I'm trying to insert Blob images retrieved from MySQL into an array using a while loop.
The database statement selected all images then i need to pass them all into an array.
So in theory, i should have an array of base64 encoded image corresponding to each record from my database.
Any help will be appreciated.
$sql = "SELECT img from artistlocation";
try{
$db = new db();
$db = $db->connect();
$stmt = $db->query($sql);
$data = array();
while($result = $stmt->fetch(PDO::FETCH_OBJ))
{
//$result = base64_encode(); ---- Something here im guessing
$data[] = $result;
}
print_r ($data);
}
catch(PDOException $e){
echo '{"error": {"text": '.$e->getMessage().'}';
}
I see big issue i your code..
You use the same variable, $result, for fetching mysql row result and image content.
Second, you miss to encoding to base64 the file content.
Here is my solution:
$sql = "SELECT img from artistlocation";
try{
$db = new db();
$db = $db->connect();
$stmt = $db->query($sql);
$data = array();
while($result = $stmt->fetch(PDO::FETCH_OBJ))
{
$data[] = base64_encode($result['img']);
}
print_r ($data);
}
catch(PDOException $e){
echo '{"error": {"text": '.$e->getMessage().'}';
}
Hope it will helps you.
So the answer to this question came from AbraCadaver.
$sql = "SELECT img from artistlocation";
try{
$db = new db();
$db = $db->connect();
$stmt = $db->query($sql);
$data = array();
while($result = $stmt->fetch(PDO::FETCH_OBJ))
{
$data[] = base64_encode($result->img);
}
Thanks guys for the help!
Related
I am writting a php file to get all users in mysql database printed. My problem is that after prepare($sql) and $statement->execute, statement is always null. Here is my code:
public function selectAllUser(){
$response = array();
$sql = "SELECT * FROM Tata.users";
$statement = $this->conn->prepare($sql);
if(!$statement){
throw new Exception($statement->error);
}
//echo json_encode($statement);
$statement->execute();
try {
throw new Exception($statement->error);
} catch (Exception $e){}
$result = $statement->get_result();
//echo json_encode($result);
while ($row = $result->fetch_assoc()){
//echo json_encode($row);
$response[] = $row;
}
return $response;
}
This is the result I get if I do: echo $statement;
{"affected_rows":null,"insert_id":null,"num_rows":null,"param_count":null,"field_count":null,"errno":null,"error":null,"error_list":null,"sqlstate":null,"id":null}
This is the code where I am using this function:
$file = parse_ini_file("../../../Tata.ini");
$dbhost = trim($file["dbhost"]);
$dbuser = trim($file["dbuser"]);
$dbpass = trim($file["dbpassword"]);
$dbname = trim($file["dbname"]);
require ("secure/access.php");
$access = new access($dbhost,$dbuser,$dbpass,$dbname);
$access->connect();
$users = $access->selectAllUser();
$access->disconnect();
echo json_encode($users);
enter image description hereDatabase sample:
$result = mysql_query("SELECT uid FROM `Aadhar` WHERE FSC LIKE CONTACT($FSC)");
$data = array();
while ($row = mysql_fetch_array($result)) {
$id = array_shift($row); // Shifts first element
$data[$id] = $row;
print($data[]);
I want to store the uid numbers in an array and pring by currusponding FSC number.
by giving FSC number , logic has to do this.
I tried.
mysql_* functions are deprecated. Please use mysqli_* or PDO. Your code is vulnerable to SQL Injection if you plan to include user input directly in to the SQL query.
This is how you do it in PDO:
try {
$conn = new PDO("mysql:host=localhost; dbname=dbname", "root", "password");
}
catch(PDOException $e) {
echo $e->getMessage();
}
$query = $conn->query("SELECT * FROM Aadhar WHERE FSC LIKE :fsc");
$query->bindParam(":fsc", $fsc = '%'.$FSC.'%');
if($query->execute()) {
$data = $query->fetchAll(PDO::FETCH_ASSOC); //get the results in the form of an associative array
} else {
die("Query failed");
}
var_dump($data);
I'm trying to write a PHP-script that will fetch multiple rows from MySQL and return them as a JSONObject, the code works if I try to only fetch 1 row but if I try to get more than one at a time the return string is empty.
$i = mysql_query("select * from database where id = '$v1'", $con);
$temp = 2;
while($row = mysql_fetch_assoc($i)) {
$r[$temp] = $row;
//$temp = $temp +1;
}
If I write the code like this it returns what I expect it to, but if I remove the // from the second row in the while loop it will return nothing. Can anyone explain why this is and what I should do to solve it?
You are using an obsolete mysql_* library.
You are SQL injection prone.
Your code is silly and makes no sense.
