I am trying to create PHP form data insert in SQL but getting error.
Even when I write code same to same but I'm still getting an error.
<?php
$un = $_POST['uname'];
$em = $_POST['email1'];
//with or what out these bellow variables
$host = "localhost";
$username = "admin";
$password = "admin";
$database = "test1";
$db = mysqli_connect('$host','$username','$password','$database');
$query = "INSERT INTO users ('username','password') VALUES ('$un','$em')";
$rs = mysqli_query($db,$query);
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Form Registration</title>
</head>
<body>
<form action="server1.php" method="post">
<label>Name</label>
<input type="text" name="uname" required="required">
<label>Email</label>
<input type="email" name="email1" required="required">
<input type="submit" name="submit" value="submit">
</form>
</body>
</html>
The error was "" just inverted comma's, now its works perfectly.
<?php
$un = $_POST['uname'];
$em = $_POST['email1'];
$host = "localhost";
$username = "admin";
$password = "admin";
$database = "test1";
$con = mysqli_connect ("$host","$username","$password","$database");
$query = "insert into users (username,email) values ('$un','$em')";
$run = mysqli_query ($con,$query);
if ($run=TRUE){
echo 'Data Submitted Successfuly';
}
else {
echo 'Error';
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Form Registration</title>
</head>
<body>
<form action="server1.php" method="post">
<label>Name</label>
<input type="text" name="uname" required="required">
<label>Email</label>
<input type="email" name="email1" required="required">
<input type="submit" name="submit" value="submit">
</form>
</body>
</html>
You can try this way.
$db = mysqli_connect($host, $username, $password) or die ('Unable to connect');
mysqli_select_db($db, $database) or die('Unable to select DB');
Related
I am new to PHP and was following a login_registration script the registration process works fine and the user is added to the database, however, when I try to log in it shows error I checked php.error log on wamp server and it says this,
PHP 1. {main}() C:\wamp64\www\php\login_register_system\login.php:0
Here is my code
connect.inc.php
<?php
//$conn_error = "could not connect";
$mysql_host= "localhost";
$mysql_user = "root";
$mysql_pass ="";
$mysql_db ="a_database";
$conn = mysqli_connect($mysql_host,$mysql_user,$mysql_pass,$mysql_db);
/*if(!mysqli_connect($mysql_host,$mysql_user,$mysql_pass) && !mysqli_select_db($mysql_db)){
die($conn_error);
}
*/
if(!$conn){
die("Connection failed: ". mysqli_connect_error());
}
?>
registration.php
<!DOCTYPE html>
<html>
<head>
<meta charset ="utf-8">
<title>Registartion</title>
<link rel ="stylesheet"href="style.css"/>
</head>
<body>
<?php
require "connect.inc.php";
if(isset($_REQUEST["username"])){
$username =stripslashes($_REQUEST["username"]);
$username =mysqli_real_escape_string($conn,$username);
$email =stripslashes($_REQUEST["email"]);
$email =mysqli_real_escape_string($conn,$email);
$password =stripslashes($_REQUEST["password"]);
$password =mysqli_real_escape_string($conn,$password);
$trn_date = date("Y-m-d H:i:s");
$query ="INSERT INTO `users2` (username,password,email,trn_date) VALUES('$username','".md5($password)."','$email','$trn_date')";
$result =mysqli_query($conn,$query);
if($result){
echo "<div class='form'>
<h3>You are registered succesfully</h3><br>
Click here to <a href='login.php'>Log in</a>
</div>";
}
}else{
?>
<div class="form">
<h1>Registration</h1>
<form name="registration" action ="registration.php" method="post">
<input type="text" name ="username" placeholder ="Username" required/>
<input type="text" name ="email" placeholder ="Email" required/>
<input type="password" name ="password" placeholder ="password" required/>
<input type="submit" type="submit" value="Register"/>
</form>
</div><!--form-->
<?php } ?>
</body>
</html>
login.php
<!DOCTYPE html>
<html>
<head>
<meta charset ="utf-8">
<title>Login</title>
<link rel ="stylesheet"href="style.css"/>
</head>
<body>
<?php
//ini_set('display_errors','1');
//error_reporting(E_ALL);
require "connect.inc.php";
session_start();
if(isset($_POST["username"])){
$username = stripslashes($_REQUEST["username"]);
$username = mysqli_real_connect($conn,$username);
$username = mysqli_real_escape_string($conn,$password);
$query ="SELECT * FROM `users` WHERE username ='$username' and password ='".md5($password)."' ";
$result =mysqli_query($conn,$query) or die(mysql_error());
$rows = mysqli_num_rows($result);
if($rows==1){
$_SESSION["username"] = $username;
header("Location: index.php");
}else{
echo "<div class='form'>
<h3>Username/password is incorrect</h3><br>
Click here to <a href='login.php'>Login</a>
</div>";
}
}else{
?>
<div class="form">
<h1>Login </h1>
<form action="login.php" method="post" name="login">
<input type="text" name ="username" placeholder ="Username" required/>
<input type="passowrd" name ="password" placeholder ="password" required/>
<input type="submit" type="submit" value="Login"/>
</form>
</div>
<?php } ?>
</body>
</html>
logout.php
<?php
session_start();
if(session_destroy()){
header("Location: login.php");
}
?>
index.php
<?php
include("auth.php");
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Welcome home</title>
</head>
<body>
<div class="form">
<p>Welcome <?php echo $_SESSION["username"];?></p>
<p>This is secure area</p>
Logout
</div>
</body>
</html>
Any help will be highly appreciated. Thanks.
