display unrelated data from 2 tables - php

Question

Trying to get data to display from 2 different and basically unrelated tables. Don't want them joined, just discrete output to look like this in a select box:
Category: current category from table1 (this part works)
Entire list of categories from table 2 (correct number of empty option tags, no data showing)
DB connection code:
//DB CONNECTION//
$dbcnx = mysqli_connect("localhost", $DBASEUSER, $DBASEPASSWORD, $DBASE);
//Main Showcase
$sql = "SELECT * FROM `dprods`";
//////HEADER in main page
<?php
$ID=$_GET['ID'];
$CAT=$_GET['cat'];
?>
//////Main SECTION
<?php
require "db_conn.php";
$sql2 = "SELECT * FROM $DBTABLE WHERE ID=$ID";
$getinfo = mysqli_query($dbcnx, $sql2);
$row = mysqli_fetch_assoc($getinfo);
$PROD = $row['dtitle'];
$PRICE = $row['dprice'];
$PP = $row['dpplink'];
echo "<tr>
<td width=\"12%\">
<div align=\"right\"><b><font face=\"Arial, Helvetica, sans-serif\" size=2>Product
Category: </font></b></div>
</td>
<td colspan=2 width=\"88%\"><select name=\"dcat\"><option value=\"$CAT\">Current Category: $CAT</option>";
$dcat = "SELECT * FROM 'dcat'";
$getcat = mysqli_query($dbcnx, $dcat);
$row2 = mysqli_fetch_assoc($getcat);
while($row2 = mysqli_fetch_assoc($result))
{ echo " <option value=\"".$row2["dcategory"]."\">".$row2["dcategory"]."</option>";
}
echo "".$row["dprice"]."</select>
</tr>
<tr>
<td width=\"12%\"> </td>
<td width=\"24%\"> </td>
<td width=\"64%\"> </td>
</tr>
<tr>
<td width=\"12%\">
<div align=\"right\"><b><font face=\"Arial, Helvetica, sans-serif\" size=2>Product
Title: </font></b></div>
</td>
<td width=\"24%\"> <b><font face=\"Arial, Helvetica, sans-serif\" size=2>
<input type=\"text\" name=\"Title\" value=\"".$row["dtitle"]."\" size=35 maxlength=25>
</font></b><b><font face=\"Arial, Helvetica, sans-serif\" size=2> </font></b></td>
<td width=\"64%\"><b><font face=\"Arial, Helvetica, sans-serif\" size=2>Price</font></b>:
<b><font face=\"Arial, Helvetica, sans-serif\" size=2>
<input type=\"text\" name=\"Price\" value=\"".$row["dprice"]."\" maxlength=10 size=20>
</font></b></td>
</tr>
<tr>
<td width=\"12%\"> </td>
<td width=\"24%\"> </td>
<td width=\"64%\"> </td>
</tr>
<tr>
<td width=\"12%\">
<div align=\"right\"><font face=\"Verdana, Arial, Helvetica, sans-serif\" size=2><b>PayPal
Link: </b></font></div>
</td>
<td colspan=2><font face=\"Arial, Helvetica, sans-serif\"><b>http://www.paypal.com</b>
</font>
<input type=\"text\" name=\"PP\" value=\"".$row["dpplink"]."\" size=50>
<font face=\"Arial, Helvetica, sans-serif\">Only put in what follows paypal.com</font></td>
</tr>
";
mysqli_close($dbcnx);
?>
Been working and researching this for hours and now I'm so horribly confused, lupus induced Swiss-cheese brain isn't helping. I think I'm very close, just unable to get the data from the 2nd table to display. Would appreciate any suggestions, but please keep it as simple as possible. Some of the complex code I've seen in my research confuses me even more. Thanks!

Answer 1

Try including getcat in your select query like this:
$dcat = "SELECT 'dcategory', 'getcat' FROM 'dcat'";
$getcat = mysqli_query($dbcnx, $dcat);
while($row2 = mysqli_fetch_assoc($getcat))
{
echo " <option value=\"".$row2["getcat"]."\">".$row2["getcat"]."</option>";
}
echo "</select>"
You could also use $dcat = "SELECT * FROM 'dcat'";, but the above is likely slightly more efficient.
Also, I don't see where $result was being set for this code while($row2 = mysqli_fetch_assoc($result))
It looks like $result isn't set, so it would obviously give you undesirable results.
You're also doing $row2 = mysqli_fetch_assoc($getcat); outside of the while loop, which will grab the first row before entering the loop. The loop would start at the second row.
Please look at http://php.net/manual/en/mysqli-result.fetch-assoc.php
Also, your script will be subject to SQL Injection, as mentioned in the comments. You will need to fix it so it is as safe as possible. Read the links in the comments and also make sure you're using prepared statements

Answer 2

adpro, your help was invaluable. I was more confused than I realized and your comments helped point that out to me. I went back & started from scratch with a clean query code that I could print out, mark up with colored hi-liters to follow the variables. Code now works as desired and I'm posting for anyone else who may need the clarification. I appreciate the input from everyone about the sql injection. My goal was to get the simple functionality working first before making it more complicated. Now I can add the protection to prevent sql injection.
<?php
require "db_conn.php";
$sql2 = "SELECT * FROM $DBTABLE WHERE ID=$ID";
$getinfo = mysqli_query($dbcnx, $sql2);
$row = mysqli_fetch_assoc($getinfo);
$PROD = $row['dtitle'];
$PRICE = $row['dprice'];
$PP = $row['dpplink'];
echo "<tr>
<td width=\"12%\">
<div align=\"right\"><b><font face=\"Arial, Helvetica, sans-serif\" size=2>Product
Category: </font></b></div>
</td>
<td colspan=2 width=\"88%\"><select name=\"dcat\"><option value=\"$CAT\">Current Category: $CAT</option>";
$sqlCAT = "SELECT * FROM dcat";
if($resultCAT = mysqli_query($dbcnx, $sqlCAT)){
if(mysqli_num_rows($resultCAT) > 0){
while($rowCAT = mysqli_fetch_array($resultCAT)){
echo "<option value=\"".$rowCAT['dcategory']."\">".$rowCAT['dcategory']."</option>";
}
// Free result set
mysqli_free_result($resultCAT);
} else{
echo "No records matching your query were found.";
}
} else{
echo "ERROR: Could not able to execute $sqlCAT. " . mysqli_error($dbcnx);
}
echo " </select>";
mysqli_close($dbcnx);
?>