Calling a function in php with link in html - php

I'm trying to call a function with a link in html. I found the following example:
click to run function!
if(isset($_POST['runfunction'])){
}
This works perfectly fine, the problem is that when I click the link, "?runfunction" keeps standing in my url bar. So when I submit a form on my page it goes totally wrong (it's way to long to upload here). I do some SQL queries and I'm getting weird values in my SQL database. When I type in just my normal url it works fine. So I'm pretty sure that's the problem. I found another example with ajax :
$("a").click(function(){
jQuery.ajax({
url: "path/to/controller",
type: "POST",
dataType: 'json',
data: {'mentod':'ExportExcel'},
success: successCallback,
error:failureCallback
});
});
I don't fully understand this example (because I never use AJAX) but my php script is included in the html page "include("")". So I can't type in url because it has to be the same page. Can someone give a little bit of info about this, or give an example of how I can fix this? Thanks in advance!

You can add a callback method then remove it from the url by javascript
function successCallback () {
url = window.location.href;
window.location = url.replace("runfunction", "");
}

Related

How to call Ajax in wordpress in custom.php page?

I have a little weird problem
I want to call wordpress ajax url in a custom page.php in public_html
The weird thing is that I have two type of these pages which have two different path :
First one is : the_permalink()/page1
Second one is : the_permalink()/page1/page2
The problem is that the ajax url call is working fine in page1 path : the_permalink()/page1
But same functions with same way of calling is not working in page2 path : the_permalink()/page1/page2
Is there any suggestions ?
Note : i have tested the the SCRIPT code which call the ajax with alert() function and found that that the code stops when it becomes to ajax part is this code :
<script>
$(document).ready(function(){
$('.checknow').click(function(e){
e.preventDefault();
var data = "test";
//alert(ajaxurl);
$.ajax({
type:"POST",
url:ajaxurl,
data: {
action:'action_function_php',
data:data,
},
success:function(data){
$('.security-check-result').html(data);
}
});
});
return false;
});
</script>
Note : i am using wildcard *, so the permalink return is subdomain if this would help
I have also tried to type the url directly but didn't work also
Here is an example page ( will remove it soon ) - just for make things
clear -
https://gameloop.bramj.store/windows
in this page if u tried to search something in the search bar you will find the ajax return works fine
but if you move to
https://gameloop.bramj.store/windows/download
you will notice that every single ajax code in the page is not working.
Thank you so much the problem is solved
i had to put the current main url ( domain/ subdomain ) without any slugs
so the best solution for this case is use this url :
var ajaxurl = "https://<?php echo $_SERVER['HTTP_HOST'];?>/wp-admin/admin-ajax.php";
You need to use wp_localize_script in order to have access to ajaxurl global.
If you don't want to do that then you can replace ajaxurl with <?php echo admin_url('admin-ajax.php');?> if you javascript is inside a PHP file.

How can I use a jQuery var in some php code?

I know there are a few topics on this subject, but after I spent 2 or 3 hours trying to get something good out of them, I just decided to ask this question on a specific point.
So here is my problem : I have got a table and I am using a jQuery function to select a row of this table. Now what i actually want to do is getting the text content of the div contained in the first td of the row.
I already used a getter on it and I am checking the getted value with an alert as you can see in th following code :
$("#myRow").click(function() {
$(".selectedRow").removeClass("selectedRow").addClass("unselected");
$(this).addClass("selectedRow").removeClass("unselected");
var myValue = $(".selectedRow .firstTd div").text();
alert('myValue');
});
So now, what I am trying to do is to send the myValue variable through an ajax request by replacing my alert by this piece of code :
$.ajax({
type: 'get',
url: 'index.php',
data: {"myValue" : myValue},
success: function(rs)
{
alert(myValue);
}
});
Then, back to my php code, I am tring to observe the obtained variable by using an echo, just like this :
<?php echo $_GET['myValue']; ?>
But there is just no way for me to know if my page got it beacause the echo just prints nothing... So i was wondering if someone could do something for me. Thanks.
PS : Oh, by the way ; I don't really know if this can matter, but my page index.php already receives data by a post.
You can't, but read this, php is on the server, while js usually runs on the client, but your ajax trick can work. Just do some processing in the recieving php.
I usually put my ajax recieving end in a different file, and process the rest by the variables posted.
Just try to put the $_GET['myValue']; into an if, or a switch.
Do a var dump of the request var to see if anything is coming through:
<?php
var_dump($_REQUEST);
If not, do a console.log() on 'myValue' to make sure it exists before sending the ajax request - the issue may lie in your js rather than you php.
If you are POSTing data then adjust accordingly - e.g.
$.ajax({
type: 'post',
url: 'index.php',
data: {"myValue" : myValue},
success: function(data)
{
console.log('successfuly posted:');
console.log(data);
}
});
then:
<?php echo $_POST['myValue']; ?>
If you were using GET your data would be in the url, e.g:
index.php?myValue=something
I'm not sure if you are aware of that, but you should wrap you function in document ready statement as below.
Next, call the AJAX request on some action, in this case we can use a click on the row in table.
$(document).ready(function () {
$("#myRow").click(function() {
$(".selectedRow").removeClass("selectedRow").addClass("unselected");
$(this).addClass("selectedRow").removeClass("unselected");
var myValue = $(".selectedRow .firstTd div").text();
alert('myValue');
$.ajax({
type: 'get',
url: 'index.php',
data: {"myValue" : myValue},
success: function(data)
{
console.log('you have posted:' + data.myValue);
}
});
});
});
Okay so it seems that i totally misunderstanded on the way that the $.ajax function works.
I now do use the $.post function (which is actually the same), this way :
$.post('pageElement.php', { myValue : $(".selectedRow .firstTd div").text() },
function(data) { $("#test").html(data); }
);
The url "pageElement.php" refers to a page containing this code :
<div><?php echo $_POST['myValue']; ?></div>
The function called at the end of the process just puts this code into a div of my original page, so i can use it as a php variable now and then send it to another page through a form.

