Avoid query to check if relation exists in Laravel - php

In Laravel I've 2 models Man and Car, and the Car model has a foreign key man_id.
Now I would like to check if a Car has an owner, so I can do
if($car->man != null)
I could also do:
if($car->man_id != null)
but I don't like this solution...
But in this way Laravel do a query to check if Man exists, is there a way to avoid this useless query?

You can create a new function on your Car model that checks for its owner.
Car.php
class Car extends Model {
public function hasOwner()
{
return empty($this->man_id); // returns boolean
}
}
Then, you can just do
$car = Car::first();
if ($car->hasOwner()) { ... }
UPDATE:
You can also use exists() method
$car->man()->exists(); // bool: true if there is at least one row
As of Laravel 5.5 or higher, you can also use doesntExist() which will determine if no rows exist for the current query.
$car->man()->doesntExist(); // bool: true if no row exists

Related

get data after check exists one query laravel 8

I need to check if the data is exist and get data after that
Exam:
Loc::fisrt()->user()->exists()->get(); // This is just an example, it's not true
->get after exists this i need
I hope my question is clear.
Just get the data and check it afterwards.
$user = Luc::first()->user;
If user() is a belongsTo, hasOne or morphOne relationship:
if ($user !== null) { /* user exists */ }
If user() is a belongsToMany, hasMany, hasManyThrough, morphMany, morphToMany or morphedByMany relationship:
if ($user->isNotEmpty()) { /* user exists */ }
There is a perfect solution for what you need in Eloquent already. The has method.
$results = Loc::has('user')->get();
The above results will only contain Loc records that have a user relation attached to them.

Laravel eloquent conditional relationship

I am trying to set up a conditional relationship in eloquent model based on the value of table column, but it does not works.
This is the code that I am using:
//RELATIONS
public function task_schedule()
{
if ($this->task_schedule_id === 0) {
return $this->belongsTo('TaskSchedule', 'hold_task_schedule_id', 'id');
} else {
return $this->belongsTo('TaskSchedule');
}
}
Basically I want to use different column to get my child model defined in belongs to relationship.
scopeProfile($query) would not work for me because I dont want to retrieve the child in every single query and also I am using Task->with('task_schedule') in a lot parts of code.

Custom method chaining with Eloquent ORM?

This is my current query:
$cars = Cars::with('brand')->get();
$cars->map(function($cars){
$cars->fullName = $cars->brand->brand." ".$cars->name;
//other manipulation...
return $cars;
});
I want to manipulate my collection in the model so that I can run something like $cars = Cars::with('brand')->getWithBrand();
How can I do this, so I don't have to write map functions for every time I run the query?
In your particular example, you don't need to use map to modify the Collection at all. You can use an Eloquent accessor to define attributes on a Model that don't exist in the database. In your example, you would define the following method on your Cars model:
public function getFullNameAttribute($value)
{
// make sure brand exists first
if ($this->brand) {
return $this->brand->brand.' '.$this->name;
}
// default if brand doesn't exist
return $this->name;
}
By defining that function on your Model, that function will be called whenever you attempt to use the full_name attribute, as shown in the following code:
$car = Cars::with('brand')->first();
// this will echo the result of the getFullNameAttribute method
echo $car->full_name;
Edit
If you would also like this new attribute to automatically show up in your toArray() or toJson() output, you can add the attribute to the $appends property on your Cars model:
class Cars extends Model
{
protected $appends = ['full_name'];
public function getFullNameAttribute($value)
{
// make sure brand exists first
if ($this->brand) {
return $this->brand->brand.' '.$this->name;
}
// default if brand doesn't exist
return $this->name;
}
}
Be aware, however, that your custom attribute depends on a related object. So, if you do something that accidentally calls toArray(), toJson(), __toString(), etc on a Collection of Cars that has not eager loaded the brand relationship, this will cause the N+1 query issue.
For example:
// Bad: N+1 issue because each printed Car will execute a
// separate query to get its brand to output full_name.
echo Cars::get();
// Good: No N+1 issue because all brands are already loaded.
echo Cars::with('brand')->get();

Laravel orWhere not working with hasMany

I have following code:
class Ingredient extends Eloquent
{
public function units()
{
return $this->hasMany('IngredientUnit')
->orWhere('ingredient_id', '=', -1);
}
}
I would expect query like:
select * from `ingredient_units` where `ingredient_id` = '-1' OR `ingredient_units`.`ingredient_id` in (...)
instead I get:
select * from `ingredient_units` where `ingredient_id` = '-1' and `ingredient_units`.`ingredient_id` in (...)
Why it use AND operator instead OR, when I used orWhere()?
Update 1:
And second question is how can I get a query which I was expected?
Update 2:
I want to use eagerloading for that
When you fetch a collection of objects through a relation on a model, the relation constraint is always included, hence the AND. And it makes perfect sense, otherwise you could get $model->units objects that are not related to $model.
I can see what you're trying to achieve here - fetch units related to that $model together with units not related to any models. You can achieve it by adding the following method to your model:
public function getAllUnits() {
$genericUnits = IngredientUnit::whereIngredientId(-1);
return $this->units()->union($genericUnits)->get();
}
OR
public function getAllUnits() {
return IngredientUnit::whereIn('ingredient_id', [$this->id, -1])->get();
}
The only issue here is that it won't be used by eager loading logic but would result in separate query for every model for which you want to return units. But if you always fetch that for a single model anyway, it won't be a problem.
One suggestion: store NULL in ingredient_id instead of -1. This way you'll be able to make use of foreign key constraints.

