While loop only showing 1 result - php

Question

I have a script that checks for dupe values in db and loops through the result and echoes the value using json. However, it is only displaying 1 record instead of 3 which is being sent to php. I would be grateful if someone could point out my error. Thanks
$boxitems = mysqli_real_escape_string($conn, $_POST['box']);
$array = array();
$array = $boxitems;
foreach ($array as $boxes) {
$sql = "SELECT item FROM act WHERE item = '".$boxes."' GROUP BY item HAVING COUNT(*) > 1";
$result = mysqli_query($conn, $sql) or die('Error selecting item: ' . mysqli_error());
$num_rows = mysqli_num_rows($result);
if($num_rows) {
while ($row = mysqli_fetch_array($result)) {
$data[] = $row['item'];
}
echo '<div style="width: 50%; margin-bottom: 20px; border-radius: 5px; border: 1px solid black; background: red; font-size: 16px; color: white; height: 50px; padding: 15px; line-height: 1.3;">';
echo json_encode($data) . ' already exists. Please enter a unique box reference.';
echo '</div>';
exit;
} else {
echo '<div style="width: 50%; margin-bottom: 20px; border-radius: 5px; border: 1px solid black; background: #63c84c; font-size: 16px; color: white; height: 50px; padding: 15px; line-height: 1.3;">';
echo 'No dupes found in database.';
echo '</div>';
exit;
}
}
UPDATED screen shot

Answer 1

Put what your want to echo into a single variable that is declared outside the foreach and concatenate each div (one for each loop your foreach does). And then echo it after the loop.
$boxitems = $_POST['box'];
$insertedItems = array();
$duplicateItems = array();
foreach ($boxitems as $boxes) {
$escapedBoxes = mysqli_real_escape_string($conn, $boxes);
$sql = "SELECT item FROM act WHERE item = '".$escapedBoxes."' GROUP BY item HAVING COUNT(*) > 0";
$result = mysqli_query($conn, $sql) or die('Error selecting item: ' . mysqli_error());
$num_rows = mysqli_num_rows($result);
if($num_rows) {
while ($row = mysqli_fetch_array($result)) {
$duplicateItems[] = $row['item'];
}
}
else
{
$insertedItems[] = $escapedBoxes;
}
}
if(!empty($duplicateItems)) {
echo '<div style="width: 50%; margin-bottom: 20px; border-radius: 5px; border: 1px solid black; background: red; font-size: 16px; color: white; height: 50px; padding: 15px; line-height: 1.3;">';
echo json_encode($duplicateItems) . ' already exists. Please enter a unique box reference.';
echo '</div>';
} else {
echo '<div style="width: 50%; margin-bottom: 20px; border-radius: 5px; border: 1px solid black; background: #63c84c; font-size: 16px; color: white; height: 50px; padding: 15px; line-height: 1.3;">';
echo 'No dupes found in database.<br/>';
echo json_encode($insertedItems) . ' has been entered successfully into the database.';
echo '</div>';
}
EDIT: Updated code considering u_mulder comment.

Answer 2

$boxitems = mysqli_real_escape_string($conn, $_POST['box']);
$array = array();
$array = $boxitems;
foreach ($array as $boxes) {
$sql = "SELECT item FROM act WHERE item = '".$boxes."' GROUP BY item HAVING COUNT(*) > 1";
$result = mysqli_query($conn, $sql) or die('Error selecting item: ' . mysqli_error());
$num_rows = mysqli_num_rows($result);
if($num_rows) {
while ($row = mysqli_fetch_array($result)) {
$data[] = $row['item'];
}
echo '<div style="width: 50%; margin-bottom: 20px; border-radius: 5px; border: 1px solid black; background: red; font-size: 16px; color: white; height: 50px; padding: 15px; line-height: 1.3;">';
echo json_encode($data) . ' already exists. Please enter a unique box reference.';
echo '</div>';
exit;
} else {
echo '<div style="width: 50%; margin-bottom: 20px; border-radius: 5px; border: 1px solid black; background: #63c84c; font-size: 16px; color: white; height: 50px; padding: 15px; line-height: 1.3;">';
echo 'No dupes found in database.';
echo '</div>';
}
exit;
}
An exit inside any function, loop or condition will make the program to go out of it and continue, so it's not iterating through, it's exiting after the first iteration.