How to run a background process in symfony - php

I have a symfony commad that needes few minutes to be completed. And i want to run it by a http request. The problem is that the server kills the command process just after sending response, he has a timeout.
i tried to use symfony process asynchronously But still not working ( i get always the timeout problem).
I dont want use the kernel.terminate event, since it is not a best practice. Here is the code in my controller :
$commandProcess=new Process('php bin/console app:doSomeThing');
$commandProcess->setWorkingDirectory('./../');
$commandProcess->start();
$commandProcess->setTimeout(50000000);
Any response will be much appreciated.

I had to desibale the process output and add '&' after the command
Here the answer:
new Process('php bin/console app:dosomthing &');
$commandProcess=new Process('php bin/console app:dosomthing &');
$commandProcess->setWorkingDirectory('./../');
$commandProcess->disableOutput();
$commandProcess->setTimeout(1800);
$commandProcess->start();

I write here the solution that has finally worked for me
First create a service:
use Symfony\Component\Process\Process;
use Symfony\Component\HttpKernel\KernelInterface;
class ProcessService {
public function __construct(
private KernelInterface $appKernel
){ }
public function executeProcessAsync($processToExecute) {
$rootDir = $this->appKernel->getProjectDir();
$process = Process::fromShellCommandline($processToExecute . ' &');
$process->setWorkingDirectory($rootDir);
$process->disableOutput();
$process->setTimeout(0);
$process->start();
}
}
Then we use the service from a controller:
class MyController {
public function __construct(
private ProcessService $procesService
){
public function __invoke(Request $request)
{
// (other stuff ...)
$this->procesService->executeProcessAsync('php bin/console mycommands:command ');
// (other stuff...)
}
}

Related

Implement locking for all commands in my Symfony app

I followed this guide: https://symfony.com/doc/current/console/lockable_trait.html and implemented the command lock feature for my one of my commands to see how it works. It worked as described and then I was going to implement it for all of my commands. But the issue is that I have about 50 commands and:
I do not want spent time adding the necessary code to each command
I want to have the centralized management of commands locking. I mean, adding extra option to regular commands so that they will be used by my future management center. For now I will need a pretty simple option protected function isLocked() for a regular command which will help me to manage if a command should have lockable feature.
So, I went to the source of \Symfony\Component\Console\Command\LockableTrait and after some time created the following listener to the event console.command:
use Symfony\Component\Console\Event\ConsoleCommandEvent;
use Symfony\Component\Console\Exception\LogicException;
use Symfony\Component\Lock\Lock;
use Symfony\Component\Lock\LockFactory;
use Symfony\Component\Lock\LockInterface;
use Symfony\Component\Lock\Store\FlockStore;
use Symfony\Component\Lock\Store\SemaphoreStore;
class LockCommandsListener
{
/**
* #var array<string, Lock>
*/
private $commandLocks = [];
private static function init()
{
if (!class_exists(SemaphoreStore::class)) {
throw new LogicException('To enable the locking feature you must install the symfony/lock component.');
}
}
public function onConsoleCommand(ConsoleCommandEvent $event)
{
static::init();
$name = $event->getCommand()->getName();
$this->ensureLockNotPlaced($name);
$lock = $this->createLock($name);
$this->commandLocks[$name] = $lock;
if (!$lock->acquire()) {
$this->disableCommand($event, $name);
}
}
private function disableCommand(ConsoleCommandEvent $event, string $name)
{
unset($this->commandLocks[$name]);
$event->getOutput()->writeln('The command ' . $name . ' is already running');
$event->disableCommand();
$event->getCommand()->setCode()
}
private function createLock(string $name): LockInterface
{
if (SemaphoreStore::isSupported()) {
$store = new SemaphoreStore();
} else {
$store = new FlockStore();
}
return (new LockFactory($store))->createLock($name);
}
private function ensureLockNotPlaced(string $name)
{
if (isset($this->commandLocks[$name])) {
throw new LogicException('A lock is already in place.');
}
}
}
I made some tests and it kind of worked. But I am not sure this is the right way of doing things.
Another problem is that I can not find the proper exit code when I disabled a command. Should I just disable it? But it seems that exit code would be a great feature here. Specially when it comes to this listener testing (PHPUnit testing).
And I also have with testing itself. How can I run commands in parallel in my test class. For now I have this:
class LockCommandTest extends CommandTest
{
public function testOneCommandCanBeRun()
{
$commandTester = new ApplicationTester($this->application);
$commandTester->run([
'command' => 'app:dummy-command'
]);
$output = $commandTester->getDisplay();
dd($output);
}
}
It will allow only to run my commands one by one. But I would like to run them both so after running the first one, the second will fail (with some exit code).
As for me the best way to make background task is doing it via supervisor, create config file, like:
[program:your_service]
command=/usr/local/bin/php /srv/www/bin/console <your:app:command>
priority=1
numprocs=1
# Each 5 min.
startsecs=300
autostart=true
autorestart=true
process_name=%(program_name)s_%(process_num)02d
user=root
this is the best way to be sure that your command will be ran only in one process

