Hello Guys im using this to Add http:// prefix to Url when missing. The problem is that he add it to the other Url's where i have http:// already.
foreach($result as $key => &$value)
{
if (strpos($sample['Internetadress'], 'http://') === false){
$sample['Internetadress'] = 'http://' .$sample['Internetadress'];
}
}
i want that he doesnt edit it when it exist.
i want that he doesnt add it when there is no URL.
Sorry about my english im from Germany :D
Your code shoud cover your first point (when http exist don't change the URL), if not provide us a sample url that you want to modify.
For the second point you just make another check like this:
<?php
$sample['Internetadress']='www.example.com';
if (strpos($sample['Internetadress'], 'http://') === false && trim($sample['Internetadress'])!==''){
if(strpos($sample['Internetadress'], 'https://') === false){
$sample['Internetadress'] = 'http://' .$sample['Internetadress'];
}
}
echo $sample['Internetadress'];
I think in this case a little regex is a good solution:
$urls = [
'http://www.example.com',
'foo.bar.com',
'https://example.com',
'www.example.com'
];
foreach ($urls as &$url) {
$url = preg_replace('/^(?!http)/i', 'http://', $url);
}
The values in $urls after the loop are:
[
"http://www.example.com",
"http://foo.bar.com",
"https://example.com",
"http://www.example.com"
]
Also instead of using a foreach loop and passing the values by reference you could use a array_map() like this:
$urls = array_map(function($url) {
return preg_replace('/^(?!http)/i', 'http://', $url);
}, $urls);
Related
I'm trying to get a very specific part of a URL using PHP so that I can use it as a variable later on.
The URL I have is:
https://forums.mydomain.com/index.php?/clubs/11-Default-Club
The particular part I am trying to extract is the 11 part between the /clubs/ and -Default-Club bits.
I was wondering what the best way to do this was. I've seen examples on here that use a regex-esque parser but I can't wrap my head around it for this particular instance.
Thanks
Edit; this is what I've tried so far using an explode query, but it seems to give me all sorts of elements which are not present in the URL above:
$url = $_SERVER['REQUEST_URI'];
$url = explode('/', $url);
$url = array_filter($url);
$url = array_merge($url, array());
Which returns:
Array ( [0] => index.php?app=core&module=system&controller=widgets&do=getBlock&blockID=plugin_9_bimBlankWidget_dqtr03ssz&pageApp=core&pageModule=clubs&pageController=view&pageArea=header&orientation=horizontal&csrfKey=8e19769b95c733b05439755827a98ac8 )
If you expect that the string with dashes (11-Default-Club) will be always at the end you can try this:
$url = $_SERVER['REQUEST_URI'];
$urlParts = explode('/', $url);
$string = end($urlParts);
$stringParts = explode('-', $string);
$theNumber = $stringParts[0]; // this will be 11
I'd rather be explicit:
<?php
$url = 'https://forums.mydomain.com/index.php?/clubs/11-Default-Club';
$query = parse_url($url, PHP_URL_QUERY);
$pattern = '#^/clubs/(\d+)[a-zA-Z-]+$#';
$digits = preg_match($pattern, $query, $matches)
? $matches[1]
: null;
var_dump($digits);
Output:
string(2) "11"
If this URL structure is fix for all URLs in your site and you only want to get the integer/number/digit part of the URL:
<?php
$url = 'https://forums.mydomain.com/index.php?/clubs/11-Default-Club';
$int = (int) filter_var($url, FILTER_SANITIZE_NUMBER_INT);
echo $int;
If this url structure is fix for all URLs in your site then below is best way to get your value.
<?php
$url = "https://forums.mydomain.com/index.php?/clubs/11-Default-Club";
$url = explode('/', $url);
$url = array_filter($url);
$end = end($url);
$end_parts = explode('-',$end);
echo $end_parts[0];
Output:
11
I need to extract the domain name out of a string which could be anything. Such as:
$sitelink="http://www.somewebsite.com/product/3749875/info/overview.html";
or
$sitelink="http://subdomain.somewebsite.com/blah/blah/whatever.php";
In any case, I'm looking to extract the 'somewebsite.com' portion (which could be anything), and discard the rest.
