I am having issues with displaying a modal when a user types a duplicate email or username, I have defined a boolean to store true when the modal should be shown and false when not. Even when I type a new username and email, the modal is still being shown and i am really confused why.
PHP:
if($checkUser->rowCount() > 0 || $checkEmail->rowCount() > 0){
$showModal = true;
}else{
$showModal = false;
HTML:
<?php if($showModal===false): ?>
<input type="submit" id="submit" name="submit" value="Register" readonly="readonly"/>
<?php else: ?>
<input type="" id="submit" name="submit" data-toggle="modal" data-target="#myModal" value="Register" readonly="readonly"/>
<div class="modal fade" id="myModal" role="dialog">
<div class="modal-dialog">
<!-- Modal content-->
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">Registration Error!</h4>
</div>
<div class="modal-body">
<p>You have entered a Username or Email Address which has already been registered!</p>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>
<?php endif; ?>
I remove the type 'submit' from the modal input as it was causing the modal to break as the page was being refreshed.
Any help is appreciated, thanks.
Related
It's my first post so welcome!
I'm struggling with one problem in my project. As you can see at my screenshot, i have few names which are fetched from database, and displayed in main menu. after clicking "modal" button, modal from bootstrap is showed with php form. user can type a 4 digit pin code, next step is to match this pin with database records. But 2 users can have same pin so i need to compare not only pin with database, but name too. i don`t know how to send "name" value with post. Here is my code and screenshot:
index.php:
<?php
$data = $worker->select_workers();
$worker->show_workers($data);
$worker->show_modal();
worker.php:
<?php
require_once('db.php');
class Worker extends db {
protected $select_workers;
public function select_workers(){
return $this->select_workers = $this->query('SELECT * FROM worker')->fetchAll();
}
public function show_workers($data){
foreach ($data as $users) {
echo '<p id="p_name">'.$users['name'].'</p><a id="button_modal" href="/?name='.$users['name'].'" type="button" class="btn btn-primary" data-toggle="modal" data-target="#exampleModal">
Modal
</a><br>';
}
}
public function show_modal(){
echo '<!-- Button trigger modal -->
<!-- Modal -->
<form action="test.php" id="submit_ajax" method="post">
<div class="modal fade" id="exampleModal" tabindex="-1" role="dialog" aria-labelledby="exampleModalLabel" aria-hidden="true">
<div class="modal-dialog" role="document">
<div class="modal-content">
<div class="modal-header">
<h5 class="modal-title" id="modal_title" name="name"></h5>
<button type="button" class="close" data-dismiss="modal" aria-label="Close">
<span aria-hidden="true">×</span>
</button>
</div>
<div class="modal-body">
<input id="hidden_name" type="text" value="" name="name" />
Hasło:<input type="text" name="password"><br>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-secondary" data-dismiss="modal">Close</button>
<button type="submit" class="btn btn-primary">Przerwa/powrót</button>
</form>
</div>
</div>
</div>
</div>';
}
Main menu of my application
I belive that solution is really simple but like always - i waste too many times for complicated things which are not working. Sorry for my english, it's not my native language :)
Thank you
Put value here <input id="hidden_name" type="text" value="<?= $name ?>" name="name" />, but if you fetch data from db, isn't it better to use ids instead of names?
Not clean solution. make for every worker a modal.
<?php
require_once('db.php');
class Worker extends db {
protected $select_workers;
public function select_workers(){
return $this->select_workers = $this->query('SELECT * FROM worker')->fetchAll();
}
public function show_workers($data){
$i=0;
foreach ($data as $users) {
$i++;
echo '<p id="p_name">'.$users['name'].'</p><a id="button_modal" href="/?name='.$users['name'].'" type="button" class="btn btn-primary" data-toggle="modal" data-target="#exampleModal'.$i.'">
Modal
</a><br>
<!-- Button trigger modal -->
<!-- Modal -->
<form action="test.php" id="submit_ajax" method="post">
<div class="modal fade" id="exampleModal'.$i.'" tabindex="-1" role="dialog" aria-labelledby="exampleModalLabel" aria-hidden="true">
<div class="modal-dialog" role="document">
<div class="modal-content">
<div class="modal-header">
<h5 class="modal-title" id="modal_title" name="name"></h5>
<button type="button" class="close" data-dismiss="modal" aria-label="Close">
<span aria-hidden="true">×</span>
</button>
</div>
<div class="modal-body">
<input id="hidden_name" type="text" value="'.$users['name'].'" name="name" />
Hasło:<input type="text" name="password"><br>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-secondary" data-dismiss="modal">Close</button>
<button type="submit" class="btn btn-primary">Przerwa/powrót</button>
</form>
</div>
</div>
</div>
</div>';
}
I have two kinds of users in database (teacher / student)
How can i show some functions of my website ( button / review section )for teacher only and vice versa ?
