How to write a php unit test case for symfony controller - php

Question

I am trying to write a unit test case for symfony controller.
Controller Code
namespace AppBundle\Controller;
use Symfony\Component\HttpFoundation\Request;
class Controller1 extends SecuredController
{
public function preExecute(Request $request) {
parent::preExecute($request);
}
public function indexAction()
{
return $this->render('help/index.html.twig');
}
I have tried writing a test case as shown below but it throws an internal error
namespace Tests\AppBundle\Controller;
use Symfony\Bundle\FrameworkBundle\Test\WebTestCase;
class Controller1Test extends WebTestCase
{
public function testIndex()
{
$client = static::createClient();
$response = $client->getResponse();
$this->assertEquals(200, $response->getStatusCode());
}
}
Any suggestion would be helpful for me

Answer 1

First of all, is a UNIT test. You here dont need a client. You just need the class you want to test.
namespace Tests\AppBundle\Controller;
use PHPUnit\Framework\TestCase;
use AppBundle\Controller\Controller1;
class Controller1Test extends TestCase
{
public function testIndex()
{
$this->request = $this->getMockBuilder(
'Symfony\Component\HttpFoundation\Request'
)->disableOriginalConstructor()
->getMock();
$controller = new Controller1();
$controller->preExecute($this->request);
$response = $controller->indexAction();
$this->assertEquals(
200,
$response->getStatusCode()
);
}
}
and for example your code could be
namespace Tests\AppBundle\Controller;
use Symfony\Component\HttpFoundation\Response;
class Controller1 extends SecuredController
{
public function indexAction()
{
return new Response();
}
}