I have a PHP file which is displaying some posted data:
$data = file_get_contents('php://input');
echo json_encode($data);
The above returns:
{"name":"mark","item":"car"}
Now I want to echo just the name so I tried:
echo $data[0].name;
But that's giving me Error: [Object].[Object]
How can I fix this?
You need to decode your JSON input first:
// $data is an input string
$data = file_get_contents('php://input');
// convert input string to PHP array
$data = json_decode(data, true);
// echo just the name
echo $data['name'];
// dump the whole parsed input
var_dump($data);
Related
Can anyone please shows me how to get the input of PHP to JSON file (.json) and read data from JSON file and display in PHP (Echo).
for example:
$myObj->name = "John";
$myObj->age= 20;
to result.json
{"name":"John","Age":20}
and retrieve from result.json and display data in PHP as
name=John
Age=20
To convert the object to json use this:
$json = json_encode($myObj);
See the json_encode docs.
To return it back to the format you want try this...
$obj = json_decode($json);
$name = $obj->name; // John
$age = $obj->age; // 20
See the json_decode docs.
To iterate over keys and values do something like this:
foreach($obj as $key=>$value)
{
echo $key . " = " . $value . "\n";
}
json_encode() is used for encoding PHP data into a JSON format and json_decode() is used to decode JSON into a PHP data
json_encode documentation:
http://php.net/manual/en/function.json-encode.php
json_decode documentation
http://php.net/manual/en/function.json-decode.php
if you are having an php array you can convert it into json.
$json_string = json_encode($array);
and write this into a json file.
$fp = fopen('results.json', 'w');
fwrite($fp, json_string);
fclose($fp);
now convert your json string which is in results.json to array.
$str = file_get_contents('./results.json');
$array = json_decode($str, true); // decode the JSON into an associative array
I need to decode the below json from a mobile app
Array
(
[{"unm":"admin","pw”:”password”}] =>
)
and my php code is
$obj1 = print_r($_REQUEST, true); //get $_request variable data(responce of login) data as it is
foreach($obj1 as $key => $value)
{
$obj2 = $key; //get first key
}
$obj3 = json_decode($obj2); //decode json data to obj3
$mob_user_name = $obj2['unm']; //getting json username field value
$mob_user_password = $obj2['pw']; //getting json password field value
Hope this will fix your issue,
Note: content is nothing but which you have received from iOS app
content = Array (
[{"unm":"admin","pw”:”password”}] => )
parse that in php
$json = json_decode($content, true);
print json[0]['unm']; /* prints the username */
print json[0]['pw']; /* prints the password */
{"unm":"admin","pw”:”password”} is an object, and json_decode() will by default build it as so.
$obj = json_decode('{"unm":"admin","pw”:”password”}');
echo $obj->unm;
echo $obj->pw;
If for some reason you want it to be converted to an associative array, set the second parameter of json_decode() to true as specified in the manual.
$arr = json_decode('{"unm":"admin","pw”:”password”}', true);
echo $arr['unm'];
echo $arr['pw'];
I am trying to access data from json in PHP but it seems not working.
code:
$raw =file_get_contents("http://api.mydomain.com/data.json");
$data = json_decode($raw->list);
echo $data;
I'm getting error that list is not an object.
Here is my json
{ "list" : [ { "data1":" my data"}, {"data2": "my data 2"}]};
What did u do wrong? Also how can i access data1 and others?
You don't need the $raw->list bit and you are getting an object back from json_decode so use print_r and not echo
$raw = file_get_contents("http://api.mydomain.com/data.json");
$data = json_decode($raw);
print_r($data);
I'm using a token:
$url = "https://api.pipedrive.com/v1/deals?api_token=3bd884bb0078f836a56f1464097fb71eac9d50ce";
and here's the json text(not everything);
{
"success":true,
"data":[{
"id":1,
"creator_user_id":{
"id":1682756,
"name":"Kamilah",
"email":"kamilah#fractal.ae",
"has_pic":false,
"pic_hash":null,
"active_flag":true,
"value":1682756},
"title":"FFS Organization deal"
}]
}
I wanted to display "title" and I always get an error
Notice: Undefined index: creator_user_id in
C:\xampp\htdocs\pipedrive\getjson.php on line 8
Here's my code so far:
$url = "https://api.pipedrive.com/v1/deals?api_token=3bd884bb0078f836a56f1464097fb71eac9d50ce";
$response = file_get_contents($url);
$object = json_decode($response, true);
echo $object['data']['creator_user_id']['title'];
I'm new to json so I'm just practicing and trying to figure out how to echo a specific value in php. Would be appreciated if you can explain exactly how it works when you echo from json to php.
Thank you! :)
First of all you need to debug the array after using json_decode().
<?php
$url = "https://api.pipedrive.com/v1/deals?api_token=3bd884bb0078f836a56f1464097fb71eac9d50ce";
$response = file_get_contents($url);
$object = json_decode($response, true);
echo "<pre>";
print_r($object); // this will print all data into array format.
?>
As per this array, you do not have title index inside the creator_user_id array. title is a separate index.
Also note that, $object['data'] containing two indexes not one. you can get title as:
<?php
foreach ($object['data'] as $key => $value) {
//print_r($value); // this will print the values inside the data array.
echo $value['title']."<br/>"; // this will print all title inside your array.
}
?>
Result:
FFS Organization deal
Google deal
Hi Guys I have a JSON data I need to convert this data Treeview a json data url: http://torrent2dl.ml/json.php
recovered state = http://torrent2dl.ml/json.php?tree
I tried to do http://torrent2dl.ml/hedef.php
how to convert this data a php function or code ?
json_decode($jsonObject, true);
Use json_decode() :
<?php
$url = 'http://torrent2dl.ml/json.php';
$JSON = file_get_contents($url);
// echo the JSON (you can echo this to JavaScript to use it there)
echo $JSON;
// You can decode it to process it in PHP
$data = json_decode($JSON);
var_dump($data);
?>
Source : https://stackoverflow.com/a/8344667/4652564