With parse_url($url)
<?php
$url = 'http://username:password#hostname/path?arg=value#anchor';
print_r(parse_url($url));
?>
The above example will output:
Array
(
[scheme] => http
[host] => hostname
[user] => username
[pass] => password
[path] => /path
[query] => arg=value
[fragment] => anchor
)
Using thos values
echo parse_url($url, PHP_URL_HOST); //hostname
or
$url_info = parse_url($url);
echo $url_info['host'];//hostname
here it is
<?php
$sitelink="http://www.somewebsite.com/product/3749875/info/overview.html";
$domain_pieces = explode(".", parse_url($sitelink, PHP_URL_HOST));
$l = sizeof($domain_pieces);
$secondleveldomain = $domain_pieces[$l-2] . "." . $domain_pieces[$l-1];
echo $secondleveldomain;
note that this is not probably the behavior you are looking for, because, for hosts like
stackoverflow.co.uk
it will echo "co.uk"
see:
http://publicsuffix.org/learn/
http://www.dkim-reputation.org/regdom-libs/
http://www.dkim-reputation.org/regdom-lib-downloads/ <-- downloads here, php included
2 complexe url
$url="https://www.example.co.uk/page/section/younameit";
or
$url="https://example.co.uk/page/section/younameit";
To get "www.example.co.uk":
$host=parse_url($url, PHP_URL_HOST);
To get "example.co.uk" only
$parts = explode('www.',$host);
$domain = $parts[1];
// ...or...
$domain = ltrim($host, 'www.')
If your url includes "www." or not you get the same end result, i.e. "example.co.uk"
VoilĂ !
You need package that uses Public Suffix List, only in this way you can correctly extract domains with two-, third-level TLDs (co.uk, a.bg, b.bg, etc.) and multilevel subdomains. Regex, parse_url() or string functions will never produce absolutely correct result.
I recomend use TLD Extract. Here example of code:
$extract = new LayerShifter\TLDExtract\Extract();
$result = $extract->parse('http://www.somewebsite.com/product/3749875/info/overview.html');
$result->getSubdomain(); // will return (string) 'www'
$result->getHostname(); // will return (string) 'somewebsite'
$result->getSuffix(); // will return (string) 'com'
$result->getRegistrableDomain(); // will return (string) 'somewebsite.com'
For a string that could be anything, new approach:
function extract_plain_domain($text) {
$text=trim($text,"/");
$text=strtolower($text);
$parts=explode("/",$text);
if (substr_count($parts[0],"http")) {
$parts[0]="";
}
reset ($parts);while (list ($key, $val) = each ($parts)) {
if (!empty($val)) { $text=$val; break; }
}
$parts=explode(".",$text);
if (empty($parts[2])) {
return $parts[0].".".$parts[1];
} else {
$num_parts=count($parts);
return $parts[$num_parts-2].".".$parts[$num_parts-1];
}
} // end function extract_plain_domain
You can use the Utopia Domains library (https://github.com/utopia-php/domains), it will return the domain TLD and public suffix based on Mozilla public suffix list (https://publicsuffix.org), it can be used as an alternative to the currently archived TLDExtract package.
You can use 'parse_url' function to get the hostname from your URL and than use Utopia Domains parser to get the correct TLD and join it together with the domain name:
<?php
require_once './vendor/autoload.php';
use Utopia\Domains\Domain;
$url = 'http://demo.example.co.uk/site';
$domain = new Domain(parse_url($url, PHP_URL_HOST)); // demo.example.co.uk
var_dump($domain->get()); // demo.example.co.uk
var_dump($domain->getTLD()); // uk
var_dump($domain->getSuffix()); // co.uk
var_dump($domain->getName()); // example
var_dump($domain->getSub()); // demo
var_dump($domain->isKnown()); // true
var_dump($domain->isICANN()); // true
var_dump($domain->isPrivate()); // false
var_dump($domain->isTest()); // false
var_dump($domain->getName().'.'.$domain->getSuffix()); // example.co.uk
What I am trying to do is to convert url of a video on youtube/vimeo return a new url that can be embed into an iframe and automate video embed codes.
This is working like a charm.