If you really wan to stick to it, why simply not do:
while($row = mysql_fetch_assoc($i)) {
$r[] = $row;
}
echo json_encode($r);
And finally, an example using PDO:
$database = 'your_database';
$user = 'your_db_user';
$pass = 'your_db_pass';
$pdo = new \PDO('mysql:host=localhost;dbname='. $database, $user, $pass);
$pdo->setAttribute(\PDO::ATTR_ERRMODE, \PDO::ERRMODE_EXCEPTION);
try
{
$stmt = $pdo->prepare("SELECT * FROM your_table WHERE id = :id");
$stmt->bindValue(':id', $id);
$stmt->execute();
$results = $stmt->fetchAll(\PDO::FETCH_ASSOC);
}
catch(\PDOException $e)
{
$results = ['error' => $e->getMessage(), 'file' => $e->getFile(), 'line' => $e->getLine());
}
echo json_encode($results);
You don't need the $temp variable. You can add an element to an array with:
$r[] = $row;
I have a Microsoft Access Database, and I am trying to query the table using PHP, and output valid JSON. I have an equivalent code for a MSSQL database, am I am trying to make my code do the same thing, but just for the Access database.
Here is the MSSQL code
$myServer = "server";
$myDB = "db";
$conn = sqlsrv_connect ($myServer, array('Database'=>$myDB));
$sql = "SELECT *
FROM db.dbo.table";
$data = sqlsrv_query ($conn, $sql);
$result = array();
do {
while ($row = sqlsrv_fetch_array ($data, SQLSRV_FETCH_ASSOC)) {
$result[] = $row;
}
} while (sqlsrv_next_result($data));
$json = json_encode ($result);
sqlsrv_free_stmt ($data);
sqlsrv_close ($conn);
Here is what I tried for the MDB file
$dbName = "/filename.mdb";
if (!file_exists($dbName)) {
die("Could not find database file.");
}
$db = odbc_connect("Driver={Microsoft Access Driver (*.mdb)};Dbq=$dbName", $user, $password);
$sql = "SELECT *
FROM cemetery";
$data = $db->query($sql); // I'm getting an error here
$result = array();
// Not sure what do do for this part...
do {
while ($row = fetch($data, SQLSRV_FETCH_ASSOC)) {
$result[] = $row;
}
} while (sqlsrv_next_result($data));
$json = json_encode ($result);
I kind of followed this to try to connect to the database: http://phpmaster.com/using-an-access-database-with-php/
Currently this is giving me a 500 Internal Server Error. I'm expecting a string such as this to be saved in the variable $json
[
{
"col1":"col value",
"col2":"col value",
"col3":"col value",
},
{
"col1":"col value",
"col2":"col value",
"col3":"col value",
},
{
etc...
}
]
Can someone help me port the MSSQL code I have above so I can use it with an MDB database? Thanks for the help!
EDIT: I'm commenting out the lines one by one, and it throws me the 500 error at the line $data = $db->query($sql);. I looked in the error log, and I'm getting the error Call to a member function query() on a non-object. I already have the line extension=php_pdo_odbc.dll uncommented in my php.ini file. Anyone know what the problem could be?
You only need 1 loop,
fetchAll is your iterable friend:
while ($row = $data->fetchAll(SQLSRV_FETCH_ASSOC)) {
$result[] = $row;
}
odbc_connect doesn't return an object, it returns a resource. see (http://php.net/manual/en/function.odbc-connect.php) so you would need to do something like this.
$db = odbc_connect("Driver={Microsoft Access Driver (*.mdb)};Dbq=$dbName", $user, $password);
$oexec = obdc_exec($db,$sql);
$result[] = odbc_fetch_array($oexec);
and then you can iterate over results..
see also:
http://www.php.net/manual/en/function.odbc-fetch-array.php
http://www.php.net/manual/en/function.odbc-exec.php
I finally figured it out.
<?php
// Location of database. For some reason I could only get it to work in
// the same location as the site. It's probably an easy fix though
$dbName = "dbName.mdb";
$tName = "table";
// Throws an error if the database cannot be found
if (!file_exists($dbName)) {
die("Could not find database file.");
}
// Connects to the database
// Assumes there is no username or password
$conn = odbc_connect("Driver={Microsoft Access Driver (*.mdb)};Dbq=$dbName", '', '');
// This is the query
// You have to have each column you select in the format tableName.[ColumnName]
$sql = "SELECT $tName.[ColumnOne], $tName.[ColumnTwo], etc...