Laravel Check If Related Model Exists

I have an Eloquent model which has a related model:
public function option() {
return $this->hasOne('RepairOption', 'repair_item_id');
}
public function setOptionArrayAttribute($values)
{
$this->option->update($values);
}
When I create the model, it does not necessarily have a related model. When I update it, I might add an option, or not.
So I need to check if the related model exists, to either update it, or create it, respectively:
$model = RepairItem::find($id);
if (Input::has('option')) {
if (<related_model_exists>) {
$option = new RepairOption(Input::get('option'));
$option->repairItem()->associate($model);
$option->save();
$model->fill(Input::except('option');
} else {
$model->update(Input::all());
}
};
Where <related_model_exists> is the code I am looking for.
In php 7.2+ you can't use count on the relation object, so there's no one-fits-all method for all relations. Use query method instead as #tremby provided below:
$model->relation()->exists()
generic solution working on all the relation types (pre php 7.2):
if (count($model->relation))
{
// exists
}
This will work for every relation since dynamic properties return Model or Collection. Both implement ArrayAccess.
So it goes like this:
single relations: hasOne / belongsTo / morphTo / morphOne
// no related model
$model->relation; // null
count($model->relation); // 0 evaluates to false
// there is one
$model->relation; // Eloquent Model
count($model->relation); // 1 evaluates to true
to-many relations: hasMany / belongsToMany / morphMany / morphToMany / morphedByMany
// no related collection
$model->relation; // Collection with 0 items evaluates to true
count($model->relation); // 0 evaluates to false
// there are related models
$model->relation; // Collection with 1 or more items, evaluates to true as well
count($model->relation); // int > 0 that evaluates to true
A Relation object passes unknown method calls through to an Eloquent query Builder, which is set up to only select the related objects. That Builder in turn passes unknown method calls through to its underlying query Builder.
This means you can use the exists() or count() methods directly from a relation object:
$model->relation()->exists(); // bool: true if there is at least one row
$model->relation()->count(); // int: number of related rows
Note the parentheses after relation: ->relation() is a function call (getting the relation object), as opposed to ->relation which a magic property getter set up for you by Laravel (getting the related object/objects).
Using the count method on the relation object (that is, using the parentheses) will be much faster than doing $model->relation->count() or count($model->relation) (unless the relation has already been eager-loaded) since it runs a count query rather than pulling all of the data for any related objects from the database, just to count them. Likewise, using exists doesn't need to pull model data either.
Both exists() and count() work on all relation types I've tried, so at least belongsTo, hasOne, hasMany, and belongsToMany.
I prefer to use exists method:
RepairItem::find($id)->option()->exists()
to check if related model exists or not. It's working fine on Laravel 5.2
After Php 7.1, The accepted answer won't work for all types of relationships.
Because depending of type the relationship, Eloquent will return a Collection, a Model or Null. And in Php 7.1 count(null) will throw an error.
So, to check if the relation exist you can use:
For relationships single: For example hasOne and belongsTo
if(!is_null($model->relation)) {
....
}
For relationships multiple: For Example: hasMany and belongsToMany
if ($model->relation->isNotEmpty()) {
....
}
I use for single relationships: hasOne, belongsTo and morphs
if($model->relation){
....
}
Because if condition is null, this will be false.
For multiple relationships: hasMany, belongsToMany and morphs
if ($model->relation->isNotEmpty()) {
....
}
You can use the relationLoaded method on the model object. This saved my bacon so hopefully it helps someone else. I was given this suggestion when I asked the same question on Laracasts.
As Hemerson Varela already said in Php 7.1 count(null) will throw an error and hasOne returns null if no row exists. Since you have a hasOnerelation I would use the empty method to check:
$model = RepairItem::find($id);
if (!empty($temp = $request->input('option'))) {
$option = $model->option;
if(empty($option)){
$option = $model->option()->create();
}
$option->someAttribute = temp;
$option->save();
};
But this is superfluous. There is no need to check if the relation exists, to determine if you should do an update or a create call. Simply use the updateOrCreate method. This is equivalent to the above:
$model = RepairItem::find($id);
if (!empty($temp = $request->input('option'))) {
$model->option()
->updateOrCreate(['repair_item_id' => $model->id],
['option' => $temp]);
}
Not sure if this has changed in Laravel 5, but the accepted answer using count($data->$relation) didn't work for me, as the very act of accessing the relation property caused it to be loaded.
In the end, a straightforward isset($data->$relation) did the trick for me.
I had to completely refactor my code when I updated my PHP version to 7.2+ because of bad usage of the count($x) function. This is a real pain and its also extremely scary as there are hundreds usages, in different scenarios and there is no one rules fits all..
Rules I followed to refactor everything, examples:
$x = Auth::user()->posts->find(6); (check if user has a post id=6 using ->find())
[FAILS] if(count($x)) { return 'Found'; }
[GOOD] if($x) { return 'Found'; }
$x = Auth::user()->profile->departments; (check if profile has some departments, there can have many departments)
[FAILS] if(count($x)) { return 'Found'; }
[GOOD] if($x->count()) { return 'Found'; }
$x = Auth::user()->profile->get(); (check if user has a profile after using a ->get())
[FAILS] if(count($x)) { return 'Found'; }
[GOOD] if($x->count()) { return 'Found'; }
Hopes this can help, even 5 years after the question has been asked, this stackoverflow post has helped me a lot!
If you use the model class and use Eloquent ORM, then create a new method and return bool data. like
public function hasPosts(): bool
{
return $this->posts()->exists();
}
RelationLoaded method of Model class could be useful.
if ($this->relationLoaded('prices')) {
return;
}

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