running mysql query on Laravel `DB::Raw` - php

Question

I have a MYSQL query that i need to run on Laravel 5.6 query builder. my query is
SELECT paper_id,user_id,COUNT(payments.user_id),users.district
FROM payments
LEFT JOIN users ON payments.user_id = users.id
WHERE payments.paper_id=3
GROUP BY users.district HAVING COUNT(payments.user_id)>=0;
I have tried running this on Laravel DB::Raw with this code
$data=DB::Raw('SELECT paper_id,user_id,COUNT(payments.user_id),users.district
FROM payments
LEFT JOIN users ON payments.user_id = users.id
WHERE payments.paper_id='.$paper_id.'
GROUP BY users.district HAVING
COUNT(payments.user_id)>=0
');
as well as through this code
$data2=DB::table('payments')
->leftJoin('users','payments.user_id','users.id')
->select('paper_id','user_id','users.district',
DB::Raw('COUNT(payments.user_id)'))
->where('payments.paper_id',$paper_id)
->groupBy('users.district')
->select(DB::Raw('HAVING COUNT(payments.user_id)>=0'))
->get();
Error I get on $data (first query) query
[{}]
i get an empty response
Error I get on `$data2 (second query) query
SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error
in your SQL syntax; check the manual that corresponds to your MariaDB server
version for the right syntax to use near 'HAVING COUNT(payments.user_id)>=0 from
payments left join users on payments at line 1 (SQL: select HAVING
COUNT(payments.user_id)>=0 from payments left join users on
payments.user_id = users.id where payments.paper_id = 1 group by
users.district)
But i get SQL syntax error can someone please let me know how to convert SQL to Laravel query builder format.

Answer 1

Running Raw SQL Queries
$data = DB::select('SELECT paper_id,user_id,COUNT(payments.user_id),users.district
FROM payments
LEFT JOIN users ON payments.user_id = users.id
WHERE payments.paper_id= ?
GROUP BY users.district HAVING
COUNT(payments.user_id)>=0', [$paper_id]);
Parameter binding provides protection against SQL injection.
https://laravel.com/docs/5.6/database#running-queries
groupBy / having
->select(DB::Raw('HAVING COUNT(payments.user_id)>=0'))
=>
->having(DB::Raw('COUNT(payments.user_id)'), '>=', 0)
https://laravel.com/docs/5.6/queries#ordering-grouping-limit-and-offset

Answer 2

Try This:
When use Raw query
$data = DB::select('SELECT paper_id,user_id,COUNT(payments.user_id),users.district
FROM payments
LEFT JOIN users ON payments.user_id = users.id
WHERE payments.paper_id='.$paper_id.'
GROUP BY users.district HAVING
COUNT(payments.user_id)>=0
');
OR
$data2= DB::table('payments')->select([
'payments.paper_id','payments.user_id','users.district',
DB::Raw('COUNT(payments.user_id)')
])
->leftJoin('users','payments.user_id','users.id')
->where('payments.paper_id',$paper_id)
->havingRaw("COUNT(payments.user_id)>=0")
->groupBy('users.district')
->get();
I think select function should use one time only in a query, No need to add multiple time. And before add any questin alway search about your problem. Hope it will work..
For your error
SQLSTATE[42000]: Syntax error or access violation: 1055
In this file
vendor\laravel\framework\src\Illuminate\Database\Connectors\Connector.php
at this location in your laravel replace this file this for laravel5.4
PDO::ATTR_EMULATE_PREPARES => true,