i want to know the concept and any thing to help me
i got an error telling me that Undefined variable user while i am using the same query in another page
<div class="container">
<!-- Trigger the modal with a button -->
<button <?php if($user[0]['type']=="student")?> type="button" id="mah"
class="btn btn-info btn-lg" data-toggle="modal" data-target="#myModal"
>Add Course</button>
<!-- Modal -->
<div class="modal fade" id="myModal" role="dialog">
<div class="modal-dialog">
<!-- Modal content-->
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">Add Course</h4>
</div>
<div class="modal-body">
<form action="/action_page.php">
Name:<br>
<input type="text" name="firstname" value="">
<br>
Course Name<br>
<input type="text" name="Add_course" value="">
<br>
Course Link<br>
<input type="text" name="Course_link" value="...">
<br><br>
<input type="submit" value="Submit">
</form>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-
dismiss="modal">Close</button>
</div>
</div>
</div>
</div>
i would suggest have a different section for teacher and the other for student . Using logic based on the names "teacher/student" the have different teacher adds marks , register student. while student view his enrollment .
Since the code is incomplete do a var_dump() on your array $user your can see if the value exist
This is my code, I was supposed to get the inputted value in db and php tag isnt working.. It is not also redirecting to "myorders.php"; My form inside is not working.. Thank you.. Really need some help :(((
<div class="container">
<form method="post">
<h2>Enter your Pin Number</h2>
<!-- Trigger the modal with a button -->
<button type="button" class="btn btn-info btn-lg" data-toggle="modal" data-target="#myModal">Open Modal</button>
<!-- Modal -->
<div class="modal fade" id="myModal" role="dialog">
<div class="modal-dialog">
<!-- Modal content-->
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">Enter your Pin Number</h4>
</div>
<div class="modal-body text-center">
<input type="password" id="first-name" required="required" class="form-control" name="pin">
</div>
<div class="modal-footer">
<button type="submit" name="submit3" class="btn btn-default" data-dismiss="modal"><i class="fa fa-key"></i> Confirm Pin</button>
</div>
</div>
</div>
</div>
<!-- START OF PHP -->
<?php include ('connectdb.php');
if(isset($_POST['submit3']))
{
$pin = $_POST["pin"];
$pww = "123";
if ($pin!=$pww) {
echo "WRONG PIN.. TRY AGAIN..";
}
else{
header('Location: myorders.php');
}
} // SUBMIT
?>
</form>
</div>
As per my comment, remove data-dismiss="modal" from your submit button. data-dismiss="modal" is used to close the modal dialog. You already have it here
<button type="button" class="close" data-dismiss="modal">×</button>
I am trying to save data inserted from a modal. I have tried the script in localhost its works perfect. After upload to Production, The "note" field not save into DB table. But my hidden type='hidden' name='leaveID' manage to save in DB table. Not sure why? Please help...
Below is my view file..
<button type="button" class="btn-cs btn-sm-cs" data-toggle="modal" data-target="#myModal" data-html="true" href="#" id="modal"><span class="fa fa-pencil"></span> Note</button>
<!-- Modal -->
<div class="modal fade" id="myModal" role="dialog">
<div class="modal-dialog">
<!-- Modal content-->
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<form action="<?php echo base_url('leave/note'); ?>" id="formid" method="POST" >
<textarea class="form-control" id="note" name="note" ><?=set_value('note')?></textarea>
<input type='hidden' name='leaveID' value="<?= set_value("leaveID", $leave->leaveID) ?>" />
</div>
<div class="modal-footer">
<button type="submit" name="submit" class="btn btn-info " >Add Note</button></div>
</div>
</form>
<script>
$("[data-toggle=modal]").popover({
html: true,
content: function() {
return $('#modal-header').html();
}
});
</script>
</div>
</div><?php } ?>
Manage to solve the issue. Just has some permission issue.
I want to display a number in a bootstrap modal after i use post method to submit a form .
But the bootstrap modal cannot show out the number ($_POST[number]).