$url = "http://vimeo.com/29431603";
$orj_value = array("watch?v=", "http://vimeo.com/");
$new_value = array("embed/", "http://player.vimeo.com/video/");
$url = str_replace($orj_value, $new_value, $url);
echo $url;
You know, youtube ads an ugly string too into url that starts with &, so when i include
$url = substr($url, 0, strpos($url, "&"));
before
echo $url;
it strips out the unwanted part of youtube url. But then, vimeo code which has no & inside just does not return anything. Seems after adding new line, code wants to see a & inside the url; otherwise to echo $url var displays blank screen.
2- For dailymotion, i need to strip out everything after first _
How should i edit the line below in order to include support of dailymotion too?
$url = substr($url, 0, strpos($url, "&"));
Thanks in advance to anyone going to answer :)
If strpos() can't find the character you search for it will return false, which could confuse substr().
Try something like this:
$url = strpos($url, "&") ? substr($url, 0, strpos($url, "&")) : $url;
As for your comment:
if(strpos($url, "&")) {
$url = substr($url, 0, strpos($url, "&"));
} else if(strpos($url, "_")) {
$url = substr($url, 0, strpos($url, "_"));
}
There are more elegant ways to do it (ex. REGEX) but this will do. Note that & or _ can't be the first character in string if you want to allow this add !== false to the condition.
Here is the url:
http://localhost/test.php?id=http://google.com/?var=234&key=234
And I can't get the full $_GET['id'] or $_REQUEST['d'].
<?php
print_r($_REQUEST['id']);
//And this is the output http://google.com/?var=234
//the **&key=234** ain't show
?>
$get_url = "http://google.com/?var=234&key=234";
$my_url = "http://localhost/test.php?id=" . urlencode($get_url);
$my_url outputs:
http://localhost/test.php?id=http%3A%2F%2Fgoogle.com%2F%3Fvar%3D234%26key%3D234
So now you can get this value using $_GET['id'] or $_REQUEST['id'] (decoded).
echo urldecode($_GET["id"]);
Output
http://google.com/?var=234&key=234
To get every GET parameter:
foreach ($_GET as $key=>$value) {
echo "$key = " . urldecode($value) . "<br />\n";
}
$key is GET key and $value is GET value for $key.
Or you can use alternative solution to get array of GET params
$get_parameters = array();
if (isset($_SERVER['QUERY_STRING'])) {
$pairs = explode('&', $_SERVER['QUERY_STRING']);
foreach($pairs as $pair) {
$part = explode('=', $pair);
$get_parameters[$part[0]] = sizeof($part)>1 ? urldecode($part[1]) : "";
}
}
$get_parameters is same as url decoded $_GET.
While creating url encode them with urlencode
$val=urlencode('http://google.com/?var=234&key=234')
Click here
and while fetching decode it wiht urldecode
You may have to use urlencode on the string 'http://google.com/?var=234&key=234'
I had a similar problem and ended up using parse_url and parse_str, which as long as the URL in the parameter is correctly url encoded (which it definitely should) allows you to access both all the parameters of the actual URL, as well as the parameters of the encoded URL in the query parameter, like so:
$get_url = "http://google.com/?var=234&key=234";
$my_url = "http://localhost/test.php?id=" . urlencode($get_url);
function so_5645412_url_params($url) {
$url_comps = parse_url($url);
$query = $url_comps['query'];
$args = array();
parse_str($query, $args);
return $args;
}
$my_url_args = so_5645412_url_params($my_url); // Array ( [id] => http://google.com/?var=234&key=234 )
$get_url_args = so_5645412_url_params($my_url_args['id']); // Array ( [var] => 234, [key] => 234 )
you use bad character like ? and & and etc ...
edit it to new code
see this links
http://antoine.goutenoir.com/blog/2010/10/11/php-slugify-a-string/
http://sourcecookbook.com/en/recipes/8/function-to-slugify-strings-in-php
also you can use urlencode
$val=urlencode('http://google.com/?var=234&key=234')
The correct php way is to use parse_url()
http://php.net/manual/en/function.parse-url.php
(from php manual)
This function parses a URL and returns an associative array containing any of the various components of the URL that are present.
This function is not meant to validate the given URL, it only breaks it up into the above listed parts. Partial URLs are also accepted, parse_url() tries its best to parse them correctly.
if (isset($_SERVER['HTTPS'])){
echo "https://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]$_SERVER[QUERY_STRING]";
}else{
echo "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]$_SERVER[QUERY_STRING]";
}
I am trying to get the search keyword from a referrer url. Currently, I am using the following code for Google urls. But sometimes it is not working...