Do note this is just for learning the purpose. I know there are flaws but please be easy.
Just change this,
$username = stripslashes($_REQUEST["username"]);
$username = mysqli_real_connect($conn,$username);
$password =stripslashes($_REQUEST["password"]);
$password = mysqli_real_escape_string($conn,$password);
to the following,
$username = stripslashes($_REQUEST['username']);
$username = mysqli_real_escape_string($conn, $username);
$password = stripslashes($_REQUEST['password']);
$password = mysqli_real_escape_string($conn, $password);
I hope you have only one user related to the entered credentials in the database. Hope this helps you!
thanks i got it resolved..problem was this line $query ="SELECT * FROM users WHERE username ='$username' and password ='".md5($password)."' "; in login.php..
correct should be this
$query ="SELECT * FROM `users2` WHERE username ='$username' and password ='".md5($password)."' ";
i was checking data in users table whereas i registered in users2 table..as i had many tables that created confusion
I am trying to send the data put into the input fields to my database and I cant seem to make it work out properly..
The ultimate goal is to put in the input fields into the database and show the inserted data in another window.
Here's my code
<?php
$servername = "localhost";
$username = "root";
$password = "";
// Create connection
$conn = new mysqli($servername, $username, $password);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
// create a variable
$naam=$_POST['namen'];
$plaats=$_POST['plaatsen'];
$land=$_POST['landen'];
//Execute the query
mysqli_query($conn,"INSERT INTO phptoets(Namen,Plaatsen,Landen)
VALUES('$naam','$plaats','$land')");
?>
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" type="text/css" href="main.css">
<title>PHP Toets</title>
</head>
<body>
<div class="import_intel">
</div>
<form method="POST">
<div class="invulform">
<h2>Vul hier de gegevens in die naar de database moeten</h2>
<input type="text" name="naam" class="input_name" placeholder="Naam"><br>
<input type="text" name="plaats" class="input_plaats" placeholder="Plaats"><br>
<input type="text" name="land" class="input_land" placeholder="Land"><br>
<input type="submit" name="submit" class="submit_button" value="Verstuur">
</div>
</form>
<div class="overzichtform">
<h3>Data</h3>
</div>
</body>
</html>
Try this. It will help you. I've done few changes in your code.
- Add form to post the data on server
- Add database name in connection
- Add provincie field in form (because you are trying to get that in php)
- Use the same variable in query as declared at the time of connection
<?php
if (isset($_POST['submit'])) {
$servername = "localhost";
$username = "root";
$password = "";
$database = "DATABASE";
// Create connection
$conn = new mysqli($servername, $username, $password, $database);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
// create a variable
$namen=$_POST['naam'];
$plaatsen=$_POST['plaats'];
$landen=$_POST['land'];
$provincie=$_POST['provincie'];
//Execute the query
mysqli_query($conn, "INSERT INTO employees1(naam,plaats,land,provincie) VALUES('$namen','$plaatsen','$landen','$provincie')");
}
?>
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" type="text/css" href="main.css">
<title>PHP Toets</title>
</head>
<body>
<div class="import_intel">
</div>
<form method="POST" action="">
<div class="invulform">
<h2>Vul hier de gegevens in die naar de database moeten</h2>
<input type="text" name="naam" class="input_name" placeholder="Naam"><br>
<input type="text" name="plaats" class="input_plaats" placeholder="Plaats"><br>
<input type="text" name="land" class="input_land" placeholder="Land"><br>
<input type="text" name="provience" class="input_provience" placeholder="Provience"><br>
<input type="button" name="submit" class="submit_button" value="Verstuur">
</div>
</form>
<div class="overzichtform">
<h3>Data</h3>
</div>
</body>
</html>
This is my solution:
You forgot to set database name and the names of your input fields where not equal to your $_POST names.
