$data1 = array();
$final_ttt = "15";
$items = [];
for ($j = 1; $j <= $final_ttt; ++$j)
{
$TeamNo = "t$j";
$items[] = $TeamNo;
}
print_r($items);
In while loop im getting below values
$day = 1;
$i = 0;
while($row = $qry->fetch())
{
$name = $row['name']; //a,b,c,d
$loopvalue = $row['loopvalue']; // getting 2,3,8,3,4
$data1[]=array("name" => $name,"loopvalue" => $loopvalue);
if( $i % $final_ttt == 0 )
{
$fday = "Day ".$day;
$day++;
}
}
output
name value Team day
a 2 t1,t12 1
b 3 t3,t4,t5 1
c 8 t5,t6,t7,t8,t9,t10,t11,t12 1
d 3 t13,t14,t15 1
e 4 t1,t2,t3,t4 2
How to allocate the teams to based on while loop value. if i get value is 2 => then i need to allocate first 2 teams t1,t2 like this. kinldy help me.
Thanks you in advance
--- We are editing the question as the solution provided does not work in certain test cases. Like the one shown in the attached image.
Here is the updated code for above image output
$lastIndex = 0;
$day = 1;
while($row = $qry->fetch())
{
$name = $row['name']; //a,b,c,d
$loopvalue = $row['loopvalue']; // getting 2,3,8,3,4
if($i==0)
{
$fday = "Day ".$day;//Day 1 for first Itration
$day = 2;
}
$team = implode(',',array_slice($items, $lastIndex, $loopvalue));
$lastIndex = $lastIndex + $loopvalue;
if($lastIndex > count($items))
{
$lastIndex = $lastIndex - count($items);
$team .= ','.implode(',',array_slice($items, 0, $lastIndex));
$fday = "Day ".$day;
$day++;
}
$data1[]=array("name" => $name,"loopvalue" => $loopvalue, "day" => $fday, 'team' => $team);
$row ++;
}
print_r($data1);
You can try something like below
$lastIndex = 0;
while($row = $qry->fetch())
{
$name = $row['name']; //a,b,c,d
$loopvalue = $row['loopvalue']; // getting 2,3,8,3,4
$team = implode(',',array_slice($items, $lastIndex, $loopvalue));
$lastIndex = $lastIndex + $loopvalue;
if($lastIndex > count($items)) {
$lastIndex = $lastIndex - count($items);
$team .= ','.implode(',',array_slice($items, 0, $lastIndex));
}
$data1[]=array("name" => $name,"loopvalue" => $loopvalue, 'team' => $team);
$row ++;
}
print_r($data1);
Will result like
Array ( [0] => Array ( [name] => a [loopvalue] => 2 [team] => t1,t2 ) [1] => Array ( [name] => b [loopvalue] => 3 [team] => t3,t4,t5 ) [2] => Array ( [name] => c [loopvalue] => 8 [team] => t6,t7,t8,t9,t10,t11,t12,t13 ) [3] => Array ( [name] => d [loopvalue] => 3 [team] => t14,t15,t1 ) [4] => Array ( [name] => e [loopvalue] => 4 [team] => t2,t3,t4,t5 ) )
Let me know if this solve your problem.
Related
I have long string which I split after each 4th char. After that I want to take 3 random of them and show how many times are in the array.
What I have is
$string = "AAAAAAABAAACAAADAAAEAAAFAAAGAAAHAAAIAAAJAAAKAAALAAAMAAANAAAOAAAPAAAQAAARAAASAAATAAAUAAAVAAAWAAAXAAAYAAAZAAAaAAAbAAAcAAAdAAAeAAAfAAAgAAAhAAAiAAAjAAAkAAAlAAAmAAAnAAAoAAApAAAqAAArAAAsAAAtAAAuAAAvAAAwAAAxAAAyAAAzAABAAABBAABCAABDAABEAABFAABGAABHAABIAABJAABKAABLAABMAABNAA";
$segmentLength = 3;
$totalLength = strlen($string);
for ($i = 0; $i < $totalLength; $i += $segmentLength) {
$result[] = substr($string, min($totalLength - $segmentLength, $i), $segmentLength);
}
print_r(array_rand(array_count_values($result), 4));
array_count_values($result) output is
Array
(
[AAA] => 19
[ABA] => 1
[AAC] => 1
........
[AAL] => 1
[MAA] => 1
[AAB] => 4
)
I'm trying with print_r(array_rand(array_count_values($result), 4)); to output
Array
(
[AAA] => 19
[ABA] => 1
[AAC] => 1
[AAB] => 4
)
or
Array
(
[ABA] => 1
[AAC] => 1
[AAL] => 1
[MAA] => 1
)
instead I get
Array
(
[0] => AHA
[1] => AAa
[2] => zAA
[3] => BGA
)
...
