Input Box is not appearing? - php

Question

I coded adding comments function to RSS articles
In the twists and turns, it is in php coding to show and enter comments. However, the input box does not appear.
Here is the php code:
$url = "./comments/" . $q.".txt";
//댓글 파일에서 컨텐츠 문자열 가져오기
$txtcomment = file_get_contents($url,true);
//댓글 나열
echo "<ol>";
if ($q !== "" ) {
$comm = $txtcomment;
$arr = [];
$arr = explode("--",$comm);
for ($i=4;$i<count($arr);$i++) {
echo "<li>".$arr[$i]."</li>";
}
} else {
echo "해당기사가 없습니다.";
}
echo "</ol>";
//중첩검색&결과내 검색 폼 만들기
echo "<br><form class=\"category B\" >
Comment: <input type=\"text\" name=\"comment1\" id=\"comment1\" onkeyup=\"inputComment()\" >
</form>";
Why?
Thank for your concern.

Answer 1

Since I use RSS, I presume that php does not properly pass the attributes of the input tag in between. I started to change the old coding.
In other words, I decided that the Show Comments and the input comments were different from the beginning.
getrss.php code as below at first.
echo " <option id=".$i." onclick=\"showComment".$i."(this.value)\" value=".$item_link4."> Show Comments </option>";
but, I added the input code as like
echo " <option id=".$i." onclick=\"showComment".$i."(this.value)\" value=".$item_link4."> Show Comments </option>";
echo "댓글: <input type='text' name='inputComment' size='200' id='input".$i."' onclick='inputComment".$i."(this.value)' >
<input type='text' name='txtfile' id='txt".$i."' value=".$item_link4." hidden>
<div id='comment".$i."'><b>information will be listed here.</b></div>";
And, I make input box as a below picture.
In the end, I am trying to solve the problem in a roundabout way.
But, I still wonder why ajax's ajax is not working!!
After I input my comment, at once I see that.
further coding makes a below picture.
Thanks a lot for your sharing.