FROM $dbName.$tName";
// Runs the query above in the table
$rs = odbc_exec($conn, $sql);
// This message is displayed if the query has an error in it
if (!$rs) {
exit("There is an error in the SQL!");
}
$data = array();
$i = 0;
// Grabs all the rows, saves it in $data
while( $row = odbc_fetch_array($rs) ) {
$data[$i] = $row;
$i++;
}
odbc_close($conn); // Closes the connection
$json = json_encode($data); // Generates the JSON, saves it in a variable
?>
I use this code to get results from an ODBC query into a JSON array:
$response = null;
$conn = null;
try {
$odbc_name = 'myODBC'; //<-ODBC connectyion name as is in the Windows "Data Sources (ODBC) administrator"
$sql_query = "SELECT * FROM table;";
$conn = odbc_connect($odbc_name, 'user', 'pass');
$result = odbc_exec($conn, $sql_query);
//this will show all results:
//echo odbc_result_all($result);
//this will fetch row by row and allows to change column name, format, etc:
while( $row = odbc_fetch_array($result) ) {
$json['cod_sistema'] = $row['cod_sistema'];
$json['sistema'] = $row['sistema'];
$json['cod_subsistema'] = $row['cod_subsistema'];
$json['sub_sistema'] = $row['sub_sistema'];
$json['cod_funcion'] = $row['cod_funcion'];
$json['funcion'] = $row['funcion'];
$json['func_desc_abrev'] = $row['desc_abreviada'];
$json['cod_tipo_funcion'] = $row['cod_tipo_funcion'];
$response[] = array('funcionalidad' => $json);
}
odbc_free_result($result); //<- Release used resources
} catch (Exception $e) {
$response = array('resultado' => 'err', 'detalle' => $e->getMessage());
echo 'ERROR: ', $e->getMessage(), "\n";
}
odbc_close($conn);
return $response;
And finnally encoding the response in JSON format:
echo json_encode($response);
i'm building an website using php and html, im used to receiving data from a database, aka Dynamic Website, i've build an CMS for my own use.
Im trying to "simplify" the receiving process using php and functions.
My Functions.php looks like this:
function get_db($row){
$dsn = "mysql:host=".$GLOBALS["db_host"].";dbname=".$GLOBALS["db_name"];
$dsn = $GLOBALS["dsn"];
try {
$pdo = new PDO($dsn, $GLOBALS["db_user"], $GLOBALS["db_pasw"]);
$stmt = $pdo->prepare("SELECT * FROM lp_sessions");
$stmt->execute();
$row = $stmt->fetchAll();
foreach ($row as $row) {
echo $row['session_id'] . ", ";
}
}
catch(PDOException $e) {
die("Could not connect to the database\n");
}
}
Where i will get the rows content like this: $row['row'];
I'm trying to call it like this:
the snippet below is from the index.php
echo get_db($row['session_id']); // Line 22
just to show whats in all the rows.
When i run that code snippet i get the error:
Notice: Undefined variable: row in C:\wamp\www\Wordpress ish\index.php
on line 22
I'm also using PDO just so you would know :)
Any help is much appreciated!
Regards
Stian
EDIT: Updated functions.php
function get_db(){
$dsn = "mysql:host=".$GLOBALS["db_host"].";dbname=".$GLOBALS["db_name"];
$dsn = $GLOBALS["dsn"];
try {
$pdo = new PDO($dsn, $GLOBALS["db_user"], $GLOBALS["db_pasw"]);
$stmt = $pdo->prepare("SELECT * FROM lp_sessions");
$stmt->execute();
$rows = $stmt->fetchAll();
foreach ($rows as $row) {
echo $row['session_id'] . ", ";
}
}
catch(PDOException $e) {
die("Could not connect to the database\n");
}
}
Instead of echoing the values from the DB, the function should return them as a string.
function get_db(){
$dsn = "mysql:host=".$GLOBALS["db_host"].";dbname=".$GLOBALS["db_name"];
$dsn = $GLOBALS["dsn"];
$result = '';
try {
$pdo = new PDO($dsn, $GLOBALS["db_user"], $GLOBALS["db_pasw"]);
$stmt = $pdo->prepare("SELECT * FROM lp_sessions");
$stmt->execute();
$rows = $stmt->fetchAll();
foreach ($rows as $row) {
$result .= $row['session_id'] . ", ";
}
}
catch(PDOException $e) {
die("Could not connect to the database\n");
}
return $result;
}
Then call it as:
echo get_db();
Another option would be for the function to return the session IDs as an array:
function get_db(){
$dsn = "mysql:host=".$GLOBALS["db_host"].";dbname=".$GLOBALS["db_name"];
$dsn = $GLOBALS["dsn"];
$result = array();
try {
$pdo = new PDO($dsn, $GLOBALS["db_user"], $GLOBALS["db_pasw"]);
$stmt = $pdo->prepare("SELECT * FROM lp_sessions");
$stmt->execute();
$rows = $stmt->fetchAll();
foreach ($rows as $row) {
$result[] = $row['session_id'];
}
}
catch(PDOException $e) {
die("Could not connect to the database\n");
}
return $result;
}
Then you would use it as:
$sessions = get_db(); // $sessions is an array
and the caller can then make use of the values in the array, perhaps using them as the key in some other calls instead of just printing them.
As antoox said, but a complete changeset; change row to rows in two places:
$rows = $stmt->fetchAll();
foreach ($rows as $row) {
echo $row['session_id'] . ", ";
}
Putting this at the start of the script after <?php line will output interesting warnings:
error_reporting(E_ALL|E_NOTICE);
To output only one row, suppose the database table has a field named id and you want to fetch row with id=1234:
$stmt = $pdo->prepare("SELECT * FROM lp_sessions WHERE id=?");
$stmt->bindValue(1, "1234", PDO::PARAM_STR);
I chose PDO::PARAM_STR because it will work with both strings and integers.