while creating task I used the command
$cmd3 = 'Register-ScheduledTask '.$ID.' -Action $action -Trigger $trigger';
$check = Shell_Exec("powershell.exe -executionpolicy bypass -NoProfile -Command " . $cmd3 . ";");
Now, I am trying to delete the task via this command:
$cmd1 = "Unregister-ScheduledTask -TaskName ". "\"".$ID."\"";
$check = Shell_Exec("powershell.exe -executionpolicy bypass -NoProfile -Command " . $cmd1 . " -Confirm:\$false;");
It's not getting deleted when I run the php script. So, I tried the same command on powershell and got this error:
Unregister-ScheduledTask : Access is denied.
At line:1 char:1
+ Unregister-ScheduledTask -TaskName 27
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
+ CategoryInfo : PermissionDenied: (MSFT_ScheduledT...TaskPath = "\"):Root/Microsoft/...T_ScheduledTask) [Unregister-ScheduledTask
], CimException
+ FullyQualifiedErrorId : HRESULT 0x80070005,Unregister-ScheduledTask
I am not sure about how I can give admin priveleges via php. Also, am I using -Confirm correctly?
When this shell_exec command runs within my function, only the first url parameter is passed to the receiving php file. I suspect I am not constructing the command correctly.
shell_exec("curl https://inklines.art/process_emails.php?url=" . $full_site_url . "&domain=" . $domain . "&site=" . $site_title . "&title=" . $title . "&permalink=" . $permalink);
How should the command be constructed to pass all the variables?
Thanks much!
I am trying to create a mysql database dump in a php class.
I am executing the following code but only an empty dump file will create. But the same command works fine when I execute it in the command line.
$script = 'mysqldump -h ' . DB_HOST . ' -u ' . DB_USER . ' -p' . DB_PASSWORD . ' ' . DB_NAME . ' > ' . DB_DUMP_PATH . 'mysql-db-dump-' . date('Y-m-d') . '.sql';
exec($script);
But when I give the full path of mysqldump, the dump file create correctly.
$script = '/usr/local/mysql/bin/mysqldump -h ' . DB_HOST . ' -u ' . DB_USER . ' -p' . DB_PASSWORD . ' ' . DB_NAME . ' > ' . DB_DUMP_PATH . 'mysql-db-dump-' . date('Y-m-d') . '.sql';
exec($script);
But I saw most of the tutorials, they just use mysqldump command. Not the full path. What is the reason behind this? I am planing to use this in both unix and windows environment.
Is it possible to get the mysqldump path in php for both environments?
You can avoid path by copying mysqldump and mysql commands from /usr/local/mysql/bin/ to /usr/bin/ path.
My goal is to be able to submit a search query from a web form and have an AppleScript execute the search in DEVONagent. The AppleScript works fine in terminal but I get an error when having PHP do a shell_exec().
<?php
$theQuery = $_GET["Query"];
$cmd = "theSearch=\"$theQuery\" osascript -e \"set theSearch to system attribute " . "\\" . "\"theSearch" . "\\" . "\"\" -e \"tell application " . "\\" . "\"DEVONagent" . "\\" . "\"\" -e \"search theSearch using set " . "\\" . "\"Web (Deep Link)" . "\\" . "\"\" -e \"end tell\" 2>&1";
echo "<pre>$cmd</pre><BR><BR>";
$theResponse = shell_exec ( $cmd );
echo "Your search for \"$theQuery\" has started and the results will be emailed to you once complete.";
echo "<pre>$theResponse</pre>";
?>
I end up with the following error from the $theResponse echo:
83:92: syntax error: Expected end of line but found identifier. (-2741)
I'm thinking maybe a permissions thing but I just cannot figure it out.
I'm using a Linux local computer and need to backup/mirror some very large file structures regularly. I only have access to SFTP.
