MySQL randomly selected questions - php

I can't find what I need. I trying to create at quizzer that takes questions from the database. Currently, it takes all the questions in the database and what I need it to take it randomly 10 questions. I am just starting to learn how to code.
Here are my getting questions code with answers:
<?php
//Set question number
$number = (int) $_GET['n'];
/*
* Get total questions
*/
$query = "SELECT * FROM `klausimai`";
//Get result
$results = $mysqli->query($query) or die($mysqli->error.__LINE__);
$total = $results->num_rows;
/*
* Get Question
*/
$query = "SELECT * FROM `klausimai`
WHERE question_number = $number";
//Get result
$result = $mysqli->query($query) or die($mysqli->error.__LINE__);
$question = $result->fetch_assoc();
/*
* Get Choices
*/
$query = "SELECT * FROM `atsakymai`
WHERE question_number = $number";
//Get results
$choices = $mysqli->query($query) or die($mysqli->error.__LINE__);
?>

As mentioned above, limit the klausimai query results to 10 by using the SQL LIMIT statement ($query = "SELECT * FROM klausimai LIMIT 10";):
<?php
//Set question number
$number = (int) $_GET['n'];
/*
* Get total questions
*/
$query = "SELECT * FROM `klausimai` LIMIT 10";
//Get result
$results = $mysqli->query($query) or die($mysqli->error.__LINE__);
$total = $results->num_rows;
/*
* Get Question
*/
$query = "SELECT * FROM `klausimai`
WHERE question_number = $number";
//Get result
$result = $mysqli->query($query) or die($mysqli->error.__LINE__);
$question = $result->fetch_assoc();
/*
* Get Choices
*/
$query = "SELECT * FROM `atsakymai`
WHERE question_number = $number";
//Get results
$choices = $mysqli->query($query) or die($mysqli->error.__LINE__);
?>

Your Code good to go, but to print 10 random question fetched directly from your mysql database, Execute the following query :
$query = SELECT * FROM `klausimai`
ORDER BY RAND()
LIMIT 10;
while(row=mysql_fetch_array($query) {
echo $row['question_feild'];
//Replace 'question_feild' it with your question_body column of your table
//assuming you have 2 choices for a particular question
echo $row['choice1']; // Same replace it with your choice/answer columns
echo $row['choice2']; // Same replace it with your choice/answer columns
}

Try this :
/*
* Get Questions
*/
$query = "SELECT * FROM `klausimai` ORDER BY RAND() LIMIT 10";
$result = mysqli_query($conn, $query);
while($row = mysqli_fetch_assoc($result)){
echo "Question number " . $row["question_number"] . "<br/>";
echo "Choices of question are:<br/>";
/*
* Get Choices
*/
$query = "SELECT * FROM `atsakymai` WHERE `question_number` = " . $row["question_number"];
$result = mysqli_query($conn, $query);
$i = 1;
while($row2 = mysqli_fetch_assoc($result)){
echo $i.") ".$row2["choice_text"]."<br/>";
$i++;
}
}

Related

How to sum column in database using php

i'm trying to sum a column name "total". and i want to display the total sorting by id. if user A login he can see total booking in his account.
I keep get the error:
"Notice: Array to string conversion in Array."
can someone help me? I want to echo the total in input form.
this is my php code:
<?php
include ('connect.php');
$sql = "SELECT * FROM penjaga WHERE p_username = '".$_SESSION['username']."'";
$result = mysqli_query($conn,$sql);
$row = mysqli_fetch_assoc($result);
$id = $row['p_id'];
$sql2 = "SELECT SUM(total) as total FROM sitter_kucing WHERE sitter_fk = '$id'";
$row2 = mysql_fetch_array($sql);
$sum = $row['total'];
?>
Try this,
$sql2 = "SELECT SUM(total) as total FROM sitter_kucing WHERE sitter_fk = '$id'";
$result2 = mysql_query($sql2) or die(mysql_error());
$row2 = mysql_fetch_array($result2) or die(mysql_error());
$sum = $row['total'];
i got it! thanks this is my code
this is the code:
<?php
include ('connect.php');
$sql8 = "SELECT * FROM penjaga WHERE p_username = '".$_SESSION['username']."'";
$result8 = mysqli_query($conn,$sql8);
$row8 = mysqli_fetch_assoc($result8);
$id = $row8['p_id'];
$sql9 = "SELECT SUM(total) as total FROM sitter_kucing WHERE sitter_fk = '$id'";
$result9 = mysqli_query($conn,$sql9);
$row9 = mysqli_fetch_array($result9);
$sum = $row9['total'];
?>