<?php
$servername = "localhost";
$username = "root";
$password = "root";
$database = "test";
// Create connection
$conn = new mysqli($servername, $username, $password, $database);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
// create a variable
$naam=$_POST['naam'];
$plaats=$_POST['plaats'];
$land=$_POST['land'];
//Execute the query
mysqli_query($conn,"INSERT INTO phptoets(namen,plaatsen,landen)
VALUES('$naam','$plaats','$land')");
?>
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" type="text/css" href="main.css">
<title>PHP Toets</title>
</head>
<body>
<div class="import_intel">
</div>
<form method="post">
<div class="invulform">
<h2>Vul hier de gegevens in die naar de database moeten</h2>
<input type="text" name="naam" class="input_name" placeholder="Naam"><br>
<input type="text" name="plaats" class="input_plaats" placeholder="Plaats"><br>
<input type="text" name="land" class="input_land" placeholder="Land"><br>
<input type="submit" name="submit" class="submit_button" value="Verstuur">
</div>
</form>
<div class="overzichtform">
<h3>Data</h3>
</div>
</body>
</html>
<?php
// TESTS
$servername = "localhost";
$username = "root";
$password = "";
$db_name = "test";
// Create connection
$conn = new mysqli($servername, $username, $password, $db_name);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully <br>";
if(isset($_POST['submit']))
{
// create a variable
$a = (string)filter_input(INPUT_POST,'naam');
$b = (string)filter_input(INPUT_POST,'plaats');
$c = (string)filter_input(INPUT_POST,'land');
$d = (string)filter_input(INPUT_POST,'provincie');
echo("executing query <br>");
//Execute the query
if($a != null && $b != null && $c != null && $c != null)
{
$sql="INSERT INTO employees1 (naam,plaats,land,provincie) VALUES (?,?,?,?)";
echo("sql ".$sql. "<br>");
if($stmt = $conn->prepare($sql))
{
$stmt->bind_param("ssss",$a,$b,$c,$d);
$stmt->execute();
$stmt->close();
}
}
$sql = "SELECT naam, plaats, land, provincie FROM employees1";
if ($stmt = $conn->prepare($sql))
{
$stmt->execute();
$stmt->bind_result($naam,$plaats,$land,$provincie);
while ($stmt->fetch())
{
printf("naam : %s, plaats: %s, land: %s, provincie: %s <br>",$naam,$plaats,$land,$provincie);
}
$stmt->close();
}
}
?>
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" type="text/css" href="main.css">
<title>PHP Toets</title>
</head>
<body>
<div class="import_intel">
</div>
<div class="invulform">
<h2>Vul hier de gegevens in die naar de database moeten</h2>
<form class="my_form" target="_self" enctype="multipart/form-data" method="post">
<input type="text" name="naam" class="input_name" placeholder="Naam"><br>
<input type="text" name="plaats" class="input_plaats" placeholder="Plaats"><br>
<input type="text" name="land" class="input_land" placeholder="Land"><br>
<input type="text" name="provincie" class="input_land" placeholder="Provincie"><br>
<input type="submit" name="submit" class="submit_button" value="Verstuur">
</form>
</div>
<div class="overzichtform">
<h3>Data</h3>
</div>
</body>
</html>
I will just name few things that I changed in your code, not mentioning syntax errors
you dont specify db_name in your sql connection
you dont use prepared statements nor any kind of input filtering
(note : my input filtering is very basic, read more about how to
filter inputs)
to address html form you need to create one and have submit input
type inside
I'm using Cloud9 to create a website. For whatever reason, the data taken from a HTML page will not get inserted into the Database.
I have tested to see if the Database is connected and it is. I would like to be able to get the data to be inserted into the Database.
