting with 3rd item, with total number retrieved = 1 records)
(select g_id from Guest limit 2,1)
UNION (select g_id from Guest limit 4,1
UNION (select g_id from Guest limit 3,1)

Update field if the ORDER BY is 1 descending?

Is there a possible way to do this:
I want to update a field 'rank' according to the ORDER BY place.
For example: (pseudocode)
If id order by place = 1 then update rank field to place were id=get id
rank place id
1 1 5 PC
2 2 8 MAC
is this possible?
Something like this?
UPDATE tbl_name
SET rank = 1
WHERE id = (
SELECT id
WHERE condition
ORDER BY place DESC
LIMIT 1
)
Or from your comment (I think MySQL http://dev.mysql.com/doc/refman/5.0/en/update.html):
UPDATE tbl_name
SET rank = 10
WHERE id = 9
ORDER BY wins DESC
LIMIT 1
You can always do a SELECT to check if these are the records you wish to UPDATE as well:
SELECT *
FROM tbl_name
WHERE id = (
SELECT id
WHERE condition
ORDER BY place DESC
LIMIT 1
)
OR
SELECT *
FROM tbl_name
WHERE id = 9
ORDER BY wins DESC
LIMIT 1
Some RDBMS have a ROWNUM pseudocolumn in queries you can use for this.
You did not specify what database you are using, for example Oracle has this.

mysql row counter

I have a mysql table. It has auto increment on the id. but I regularly delete rows so the numbers are all over the place. I need to get the last n rows out, but because of deletions, the common way of using the max of the autoincremented id column doesn't work well...
1 - Is their another way to get the bottom 50?
2 - Is their a way to get rows by actual row number? so if I have 4 rows labelled 1,2,3,4 delete row 2 then it will become 1,2,3 rather than 1,3,4?
SELECT ... ORDER BY id DESC LIMIT 50
SELECT *
FROM TABLE
ORDER BY id DESC
LIMIT 50
EDIT
To pick the last 50, but sort by id ASC
SELECT X.*
FROM ( SELECT *
FROM TABLE
ORDER BY id DESC
LIMIT 50
) X
ORDER BY X.id
1 - First get total row count like
SELECT COUNT(*) AS c FROM ...
then use
SELECT ..... LIMIT [start],[count]
2 - One idea is to use view , or procedure, but this is much more harder and may be used when there is no other way to avoid this
1 - Is their another way to get the bottom 50?
SELECT * FROM table_name ORDER BY record_id DESC LIMIT 50
2 - Is their a way to get rows by actual row number? so if I have 4 rows labelled 1,2,3,4 delete row 2 then it will become 1,2,3 rather than 1,3,4?
SELECT * FROM table_name
1 - Yes but it is ugly afaik, you do a
SELECT whateveryouwant FROM table ORDER BY yourprimarykey DESC LIMIT 50
the you fetch the rows into an array and reverse the array, in php :
$r = mysql_query('SELECT * FROM table ORDER BY primarykey DESC LIMIT 50');
$set = array();
while($row = mysql_fetch_assoc($r)) $set = $row;
$set = array_reverse($set);
foreach($set as $row) {
// display row ...
}
2 - You'll have to manage your primary key by yourself, its a bit risky ...

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