Send "iframe.contents()" to PHP Script through Ajax any ideas ?

In my code I have an iFrame which loads dynamic content it's like a webpage(B.html) inside a page(A.php). in "A.php" user can edit inline the "B.html" once the process of editing has completed. In my submission I am sending iframes information to another page (script.php). I tried everything but content is not comming up in "script.php".
In nutshell, I want to tranfer my big html text with all stuff to a PHP via AJAX. I have no idea how to do it... my code would be something like below :-
Code for "A.php" inscript :
"myframe" is the iframe which contains the big chunk of HTML.
sendString = $("#myframe").contents();//Tried everything here[JSON as well]
$.ajax({
url: "script.php",
type: "POST",
data: sendingString,
cache: false,
success: function (html) {
return html;
}
});
Any help would be appreciated.
Regards,
Amjad
$("#myframe").contents() will get you it's nodes as a jQuery object. Try $("#myframe").html() instead to get the contents as a string.
EDIT: Oh, and it also helps if you fix your variable names. Change data: sendingString to data: sendString.

Ajax Post PHP Div Refreshing

It is me again. I am getting so frustrated with this code it is not even funny. It's not that I am wanting to post it again. It is just that now I understand the where the problem was in the code and wanted to see if you guys can help me figure the last part out.
Basically I am trying to refresh a div without reloading the entire page. It's killing me. Here is some more information on it:
here is my js file first
$(function() {
$(".button").click(function() {
// validate and process form
// first hide any error messages
var email = $("input#email").val();
//var dataString = '&email=' + email; commented out
var dataString = email;
//try insted this //alert (dataString);return false;
$.ajax({ type: "POST", dataType:'HTML',
//or the appropiate type of data you are getting back
url: "http://www.edshaer.com/EdinburgCISD/Gorena/Gorena.php", data: {email:dataString},
//in the php file do $email = $_POST['email'];
//not a good practice but you can try with it and without it
success: function() {
$("#div").fadeOut($("#div").html());
$("#div").fadeIn($("#div").html());
$("#email").val('');
// Change the content of the message element
// Fade the element back in
} });
//ajax ends
return false; });
//click ends
});//document ready ends
Now the problem that I am running into with this code is on the Ajax part. After placing the alert(), I have relized that if I use the function() like this:
success: function(data)
Then the alert came out blank. The reason behind it is that my URL is going to my php file, but my div that I am trying to refresh is on my html file. Meaning if I do this:
success: function(data) {
$("#div").html(data)}
I am sending blank data because it's trying to get the div from my php file instead of my html file.
Now if I do this:
$("#div").html()
Then that gives me the div that is in my html file.
By knowing what is going on now, Can you guys please help me???
My dear you should generate some sort of html in your php file that you want to generate in your div. Then you will see that you are having some content in data in the success function. This is an easy approach.
But there is also some other approach that is more efficient but it needs some sort of search. This is the implementation of Client Side Scripting. You can do this with the help of a jquery plugin jquote2. I hope it will work for you.
You're using
$("#div").fadeOut($("#div").html());
$("#div").fadeIn($("#div").html());
Both are wrong, jQuery .fadeIn() and .fadeOut() arguments are either [duration,] [callback] or [duration,] [easing,] [callback]. None take HTML as input.
Try changing
$("#div").fadeOut($("#div").html());
to
$("#div").fadeOut();
and moving it outside the $.ajax call to hide the previously showed (if any) results before the post and also change
$("#div").fadeIn($("#div").html());
to
$("#div").html(result).fadeIn();
Also change
success: function()
to
success: function(result)
Hope it helps.
This might be a problem relating to the response from the php script. Jquery doesn't always correctly render the Ajax response as html.
Setting dataType: html in the $.ajax({ ... }) call can help. Also setting header("Content-Type: text/html"); at the top of your php ajax script.

PHP json_encode unread by jQuery AJAX Post

I'm posting from a form to a URL like so:
$.post('?class=articles&method=submit', $(this).serialize(), function(msg)
{
alert(msg);
$(msg.html).hide().insertBefore('#addCommentContainer').slideDown();
$('#body').val('');
},'json');
And in the 'submit' method the last line is:
print json_encode( array('html'=>$content) );
Yet I'm not even getting to the alert portion in the jQuery.
I have a feeling it is because the 'submit' method is in a class file that is part of a template system (similar to phpBB). I know that creating a seperate .php file for submitting would work, but was curious if there was any other way.
Looks like you don't even have a specific url:
$.post('?class=articles&method=submit', $(this).serialize(), function(msg)
Should be I think
$.post('thePlaceIsubmitTo.php?class=articles&method=submit', $(this).serialize(), function(msg)
I believe that the serialize data will be appended to the url with and &, Be sure that this refers to the form tag
try using the $.ajax method, instead of the shorthand. I believe the problem is that you're using the POST shortcut method, while specifying GET variables appended to the URL.
Let me know if this helps, if not, We'll be able to help you :-)
I'm on vacation, on a netbook, so I can't exactly write a whole new method at the moment.

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