I try to insert data in my custom table
$month = date('m');
$year = date('y');
$number = cal_days_in_month(CAL_GREGORIAN, $month, $year);
for ($i = 0; $i < $number; $i++) {
$test = new Test();
$test->cuid = $user->id;
$test->name = $user->name;
$test->month = date('m');
$test->created_at = '2018-04-'+$i;
$test->save();
}
i try to insert number record in a month
let's say April have 30 days i try to insert it working fine but in created_at field i need insert 2018-04-01 to 2018-04-30 but this is insert only current date so that i try above but not working
you need to set timestamps = false;
$test->timestamps = false
Related
I really need help to display a month list view in which deposit received month should be green in color and no-deposit month should be in red color.
I have stuck in comparing the array values. and I am using codeigniter.
I have a table with start-date and end-date by using this I have created an array to display all months in between these dates. Please find the code which I have used to do it below:
$datefrom = strtotime($showrangecalendar['chitdate_start']);
$dateto = strtotime($showrangecalendar['chitdate_end']);
$start_date = date('Y-m-d', $datefrom);
$end_date = date('Y-m-d', $dateto);
$day = 2.628e+6; // Day in Months
$format = 'Y-F'; // Output format (see PHP date funciton)
$sTime = strtotime($start_date); // Start as time
$eTime = strtotime($end_date); // End as time
$numDays = round(($eTime - $sTime) / $day) + 1;
$days = array();
for ($d = 0; $d < $numDays; $d++) {
$days[] = date($format, ($sTime + ($d * $day)));
}
This code got me the Days list and I have displayed this using foreach statement to a table.
Now I have another table (accounts) with columns such as ID, Book_number, Deposit_Amount and Deposit_Month. Here the problem starts I have fetched data from "accounts" and loaded to my view using the below code from controller
$data['show_account']= $this->Accounts_model->get_all_accounts($sess_data);
My Model (Accounts_Model) is as shown below:
public function get_all_accounts($id)
{
$this->db->select("*");
$this->db->order_by('book_id','desc');
$this->db->from("accounts");
$this->db->where('bh_id',$id);
$query = $this->db->get();
return $query->result();
}
If I run the belowcode:
foreach($show_account as $values){
echo $values->deposit_month;
}
Its getting me the array result of all deposit month. Suppose I have data as 2018-Sep and 2018-Oct, These 2 months column should turn green in the above mentioned $days array.
Hope I have explained my requirement clearly. Please help me with this as I am already spent long hours in this.
Thanks in Advance.
Updated:
Now could you please check my model as follows:
public function get_dep_month($bh_id)
{
$this->db->select('deposit_month');
$this->db->from('accounts');
$this->db->where('bh_id',$_SESSION['bh_id']);
$this->db->order_by('deposit_month','asc');
$query = $this->db->get();
return $query->result_array();
}
And My Controller is as follows:
$sess_data = $this->session->userdata('bh_id');
$data['depM_array'] = $this->Accounts_model->get_dep_month($sess_data);
Now please check my View as follows:
<?php
// option 2
foreach($days as $day) { // using your already exist $day for-loop for display
if (!in_array($day, $depM_array)){
$calhilight = "calgreen";
}
else{
$calhilight = "calred";
}
?>
<li class="<?php echo $calhilight; ?>"><?= $day ?></li>
<?php
}
?>
But as my doposit_month column having only 2 values ie: 2018-Sep and 2018-Oct, Instead of getting green color for those 2 values, I am getting Green for who li element. Not getting where I have done wrong.
This is the Current page view which I am getting, Actually I am expecting a calendar view with 2 green fields for 2018-Sep and 2018-Oct and all other fields in Red
Performed Var Dumb in arrays:
Pls check this screenshot
FYI:
Below is the code from where I am getting $days array.
