show all employees from specific set of stores - php

Question

My job is to cleanse the database from broken store records(records with missing data like a store name or streetname, database example below). However it turns out some of those records have employees linked to them so we can't just delete them.
Question: what kind of query do I need to make sure only the employees of those stores are shown?
I have three tables in which i need to work: user, department and store_users (store_users is a table in which all ID's are packed together to see which user_id belongs to which store_id.)
Example of code
its most likely wrong but its to give some insight in what I am trying to accomplish.(its purely mysql at the moment)
SELECT
*
FROM
gebruiker
WHERE
(SELECT
*
FROM
winkel_adresgegevens
WHERE
winkel_id IN (SELECT
winkel_gebruikers_winkel_id
FROM
winkel_gebruikers)
AND (winkel_naam = '' OR winkel_straat = ''
OR winkel_huisnummer = ''
OR winkel_postcode = ''
OR winkel_plaats = ''));
database example
+--------+---------------+----------+------------+------------------+
|store_id|store_branch_id|store_name|store_street|store_streetnumber|
|-------------------------------------------------------------------|
| 1 | 100 | Jumbo | Hilversum | 14 |
|--------+---------------+----------+------------+------------------|
| 2 | 150 | Lidl | Kerkelanden| 24 |
|--------+---------------+----------+------------+------------------|
| 3 | 105 | | Loosdrecht | |
|--------+---------------+----------+------------+------------------|
| 4 | 200 | Coop | | 14 |
+--------+---------------+----------+------------+------------------+
hence the question: only show employees from the broken records. (the ones with missing data, see store_name, store_street and store_streetnumber)

Answer 1

UPDATE : This is what you want
SELECT *
FROM employees
WHERE store_name IS NULL OR store_street IS NULL OR store_streetnumber IS NULL ;