I was after a simple one click solution. I originally tried to write the little script in BASH but I've never used it before and am not up to scratch with the syntax so I resorted to PHP. (I do understand PHP is not designed for this kind of work, but I'm on a tight time scale and don't have the time to get into BASH atm)
<?php
//init
parse_str(implode('&', array_slice($argv, 1)), $_GET);
$error = array();
$lPrefix = '/home/hozza/Sites/';
$archiveLocation = '/home/hozza/Backups/';
$lDir = isset($_GET['l']) ? $_GET['l'] : $error[] = 'Local Directory Required';
$rDir = isset($_GET['r']) ? $_GET['r'] : $error[] = 'Remote Directory Required';
$bookmark = isset($_GET['b']) ? $_GET['b'] : $error[] = 'lftp Bookmark Required';
//Check for args
if(count($error) == 0) {
$archiveName = end(explode('/', $lDir)) . '_' . date('Y-m-d_H-i');
//Validate local dir
if(is_dir($lPrefix . $lDir)) {
//preserve Sublime Text 2 config SFTP files
$ST2_SFTP_conf = false;
if(file_exists($lPrefix . $lDir . '/sftp-config.json')) {
$ST2_SFTP_conf = file_get_contents($lPrefix . $lDir . '/sftp-config.json');
unlink($lPrefix . $lDir . '/sftp-config.json');
}
//Start mirror
$lftOutput = explode("\n", shell_exec('lftp -e "mirror -e -p --parallel=10 --log=' . $archiveLocation . 'logs/' . $archiveName . '.txt ' . $rDir . '/ ' . $lPrefix . $lDir . '/; exit top" ' . $bookmark));
//Tar regardless of lftp error or success
$tarOutput = shell_exec('cd ' . $lPrefix . ' && tar -czf ' . $archiveLocation . $archiveName . '.tar.gz ' . $lDir);
//Output completion or errors
shell_exec('notify-send -i gnome-network-properties -t 0 "Mirror & Archive Complete" "' . $archiveName . '\n\n' . implode('\n', $lftOutput) . $tarOutput . '"');
//put back ST2 SFTP conf
if($ST2_SFTP_conf != false) file_put_contents($lPrefix . $lDir . '/sftp-config.json', $ST2_SFTP_conf);
exit;
}
else shell_exec('notify-send -i error -t 0 "Mirror & Archive Error" "' . date('Y-m-d') . ' ' . date('H-i') . '\n' . $lDir . ' \n Does not exist! D:"');
}
else shell_exec('notify-send -i error -t 0 "Mirror & Archive Error" "' . date('Y-m-d') . ' ' . date('H-i') . '\n' . implode('\n', $error) . '"');
?>
It can be run for many sites via a short-cut like so...
terminator -T "Mirror & Archive" -e "php ~/Programs/mirror.php l=local-dir_path r=./ b=lftp-bookmark-name"
If no password is in the LFTP bookmark (there shouldn’t be as it's stored in plain text) the terminal prompts for a password, after the script has run, a nice notification is given with some info about files/folders/speed etc.
However, when the script is running in a terminal, only the "input password" bit is output to the terminal, I would like all the output displayed in the terminal (normally that would display what file/folder is currently working with etc.)
Anyone know how to do that?
IIRC the reason that you see the password prompt output to the terminal is that it is using stderr. You could try redirecting stdout to stderr for your commands which should show you the 'real-time' progress. Tack this on to the end of the shell_exec() command: 1>&2
ie:
shell_exec('lftp -e "mirror -e -p --parallel=10 --log=' . $archiveLocation . 'logs/' . $archiveName . '.txt ' . $rDir . '/ ' . $lPrefix . $lDir . '/; exit top" ' . $bookmark . ' 1>&2')
However, this will preclude you from having anything returned by shell_exec for logging purposes. What I would suggest is something like:
$log_stem = '/tmp/' . time() . '_'; // ie: /tmp/1357581737_
$lfOutfile = $log_stem . 'lftp.log';
$tarOutfile = $log_stem . 'tar.log';
shell_exec('lftp -blah | tee ' . $lfOutfile ' 1>&2' );
shell_exec('tar -blah | tee ' . $tarOutfile ' 1>&2' );
$lfOut = file_get_contents($lfOutfile);
$tarOut = file_get_contetns(tarOutfile);
// remove tmp files
unlink($lfOutfile);
unlink($tarOutfile);
Which will capture a copy of the output to a file before redirecting the output to stderr so you can watch it live.
However, if you want to run this via cron I would recommend against writing anything to stderr that is not an error, otherwise cron will send a warning email every time it is run.
I think the last answer was close:
Either this:
shell_exec('lftp -blah |& tee ' . $lfOutfile );
shell_exec('tar -blah |& tee ' . $tarOutfile );
Or if that still doesn't work try this:
shell_exec('lftp -blah 2>&1 | tee ' . $lfOutfile );
shell_exec('tar -blah 2>&1 | tee ' . $tarOutfile );