Array
(
[0] => GAA
[1] => AxA
[2] => CAA
[3] => BGA
)
... so on
You could store the result of array_count_values($result); to a variable and then get a random set of keys from that result. Then loop through that random list of keys and generate your desired output. For example:
$string = "AAAAAAABAAACAAADAAAEAAAFAAAGAAAHAAAIAAAJAAAKAAALAAAMAAANAAAOAAAPAAAQAAARAAASAAATAAAUAAAVAAAWAAAXAAAYAAAZAAAaAAAbAAAcAAAdAAAeAAAfAAAgAAAhAAAiAAAjAAAkAAAlAAAmAAAnAAAoAAApAAAqAAArAAAsAAAtAAAuAAAvAAAwAAAxAAAyAAAzAABAAABBAABCAABDAABEAABFAABGAABHAABIAABJAABKAABLAABMAABNAA";
$segmentLength = 3;
$totalLength = strlen($string);
for ($i = 0; $i < $totalLength; $i += $segmentLength) {
$result[] = substr($string, min($totalLength - $segmentLength, $i), $segmentLength);
}
$countedValues = array_count_values($result);
$randValues = array_rand($countedValues, 4);
$output = [];
for ($i = 0; $i < count($randValues); $i++) {
$key = $randValues[$i];
$output[$key] = $countedValues[$key];
}
print_r($output);
I have numbers, from 0 to 8. I would like in result, all possible sets of those numbers, each set should use all numbers, each number can occur only once in a set.
I would like to see solution made in PHP that could print out result. Or, at least, I would like some refreshment in theory of combinatorics, as I have long forgotten it. What is the formula to calculate how many permutations will there be?
Example sets:
0-1-2-3-4-5-6-7-8
0-1-2-3-4-5-6-8-7
0-1-2-3-4-5-8-6-7
0-1-2-3-4-8-5-6-7
0-1-2-3-8-4-5-6-7
0-1-2-8-3-4-5-6-7
and so on...
You're looking for the permutations formula:
nPk = n!/(n-k)!
In your case, you have 9 entries and you want to choose all of them, that's 9P9 = 9! = 362880
You can find a PHP algorithm to permutate in recipe 4.26 of O'Reilly's "PHP Cookbook".
pc_permute(array(0, 1, 2, 3, 4, 5, 7, 8));
Copied in from O'Reilly:
function pc_permute($items, $perms = array( )) {
if (empty($items)) {
print join(' ', $perms) . "\n";
} else {
for ($i = count($items) - 1; $i >= 0; --$i) {
$newitems = $items;
$newperms = $perms;
list($foo) = array_splice($newitems, $i, 1);
array_unshift($newperms, $foo);
pc_permute($newitems, $newperms);
}
}
}
Since PHP 5.5 you can use Generators. Generators save a lot of memory and are way faster (more than half compared to pc_permute()). So if you have any chance of having PHP 5.5 installed, you definitely want Generators.
This snipped is ported from Python: https://stackoverflow.com/a/104436/3745311
function permutations(array $elements)
{
if (count($elements) <= 1) {
yield $elements;
} else {
foreach (permutations(array_slice($elements, 1)) as $permutation) {
foreach (range(0, count($elements) - 1) as $i) {
yield array_merge(
array_slice($permutation, 0, $i),
[$elements[0]],
array_slice($permutation, $i)
);
}
}
}
}
Sample usage:
$list = ['a', 'b', 'c'];
foreach (permutations($list) as $permutation) {
echo implode(',', $permutation) . PHP_EOL;
}
Output:
a,b,c
b,a,c
b,c,a
a,c,b
c,a,b
c,b,a
Since this question often comes up in Google Search results, here's a modified version of the accepted answer that returns all combinations in an array and passes them as a return value of the function.
function pc_permute($items, $perms = array( )) {
if (empty($items)) {
$return = array($perms);
} else {
$return = array();
for ($i = count($items) - 1; $i >= 0; --$i) {
$newitems = $items;
$newperms = $perms;
list($foo) = array_splice($newitems, $i, 1);
array_unshift($newperms, $foo);
$return = array_merge($return, pc_permute($newitems, $newperms));
}
}
return $return;
}
To use:
$value = array('1', '2', '3');
print_r(pc_permute($value));
I've something that You may like
function combination_number($k,$n){
$n = intval($n);
$k = intval($k);
if ($k > $n){
return 0;
} elseif ($n == $k) {
return 1;
} else {
if ($k >= $n - $k){
$l = $k+1;
for ($i = $l+1 ; $i <= $n ; $i++)
$l *= $i;
$m = 1;
for ($i = 2 ; $i <= $n-$k ; $i++)
$m *= $i;
} else {
$l = ($n-$k) + 1;
for ($i = $l+1 ; $i <= $n ; $i++)
$l *= $i;
$m = 1;
for ($i = 2 ; $i <= $k ; $i++)
$m *= $i;
}
}
return $l/$m;
}
function array_combination($le, $set){
$lk = combination_number($le, count($set));
$ret = array_fill(0, $lk, array_fill(0, $le, '') );
$temp = array();
for ($i = 0 ; $i < $le ; $i++)
$temp[$i] = $i;
$ret[0] = $temp;
for ($i = 1 ; $i < $lk ; $i++){
if ($temp[$le-1] != count($set)-1){
$temp[$le-1]++;
} else {
$od = -1;
for ($j = $le-2 ; $j >= 0 ; $j--)
if ($temp[$j]+1 != $temp[$j+1]){
$od = $j;
break;
}
if ($od == -1)
break;
$temp[$od]++;
for ($j = $od+1 ; $j < $le ; $j++)
$temp[$j] = $temp[$od]+$j-$od;
}
$ret[$i] = $temp;
}
for ($i = 0 ; $i < $lk ; $i++)
for ($j = 0 ; $j < $le ; $j++)
$ret[$i][$j] = $set[$ret[$i][$j]];
return $ret;
}
Here is how to use it:
To get the number of combinations:
combination_number(3,10); // returns number of combinations of ten-elements set.