Getting exact value from fetched array from MySql

Not a duplicate of Select specific value from a fetched array
I have a MySql database as:
Here's my query:
$sql = "SELECT * FROM data ORDER BY Score DESC";
I want it to be a leaderboard which people can update their scores so I can't use
$sql = "SELECT * FROM data ORDER BY Score DESC WHERE ID = 1";
I want to get Username of the second row in my query.So I wrote:
<?php
include "l_connection.php";
$sql = "SELECT * FROM data ORDER BY Score";
$result = mysqli_query($conn, $sql);
if($result->num_rows>0){
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)){
}
echo "Result = '".$row[1]['Username']."''";
}
?>
But it returns Result = '' like there's nothing in the array.
But if I write
if($result->num_rows>0){
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)){
echo "Name = '".$row['Username']."''";
}
}
It will return : Parham, Mojtaba, Gomnam, Masoud,
So what am I doing wrong in the first snippet?
You can not access $row outside of while loop.
So store result in one new array, and then you can access that new array outside the while loop:
$newResult = array();
if($result->num_rows>0){
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)){
$newResult[] = $row;
}
}
echo "Result = '".$newResult[1]['Username']."''"; // thus you can access second name from array
Because you write where condition after ORDER by at
$sql = "SELECT * FROM data ORDER BY Score DESC WHERE ID = 1";
The sequence of query is
SELECT * FROM data // select first
WHERE ID = 1
ORDER BY Score DESC// Order by at last
Check http://dev.mysql.com/doc/refman/5.7/en/select.html
And for second case you need to fetch Username inside while loop and use $row['Username'] instead $row[1]['Username']
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)){
echo "Result = '".$row['Username']."''";// write inside while loop
}
You can assign row value to any array and use that array.
<?php
include "l_connection.php";
$sql = "SELECT * FROM data ORDER BY Score";
$result = mysqli_query($conn, $sql);
if($result->num_rows>0){
$rows = array();
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)){
$rows[] = $row;
}
echo "Result = '".$rows[1]['Username']."'";
}
?>
Or if you want only second highest score from column you can user limit as
$sql = "SELECT * FROM data ORDER BY Score limit 1,1";

Random row selection using MySQL returns NULL

I am trying to get a random row from MySQL table but all three attemps:
$query = "SELECT cid FROM table LIMIT 1 OFFSET ".rand(1,$num_rows);
$query = "SELECT cid FROM table OFFSET RANDOM() * (SELECT COUNT(*) FROM table) LIMIT 1";
$query = "SELECT * FROM table ORDER BY RAND() LIMIT 1";
give a NULL result in mysql_query($query).
Higher up my PHP code I obtain a row from the same table OK by specifying WHERE, so I don't understand why I can't retrieve a random one.
Here is the code snippet:
$query = "SELECT uid,clu FROM uable WHERE un = '$un'";
$result = mysql_query($query) or die(sqlerror(__LINE__,mysql_errno(),mysql_error()));
$resultid = mysql_fetch_assoc($result);
$uid = $resultid['uid'];
file_put_contents('debugging.txt',__LINE__.' - $uid = '.var_export($uid,true).PHP_EOL,FILE_APPEND);
$query = "SELECT * FROM table WHERE uid = $uid AND cn = '$cn'";
$result = mysql_query($query) or die(sqlerror(__LINE__,mysql_errno(),mysql_error()));
$cr = mysql_fetch_assoc($result);
$cid= $cr['cid'];
file_put_contents('debugging.txt',__LINE__.' - $cid= '.var_export($cid,true).PHP_EOL,FILE_APPEND);
$query = "SELECT * FROM fable WHERE cid= '$cid'";
$result = mysql_query($query) or die(sqlerror(__LINE__,mysql_errno(),mysql_error()));
file_put_contents('debugging.txt',__LINE__.' - $result = '.var_export($result,true).PHP_EOL,FILE_APPEND);
$fr = mysql_fetch_assoc($result);
file_put_contents('debugging.txt',__LINE__.' - $fr = '.var_export($fr,true).PHP_EOL,FILE_APPEND);
echo '<form action="'.$_SERVER['PHP_SELF'].’" method="post">';
if (!$fr) {
$o= $cn;
while ($o= $cn) {
// $ac = mysql_query("SELECT * FROM table") or die(sqlerror(__LINE__,mysql_errno(),mysql_error()));
// $num_rows = mysql_num_rows($ac);
//file_put_contents('debugging.txt',__LINE__.' - $num_rows = '.$num_rows.PHP_EOL,FILE_APPEND);
// --$num_rows;
// $query = "SELECT cid FROM table LIMIT 1 OFFSET ".rand(1,$num_rows);
$query = "SELECT cid FROM table OFFSET RANDOM() * (SELECT COUNT(*) FROM table) LIMIT 1";
// $query = "SELECT * FROM table ORDER BY RAND() LIMIT 1";
$resultid = mysql_query($query) or die(sqlerror(__LINE__,mysql_errno(),mysql_error()));
$opr = mysql_fetch_assoc($resultid);
$o= $opr['cn'];
}
file_put_contents('debugging.txt',__LINE__.' - $query = '.$query.PHP_EOL,FILE_APPEND);
file_put_contents('debugging.txt',__LINE__.' - $resultid = '.var_export($resultid,true).PHP_EOL,FILE_APPEND);
file_put_contents('debugging.txt',__LINE__.' - $op[\'cid\'] = '.$op['cid'].PHP_EOL,FILE_APPEND);
$query = "SELECT * FROM table WHERE cid= ".$op;
$result = mysql_query($query) or die(sqlerror(__LINE__,mysql_errno(),mysql_error()));
$opr = mysql_fetch_assoc($opr);
$o= $opr['cn'];
$od= $opr['description'];
echo '<p>'.$op;
if ($od<> '') {
echo ','.$odesc;
}
echo '</p>';
echo '<input type="submit" name="continue" id="continue" value="Continue">';
} else {
echo '<p>'.$fr['p'].'</p>';
echo '<input type="submit" name="continue" id="continue" value="Continue">';
}
echo '</form>';
The resulting debugging.txt:
24 - $uid = '4'
29 - $cid = '21'
32 - $result = NULL
34 - $fr = false
These queries look OK, but I think you're starting at the wrong place. When you're uncertain how to frame something in SQL, open up a SQL client like SequelPro or Navicat and try writing a few queries by hand until you get the result you want. (Also this gives you a chance to double-check the contents of relevant tables and ensure the expected data are there.) Then you can go back into the PHP with full confidence that the SQL code is correct, so if there's a problem it must be with the PHP (either the variables you inject into a Mysql statement, or the way you call that statement).