<?php
$datefrom = strtotime($showrangecalendar['chitdate_start']);
$dateto = strtotime($showrangecalendar['chitdate_end']);
$start_date = date('Y-m-d', $datefrom);
$end_date = date('Y-m-d', $dateto);
$day = 2.628e+6; // Day in Months
$format = 'Y-F'; // Output format (see PHP date funciton)
$sTime = strtotime($start_date); // Start as time
$eTime = strtotime($end_date); // End as time
$numDays = round(($eTime - $sTime) / $day) + 1;
$days = array();
for ($d = 0; $d < $numDays; $d++) {
$days[] = date($format, ($sTime + ($d * $day)));
}
?>
Here $start_date & $end_date is fetching from another table named chitdate.
Thanks Again.
You can use array-diff or simple for-loop.
Consider the following simple example:
$days = array("2018-September", "2018-October", "2018-November", "2018-December");
$deposit_month = array("2018-September", "2018-October");
// option 1:
$diff = array_diff($days, $deposit_month);
// now $diff has: "2018-November" and "2018-December"
// option 2
foreach($days as $day) { // using your already exist $day for-loop for display
if (!in_array($day, $deposit_month))
// color in red as not found in "deposit_month"
else
// color in green
}
Nicer writing for that if can be as:
$color = in_array($day, $deposit_month) ? "Green" : "Red";
this is my insert section the $total_minutes and $total_hour cant be inserted in the table
$year = $_POST['year'];
$month = $_POST['month'];
$day = $_POST['day'];
$hour = $_POST['hour'];
$min = $_POST['min'];
$sec = $_POST['sec'];
$year1 = $_POST['year1'];
$month1 = $_POST['month1'];
$day1 = $_POST['day1'];
$hour1 = $_POST['hour1'];
$min1 = $_POST['min1'];
$sec1 = $_POST['sec1'];
$time_in = $year.'-'.$month.'-'.$day.' '.$hour.'-'.$min.'-'.$sec;
$time_out = $year1.'-'.$month1.'-'.$day1.' '.$hour1.'-'.$min1.'-'.$sec1;
$total_minutes = $total_min;
$total_hour = $total_hr;
$sql = "INSERT INTO time (year, month, day, hour, min, sec, year1, month1, day1, hour1, min1, sec1, time_in, time_out, total_minutes, total_hour)
VALUES
('$year','$month','$day','$hour','$min','$sec','$year1','$month1','$day1','$hour1','$min1','$sec1','$time_in','$time_out', '$total_minutes', '$total_hour')";
how can i add this in my table?
minutes
$datetime1 = strtotime($row['time_in']); //year-month-day hr:min:sec timein
$datetime2 = strtotime($row['time_out']); //year-month-day hr:min:sec timeout
$interval = abs($datetime2 - $datetime1);
$total_min = round($interval / 60);
$total_minutes = $total_min;
hour
function convertToHoursMins($total_minutes, $format = '%02d:%02d') {
if ($total_minutes < 1) {
return;
}
$hours = floor($total_minutes / 60);
$wmin = ($total_minutes % 60);
return sprintf($format, $hours, $wmin);
}
$total_hr = convertToHoursMins($total_minutes, '%02d hours %02d minutes');
$total_hour = $total_hr;
im new and i wanted a simple answer
Use MySQL TIMEDIFF() function to get the answer. Instead of PHP, MySQL Function gives the result in very easiest manner.
$datetime1 = strtotime($row['time_in']); //year-month-day hr:min:sec timein
$datetime2 = strtotime($row['time_out']); //year-month-day hr:min:sec timeout
$timeInterval = mysql_query("SELECT TIMEDIFF($datetime2, $datetime1)");
$timeArray = explode(":", $timeInterval);
Hope this may help you :)
You have to convert your datetime1 and datetime2 in this format first :
datetime1 = 2012-01-01 12:00:00;
datetime2 = 2012-01-02 13:00:00;
Then in my sql insert query directly insert value from following functions :
TIMESTAMPDIFF(HOUR, datetime2, datetime1) // For Hours Calculation
TIMESTAMPDIFF(MINUTE,datetime2, datetime1) // For Minutes Calculation
Hope this may help you :)
I am trying to show results of each month.
