I want to extract JSON data from laravel using JQUERY but the result is always undefined.
this is the json code I've got:
{"data":{"id":1,"title":"glove hard","code":"0102","category":"glove"}}
and this is the js code:
$('#show').click(function(){
$.ajax({
url: 'example.com/api/product/1',
method: 'GET',
dataType: 'json',
success: function(data){
$('#result').text(data.category)
}
})
})
Since your code return JSON data is
{"data":{"id":1,"title":"glove hard","code":"0102","category":"glove"}}
The ajax success function parameter is called data and the first key in the json result is named data, to access the value of category, your code should be
$('#show').click(function(){
$.ajax({
url: 'example.com/api/product/1',
method: 'GET',
dataType: 'json',
success: function(data){
//Call the first wrapper key first.
$('#result').text(data.data.category)
}
})
})
Use the $.parseJSON which parse the well formatted json string into js object.
Your success callback will be
success: function(data){
var obj = $.parseJSON(data);
$('#result').text(obj.data.category)
}
Make it even simpler:
jQuery('#show')
.click(function() {
jQuery
.getJSON('example.com/api/product/1')
.done(function(data) {
jQuery('#result').text(data.data.category);
}
});
Related
I am using ajax to send parameters and consult them, everything is functional only when obtaining the array with the records does not allow me to display the values independently
this is index.php
<script>
$(document).ready(function(){
$("#Montox").change(function(){
var varmonto = $("#Montox").val();
$.ajax({
method: "post",
url: "ajax/calc.php",
data: {monto:varmonto}
})
.done(function(data){
$('#chattext').html(data['username1']);
$('#chattext2').html(data['username2']);/*I NEED TO SHOW THE DATA 'username2'*/
});
});
});
</script>
this is my calc.php
<?php
echo json_encode(array('username1' => "luis", 'username2' => "jose"));
?>
You're not parsing the response as JSON. You can:
Use the dataType: 'json' option to $.ajax() to make it parse it as JSON automatically.
Call header("Content-type: text/json"); in PHP to tell jQuery that the response is JSON.
Use data = JSON.parse(data) in the .done() function to parse it explicitly.
Since you're expecting a JSON result from your server, you need to set the dataType property on your ajax call to return a Javascript object that you can manipulate. Like this:
<script>
$(document).ready(function(){
$("#Montox").change(function(){
var varmonto = $("#Montox").val();
$.ajax({
method: "post",
url: "ajax/calc.php",
data: {monto:varmonto},
dataType: 'json'
})
.done(function(data){
// 'data' is a javascript object, not an array!
$('#chattext').html(data.username1);
$('#chattext2').html(data.username2);/*I NEED TO SHOW THE DATA 'username2'*/
});
});
});
</script>
That should work.
Force JSON object inside the ajax with:
$.ajax({
method: "post",
url: "ajax/calc.php",
data: {monto:varmonto},
dataType: "json" //<--- HERE
})
You need add Json TYPE in your ajax header dataType: "json" it will allow you to get json text and parse it.
And for the next time, post the RESULT of (data) if you wanna a real help
I want to pass values to a PHP script so i am using AJAX to pass those, and in the same function I am using another AJAX to retrieve those values.
The problem is that the second AJAX is not retrieving any value from the PHP file. Why is this? How can I store the variable passed on to the PHP script so that the second AJAX can retrieve it?
My code is as follows:
AJAX CODE:
$(document).ready(function() {
$("#raaagh").click(function(){
$.ajax({
url: 'ajax.php', //This is the current doc
type: "POST",
data: ({name: 145}),
success: function(data){
console.log(data);
}
});
$.ajax({
url:'ajax.php',
data:"",
dataType:'json',
success:function(data1){
var y1=data1;
console.log(data1);
}
});
});
});
PHP CODE:
<?php
$userAnswer = $_POST['name'];
echo json_encode($userAnswer);
?>
Use dataType:"json" for json data
$.ajax({
url: 'ajax.php', //This is the current doc
type: "POST",
dataType:'json', // add json datatype to get json
data: ({name: 145}),
success: function(data){
console.log(data);
}
});
Read Docs http://api.jquery.com/jQuery.ajax/
Also in PHP
<?php
$userAnswer = $_POST['name'];
$sql="SELECT * FROM <tablename> where color='".$userAnswer."'" ;
$result=mysql_query($sql);
$row=mysql_fetch_array($result);
// for first row only and suppose table having data
echo json_encode($row); // pass array in json_encode
?>
No need to use second ajax function, you can get it back on success inside a function, another issue here is you don't know when the first ajax call finished, then, even if you use SESSION you may not get it within second AJAX call.
SO, I recommend using one AJAX call and get the value with success.
example: in first ajax call
$.ajax({
url: 'ajax.php', //This is the current doc
type: "POST",
data: ({name: 145}),
success: function(data){
console.log(data);
alert(data);
//or if the data is JSON
var jdata = jQuery.parseJSON(data);
}
});
$(document).ready(function() {
$("#raaagh").click(function() {
$.ajax({
url: 'ajax.php', //This is the current doc
type: "POST",
data: ({name: 145}),
success: function(data) {
console.log(data);
$.ajax({
url:'ajax.php',
data: data,
dataType:'json',
success:function(data1) {
var y1=data1;
console.log(data1);
}
});
}
});
});
});
Use like this, first make a ajax call to get data, then your php function will return u the result which u wil get in data and pass that data to the new ajax call
In your PhP file there's going to be a variable called $_REQUEST and it contains an array with all the data send from Javascript to PhP using AJAX.