To get all possible combinations:
$mySet = array("A","B","C","D","E","F");
array_combination(3, $mySet); // returns all possible combinations of 3 elements of six-elements set.
Hope You make use of that.
I've ported the Python itertools code listed here (using generators). The advantage over the solutions posted so far is that it allows you to specify r (permutation size).
function permutations($pool, $r = null) {
$n = count($pool);
if ($r == null) {
$r = $n;
}
if ($r > $n) {
return;
}
$indices = range(0, $n - 1);
$cycles = range($n, $n - $r + 1, -1); // count down
yield array_slice($pool, 0, $r);
if ($n <= 0) {
return;
}
while (true) {
$exit_early = false;
for ($i = $r;$i--;$i >= 0) {
$cycles[$i]-= 1;
if ($cycles[$i] == 0) {
// Push whatever is at index $i to the end, move everything back
if ($i < count($indices)) {
$removed = array_splice($indices, $i, 1);
array_push($indices, $removed[0]);
}
$cycles[$i] = $n - $i;
} else {
$j = $cycles[$i];
// Swap indices $i & -$j.
$i_val = $indices[$i];
$neg_j_val = $indices[count($indices) - $j];
$indices[$i] = $neg_j_val;
$indices[count($indices) - $j] = $i_val;
$result = [];
$counter = 0;
foreach ($indices as $indx) {
array_push($result, $pool[$indx]);
$counter++;
if ($counter == $r) break;
}
yield $result;
$exit_early = true;
break;
}
}
if (!$exit_early) {
break; // Outer while loop
}
}
}
It works for me, but no promises!
Example usage:
$result = iterator_to_array(permutations([1, 2, 3, 4], 3));
foreach ($result as $row) {
print implode(", ", $row) . "\n";
}
This is my version of class. This class builds and returns permutated array as result
class Permutation {
private $result;
public function getResult() {
return $this->result;
}
public function permute($source, $permutated=array()) {
if (empty($permutated)){
$this->result = array();
}
if (empty($source)){
$this->result[] = $permutated;
} else {
for($i=0; $i<count($source); $i++){
$new_permutated = $permutated;
$new_permutated[] = $source[$i];
$new_source = array_merge(array_slice($source,0,$i),array_slice($source,$i+1));
$this->permute($new_source, $new_permutated);
}
}
return $this;
}
}
$arr = array(1,2,3,4,5);
$p = new Permutation();
print_r($p->permute($arr)->getResult());
The last three lines to test my class.
This is a simple recursive function that prints all permutations (written in pseudocode)
function rec(n, k) {
if (k == n) {
for i = 0 to n-1
print(perm[i], ' ');
print('\n');
}
else {
for i = 0 to n-1 {
if (not used[i]) {
used[i] = true;
perm[k] = i;
rec(n, k+1);
used[i] = false;
}
}
}
}
And it is called like this:
rec(9, 0);
Lexicographical order. There is no recursion. Almost no limits for array length.
There is no sort. It's running rather fast. It's easy to understand.
Minus: it gives a notice, but you can add a condition to start compare with the second element or error_reporting(0).
$a = array(
1,
2,
3,
4,
5
);
$b = array_reverse($a);
print_r($a);
//here need "br"
while ($a != $b)
{
foreach(array_reverse($a, true) as $k => $v)
{
if ($v < $a[$k + 1])
{
foreach(array_reverse($a, true) as $ka => $val)
{
if ($val > $v) break;
}
$ch = $a[$k];
$a[$k] = $a[$ka];
$a[$ka] = $ch;
$c = array_slice($a, 0, $k + 1);
print_r($a = array_merge($c, array_reverse(array_slice($a, $k + 1))));
//here need "br"
break;
}
}
}
You're basically talking about permutations where both n and k are 9 so you'll have 9! different permutations; see this: http://en.wikipedia.org/wiki/Permutation.
Here is my proposal, hope a little bit clearer than accepted answer.