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]); ?>" method="post">
<label class="control-label" >Number</label>
<div class="controls">
<input class="form-control" name="number" type="text">
<p class="help-block">Enter a number</p>
</div>
<button class="btn btn-primary btn-lg" data-toggle="modal" data-target="#myModal" type="submit">submit</button>
<?php
$number = $_POST['number'];
?>
<div class="modal fade" id="myModal" tabindex="-1" role="dialog"
aria-labelledby="myModalLabel" aria-hidden="true">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close"
data-dismiss="modal" aria-hidden="true">
×
</button>
<h4 class="modal-title" id="myModalLabel">
number
</h4>
</div>
<div class="modal-body">
<?php
echo $number;
?>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default"
data-dismiss="modal">close
</button>
<button type="button" class="btn btn-primary">
ok
</button>
</div>
</div>
</div>
</div>
How can i do it?
A few observations and flaws with your approach:
Fix HTML Errors (e.g. you are not properly closing your form, add: </form>
PHP is a server-side scripting language.
Bootstrap cannot function without Jquery which is a client-side scripting language.
You cannot trigger a Bootstrap modal on a form submission button, unless its Ajax driven!
Show the Modal after the form has been submitted (Page load) see jsfiddle example
Complete code:
<html>
<head>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.1.3/jquery.js"></script>
<link rel="stylesheet" href="//maxcdn.bootstrapcdn.com/bootstrap/3.3.2/css/bootstrap.min.css">
<script src="//maxcdn.bootstrapcdn.com/bootstrap/3.3.2/js/bootstrap.min.js"></script>
</head>
<body>
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]); ?>" method="post">
<label class="control-label" >Number</label>
<div class="controls">
<input class="form-control" name="number" type="text">
<p class="help-block">Enter a number</p>
</div>
<button class="btn btn-primary btn-lg" data-toggle="modal" data-target="#myModal" type="submit">submit</button>
</form>
<?php if (isset($_POST["number"])) : ?>
<!-- Show the Modal -->
<div class="modal fade" id="myModal" tabindex="-1" role="dialog"
aria-labelledby="myModalLabel" aria-hidden="true">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close"
data-dismiss="modal" aria-hidden="true">
×
</button>
<h4 class="modal-title" id="myModalLabel">
number
</h4>
</div>
<div class="modal-body">
<?php
echo htmlspecialchars($_POST["number"]);
?>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default"
data-dismiss="modal">close
</button>
<button type="button" class="btn btn-primary">
ok
</button>
</div>
</div>
</div>
</div>
</body>
</html>
<script type="text/javascript">
$(window).load(function(){
$('#myModal').modal('show');
});
</script>
<?php else : ?>
<!-- Do other stuff here -->
<?php endif; ?>
You need to add one more button ( input submit button ). that button will send the post request to self and update the variable $number.
First of all, you didn't close your form tag and you are trying to use submit button as a button for your modal...I don't know if that is gonna work.
Close your form tag and add input field of submit type...and then add a button for modal..that will work.
Here is the working code:
<html>
<head>
<link rel="stylesheet" href="../includes/css/bootstrap-theme.min.css">
<link rel="stylesheet" href="../includes/css/bootstrap.min.css">
</head>
<body>
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]); ?>" method="post">
<label class="control-label" >Number</label>
<div class="controls">
<input class="form-control" name="number" type="text">
<p class="help-block">Enter a number</p>
</div>
<input type="submit" value="submit">
</form>
<?php
$number = $_POST['number'];
?>
<button class="btn btn-primary btn-lg" data-toggle="modal" data-target="#myModal" type="submit">Modal</button>
<div class="modal fade" id="myModal" tabindex="-1" role="dialog"
aria-labelledby="myModalLabel" aria-hidden="true">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close"
data-dismiss="modal" aria-hidden="true">
×
</button>
<h4 class="modal-title" id="myModalLabel">
number
</h4>
</div>
<div class="modal-body">
<?php
echo $number;
?>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default"
data-dismiss="modal">close
</button>
<button type="button" class="btn btn-primary">
ok
</button>
</div>
</div>
</div>
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script src="../includes/js/bootstrap.min.js"></script>
</body>
</html>
Change <script> and <link> tag source according to your needs.
u can remove class model and fade from 'myModel' class div or can write style for display:block. I tried your code and checked in my browser and removed above classes. I hope you get the problem. You can also view your number with viewing page source.
I also noticed something about this Modal Problem, remove type="button" from your <button> and the code runs.
Would have posted this as comment but I don't have enough rep yet.
This is because the PHP code gets executed server side and is executed before the HTML is loaded, so the $number is an empty string.