Im having this for loop:
foreach ($overview as $day) {
$year = date("Y") - 1;
if ($day->user == $info->id) {
$startDate = new DateTime($day->Calendar_startdate);
$endDate = new DateTime($day->Calendar_enddate);
$s = $startDate->format('Y-m-d');
$e = $endDate->format('Y-m-d');
if ($s > $year) {
$workdays = number_of_working_days($s, $e);
$daysleft = $daysleft + $workdays;
} else {
}
}
}
This for loop is also in an if statement which echos the months.
Now I need to let it work for the months January, February etc...
I am able to not show results if in the previous year which works well.
If you want to compare $s with $year just change $year to :
$time = new DateTime('now');
/*** you can use `now` for today
/* or you can change to a fixed date exmp: 2016-01-01
*/
$year = $time->modify('-1 year')->format('Y-m-d');
Than you can compare $s > $year
I fixed by checking each month if it contained for example -01-
DB::table('Calendar')->where('Calendar_startdate', 'like','%' . $monthnumber . '%')->where('user', $info->id)->where('Calendar_type',2)->get();
Hey guys take a look over this code. This code is showing current month stats,but if i want to check last month stats instead of this month then what changes i need to do in this small code ?
$date_time_array = getdate(time());
$last_month = $date_time_array["month"];
$this_year = $date_time_array["year"];
$last_mon = $date_time_array["mon"];
$date = mktime(0,0,0,$last_mon,1,$this_year); //The get's the first of March 2009
$links = array();
$newstamp = time() - 3600;
$cpc = 0;
$cpm = 0;
$click = 0;
for($n=1;$n <= date('t',$date);$n++){
$thisdate = $this_year.'-'.$last_mon.'-'.str_pad($n, 2, '0', STR_PAD_LEFT );
$sql = "select * from pub_st_daily where user='$user' && STR_TO_DATE(pdate,'%Y-%m-%d') = '$thisdate' ";
You can do this :
$date = new DateTime("07/30/2015"); //Will give you July 30th
$date_time_array=getdate($date->format("U"));
...
Demo
i'm trying to add X month to a date taken from my database
$sql_batch = "SELECT * FROM mgm_subscription WHERE status = '1'"
$query_batch = mysql_query($sql_batch);
$row_batch = mysql_fetch_array($query_batch);
$addMonth = 3;
$startDate = $row_batch['start_month'];
$endDate = strtotime('+'.$addMonth.' month', $startMonth); // add number of days from form
$endDate = date('m/d/y H:i:s', $endDate );
$sql_date = "INSERT INTO user_subscription (user_id, start_month, end_month, sub_status) VALUES ('".$usercode2."','".$startDate."','".$endDate."', '')";
$query_date = mysql_query($sql_date);
NULL was inserted into the end_month.
start_month and end_month is DATE type in the mysql
how do i fix this? tq.
If I understood your question, your $endDate should be
$endDate = date('Y-m-d', strtotime($startDate.' +'.$addMonth.' months'));
So this will equate to:
$endDate = $startDate + 3 months /* in Y-m-d format */
EDIT: Just saw that your column datatype is Date. This would mean that you can't store timestamp in your date. It has to be Y-m-d format only as that is the valid mysql format supported.
You insert $endMonth a value(number of days from form) then you try to replace it ($endMonth) and you call back your replaced variable..
$endMonth = strtotime('+'.$addMonth.' month', $startMonth); // add number of days from form
$endMonth = date('m/d/y H:i:s', $endMonth);
It will return null value.. My suggestion, try to put other variable to prevent duplicate value or missing data
You only mention adding X months. Maybe I misunderstood your question, but if all you care about is the month, I would do the following:
if ($startMonth === 'January') {
$monthNumber = 1;
} else if ($startMonth === 'February') {
$monthNumber = 2;
} //Up to November then finish with {
else {
$monthNumber = 12;//December
}
$newMonthNumber = $monthNumber + $addMonth;
if ($newMonthNumber % 12 == 1) {
$endMonth = 'January';
} else if ($newMonthNumber % 12 == 1) {
$endMonth = 'February';
} //Up to November then finish with {
else {
$endMonth = 'December';
}
$sql_date = "INSERT INTO user_subscription (user_id, start_month, end_month, sub_status) VALUES ('".$usercode2."','".$startMonth."','".$endMonth."', '')";
$query_date = mysql_query($sql_date);