function permutate($elements, $perm = array(), &$permArray = array())
{
if(empty($elements))
{
array_push($permArray,$perm); return;
}
for($i=0;$i<=count($elements)-1;$i++)
{
array_push($perm,$elements[$i]);
$tmp = $elements; array_splice($tmp,$i,1);
permutate($tmp,$perm,$permArray);
array_pop($perm);
}
return $permArray;
}
and usage:
$p = permutate(array('a','b','c'));
foreach($p as $perm)
print join(",",$perm)."|\n";
//function call
print_r(combinations([1,2,3,4,5,6,7,8,9,10,11,12,13]));
/**
* #param $mainArray
* #param int $size - optional
* #param array $combinations - optional
* #return mixed
*/
function combinations($mainArray, $size = 3, $combinations = [])
{
if (empty($combinations)) {
$combinations = $mainArray;
}
if ($size == 1) {
return str_replace('-','',$combinations);;
}
$newCombination = array();
foreach ($mainArray as $key => $val){
foreach ($combinations as $char) {
if(in_array($val, explode('-', $char))){
continue;
}
$newCombination[] = $val . '-' . $char;
}
}
return combinations($mainArray, $size - 1, $newCombination);
}
//========================= Next solution ==================================
function sampling($chars, $size, $combinations = array()) {
# if it's the first iteration, the first set
# of combinations is the same as the set of characters
if (empty($combinations)) {
$combinations = $chars;
}
# we're done if we're at size 1
if ($size == 1) {
return $combinations;
}
# initialise array to put new values in
$new_combinations = array();
# loop through existing combinations and character set to create strings
foreach ($combinations as $combination) {
foreach ($chars as $char) {
$new_combinations[] = $combination .'-'. $char ;
}
}
# call same function again for the next iteration
return $this->sampling($chars, $size - 1, $new_combinations);
}
function array_has_dupes($array) {
return count($array) !== count(array_unique($array));
}
function total() {
// Generate ticket price
$arrfinal = array();
// combinations
$chars = array(1,2,3,4,5,6,7,8,9,10,11,12,13); // for 10 digits
$combinations = $this->sampling($chars, 3);
//print_r($combinations); //exit;
foreach($combinations as $key => $val)
{
$arr = explode('-', $val);//str_split($val);
if(!$this->array_has_dupes($arr)){
$arrfinal[] = str_replace('-', '', $val);
}
}
echo '<pre>'; print_r($arrfinal); echo '</pre>';
}
Simple solution using recursion
function filterElement($element){
if(is_array($element[0])){
return $element[0];
}
# base case
return $element;
}
function permutation($input, $path){
// base case 1
if(count($input) == 0){
return [$path];
}
$output = [];
foreach($input as $index => $num){ # 1, 2,3, 4
$copyPath = $path; # copy the path - []
$copyPath[] = $num; # append the number [1]
# remove the current number
$inputLocal = $input;
unset($inputLocal[$index]); # [2, 3, 4]
$permute = permutation($inputLocal, $copyPath); # call [2, 3, 4], [1]
# for all element find add to output
foreach($permute as $ele){
# filter ouput
$output[] = filterElement($ele);
}
}
return $output;
}
print_r(permutation([1,2,3,4], []));
output
Array
(
[0] => Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 4
)
[1] => Array
(
[0] => 1
[1] => 2
[2] => 4
[3] => 3
)
[2] => Array
(
[0] => 1
[1] => 3
[2] => 2
[3] => 4
)
[3] => Array
(
[0] => 1
[1] => 3
[2] => 4
[3] => 2
)
[4] => Array
(
[0] => 1
[1] => 4
[2] => 2
[3] => 3
)
[5] => Array
(
[0] => 1
[1] => 4
[2] => 3
[3] => 2
)
[6] => Array
(
[0] => 2
[1] => 1
[2] => 3
[3] => 4
)
[7] => Array
(
[0] => 2
[1] => 1
[2] => 4
[3] => 3
)
[8] => Array
(
[0] => 2
[1] => 3
[2] => 1
[3] => 4
)
[9] => Array
(
[0] => 2
[1] => 3
[2] => 4
[3] => 1
)
[10] => Array
(
[0] => 2
[1] => 4
[2] => 1
[3] => 3
)
[11] => Array
(
[0] => 2
[1] => 4
[2] => 3
[3] => 1
)
[12] => Array
(
[0] => 3
[1] => 1
[2] => 2
[3] => 4
)
[13] => Array
(
[0] => 3
[1] => 1
[2] => 4
[3] => 2
)
[14] => Array
(
[0] => 3
[1] => 2
[2] => 1
[3] => 4
)
[15] => Array
(
[0] => 3
[1] => 2
[2] => 4
[3] => 1
)
[16] => Array
(
[0] => 3
[1] => 4
[2] => 1
[3] => 2
)
[17] => Array
(
[0] => 3
[1] => 4
[2] => 2
[3] => 1
)
[18] => Array
(
[0] => 4
[1] => 1
[2] => 2
[3] => 3
)
[19] => Array
(
[0] => 4
[1] => 1
[2] => 3
[3] => 2
)
[20] => Array
(
[0] => 4
[1] => 2
[2] => 1
[3] => 3
)
[21] => Array
(
[0] => 4
[1] => 2
[2] => 3
[3] => 1
)
[22] => Array
(
[0] => 4
[1] => 3
[2] => 1
[3] => 2
)
[23] => Array
(
[0] => 4
[1] => 3
[2] => 2
[3] => 1
)
)
I've got an array with about 40 keys. I'd like to have a small function that returns a summary array.
Right now I've got the following that works:
foreach ($all_data as $value){
$new_array[ $value['location'] ][ $value['manufacturer'] ][ $value['model'] ] += 1;
}
This returns an array with everything I need. However, the location, manufacturer and model could be changed up for a bunch of other values.
what I am trying to do is have something simple as:
$new_array = summarize($all_data,array('location','manufacturer','model','count'),array('list','list','list','count') );}
where this summarize function would build the call. I think I just need a bit of help on how to get it to run the string as code for this array. Otherwise I get
$current_selection = "[ $row_item['location'] ][ $row_item['manufacturer'] ][ $row_item['model'] ]"
$return_array{$current_selection} += 1;
Where the end goal is to have a function like:
function summarize($data_array, $fields_array, $process_array){
//data_array = associative multi-dimensional data array
//fields = values to pull from the data_array
//process = array specifying whether to list, sum, count, average, max, min
$return_array = array();
$current_selection = "";
foreach($fields_array as $field){
$current_selection .= '[ $row_item[\'' . $field . '\'] ]';
}
foreach ($data_array as $row_item){
//dynamic = DOES NOT WORK
$return_array[$current_selection] += 1;//eval? create function? abstract?