$query_get = "(q|p)";
$referrer = "http://www.google.com/search?hl=en&q=learn+php+2&client=firefox";
preg_match('/[?&]'.$query_get.'=(.*?)[&]/',$referrer,$search_keyword);
Is there another/clean/working way to do this?
Thank you,
Prasad
If you're using PHP5 take a look at http://php.net/parse_url and http://php.net/parse_str
Example:
// The referrer
$referrer = 'http://www.google.com/search?hl=en&q=learn+php+2&client=firefox';
// Parse the URL into an array
$parsed = parse_url( $referrer, PHP_URL_QUERY );
// Parse the query string into an array
parse_str( $parsed, $query );
// Output the result
echo $query['q'];
There are different query strings on different search engines. After trying Wiliam's method, I have figured out my own method. (Because, Yahoo's is using 'p', but sometimes 'q')
$referrer = "http://search.yahoo.com/search?p=www.stack+overflow%2Ccom&ei=utf-8&fr=slv8-msgr&xargs=0&pstart=1&b=61&xa=nSFc5KjbV2gQCZejYJqWdQ--,1259335755";
$referrer_query = parse_url($referrer);
$referrer_query = $referrer_query['query'];
$q = "[q|p]"; //Yahoo uses both query strings, I am using switch() for each search engine
preg_match('/'.$q.'=(.*?)&/',$referrer,$keyword);
$keyword = urldecode($keyword[1]);
echo $keyword; //Outputs "www.stack overflow,com"
Thank you,
Prasad
To supplement the other answers, note that the query string parameter that contains the search terms varies by search provider. This snippet of PHP shows the correct parameter to use:
$search_engines = array(
'q' => 'alltheweb|aol|ask|ask|bing|google',
'p' => 'yahoo',
'wd' => 'baidu',
'text' => 'yandex'
);
Source: http://betterwp.net/wordpress-tips/get-search-keywords-from-referrer/
<?php
class GET_HOST_KEYWORD
{
public function get_host_and_keyword($_url) {
$p = $q = "";
$chunk_url = parse_url($_url);
$_data["host"] = ($chunk_url['host'])?$chunk_url['host']:'';
parse_str($chunk_url['query']);
$_data["keyword"] = ($p)?$p:(($q)?$q:'');
return $_data;
}
}
// Sample Example
$obj = new GET_HOST_KEYWORD();
print_r($obj->get_host_and_keyword('http://www.google.co.in/search?sourceid=chrome&ie=UTF-&q=hire php php programmer'));
// sample output
//Array
//(
// [host] => www.google.co.in
// [keyword] => hire php php programmer
//)
// $search_engines = array(
// 'q' => 'alltheweb|aol|ask|ask|bing|google',
// 'p' => 'yahoo',
// 'wd' => 'baidu',
// 'text' => 'yandex'
//);
?>
$query = parse_url($request, PHP_URL_QUERY);
This one should work For Google, Bing and sometimes, Yahoo Search:
if( isset($_SERVER['HTTP_REFERER']) && $_SERVER['HTTP_REFERER']) {
$query = getSeQuery($_SERVER['HTTP_REFERER']);
echo $query;
} else {
echo "I think they spelled REFERER wrong? Anyways, your browser says you don't have one.";
}
function getSeQuery($url = false) {
$segments = parse_url($url);
$keywords = null;
if($query = isset($segments['query']) ? $segments['query'] : (isset($segments['fragment']) ? $segments['fragment'] : null)) {
parse_str($query, $segments);
$keywords = isset($segments['q']) ? $segments['q'] : (isset($segments['p']) ? $segments['p'] : null);
}
return $keywords;
}
I believe google and yahoo had updated their algorithm to exclude search keywords and other params in the url which cannot be received using http_referrer method.
Please let me know if above recommendations will still provide the search keywords.
What I am receiving now are below when using http referrer at my website end.
from google: https://www.google.co.in/
from yahoo: https://in.yahoo.com/
Ref: https://webmasters.googleblog.com/2012/03/upcoming-changes-in-googles-http.html