php Query a database - php

Question

I queried an sql server database and got a recordset with 5 rows. I then looped through the recordset doing my output. All was fine when i used:
<?= $row.['Photo'] ?>
to output the value.
When I tried to ask if the value from the database was null, I ran into problems. PHP Notice: Array to string conversion.
if ($row.['Photo'] == "" || $row.['Photo'] == null){
echo $row.['Photo'];
else{
//something else;
}
This was so that if no photo was indicated in the record, I could display something else.
I have researched this and was unable to find the answer. I tried
$photo = strval($row.['Photo']);
$photo = implode("",$row.['Photo']);
Here is my query:
$serverName = "IT-NEWITWEB-D\sqlexpress";
$connectionInfo = array( "Database"=>"eVENTS", "UID"=>"uSER", "PWD"=>"P#\$\$" );
$conn = sqlsrv_connect( $serverName, $connectionInfo);
if( $conn === false ) {
die( print_r( sqlsrv_errors(), true));
}
$sql = "SELECT tblEvents.EventID, tblEvents.Photo, tblEvents.title, tblLocation.Date, tblLocation.Location, tblEvents.unlist, tblEvents.description, tblEvents.Par_num FROM tblLocation INNER JOIN tblEvents ON tblLocation.Event_ID = tblEvents.EventID GROUP BY tblEvents.EventID, tblEvents.Photo, tblEvents.title, tblLocation.Date, tblLocation.Location, tblEvents.unlist, tblEvents.description, tblEvents.Par_num HAVING (((tblEvents.unlist)>getdate()) AND ((tblEvents.Par_num)=261));";
//$params = array();
$stmt = sqlsrv_query( $conn, $sql);
if( $stmt === false ) {
die( print_r( sqlsrv_errors(), true));
}
$result = sqlsrv_query($conn, $sql);
while($row = sqlsrv_fetch_array($result)) {
//if photo is empty, display date instead.
}

Answer 1

you're doing wrong, use this $row['Phone']; instead of $row.[];
getting property of Object!

Answer 2

I think that PHP interprets that you are trying to concatenate $row with something else. Try removing the dots "$row.['Phone']".
Another thing that I noticed is that, in your example, you are printing only when the value is empty or null. To do the opposite you should do:
if ($row['Photo'] != "" && $row['Photo'] != null){
echo $row['Photo'];
else{
//something else;
}
Or
if (is_array($row) && !empty($row['Photo'])) {
echo $row['Photo'];
else{
//something else;
}