I am trying to decode a json file with php, but it's not displaying anything. The code I have so far:
PHP
$str = file_get_contents('llt_stops.json');
$json = json_decode($str, true);
print_r($json, true);
JSON
{
"stops": [
{
"id": "1",
"name": "Andreaskyrkan",
"locId": "740037195"
},
{
"id": "2",
"name": "Ankarkronan",
"locId": "740037329"
},
{
"id": "3",
"name": "Arcushallen",
"locId": "740037262"
}
]
}
I've also tried with a foreach loop, but it doesn't display anything either.
foreach ($json['stops'] as $field => $value) {
// Use $field and $value here
}
Update:
I get this error, don't know whats wrong with the loop:
Invalid argument supplied for foreach()
Use
print_r($json);
With true it returns the value, does not print it.
It works now. It was the swedish characters in the json file that were not correctly displayed. I changed them from ? to å ä ö, and it worked.
Related
I have a string that i get from an API and i wish i could put it in a array so i could check the values that came from the return.
String return example:
{
"code":"000",
"message":"XXX",
"date":"2018-05-17",
"hour":"09:16:09",
"revision":"",
"server":"XX",
"content":{
"nome":{"info":"SIM","conteudo":[{"field1":"XXXX","field2":"XX"}]}
}
}
What I need:
echo $string['code'];
Javascript has no problem with JSON encode command. But how can I do it with PHP?
First of all your JSON data seems to be invalid (Some brackets missing). It needs to be like this:-
{
"code": "000",
"message": "XXX",
"date": "2018-05-17",
"hour": "09:16:09",
"revision": "",
"server": "XX",
"content": {
"nome": {
"info": "SIM",
"conteudo": [{
"field1": "XXXX",
"field2": "XX"
}]
}
}
}
Now You need to decode this JSON data and then get data based on the index
$array = json_decode($json,true);
echo $array['code'];
Output:-https://eval.in/1005949
You can decode the JSON string to Array in PHP.
$str = '{"code":"000","message":"XXX","date":"2018-05-17","hour":"09:16:09","revision":"","server":"XX","content":{"nome":{"info":"SIM","conteudo":[{"field1":"XXXX","field2":"XX"}]}';
$decodedValue = json_decode($str, true);
var_dump($decodedValue);
Your example string is not valid json, you are missing some closing brackets.
This should be the correct way:
'{"code":"000","message":"XXX","date":"2018-05-17","hour":"09:16:09","revision":"","server":"XX","content":{"nome":{"info":"SIM","conteudo":[{"field1":"XXXX","field2":"XX"}]}}}'
As for your question. in PHP you can easily use json_decode
Example:
<?php
$json = '{"code":"000","message":"XXX","date":"2018-05-17","hour":"09:16:09","revision":"","server":"XX","content":{"nome":{"info":"SIM","conteudo":[{"field1":"XXXX","field2":"XX"}]}}}';
$decoded_json = json_decode($json, true);
echo $decoded_json['code'];
You can see it working here
How do I convert JSON-LD extracted from website to a PHP array.
This is the Error I'm getting with the following code---
"Warning: Illegal string offset 'name' in
/Users/lightingsystem/sigclub/signatureclub/public/json/json2php.php
on line 12 {"
--code--
$json = '{ "#context": "http://schema.org", "#type": "LodgingBusiness", "name":"Breakerwood Suites", "amenityFeature":"A nice place to sleep", "audience":{ "#type":"Audience", "audienceType":"All" }, "checkinTime":"16:00", "checkoutTime":"10:00", "petsAllowed":"No", "availableLanguage":"", "openingHours":"", "paymentAccepted":"", "address":"2323 Bowers St.,New Orleans,LA,USA,69969", "image": "https://www.picturebook.com/resort2.jpg", "telephone":"Resort telephone number: 504/339-4543" }';
$coded = json_encode($json);
$data = json_decode($coded, true);
echo $data['name'];
Your call to json_encode is wrong because $json is already in the JSON format.
So what happens is: your JSON gets converted to JSON again, returning a JSON string.