//another attempt
${'return_array' . $current_selection} += 1;
//Manual = Does work
//$return_array[ $row_item['location'] ][ $row_item['manufacturer'] ][ $row_item['model'] ] += 1;
}
}
Thanks for any help on how to do an indirect reference.
JC
RESOLUTION
The final version that managed to resolve this looks like the following, thanks to user: check, for getting me on the correct path.
function summarize($data_array, $fields_array, $process_array){
$return_array = array();
$i = 0;
foreach ($data_array as $row){
$ii = 0;
$temp = array();
$temp2 = array();
foreach($fields_array as $key=>$field){
if($process_array[$ii] == 'list') $temp[$ii] = $row[$field];
if($process_array[$ii] == 'count') $temp2[$ii] = 1;
if($process_array[$ii] == 'sum') $temp2[$ii] = $row[$field];
$ii++;
}
$unique = true;
$ii = 0;
foreach($return_array as $row2){
if(array_intersect_key($row2,$temp) == $temp){//$row2 == $temp){
$unique = false;
break;
}
$ii++;
}
if($unique){
$return_array[$i] = $temp;
if(!empty($temp2)) $return_array[$i] = array_merge($temp,$temp2);
$i++;
}else{
if(!empty($temp2)){
foreach($temp2 as $key => $value){
if($process_array[$key] == 'sum') $temp2[$key] = $return_array[$ii][$key] + $value;
if($process_array[$key] == 'count') $temp2[$key] = $return_array[$ii][$key] + 1;
if($process_array[$key] == 'max') $temp2[$key] = ($return_array[$ii][$key] < $value) ? $value : $return_array[$ii][$key];
if($process_array[$key] == 'min') $temp2[$key] = ($return_array[$ii][$key] > $value) ? $value : $return_array[$ii][$key];
//TODO:(JC) 'average' - need to create a count field if not present (or always despite and assume overhead of extra computations).
// - then just calculate the 'sum' and divide by the counter as a last step before returning the array.
}
$return_array[$ii] = array_merge($temp,$temp2);
}
}
}
print_r($return_array);
return $return_array;
}
Which gives the following result:
/*
CALL: summarize($data,array('location','manufacturer','model','model','volume','colourvolume'),array('list','list','list','count','sum','sum') );
[0] = location
[1] = manufacturer
[2] = model
[3] = model count
[4] = mono volume sum
[5] = colour volume sum
*/
Array
(
[0] => Array
(
[0] =>
[1] => HP
[2] => LaserJet 4000
[3] => 3
[4] => 3000
[5] => 0
)
...
[17] => Array
(
[0] => Room 114
[1] => CANON
[2] => iR3235
[3] => 1
[4] => 4012
[5] => 0
)
[18] => Array
(
[0] => Room 115
[1] => LEXMARK
[2] => T652
[3] => 1
[4] => 20
[5] => 0
)
)
alternatively, if I assume that's $field_array contains sequentially key fields from root to sub key, you can loop your $field_array within $data_array loop
function summarize($data_array, $fields_array, $process_array){
$return_array = array();
foreach ($data_array as $row){
$temp = array();
foreach($fields_array as $key=>$field){
$temp = $key==0?$row[$field]:$temp[$field];
}
if(!empty($temp)) $return_array[] = $temp;
}
return $return_array;
}
and this is my array, will summarize with these function
$array = array(
array("multi"=>array("dimensional"=>array("array"=>"foo1"))),
array("multi"=>array("dimensional"=>array("array"=>"foo2"))),
array("multi"=>array("dimensional"=>array("array"=>"foo3"))),
array("multi"=>array("dimensional"=>array("array"=>"foo4"))),
array("multi"=>array("dimensional"=>array("array"=>"foo5"))),
array("multi"=>array("dimensional"=>array("array"=>"foo6"))),
array("multi"=>array("dimensional"=>array("array"=>"foo7"))),
array("multi"=>array("dimensional"=>array("array"=>"foo8"))),
array("multi"=>array("dimensional"=>array("array"=>"foo9")))
);
print_r(summarize($array,array("multi","dimensional","array"),NULL));
Ouput
Array ( [0] => foo1 [1] => foo2 [2] => foo3 [3] => foo4 [4] => foo5 [5] => foo6 [6] => foo7 [7] => foo8 [8] => foo9 )
I have an array and the createtime is already sorted by AES.
$list = array(0 => array('createtime' => 90,'message'=>'ad','user'=>'a'),
1 => array('createtime' => 91,'message'=>'ae','user'=>'b'),
2 => array('createtime' => 93,'message'=>'ae','user'=>'b'),
3 => array('createtime' => 93,'message'=>'ae','user'=>'c'),
4 => array('createtime' => 94,'message'=>'ah','user'=>'d'),
5 => array('createtime' => 99,'message'=>'ah','user'=>'a'),
6 => array('createtime' => 100,'message'=>'ah','user'=>'a'));
As you can see,maybe the array is from a sql table,what I want is to deal with these data,the result of array like this.
$list = array(0 => array('createtime' => 90,'message'=>'ad','user'=>'a'),
1 => array('createtime' => 91,'message'=>'ae+ae','user'=>'b'),
2 => array('createtime' => 93,'message'=>'ae','user'=>'c'),
3 => array('createtime' => 94,'message'=>'ah','user'=>'d'),
4 => array('createtime' => 99,'message'=>'ah+ah','user'=>'a'));
Yeah, you may find the createtime between 5 and the same user data combined.What I want is just like this,and in the future it may includes more users and more createtimes.
