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Note! I can not use filter_var in my application. Only generic functions.
Perhaps a regex?
<?php
if (is_valid_ipv4($ip)) { ... }
else if (is_valid_ipv6($ip) { ... }
else { ... }
?>
You can just use inet_pton. It returns false if the IP is not a valid IPv6 or IPv4:
function validateIP($ip){
return inet_pton($ip) !== false;
}
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I tried things like
$query = parse_url($url, PHP_URL_QUERY);
// Returns a string if the URL has parameters or NULL if not
if ($query) {
$url .= '&category=1';
} else {
$url .= '?category=1';
echo "hi";
}
?>
but still i cant seem to find the answer.
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How can I create a crawler in php which search for a particular string in a webpage and returns whether it is present or not?
Try this function I made, it takes in the pages URL and the string to look for in this URL's content.
<?php
var_dump(searchPage("http://google.com", "Tacos")); //False
var_dump(searchPage("http://google.com", "Google")); //True
function searchPage($url, $string){
$input = file_get_contents($url);
if (strpos($input,$string) !== false) {
return true;
}else{
return false;
}
}
?>
I hope this helped,
Sebastian
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In PHP, i have strings , similar:
"www.mysite.com/fa/doc/report/67571/مطذح کردنو تت";
"www.mysite.com/fa/571/نهتال اهخع";
"www.mysite.com/fa/";
I want if there are Persian's Chars of string, delete them.
Output:
www.mysite.com/fa/doc/report/67571/
www.mysite.com/fa/571/
www.mysite.com/fa/
How can i do this?
You should try this code.
<?php
echo remove_persian("www.mysite.com/fa/doc/report/67571/مطذح کردنو تت");
function remove_persian($text)
{
return preg_replace('#[^a-zA-Z0-9./]#', '', $text);
}
This will output like this:
www.mysite.com/fa/doc/report/67571/
You can use a regex :
$clean = preg_replace('[^a-zA-Z\/\d\s:]', '', $url);
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I have a number field: <?php echo $entity->field_zip_code_name[0];?>
I want to create an if then statement based on the output number. Here is what I have:
if ($entity->field_areacode[0] = 92919,92923,94975,37783) {
<h3 style="font-size: 20px;"><strong>Area Code:</strong></h3>;
}
else {
NONE;
}
any help would be greatly appreciated.
Not sure what x is, if it's $entity->field_zip_code_name[0] then echo that:
if(in_array($entity->field_zip_code_name[0], [92919,92923,94975,37783])) {
//display x
}
If your PHP version doesn't support [] then use array():
if(in_array($entity->field_zip_code_name[0], array(92919,92923,94975,37783))) {
//display x
}
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Right now I'm using strcmp but that's not really optimal.
So, what's the best way to do it?
You can also use filter_var :
if(filter_var($ip, FILTER_VALIDATE_IP, FILTER_FLAG_IPV6)) {
echo "IPV6 valid.";
} else {
echo "Not valid.";
}
You can find the list of filters here.
Use strcmp instead of strcpy. That must be the issue.
You can just check, if a : is in the ip-adress:
if (strpos($_SERVER["REMOTE_ADDR"],":") !== false) //....IPv6
else //....IPv4
Use inet_pton. Also works for ipv4:
function ip_validate($ip){
return inet_pton($ip) !== false;
}
$_SERVER["REMOTE_ADDR"] this is your buddy. It checks for the adress. I suppose the simplest way would be to check this address for a non-numeric sign. If it contains one, its a IPv6 address. Maybe there are better or more elegant ones, but ive never used it because no provider is using IPv6 yet.