How to properly set headers for a json request through curl - php

Question

I am new at API´s, Curl and Json. I need to link my appilcation with the an API.
The API I want to connect with has a CURL example which is this:
curl -v -H "Accept: application/json" -H "Content-type: application/json" -X GET https://www.api.com -u 'user:token'
I have made some research and I make a request like this:
$url = "https://www.api.com";
$headers = array(
-H "Accept: application/json",
-H "Content-type: application/json"
-u 'Authorization: Basic '. base64_encode("user:token") // <---
);
//initializing curl object
$curl = curl_init();
//adding fields to the curl object to enter the site
curl_setopt($curl, CURLOPT_URL, $url);
curl_setopt($curl, CURLOPT_HTTPHEADER, $headers);
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_ENCODING, 'gzip,deflate');
//executing the curl call and getting data back
$json = curl_exec($curl);
curl_close($curl); // close the connection
//echo $json;
return $json;
I get the Json request but I still don´t understand the example the API gives. I even don´t know if I am setting well the Curl.
can someone explain to me how can I interpret the Curl example if I doing it well ?

Answer 1

This is not valid PHP syntax:
$headers = array(
-H "Accept: application/json",
-H "Content-type: application/json"
-u 'Authorization: Basic '. base64_encode("user:token") // <---
);
You should use this instead:
$headers = array(
'Accept: application/json',
'Content-type: application/json',
);
And for the auth, use this:
curl_setopt($curl, CURLOPT_USERPWD, $username . ':' . $password);