Asynchronously calling a Command in Symfony2

I want to asynchronously call a Command from within a Controller in Symfony2.
So far i found the following solution:
$cmd = $this->get('kernel')->getRootDir().'/console '.(new MLCJobWorkerCommand)->getName().' '.$job->getId().' 2>&1 > /dev/null';
$process = new Process($cmd);
$process->start();
Is there a better way to accomplish this?
Edit:
I need the Process to run in background and the Controller to return right after it started the former. I tried:
$cmd = $this->get('kernel')->getRootDir().'/console '
.(new MLCJobWorkerCommand)->getName()
.' '.$job->getId().' 2>&1 > /dev/null & echo \$!';
$process = new Process($cmd);
$process->mustRun();
$params["processid"] = $process->getOutput();
but the Controller doesn't return a Response until the Process has finished.
I agree with Gerry that if you want to be "asynchronously" then you selected not the best way
I can recommend an alternative of RabbitMQ: JMSJobBundle
http://jmsyst.com/bundles/JMSJobQueueBundle/master/installation
Where you can create a queue of you console commands something like:
class HomeController ... {
// inject service here
private $cronJobHelper;
// inject EM here
private $em;
public function indexAction() {
$job = $this->cronJobHelper->createConsoleJob('myapp:my-command-name', $event->getId(), 10);
$this->em->persist($job);
$this->em->persist($job);
$this->em->flush();
}
}
use JMS\JobQueueBundle\Entity\Job;
class CronJobHelper{
public function createConsoleJob($consoleFunction, $params, $delayToRunInSeconds, $priority = Job::PRIORITY_DEFAULT, $queue = Job::DEFAULT_QUEUE){
if(!is_array($params)){
$params = [$params];
}
$job = new Job($consoleFunction, $params, 1, $queue, $priority);
$date = $job->getExecuteAfter();
$date = new \DateTime('now');
$date->setTimezone(new \DateTimeZone('UTC')); //just in case
$date->add(new \DateInterval('PT'.$delayToRunInSeconds.'S'));
$job->setExecuteAfter($date);
return $job;
}
}
Checkout AsyncServiceCallBundle, it allows you to call your service's methods completely asynchronously using this approach. The process responsible for current request handling doesn't wait for its child to be finished.
Everything you need is to call it like this:
$pid = $this->get('krlove.async')->call('service_id', 'method', [$argument1, $argument2]);

Symfony command line program output from service

I have a Symfony service that processes a file and does stuff with its information. I call this service from a controller and separately from a command class. The actual service takes a long time to run, and I'd like to show some status output on the command line while it processes the file. What is the best way to accomplish this without adding echo commands in my service?
Edit
This seems to be the solution: http://symfony.com/blog/new-in-symfony-2-4-show-logs-in-console
There are commands like
$output->write('Blah blah blah');
$output->writeLn('Blah blah blah'); // Above with a line break
You can also add colours and progress bars and possibly other stuff that I've never got round to using.
http://symfony.com/doc/current/components/console/introduction.html#coloring-the-output
UPDATE
You could use the EventDisptcher service to update your command on events in your service.
For example...
You command
protected function execute(InputInterface $input, OutputInterface $output)
{
//....
$dispatcher = $this->getContainer->get('event_dispatcher');
$dispatcher->addListener(
'an.event.that.you.have.set.up',
function (GenericEvent $event) use ($output) {
$output->writeLn('<info>This event has happened</info');
}
});
//....
}
Your service
protected $dispatcher;
//....
public function __construct(EventDispatcherInterface $dispatcher, ...)
{
$this->dispatcher = $dispatcher;
//...
}
public function someFunction()
{
//...
$variable = 'something you are using');
$dispatcher->dispatch(
'an.event.that.you.have.set.up',
new GenericEvent($variable)
);
//...
}
Obviously there would be a lot more to both you command your service but this give the basic of how to tie it all together.
An actual use example can be seen here..
Command - https://github.com/Richtermeister/Sylius/blob/subscription-bundle/src/Sylius/Bundle/SubscriptionBundle/Command/ProcessSubscriptionsCommand.php
Service - https://github.com/Richtermeister/Sylius/blob/subscription-bundle/src/Sylius/Bundle/SubscriptionBundle/Processor/SubscriptionProcessor.php
This seems to be the solution: http://symfony.com/blog/new-in-symfony-2-4-show-logs-in-console