Remove the json_encode call and your code works as expected.
<?php
$json = '{ "#context": "http://schema.org", "#type": "LodgingBusiness", "name":"Breakerwood Suites", "amenityFeature":"A nice place to sleep", "audience":{ "#type":"Audience", "audienceType":"All" }, "checkinTime":"16:00", "checkoutTime":"10:00", "petsAllowed":"No", "availableLanguage":"", "openingHours":"", "paymentAccepted":"", "address":"2323 Bowers St.,New Orleans,LA,USA,69969", "image": "https://www.picturebook.com/resort2.jpg", "telephone":"Resort telephone number: 504/339-4543" }';
$data = json_decode($json, true);
echo $data['name'];
Note:
You can get the last JSON error with json_last_error_msg
I am trying to parse my JSON response so I can print a specific value. Please help me in the right direction.
I am getting the following response:
{
"services": [{
"id": "9999999",
"domainname": "example.com",
"total": "100.90",
"status": "Active",
"billingcycle": "Monthly",
"date": "2017-11-25",
"category": "mobile phone",
"url": "example.com",
"name": "Iphone"
}]
}
How can I be able to print only the "name" value of this JSON value?
What I tried:
$someData = json_decode($response, TRUE);
// this print the whole response
print_r($someData);
foreach($someData['services'] as $result) {
echo $result['name'], '<br>';
}
But the foreach loop does not print the value which I need from the JSON response. What's wrong with this piece of PHP code?
Update: edited the json the first name was domainname my bad
You have a simple syntax error here
echo $result['name'],'<br>';
Try this
echo $result['name']. '<br>';
with a . dot instead of a comma ,
Otherwise It works fine as you can see here.
http://sandbox.onlinephpfunctions.com/code/9be6789973b0e70772403a786b379749f6db0a7a
I suggest turning error reporting on.
<?php
error_reporting(-1);
ini_set('display_errors', 1);
And you will be able to see most of these issues more clearly.
I have json from stripe and I am trying to decode it json_decode.
I am not getting an error. Just nothing is returning. I am getting the data back from stripe, I just cant decode it.
{
"created":1326853478,
"data":{
"object":{
"amount":4500,
"card":{
"country":"US",
"cvc_check":"pass",
"exp_month":7,
"exp_year":2014,
"fingerprint":"9aQtfsI8a17zjEZd",
"id":"cc_00000000000000",
"last4":"9782",
"object":"card",
"type":"Visa"
},
"created":1322700852,
"currency":"usd",
"disputed":false,
"fee":0,
"id":"ch_00000000000000",
"livemode":false,
"object":"charge",
"paid":true,
"refunded":true
}
},
"id":"evt_00000000000000",
"livemode":false,
"type":"charge.refunded"
}
// retrieve the request's body and parse it as JSON
$body = #file_get_contents('php://input');
$event_json = json_decode($body,true);
print_r($event_json);
Any ideas?
The php://input stream allows you to read raw data from the request body. This data will be a string and depending on what sort of values are in the request, will look something like:
"name=ok&submit=submit"
This is not JSON and therefore won't decode as JSON the way you expect.The json_decode() function returns null if it can't be decoded.
Where are you getting the JSON you posted above? That is the value you need to pass into json_decode().
If JSON is being passed in the request, like in the instance of callbacks, you would still need to parse that portion out to get just the JSON. If the php://input stream gives you name=ok&submit=submit&json={"created": 1326853478} then you'd have to parse it out. You can use this function from the PHP manual to seperate the values to work like the $_POST array:
<?php
// Function to fix up PHP's messing up POST input containing dots, etc.
