PHP Variable from another file without include or session - php

Question

I've tried using $_SESSION and include, none which have worked. What I'm doing is uploading an image to my server. Using Ajax to run a file called upload.php which has the upload script in it. When the file gets uploaded I want to pass the filename to my main.php page to use as a php variable. Include would just throw errors of undefined variables and session just wouldn't work.
Ajax
$(document).ready(function(){
$(document).on('change', '#file', function(){
var name = document.getElementById("file").files[0].name;
var form_data = new FormData();
var ext = name.split('.').pop().toLowerCase();
var oFReader = new FileReader();
oFReader.readAsDataURL(document.getElementById("file").files[0]);
var f = document.getElementById("file").files[0];
var fsize = f.size||f.fileSize;
if(fsize < 4000000)
{
form_data.append("file", document.getElementById('file').files[0]);
$.ajax({
url:"upload.php",
method:"POST",
data: form_data,
contentType: false,
cache: false,
processData: false,
success:function(data)
{
$('#image_upload_info').html(data);
}
});
}
});
Part of the upload script, $imagenameupload is the variable I want to pass back to my main.php page
if (move_uploaded_file($_FILES["file"]["tmp_name"], $target_file)) {
echo '<div class="container">';
echo '<div class="row">';
echo '<div class="col-md-8">';
echo '<div class="alert alert-success">';
echo "Pilt: ". basename( $_FILES["file"]["name"]). " on lisatud!";
move_uploaded_file($_FILES["file"]["tmp_name"], $target_file);
echo '</div>';
echo '</div>';
echo '</div>';
echo '</div>';
$imageNameUpload = basename( $_FILES["file"]["name"]);
}
EDIT
I explained it a little rought before. I want to be able to insert said variable into a database with other data. Heres a little more code.
SQL INSERT
if(isset($_POST['submit'])){
date_default_timezone_set('Europe/Tallinn');
$typeSelector = $_POST['typeSelector'];
if (isset($_POST['regionSelector']) ? $_POST['regionSelector'] : null) {
$checkBox = implode(',', $_POST['regionSelector']);
}
if(isset($_SESSION['imageNameUpload'])) {
$uploadedPic = $_SESSION['imageNameUpload'];
}
$now = new DateTime();
$timestring = $now->format('d.m.Y H:i');
$_POST = array_map('stripslashes', $_POST);
//$_POST = json_decode(stripslashes(json_encode($_POST)), true);
extract($_POST);
if($title ==''){
$error[] = 'Pealkiri on puudu.';
}
if($newstext ==''){
$error[] = 'Uudise sisu on puudu.';
}
if ($checkBox == '') {
$error[] = 'Regioon on puudu.';
}
if(!isset($error)){
try {
$stmt = $db->prepare('INSERT INTO news (title,shortdesc,newstext,tag,region,publish_date,imageName) VALUES (:title, :shortdesc, :newstext, :tag, :region, :publish_date, :imageName)') ;
$stmt->execute(array(
':title' => $title,
':shortdesc' => $shortdesc,
':newstext' => $newstext,
':tag' => $typeSelector,
':region' => $checkBox,
':imageName' => $imageName,
':publish_date' => $timestring
));
header('Location: index.php?news=addednews');
exit;
} catch(PDOException $e) {
echo $e->getMessage();
}
}
}

Answer 1

In upload.php
First you must start the seesion via session_start();
directly after the opening PHP 'tag' ()
Then you must save your variable to the session.
You can do this like,
$_SESSION['imageNameUpload'] = $imageNameUpload;
For main.php
And in the other file you must also use session_start(); at the very first after the
Then you could access the old variable via $imageNameUpload = $_SESSION['imageNameUpload'];.
You now can also use $imageNameUpload in the main.php file. But you only can use it if it's set (and you where at the first file before).
upload.php
<?php
session_start();
if (move_uploaded_file($_FILES["file"]["tmp_name"], $target_file)) {
echo '<div class="container">';
echo '<div class="row">';
echo '<div class="col-md-8">';
echo '<div class="alert alert-success">';
echo "Pilt: ". basename( $_FILES["file"]["name"]). " on lisatud!";
move_uploaded_file($_FILES["file"]["tmp_name"], $target_file);
echo '</div>';
echo '</div>';
echo '</div>';
echo '</div>';
$imageNameUpload = basename( $_FILES["file"]["name"]);
$_SESSION['imageNameUpload'] = $imageNameUpload;
}
main.php
<?php
session_start();
if(isset($_SESSION['imageNameUpload'])) {
$imageNameUpload = $_SESSION['imageNameUpload'];
}
// Other content of file
?>
If you don't want to refresh the page after image upload just want to show the uploaded image name without refreshing the page
Then,Change in your upload.php
if (move_uploaded_file($_FILES["file"]["tmp_name"], $target_file)) {
$imageNameUpload = basename( $_FILES["file"]["name"]);
$data = '<div class="container"><div class="row"><div class="col-md-8"><div class="alert alert-success">Pilt: '. $imageNameUpload. ' on lisatud!</div></div></div></div>';
echo $data;
exit();
}
And if you want to refresh the page then show image name on main.php. In that case you have to store data in session as i explain above. and add page refresh statement in ajax success block. And check in main.php if isset $imageNameUpload varible then first show it on html and then unset it. SO it will not seen in another page refresh request.
Hope this helps