Try this: var_dump($_REQUEST); and check if you're receiving the values.
you have to pass values with the single quotes
$(document).ready(function() {
$("#raaagh").click(function(){
$.ajax({
url: 'ajax.php', //This is the current doc
type: "POST",
data: ({name: '145'}), //variables should be pass like this
success: function(data){
console.log(data);
}
});
$.ajax({
url:'ajax.php',
data:"",
dataType:'json',
success:function(data1){
var y1=data1;
console.log(data1);
}
});
});
});
try it it may work.......
This is the jquery ajax part in which i have sent json data to the php file.
$(function () {
$('form').submit(function () {
var fields = $(this).serializeArray();
var ans_json = JSON.stringify(fields);
console.log(ans_json);
$.ajax({
url: "results.php",
type: "POST",
data: ans_json,
dataType: "json",
success: function (result) {
console.log(result);
}
});
return false;
});
});
Now i want to use this json data sent to the php page.How can i do it? I have done it this way but it returns null.
<?php
echo json_decode('ans_json');
?>
I have a set of 10 questions which need to be answered. 3 questions were answered so got the below result.This is what i got in my console.
[{"name":"answer_9","value":"a"},{"name":"answer_10","value":"a"}] quizzes.php:14
null
You don't need to decode any JSON string at server-side if you encode properly your parameters.
You can use .serialize() to do the form serialization for you, and it's ready to send.
$(function () {
$('form').submit(function () {
var serialized = $(this).serialize();
$.ajax({
url: "results.php",
type: "POST",
data: serialized,
...
});
return false;
});
});
Your parameters will be available in your $_POST as in any normal POST request. For example,
$ninth_answer = $_POST["answer_9"];
You need to decode the POST variable. Currently you're decoding just a string which even isn't valid JSON.
<?php
$json_arr = json_decode($_POST['my_json'], true);
var_dump($json_arr);
echo "First name in json is:". $json_arr[0]['name'];
?>
and edit your javascript to reflect following:
This posts my_json parameter with your json as an value. This makes it easy for PHP to recieve it using $_POST.
$.ajax({
url: "results.php",
type: "POST",
data: {"my_json": ans_json},
dataType: "json",
success: function (result) {
console.log(result);
}
});
I suggest to read a little about those things:
http://api.jquery.com/jQuery.ajax/
http://ee1.php.net/manual/en/function.json-decode.php
For some reason this jQuery function is not working properly. Here's my code... the response div is not updating with my response.
WHEN AJAX FUNCTION IS CALLED
if ($action == 'sort') {
echo 'getting a response';
return 0;
}
JQuery FUNCTION
function sort() {
$.ajax({
type: "POST",
url: "contributor_panel.php?action=sort",
data:"sort_by=" + document.getElementById("sort_by").value +
"&view_batch=" + document.getElementById("view_batch").value,
success: function(html){
$("#ajaxPhotographSortResponse").html(html);
}
});
}
DIV TO REPLACE
<div id="ajaxPhotographSortResponse"></div>
Move the action=sort into the data property of the $.ajax function. You're making a POST request, but appending data onto your query string like a GET request. Data only appends to the query string if it's a GET request.
Example:
$.ajax({
type: "POST",
url: "contributor_panel.php",
data: {action:'sort', sort_by: $('#sort_by').val(), view_batch: $('#view_batch').val()},
success: function(html){
$("#ajaxPhotographSortResponse").html(html);
}
});
http://api.jquery.com/jQuery.ajax/
Instead of concatenating the arguments you are passing to your server side script I would recommend you using the following syntax. Also if you already use jQuery you no longer need the document.getElementById function:
$.ajax({
type: "POST",
url: "contributor_panel.php?action=sort",
data: { sort_by: $("#sort_by").val(), view_batch: $("#view_batch").val() },
success: function(html){
$("#ajaxPhotographSortResponse").html(html);
}
});
or even shorter using the .load() function:
$('#ajaxPhotographSortResponse').load('contributor_panel.php?action=sort',
{ sort_by: $("#sort_by").val(), view_batch: $("#view_batch").val() });
I'm writing a simple ajax function and looking to populate two text input fields with the 'success' results. I'm wondering what my php syntax has to be to return an object.
Here is my Javascript function
function editModule(a){
data = {moduleNum:a}
$.ajax({
type: 'POST',
data: data,
url: 'includes/ajaxCalls.php',
success: function(data) {
alert(data['title']); // <-- This is where I'm not sure what to return from php
}
});
}
Here is my php doc (so far, this is where I need to know how to return an object)...
<?php
$data = array('title'=>'this');
echo json_encode($data);
When I run the function I just get the alert "undefined".
Suggestions?
Thanks,
-J
Try this. You can specify that you're expecting a JSON object and then you can interpret data accordingly.
function editModule(a){
data = {moduleNum:a}
$.ajax({
type: 'POST',
data: data,
dataType: 'json',
url: 'includes/ajaxCalls.php',
success: function(data) {
alert(data.title);
}
});
}
I have returned JSON data from the server via a jQuery Ajax call, not in PHP but it should be the same. As long as you set the content-type of your response to application/json jQuery should consider the responseText as a JSON string. Alternatively you can also set dataType: "JSON" in your Ajax call which tells jQuery that you expect JSON.
Your php page returns: {"title":"this"} in this case.
So you can reference the result with:
alert(data.title);
You may need to specify the data type:
function editModule(a){
data = {moduleNum:a}
$.ajax({
type: 'POST',
data: data,
url: 'includes/ajaxCalls.php',
dataType: 'json',
success: function(data) {
alert(data['title']); // <-- This is where I'm not sure what to return from php
}
});
}