open file on client stored on server - php

Question

I want to open a server stored html report file on a client machine.
I want to bring back a list of all the saved reports in that folder (scandir).
This way the user can click on any of the crated reports to open them.
So id you click on a report to open it, you will need the location where the report can be opend from
This is my dilemma. Im not sure how to get a decent ip, port and folder location that the client can understand
Here bellow is what Ive been experimenting with.
Using this wont work obviously:
$path = $_SERVER['DOCUMENT_ROOT']."/reports/saved_reports/";
So I though I might try this instead.
$host= gethostname();
$ip = gethostbyname($host);
$ip = $ip.':'.$_SERVER['SERVER_PORT'];
$path = $ip."/reports/saved_reports/";
$files = scandir($path);
after the above code I loop through each file and generate a array with the name, date created and path. This is sent back to generate a list of reports in a table that the user can interact with. ( open, delete, edit)
But this fails aswell.
So im officially clueless on how to approach this.
PS. Im adding react.js as a tag, because that is my front-end and might be useful to know.

Answer 1

Your question may be partially answered here: https://stackoverflow.com/a/11970479/2781096
Get the file names from the specified path and hit curl or get_text() function again to save the files.
function get_text($filename) {
$fp_load = fopen("$filename", "rb");
if ( $fp_load ) {
while ( !feof($fp_load) ) {
$content .= fgets($fp_load, 8192);
}
fclose($fp_load);
return $content;
}
}
$matches = array();
// This will give you names of all the files available on the specified path.
preg_match_all("/(a href\=\")([^\?\"]*)(\")/i", get_text($ip."/reports/saved_reports/"), $matches);
foreach($matches[2] as $match) {
echo $match . '<br>';
// Again hit a cURL to download each of the reports.
}

Answer 2

Get list of reports:
<?php
$path = $_SERVER['DOCUMENT_ROOT']."/reports/saved_reports/";
$files = scandir($path);
foreach($files as $file){
if($file !== '.' && $file != '..'){
echo "<a href='show-report.php?name=".$file. "'>$file</a><br/>";
}
}
?>
and write second php file for showing html reports, which receives file name as GET param and echoes content of given html report.
show-report.php
<?php
$path = $_SERVER['DOCUMENT_ROOT']."/reports/saved_reports/";
if(isset($_GET['name'])){
$name = $_GET['name'];
echo file_get_contents($path.$name);
}