wrong resault in php - php

Question

I tried to catch two variable ($phone,$key) and if $key exists in the random table from the first DB then check if &phone exists in users table in second DB return id else if doesn't exist make a row and then echo id. here is my code.where is my problem?
$Key = $_GET['key'];
$phone = $_GET['phone'];
$dublicate = "SELECT id,phone FROM users WHERE phone = $phone;";
$valid = "SELECT id,phone,random FROM random WHERE random = $Key;";
$verifyresult=mysqli_query($con,$valid);
$dublicateresult=mysqli_query($con2,$dublicate);
if($verifyresult == true )
{
if($dublicateresult == true){
$response=array();
while($row=mysqli_fetch_array($dublicateresult)){
array_push($response,array("id"=>$row[0],"phone"=>$row[1]));
echo $row[0];
}
}else{
$response=array();
while($row=mysqli_fetch_array($result)){
array_push($response,array("id"=>$row[0],"phone"=>$row[1],"random"=>$row[2]));
$result2 = mysqli_query($con2,"INSERT INTO users (phone)
VALUES ('$row[1]')");
$uniq = "SELECT id FROM users WHERE phone = $row[1];";
$result3=mysqli_query($con2,$uniq);
if($result3==true){
$response2=array();
while($row=mysqli_fetch_array($result3)){
array_push($response2,array("id"=>$row[0]));
echo $row[0];
}
}
}
}
}else echo "null";