And I coded like this to deal with it,but it worked not well when I change my datas like add user or change user and so on.
$diff = 0;
$count = 0;
$d = array();
$j = array();
for($i = 1;isset($list[$i]);){
if ($list[$i]['user'] != $list[$i-1-$count]['user']) {
if (!in_array($list[$i]['user'], $d)) {
$d[$diff] = $list[$i]['user'];
$j[$diff] = $i;
$count++;
$diff++;
$i++;
continue;
} else {
$i++;
$count++;
continue;
}
}
if($list[$i]['createtime'] - $list[$i-1-$count]['createtime'] < 5){
$list[$i-1-$count]['message'] = $list[$i-1-$count]['message'].'<br>'.$list[$i]['message'];
array_splice($list,$i,1);
} else if ($count == 0) {
$i++;
} else {
$i = $j[0] + 1;
$count = 0;
$diff = 0;
$d = array();
$j = array();
}
}
It seems to have something wrong.So how should I do to meet my requirements.And more users between short createtime should also be considered.Thanks.
So, you're after something like this?
$list = array(0 => array('createtime' => 90,'message'=>'ad','user'=>'a'),
1 => array('createtime' => 91,'message'=>'ae','user'=>'b'),
2 => array('createtime' => 93,'message'=>'ae','user'=>'b'),
3 => array('createtime' => 93,'message'=>'ae','user'=>'c'),
4 => array('createtime' => 94,'message'=>'ah','user'=>'d'),
5 => array('createtime' => 99,'message'=>'ah','user'=>'a'),
6 => array('createtime' => 100,'message'=>'ah','user'=>'a'));
$out = array();
$prevUser = 0;
foreach($list as $key => $value){
if($value['user'] === $prevUser){
echo $value['user'], $prevUser, '<br>';
end($out);
$k = key($out);
$out[$k]['message'] .= $value['message'];
continue;
}
$out[] = $value;
$prevUser = $value['user'];
}
echo '<pre>';
print_r($out);
I have numbers, from 0 to 8. I would like in result, all possible sets of those numbers, each set should use all numbers, each number can occur only once in a set.
I would like to see solution made in PHP that could print out result. Or, at least, I would like some refreshment in theory of combinatorics, as I have long forgotten it. What is the formula to calculate how many permutations will there be?
Example sets:
0-1-2-3-4-5-6-7-8
0-1-2-3-4-5-6-8-7
0-1-2-3-4-5-8-6-7
0-1-2-3-4-8-5-6-7
0-1-2-3-8-4-5-6-7
0-1-2-8-3-4-5-6-7
and so on...
You're looking for the permutations formula:
nPk = n!/(n-k)!
In your case, you have 9 entries and you want to choose all of them, that's 9P9 = 9! = 362880
You can find a PHP algorithm to permutate in recipe 4.26 of O'Reilly's "PHP Cookbook".
pc_permute(array(0, 1, 2, 3, 4, 5, 7, 8));
Copied in from O'Reilly:
function pc_permute($items, $perms = array( )) {
if (empty($items)) {
print join(' ', $perms) . "\n";
} else {
for ($i = count($items) - 1; $i >= 0; --$i) {
$newitems = $items;
$newperms = $perms;
list($foo) = array_splice($newitems, $i, 1);
array_unshift($newperms, $foo);
pc_permute($newitems, $newperms);
}
}
}
Since PHP 5.5 you can use Generators. Generators save a lot of memory and are way faster (more than half compared to pc_permute()). So if you have any chance of having PHP 5.5 installed, you definitely want Generators.
This snipped is ported from Python: https://stackoverflow.com/a/104436/3745311
function permutations(array $elements)
{
if (count($elements) <= 1) {
yield $elements;
} else {
foreach (permutations(array_slice($elements, 1)) as $permutation) {
foreach (range(0, count($elements) - 1) as $i) {
yield array_merge(
array_slice($permutation, 0, $i),
[$elements[0]],
array_slice($permutation, $i)
);
}
}
}
}
Sample usage:
$list = ['a', 'b', 'c'];
foreach (permutations($list) as $permutation) {
echo implode(',', $permutation) . PHP_EOL;
}
Output:
a,b,c
b,a,c
b,c,a
a,c,b
c,a,b
c,b,a
Since this question often comes up in Google Search results, here's a modified version of the accepted answer that returns all combinations in an array and passes them as a return value of the function.