How to run custom Symfony2 command in background

Symfony2 enables developers to create their own command-line commands. They can be executed from command line, but also from the controller. According to official Symfony2 documentation, it can be done like that:
protected function execute(InputInterface $input, OutputInterface $output)
{
$command = $this->getApplication()->find('demo:greet');
$arguments = array(
...
);
$input = new ArrayInput($arguments);
$returnCode = $command->run($input, $output);
}
But in this situation we wait for the command to finish it's execution and return the return code.
How can I, from controller, execute command forking it to background without waiting for it to finish execution?
In other words what would be equivalent of
$ nohup php app/console demo:greet &
From the documentation is better use start() instead run() if you want to create a background process. The process_max_time could kill your process if you create it with run()
"Instead of using run() to execute a process, you can start() it: run() is blocking and waits for the process to finish, start() creates a background process."
According to the documentation I don't think there is such an option: http://api.symfony.com/2.1/Symfony/Component/Console/Application.html
But regarding what you are trying to achieve, I think you should use the process component instead:
use Symfony\Component\Process\Process;
$process = new Process('ls -lsa');
$process->run(function ($type, $buffer) {
if ('err' === $type) {
echo 'ERR > '.$buffer;
} else {
echo 'OUT > '.$buffer;
}
});
And as mentioned in the documentation "if you want to be able to get some feedback in real-time, just pass an anonymous function to the run() method".
http://symfony.com/doc/master/components/process.html

Running console command from a Symfony 2 test case

Is there a way to run a console command from a Symfony 2 test case? I want to run the doctrine commands for creating and dropping schemas.
This documentation chapter explains how to run commands from different places. Mind, that using exec() for your needs is quite dirty solution...
The right way of executing console command in Symfony2 is as below:
Option one
use Symfony\Bundle\FrameworkBundle\Console\Application as App;
use Symfony\Component\Console\Tester\CommandTester;
class YourTest extends WebTestCase
{
public function setUp()
{
$kernel = $this->createKernel();
$kernel->boot();
$application = new App($kernel);
$application->add(new YourCommand());
$command = $application->find('your:command:name');
$commandTester = new CommandTester($command);
$commandTester->execute(array('command' => $command->getName()));
}
}
Option two
use Symfony\Component\Console\Input\StringInput;
use Symfony\Bundle\FrameworkBundle\Console\Application;
class YourClass extends WebTestCase
{
protected static $application;
public function setUp()
{
self::runCommand('your:command:name');
// you can also specify an environment:
// self::runCommand('your:command:name --env=test');
}
protected static function runCommand($command)
{
$command = sprintf('%s --quiet', $command);
return self::getApplication()->run(new StringInput($command));
}
protected static function getApplication()
{
if (null === self::$application) {
$client = static::createClient();
self::$application = new Application($client->getKernel());
self::$application->setAutoExit(false);
}
return self::$application;
}
}
P.S. Guys, don't shame Symfony2 with calling exec()...
The docs tell you the suggested way to do it. The example code is pasted below:
protected function execute(InputInterface $input, OutputInterface $output)
{
$command = $this->getApplication()->find('demo:greet');
$arguments = array(
'command' => 'demo:greet',
'name' => 'Fabien',
'--yell' => true,
);
$input = new ArrayInput($arguments);
$returnCode = $command->run($input, $output);
// ...
}
Yes, if your directory structure looks like
/symfony
/app
/src
then you would run
phpunit -c app/phpunit.xml.dist
from your unit tests you can run php commands either by using
passthru("php app/console [...]") (http://php.net/manual/en/function.passthru.php)
exec("php app/console [...]") (http://www.php.net/manual/en/function.exec.php)
or by putting the command in back ticks
php app/consode [...]
If you are running the unit tests from a directory other than symofny, you'll have to adjust the relative path to the app directory for it to work.
To run it from the app:
// the document root should be the web folder
$root = $_SERVER['DOCUMENT_ROOT'];
passthru("php $root/../app/console [...]");
The documentation has been updated since my last answer to reflect the proper Symfony 2 way of calling an existing command:
http://symfony.com/doc/current/components/console/introduction.html#calling-an-existing-command

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