function getRealPOST() {
$pairs = explode("&", file_get_contents("php://input"));
$vars = array();
foreach ($pairs as $pair) {
$nv = explode("=", $pair);
$name = urldecode($nv[0]);
$value = urldecode($nv[1]);
$vars[$name] = $value;
}
return $vars;
}
?>
To use it:
$post = getRealPOST();
$stripe_json = $post['json'];
$event_json = json_decode($stripe_json);
Here, I ran this:
<?php
$data = '{ "created": 1326853478, "data": { "object": { "amount": 4500, "card": { "country": "US", "cvc_check": "pass", "exp_month": 7, "exp_year": 2014, "fingerprint": "9aQtfsI8a17zjEZd", "id": "cc_00000000000000", "last4": "9782", "object": "card", "type": "Visa" }, "created": 1322700852, "currency": "usd", "disputed": false, "fee": 0, "id": "ch_00000000000000", "livemode": false, "object": "charge", "paid": true, "refunded": true } }, "id": "evt_00000000000000", "livemode": false, "type": "charge.refunded" }';
$arr = json_decode($data, true);
print_r($arr);
?>
And it worked. So, theoretically you should be able to use:
<?php
$arr = json_decode(file_get_contents('php://input'), true);
print_r($arr);
?>
As Ignacio Vazquez-Abrams said, don't use the '#' character because it obscures error messages and makes it harder to debug.
I would also check what version of PHP you have. json_decode() is only available on version 5.2.0 and later.
I tried to request the weather from a web service supplying data in JSON format. My PHP request code, which did not succeed was:
$url="http://www.worldweatheronline.com/feed/weather.ashx?q=schruns,austria&format=json&num_of_days=5&key=8f2d1ea151085304102710";
$json = file_get_contents($url);
$data = json_decode($json, TRUE);
echo $data[0]->weather->weatherIconUrl[0]->value;
This is some of the data that was returned. Some of the details have been truncated for brevity, but object integrity is retained:
{ "data":
{ "current_condition":
[ { "cloudcover": "31",
... } ],
"request":
[ { "query": "Schruns, Austria",
"type": "City" } ],
"weather":
[ { "date": "2010-10-27",
"precipMM": "0.0",
"tempMaxC": "3",
"tempMaxF": "38",
"tempMinC": "-13",
"tempMinF": "9",
"weatherCode": "113",
"weatherDesc": [ {"value": "Sunny" } ],
"weatherIconUrl": [ {"value": "http:\/\/www.worldweatheronline.com\/images\/wsymbols01_png_64\/wsymbol_0001_sunny.png" } ],
"winddir16Point": "N",
"winddirDegree": "356",
"winddirection": "N",
"windspeedKmph": "5",
"windspeedMiles": "3" },
{ "date": "2010-10-28",
... },
... ]
}
}
}
This appears to work:
$url = 'http://www.worldweatheronline.com/feed/weather.ashx?q=schruns,austria&format=json&num_of_days=5&key=8f2d1ea151085304102710%22';
$content = file_get_contents($url);
$json = json_decode($content, true);
foreach($json['data']['weather'] as $item) {
print $item['date'];
print ' - ';
print $item['weatherDesc'][0]['value'];
print ' - ';
print '<img src="' . $item['weatherIconUrl'][0]['value'] . '" border="0" alt="" />';
print '<br>';
}
If you set the second parameter of json_decode to true, you get an array, so you cant use the -> syntax. I would also suggest you install the JSONview Firefox extension, so you can view generated json documents in a nice formatted tree view similiar to how Firefox displays XML structures. This makes things a lot easier.
If you use the following instead:
$json = file_get_contents($url);
$data = json_decode($json, TRUE);
The TRUE returns an array instead of an object.
Try this example
$json = '{"foo-bar": 12345}';
$obj = json_decode($json);
print $obj->{'foo-bar'}; // 12345
http://php.net/manual/en/function.json-decode.php
NB - two negatives makes a positive . :)
Seems like you forgot the ["value"] or ->value:
echo $data[0]->weather->weatherIconUrl[0]->value;
When you json decode , force it to return an array instead of object.
$data = json_decode($json, TRUE); -> // TRUE
This will return an array and you can access the values by giving the keys.
You have to make sure first that your server allow remote connection so that the function file_get_contents($url) works fine , most server disable this feature for security reason.
While editing the code (because mild OCD), I noticed that weather is also a list. You should probably consider something like
echo $data[0]->weather[0]->weatherIconUrl[0]->value;
to make sure you are using the weatherIconUrl for the correct date instance.