function pc_permute($items, $perms = array( )) {
if (empty($items)) {
$return = array($perms);
} else {
$return = array();
for ($i = count($items) - 1; $i >= 0; --$i) {
$newitems = $items;
$newperms = $perms;
list($foo) = array_splice($newitems, $i, 1);
array_unshift($newperms, $foo);
$return = array_merge($return, pc_permute($newitems, $newperms));
}
}
return $return;
}
To use:
$value = array('1', '2', '3');
print_r(pc_permute($value));
I've something that You may like
function combination_number($k,$n){
$n = intval($n);
$k = intval($k);
if ($k > $n){
return 0;
} elseif ($n == $k) {
return 1;
} else {
if ($k >= $n - $k){
$l = $k+1;
for ($i = $l+1 ; $i <= $n ; $i++)
$l *= $i;
$m = 1;
for ($i = 2 ; $i <= $n-$k ; $i++)
$m *= $i;
} else {
$l = ($n-$k) + 1;
for ($i = $l+1 ; $i <= $n ; $i++)
$l *= $i;
$m = 1;
for ($i = 2 ; $i <= $k ; $i++)
$m *= $i;
}
}
return $l/$m;
}
function array_combination($le, $set){
$lk = combination_number($le, count($set));
$ret = array_fill(0, $lk, array_fill(0, $le, '') );
$temp = array();
for ($i = 0 ; $i < $le ; $i++)
$temp[$i] = $i;
$ret[0] = $temp;
for ($i = 1 ; $i < $lk ; $i++){
if ($temp[$le-1] != count($set)-1){
$temp[$le-1]++;
} else {
$od = -1;
for ($j = $le-2 ; $j >= 0 ; $j--)
if ($temp[$j]+1 != $temp[$j+1]){
$od = $j;
break;
}
if ($od == -1)
break;
$temp[$od]++;
for ($j = $od+1 ; $j < $le ; $j++)
$temp[$j] = $temp[$od]+$j-$od;
}
$ret[$i] = $temp;
}
for ($i = 0 ; $i < $lk ; $i++)
for ($j = 0 ; $j < $le ; $j++)
$ret[$i][$j] = $set[$ret[$i][$j]];
return $ret;
}
Here is how to use it:
To get the number of combinations:
combination_number(3,10); // returns number of combinations of ten-elements set.
To get all possible combinations:
$mySet = array("A","B","C","D","E","F");
array_combination(3, $mySet); // returns all possible combinations of 3 elements of six-elements set.
Hope You make use of that.
I've ported the Python itertools code listed here (using generators). The advantage over the solutions posted so far is that it allows you to specify r (permutation size).
function permutations($pool, $r = null) {
$n = count($pool);
if ($r == null) {
$r = $n;
}
if ($r > $n) {
return;
}
$indices = range(0, $n - 1);
$cycles = range($n, $n - $r + 1, -1); // count down
yield array_slice($pool, 0, $r);
if ($n <= 0) {
return;
}
while (true) {
$exit_early = false;
for ($i = $r;$i--;$i >= 0) {
$cycles[$i]-= 1;
if ($cycles[$i] == 0) {
// Push whatever is at index $i to the end, move everything back
if ($i < count($indices)) {
$removed = array_splice($indices, $i, 1);
array_push($indices, $removed[0]);
}
$cycles[$i] = $n - $i;
} else {
$j = $cycles[$i];
// Swap indices $i & -$j.
$i_val = $indices[$i];
$neg_j_val = $indices[count($indices) - $j];
$indices[$i] = $neg_j_val;
$indices[count($indices) - $j] = $i_val;
$result = [];
$counter = 0;
foreach ($indices as $indx) {
array_push($result, $pool[$indx]);
$counter++;
if ($counter == $r) break;
}
yield $result;
$exit_early = true;
break;
}
}
if (!$exit_early) {
break; // Outer while loop
}
}
}
It works for me, but no promises!
Example usage:
$result = iterator_to_array(permutations([1, 2, 3, 4], 3));
foreach ($result as $row) {
print implode(", ", $row) . "\n";
}
This is my version of class. This class builds and returns permutated array as result
class Permutation {
private $result;
public function getResult() {
return $this->result;
}
public function permute($source, $permutated=array()) {
if (empty($permutated)){
$this->result = array();
}
if (empty($source)){
$this->result[] = $permutated;
} else {
for($i=0; $i<count($source); $i++){
$new_permutated = $permutated;
$new_permutated[] = $source[$i];
$new_source = array_merge(array_slice($source,0,$i),array_slice($source,$i+1));
$this->permute($new_source, $new_permutated);
}
}
return $this;
}
}
$arr = array(1,2,3,4,5);
$p = new Permutation();
print_r($p->permute($arr)->getResult());
The last three lines to test my class.
This is a simple recursive function that prints all permutations (written in pseudocode)
function rec(n, k) {
if (k == n) {
for i = 0 to n-1
print(perm[i], ' ');
print('\n');
}
else {
for i = 0 to n-1 {
if (not used[i]) {
used[i] = true;
perm[k] = i;
rec(n, k+1);
used[i] = false;
}
}
}
}
And it is called like this:
rec(9, 0);
Lexicographical order. There is no recursion. Almost no limits for array length.
There is no sort. It's running rather fast. It's easy to understand.
Minus: it gives a notice, but you can add a condition to start compare with the second element or error_reporting(0).
$a = array(
1,
2,
3,
4,
5
);
$b = array_reverse($a);
print_r($a);
//here need "br"
while ($a != $b)
{
foreach(array_reverse($a, true) as $k => $v)
{
if ($v < $a[$k + 1])
{
foreach(array_reverse($a, true) as $ka => $val)
{
if ($val > $v) break;
}
$ch = $a[$k];
$a[$k] = $a[$ka];
$a[$ka] = $ch;
$c = array_slice($a, 0, $k + 1);
print_r($a = array_merge($c, array_reverse(array_slice($a, $k + 1))));
//here need "br"
break;
}
}
}
You're basically talking about permutations where both n and k are 9 so you'll have 9! different permutations; see this: http://en.wikipedia.org/wiki/Permutation.