The HTML code and PHP code is:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Add Record Form
</title>
</head>
<body>
<form action="../php/keithphp/address_submit.php" method="post">
<p>
<label for="address_street">Street</label>
<input type="text" name="address_street" id="address_street">
</p>
<p>
<label for="address_street2">Street 2</label>
<input type="text" name="address_street2" id="address_street2">
</p>
<p>
<label for="address_city">City</label>
<input type="text" name="address_city" id="address_city">
</p>
<p>
<label for="address_county">County</label>
<input type="text" name="address_county" id="address_county">
</p>
<p>
<label for="eircode">Eircode</label>
<input type="text" name="eircode" id="eircode">
</p>
<!-- <p>
<label for="address_geo_latitude">Latitude</label>
<input type="float" name="address_geo_latitude" id="address_geo_latitude">
</p>
<p>
<label for="address_geo_longtitude">Longitude</label>
<input type="float" name="address_geo_longtitude" id="address_geo_longtitude">
</p> -->
<input type="submit" value="Submit">
</form>
</body>
</html>
*****************
<?php
$servername = getenv('IP');
$username = getenv('C9_USER');
$password = "";
$database = "c9";
$dbport = 3306;
// Create connection
$db = new mysqli($servername, $username, $password, $database, $dbport);
// Check connection
if ($db->connect_error) {
die("Connection failed: " . $db->connect_error);
}
/*$address_id = $_POST['address_id'];*/
$address_street = $_POST['address_street'];
$address_street2 = $_POST['address_street2'];
$address_city = $_POST['address_city'];
$address_county = $_POST['address_county'];
$address_eircode = $_POST['address_eircode'];
/*$address_geo_latitude = $_POST['address_geo_latitude'];
$address_geo_longtitude = $_POST['address_geo_longtitude'];*/
$sql = "INSERT INTO Address(address_id, address_street, address_street2, address_city, address_county, address_eircode, address_geo_latitude, address_geo_longtitude) VALUES ('$address_id', '$address_street', '$address_street2', '$address_city', '$address_county', '$address_eircode', '$address_geo_latitude', '$address_geo_longtitude')";
$success = $db->query($sql);
if (!$sucess){
die("Could not enter data: ".$db->error);
}
echo "Thank you. Address submitted!"
/*my$db->close();*/
?>
And the result after typing in test data is (no error message after text), I get;
Could not enter data:
I am creating a login page using PHP and Mysqli database, I wrote the query, however mysqli_num_rows() give me an error when value is given. PS: I did this in Object Oriented Format
<?php
$host = "localhost";
$user = "root";
$pass = "";
$db = "customerdb";
$connection = #new mysqli($host, $user, $pass, $db);
if ($connection->connect_errno) {
die("Connection failed!");
exit();
}
if (isset($_POST['submit'])) {
$username = $connection->real_escape_string($_POST['username']);
$password = $connection->real_escape_string($_POST['password']);
$script = "SELECT * FROM customer_management WHERE
customer_management.Username='".$username."'AND WHERE customer_management_Password='".$password."'";
$result = $connection->query($script, MYSQLI_USE_RESULT);
$check = $result->num_rows;
if ($check >= 1){
echo "Welcome to this website";
}
else{
echo"Sorry but your input is incorrect!";
}
}
?>
<!DCOTYPE html>
<html lang='en'>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Login Page</title>
</head>
<body>
<h1>Login Page</h1>
<form method="post" action="login.php">
<input type="text" placeholder = 'username' name="username" /><br /><br />
<input type="password" placeholder="password" name="password" /><br /><br />
<input type="submit" name="submit" value="Log In" />
</form>
</body>
</html>
Change customer_management_Password to customer_management.Password in your query.
Trying to simply register, although file is named as Login.html/.php
My HTML form in Login.html :
<!DOCTYPE html>
<html>
<head>
<title>Register/ Login</title>
<link rel="stylesheet" type="text/css" href="Assets/bootstrap.css">
<script src="Assets/jquery.min.js"></script>
<script src="Assets/bootstrap.min.js"></script>
</head>
<body>
<form action="Login.php" method="post">
<fieldset>
<legend>Register:</legend>
Username : <input type="text" name="Username"> <br>
Password : <input type="password" name="Password"> <br>
<input type="submit"><br>
</fieldset>
</form>
</body>
</html>
Have set up the MySQL side of the code and run it as well, it works fine.
The PHP file, Login.php :
<?php
$userErr = $passErr = "";
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "testdb";
$conn = mysqli_connect($servername, $username, $password, $dbname) or die("Connection failed");
$Username = $_POST['Username'];
$Password = $_POST['Password'];
echo("Reached 1. <br>");
$stmt = "INSERT INTO Login (Username, Password) VALUES ('$Username', '$Password')";
$result = mysqli_query($conn, $stmt);
if($result) {
echo("Registered Successfully!");
}
mysqli_close($conn);
?>
When I enter the details and submit, the code for Login.php is displayed, with the url being: (file:///C:/xampp/htdocs/Login.php)
Also, Login.html was run on localhost, i.e., url being:
(http://localhost/Login.html)
I can guess you are browsing your Login.html with
file:///C:/xampp/htdocs/Login.html
But you have to use like this
http://localhost/Login.html