I have date in this type of format: April 1st 2017 and I want to convert it into this type of format: 2017/04/01 in my CodeIgniter code using php. I have used below posted piece of code but it is not working. Please solve the issue.
Code:
$date = DateTime::createFromFormat('m/d/Y', "April 1st 2017");
echo "Date = ".$date->format('Y-m-d');
You can use strtotime() and date() php functions as
$newDate = date("m/d/Y", strtotime("April 1st 2017"));
Or in CodeIgniter
$date = DateTime::createFromFormat('j F Y - H:i', 'April 1st 2017');
echo $date->format('m/d/Y H:i:s');
Your format can be used in the constructor of DateTime. See accepted formats.
$date = new DateTime("April 1st 2017");
echo "Date = ".$date->format('Y-m-d');
Outputs:
Date = 2017-04-01
If you want to use DateTime::createFromFormat(), you have to use the proper format
"F jS Y"
The format you specified for your date is incorrect.
It would convert '04/01/2017' but it does not suit
April 1st 2017.
Try instead: createFromFormat('F dS Y')
Explanation:
F - full textual representation of a month, such as January.
d - day
S - English ordinal suffix for the day of the month
Y - 4-digit representation of year
you can try this also
<?php
$date='22 march 2018';
echo date('m/d/Y', strtotime($date));
?>
Related
I am trying to change the date 13 December, 2016 using date('Y-m-d',strtotime('13 December, 2016')) and it gives me the result of 2017-12-13, what i am missing here
Actually that comma within the date strings create an issue while using the strtotime function you can replace it with str_replace or instead you can simply use DateTime::createFromFormat method so no need of using extra function like as
$date = DateTime::createFromFormat('d F, Y','13 December, 2016');
echo $date->format('Y-m-d');
or simply date_create_from_format
$date = date_create_from_format('d F, Y','13 December, 2016');
echo $date->format('Y-m-d');
date('Y-m-d', strtotime('13 December 2016'));
You need to remove your comma.
This will give the expected result.
Try this
$date = '13 December 2016';
echo date('d-m-Y', strtotime($date));
The m formats the month to its numerical representation there.
Mistake: You don't have to put coma there.
use
$time = strtotime('10/21/2016');
$newformat = date('Y-m-d',$time);
echo $newformat;
I have a feed which gives feed in the following format: "Fri 14 Oct"
I want to see if today's date matches the date from the feed. My problem is the format of today's date/
$today = date("d m");
This outputs 17 10.
What is the best way to format $today so that it outputs Day (shorthand) space date (number) Month (shorthand) ?
how about:
$today = date("D j M");
As explained in date() reference manual.
Anyway you should be aware of timezone issues unless you are 100% sure that your server is in the same timezone of the feed you are comparing.
I would follow a different approach though, you can parse the feed's date using DateTime::createFromFormat() which also understand timezones, and then compare it with today's date.
$today = date("D d M");
PHP Date Documentation
<?php
// Prints the day
echo date("l") . "<br>";
// Prints the day, date, month, year, time, AM or PM
echo date("l jS \of F Y h:i:s A");
?>
For more details, please visit http://www.w3schools.com/php/func_date_date.asp
I have dates currently in this format: yy-mm-dd (e.g. 2011-11-18)
I want them in this format: Friday 18 November 2011
I've tried reading through the PHP documentation manual, but I can't see how to manage dates in the format that I have. If the date needs to be in a different order I can arrange that, but I'm a bit stuck at the meoment.
Any help would be much appreciated.
Use PHP5s new date classes. Much cleaner:
$date = DateTime::createFromFormat('Y-m-d', '2011-11-18');
echo $date->format('l d F Y');
date('l j F Y', strtotime($date));
Just use starttime to change the the dates in many formats using this link.
echo date('l d F Y');
gives you the date format you want.
This was all in the manual you yourself linked.
just use strtotime to get back a timestamp and then use date() to format that:
$date = '2011-11-18'; // your date
$timestamp = strtotime($date); // convert to a timestamp
$new_date = date('l j F Y',$timestamp) // format timestamp
echo $new_date;
I have date in format 2011-01-28 06:34:33 i.e. date("Y-m-d H:i:s"). I want to convert it into 28th January 2011.
How can I change it?
Supply the date function with your format, which can be found here. Pass the timestamp of your original date as the second parameter to date. You can obtain the timestamp by using strtotime.
date("dS F Y", strtotime("2011-01-28 06:34:33"));
Use
$dateStr = date("jS F Y", time());
The day value is without leading zero.
Try this echo date('jS F Y h:i:s A');
I am pulling the dates of various posts from a database. The dates are in the following format:
2009-08-12
Numeric Year - Numeric Month - Numeric Day
How can I reformat these dates to something more user friendly like:
August 12, 2009
Numeric Month Numeric Date, Numeric Year
Assuming that the date gotten from the mysql database is stored in a variable called:
$date = $row['date_selected'];
Unlike the strtotime based examples, this allows you to ensure the month and day are interpreted in the correct order regardless of locale settings specified on the server.
$date = DateTime::createFromFormat('Y-m-d', '2009-08-12');
$output = $date->format('F j, Y');
date("F d, Y", strtotime($input))
$new_format = date("Your Date String", strtotime($date));
See:
- http://php.net/strtotime
- http://php.net/date
Basically, if strtotime() can read it correctly, you can reformat it anyway you please.
In this case, Year - Month - Day is a properly recognized strtotime() format, this might not be the case for other formats.
You might consider doing your date formatting in MySQL with your select statement:
DATE_FORMAT(date,'%M %e, %Y') as date_selected
http://www.w3schools.com/sql/func_date_format.asp
<?php
echo date('F j, Y', strtotime($date));
You might want to look at the php function strtotime:
http://php.net/manual/en/function.strtotime.php
It'll parse a large number of date representations to a Unix timestamp.
Then use the date function.
Using strtodate or explode to split the date into its different components, you can then use the date function with the appropriate format string:http://php.net/manual/en/function.date.php
$date = "2009-08-12";
list($year,$month,$day) = explode("-",$date);
$formattedDate = date("F d, Y", mktime(0,0,0,$month,$day,$year));
Outputs: "August 12, 2009"
<?php
//Date Formatter
/*
date: date you want to convert
format: its current format ie m-d-Y, m/d/Y, Y-m-d, Y/m/d
delimS: Current delimiter ie - or / or .
delimF: The delimiter you want for the result
NOTE: this will only convert m-d-Y to Y-m-d and back
*/
function dtform($date,$format,$delimS,$delimF){
$dateFinal = '';
if($format == 'm'.$delimS.'d'.$delimS.'Y'){
$dateFinal_exp = explode($delimS,$date);
$dateFinal = $dateFinal_exp[2].$delimF.$dateFinal_exp[0].$delimF.$dateFinal_exp[1];
}else if($format == 'Y'.$delimS.'m'.$delimS.'d'){
$dateFinal_exp = explode($delimS,$date);
$dateFinal = $dateFinal_exp[1].$delimF.$dateFinal_exp[2].$delimF.$dateFinal_exp[0];
}
return $dateFinal;
}
?>
Use it like this:
// February 1, 2005
print date ("F j, Y", mktime (0,0,0,14,1,2004));