how to print whole XML using DOMDocument - php

Question

i want to grab all link from a url.
but i want it showing in XML.
for example i want to take all link from this url http://www.example.com/xxxx/
i want it to print like this:
anotherxxx
here my code but i got error
Fatal error: Uncaught TypeError: Argument 1 passed to
DOMDocument::saveXML() must be an instance of DOMNode or null, string
given in C:\xampp\htdocs\sh\index.php:18 Stack trace: #0
C:\xampp\htdocs\sh\index.php(18): DOMDocument->saveXML('/') #1 {main}
thrown in C:\xampp\htdocs\sh\index.php on line 18
$url = "http://www.example.com/xxxx/";
$ch = curl_init();
$timeout = 5;
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);
$html = curl_exec($ch);
curl_close($ch);
$dom = new DOMDocument();
#$dom->loadHTML($html);
foreach($dom->getElementsByTagName('a') as $link) {
$short_link = $link->getAttribute('href');
echo $short_link1 = $dom->saveXML($short_link);
echo "<br />";
}

Answer 1

Use DOMXPath to retrieve all links as
$links = $xpath->query("//a/#href");
Then loop through links and get its html content as
$dom->saveHTML($link)
Full code here ..
$dom = new domDocument();
$dom->loadHTML($html);
$xpath = new DomXPath($this->dom);
$links = $xpath->query("//a/#href");
foreach($links as $link){
echo $dom->saveHTML($link);
echo "<br />";
}

Answer 2

The call to getAttribute() will return the attributes value as a string. So if you just want the href then
$short_link = $link->getAttribute('href');
echo $short_link;
with...
anotherxxx
will give you http://www.example.com/yyyy/
If you want the anchor tag itself...
foreach($dom->getElementsByTagName('a') as $link) {
echo $dom->saveXML($link);
}
Will give
anotherxxx