How to list records by date? - php

Question

you see I am trying to list the records of a table in my database, but I want to do it in the following way:
First, it has to display the date
and then all the records on that date should appear
In my table of the database I have 4 fields:
id, task, date, time
For example there are multiple tasks that are performed in a day, but at different times. Then I have stored in my database many tasks of different days and in different hours. What I want is to list them per day. Consult the database and show a list where the date appears first and then all the tasks that were done on that date, then show the other date and then all the tasks of that date and so on.
Something like that
That's my php code
$obj = new Task();
$consult = $obj->Lists();
date_default_timezone_set("America/Mexico_City");
$dateActual = date("Y-m-d");
while ($result = $consult->fetch_object()) {
echo "<button class='btn btn-default'>date = " . $result->date . "</button><br>";
$consult2 = $obj->Lists2($dateActual);
while($result2 = $consult2->fetch_object()) {
echo "<span>". $result2->time ."</span><br>";
}
$dateActual = $result->date;
}
my query to the database is:
public function Lists2($date)
{
global $conexion;
$sql = "SELECT ar.*, date_format(ar.date, '%d/%m/%Y') as date,
date_format(ar.time, '%r') as time,
u.user as User
FROM task_recents ar
INNER JOIN user u ON ar.iduser = u.iduser
WHERE date = '$date'
ORDER BY ar.time DESC";
$query = $conexion->query($sql);
return $query;
}
public function Lists()
{
global $conexion;
$sql = "SELECT ar.*, date_format(ar.date, '%d/%m/%Y') as date,
date_format(ar.time, '%r') as time,
u.user as User
FROM task_recents ar
INNER JOIN user u ON ar.iduser = u.iduser
ORDER BY ar.time DESC";
$query = $conexion->query($sql);
return $query;
}
The result is that it shows me the repeated date with their respective records.
What I'm trying to achieve is something like this:
How could I do it?
PD: The result that I'm getting is this:
But I don't like that...

Answer 1

The INNER JOIN keyword selects all rows from both tables as long as there is a match between the columns. If there are records in the "Orders" table that do not have matches in "Customers", these orders will not be shown!
The following query should no longer generate duplicate records
SELECT
ar.id,
ar.task,
date_format(ar.date, '%d/%m/%Y') as formattedDate,
date_format(ar.time, '%r') as formattedTime,
u.user as User
FROM
task_recents ar
LEFT JOIN
user u
ON
u.iduser = ar.iduser
WHERE
date = '$date'
ORDER BY
ar.time
DESC