if the date is same just display one time - php

Question

if the date is same with database date just display one time only.Example:database date 16/2 then all 16/2 must display in a box, but other date also need to display. who help me to solve this problem.
<h1>Payment Record</h1>
<?php
$user_check=$_SESSION['login_user'];
$query = "SELECT * FROM `confirm_order` where customer = '$user_check'";
$result=mysqli_query($mysqli,$query);
while($row=mysqli_fetch_array($result))
{
?>
<table style="width:100%;border:1px solid black;margin-bottom:20px;">
<tr>
<td>Product Name: <?php echo $row['product_name'];?></td>
</tr>
<tr>
<td>Quantity: <?php echo $row['quantity']?></td>
</tr>
<tr>
<td>Receiver Name: <?php echo $row['receiver_name']?></td>
</tr>
<tr>
<td>Receiver Address: <?php echo $row['receiver_address']?></td>
</tr>
<tr>
<td>Receiver Contact: <?php echo $row['receiver_contact']?></td>
</tr>
<tr>
<td style="float:right">Date: <?php echo $row['date']?></td>
</tr>
</table>
<?php
}
?>
Example
id | product | date |
---|---------|------|
1 | book | 16/2 |
2 | pencil | 16/2 |
3 | shoe | 18/2 |
Result
-------
book |
pencil |
-------
shoe |
-------

Answer 1

Here is the complete solution:
$user_check=$_SESSION['login_user'];
$query = "SELECT * FROM `confirm_order` where customer = '$user_check'";
$result=mysqli_query($mysqli,$query);
$current_date=NULL;
$previous_date=NULL;
$table_open="<table border='1'>";
$table_close="</table><hr>";
$output=NULL;
while($row=mysqli_fetch_array($result))
{
$current_date=$row['date'];
if ($current_date==$previous_date) {
// SAME DATE
$output.= "<tr><td>SAME DATE</td><td>".$current_date."</td></tr>";
} else {
// NEW DATE
if ($previous_date<>NULL) {
$output.= $table_close;
}
$output.= $table_open."<tr><td>NEW DATE</td><td>".$current_date."</td></tr>";
}
$previous_date=$row['date'];
}
echo $output;