Here is my proposal, hope a little bit clearer than accepted answer.
function permutate($elements, $perm = array(), &$permArray = array())
{
if(empty($elements))
{
array_push($permArray,$perm); return;
}
for($i=0;$i<=count($elements)-1;$i++)
{
array_push($perm,$elements[$i]);
$tmp = $elements; array_splice($tmp,$i,1);
permutate($tmp,$perm,$permArray);
array_pop($perm);
}
return $permArray;
}
and usage:
$p = permutate(array('a','b','c'));
foreach($p as $perm)
print join(",",$perm)."|\n";
//function call
print_r(combinations([1,2,3,4,5,6,7,8,9,10,11,12,13]));
/**
* #param $mainArray
* #param int $size - optional
* #param array $combinations - optional
* #return mixed
*/
function combinations($mainArray, $size = 3, $combinations = [])
{
if (empty($combinations)) {
$combinations = $mainArray;
}
if ($size == 1) {
return str_replace('-','',$combinations);;
}
$newCombination = array();
foreach ($mainArray as $key => $val){
foreach ($combinations as $char) {
if(in_array($val, explode('-', $char))){
continue;
}
$newCombination[] = $val . '-' . $char;
}
}
return combinations($mainArray, $size - 1, $newCombination);
}
//========================= Next solution ==================================
function sampling($chars, $size, $combinations = array()) {
# if it's the first iteration, the first set
# of combinations is the same as the set of characters
if (empty($combinations)) {
$combinations = $chars;
}
# we're done if we're at size 1
if ($size == 1) {
return $combinations;
}
# initialise array to put new values in
$new_combinations = array();
# loop through existing combinations and character set to create strings
foreach ($combinations as $combination) {
foreach ($chars as $char) {
$new_combinations[] = $combination .'-'. $char ;
}
}
# call same function again for the next iteration
return $this->sampling($chars, $size - 1, $new_combinations);
}
function array_has_dupes($array) {
return count($array) !== count(array_unique($array));
}
function total() {
// Generate ticket price
$arrfinal = array();
// combinations
$chars = array(1,2,3,4,5,6,7,8,9,10,11,12,13); // for 10 digits
$combinations = $this->sampling($chars, 3);
//print_r($combinations); //exit;
foreach($combinations as $key => $val)
{
$arr = explode('-', $val);//str_split($val);
if(!$this->array_has_dupes($arr)){
$arrfinal[] = str_replace('-', '', $val);
}
}
echo '<pre>'; print_r($arrfinal); echo '</pre>';
}
Simple solution using recursion
function filterElement($element){
if(is_array($element[0])){
return $element[0];
}
# base case
return $element;
}
function permutation($input, $path){
// base case 1
if(count($input) == 0){
return [$path];
}
$output = [];
foreach($input as $index => $num){ # 1, 2,3, 4
$copyPath = $path; # copy the path - []
$copyPath[] = $num; # append the number [1]
# remove the current number
$inputLocal = $input;
unset($inputLocal[$index]); # [2, 3, 4]
$permute = permutation($inputLocal, $copyPath); # call [2, 3, 4], [1]
# for all element find add to output
foreach($permute as $ele){
# filter ouput
$output[] = filterElement($ele);
}
}
return $output;
}
print_r(permutation([1,2,3,4], []));
output
Array
(
[0] => Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 4
)
[1] => Array
(
[0] => 1
[1] => 2
[2] => 4
[3] => 3
)
[2] => Array
(
[0] => 1
[1] => 3
[2] => 2
[3] => 4
)
[3] => Array
(
[0] => 1
[1] => 3
[2] => 4
[3] => 2
)
[4] => Array
(
[0] => 1
[1] => 4
[2] => 2
[3] => 3
)
[5] => Array
(
[0] => 1
[1] => 4
[2] => 3
[3] => 2
)
[6] => Array
(
[0] => 2
[1] => 1
[2] => 3
[3] => 4
)
[7] => Array
(
[0] => 2
[1] => 1
[2] => 4
[3] => 3
)
[8] => Array
(
[0] => 2
[1] => 3
[2] => 1
[3] => 4
)
[9] => Array
(
[0] => 2
[1] => 3
[2] => 4
[3] => 1
)
[10] => Array
(
[0] => 2
[1] => 4
[2] => 1
[3] => 3
)
[11] => Array
(
[0] => 2
[1] => 4
[2] => 3
[3] => 1
)
[12] => Array
(
[0] => 3
[1] => 1
[2] => 2
[3] => 4
)
[13] => Array
(
[0] => 3
[1] => 1
[2] => 4
[3] => 2
)
[14] => Array
(
[0] => 3
[1] => 2
[2] => 1
[3] => 4
)
[15] => Array
(
[0] => 3
[1] => 2
[2] => 4
[3] => 1
)
[16] => Array
(
[0] => 3
[1] => 4
[2] => 1
[3] => 2
)
[17] => Array
(
[0] => 3
[1] => 4
[2] => 2
[3] => 1
)
[18] => Array
(
[0] => 4
[1] => 1
[2] => 2
[3] => 3
)
[19] => Array
(
[0] => 4
[1] => 1
[2] => 3
[3] => 2
)
[20] => Array
(
[0] => 4
[1] => 2
[2] => 1
[3] => 3
)
[21] => Array
(
[0] => 4
[1] => 2
[2] => 3
[3] => 1
)
[22] => Array
(
[0] => 4
[1] => 3
[2] => 1
[3] => 2
)
[23] => Array
(
[0] => 4
[1] => 3
[2] => 2
[3] => 1
)
)