Creating an array of IDs from a while loop

Im trying to generate an array but not sure how to go about it.
I'm currently getting my data like so:
$query = mysql_query("SELECT * FROM users WHERE userEmail LIKE 'test#test.com'");
$row = mysql_fetch_array($query);
$query1 = mysql_query("SELECT * FROM categories");
while($row1 = mysql_fetch_array($query1)){
$query2 = mysql_query("SELECT * FROM usersettings WHERE userId = ".$row['userId']." AND usersettingCategory".$row1['categoryId']." LIKE 'y'");
$isyes = mysql_num_rows($query2);
if($isyes > 0){
$cat1 = mysql_query("SELECT * FROM shops WHERE shopstateId = 1 AND (categoryId1 = ".$row1['categoryId']." OR categoryId2 = ".$row1['categoryId']." OR categoryId3 = ".$row1['categoryId'].")");
$cat1match = mysql_num_rows($cat1);
if($cat1match > 0){
while($cat1shop = mysql_fetch_array($cat1)){
$cat1msg = mysql_query("SELECT * FROM messages WHERE shopId = ".$cat1shop['shopId']." and messagestateId = 1");
while($cat1msgrow = mysql_fetch_array($cat1msg)){
echo $cat1msgrow['messageContent']." - ".$cat1msgrow['messageCode'];
$cat1img = mysql_query("SELECT shopimagePath FROM shopimages WHERE shopimageId = ".$cat1shop['shopimageId']);
$imgpath = mysql_fetch_array($cat1img);
echo " - ".$imgpath['shopimagePath']."<br/>";
}
}
}
}
}
But this can cause duplicates when a user has all 3 of a shops categories picked in their preferences. I am trying to find a way to just pull the message ID out instead of the whole thing and put it into an array giving me, for example:
1,3,5,7,1,3,5,2,4,7,8
Then I can just run a separate query to say get me all messages where the ID is in the array, but i am unsure of the most constructive way to build such an array and examples of array from a while loop I have seen do not seem to be what I am looking for.
Is there anyone out there that can push me in the right direction?
Can't help with this code. But if you want an array from a query without duplicate result, you can use " select DISTINCT (id) " in your query or for more simple solution :
$id_arr = array();
$sql = mysql_query("select id from id_table");
while ($id_result = mysql_fetch_array($sql) {
$id = $id_result['id'];
if (!in_array($id, $id_arr)) {
$id_arr[] = $id;
}
}
I have found a much easier way to create the required result. I think at 6am after a hard night coding my brain was fried and I was making things a lot more complicated than I needed to. A simple solution to my issue is as follows:
$query = mysql_query("SELECT * FROM users WHERE userEmail LIKE 'test2#test2.com'");
$row = mysql_fetch_array($query);
$categories = "(";
$query1 = mysql_query("SELECT * FROM categories");
while($row1 = mysql_fetch_array($query1)){
$query2 = mysql_query("SELECT usersettingCategory".$row1['categoryId']." FROM usersettings WHERE userId = ".$row['userId']);
$row2 = mysql_fetch_array($query2);
if($row2['usersettingCategory'.$row1['categoryId']] == y){
$categories .= $row1['categoryId'].",";
}
}
$categories = substr_replace($categories ,")",-1);
echo $categories."<br />";
$query3 = mysql_query("SELECT * FROM shops,messages WHERE shops.shopId = messages.shopId AND messages.messagestateId = 1 AND (shops.categoryId1 IN $categories OR shops.categoryId2 IN $categories OR shops.categoryId3 IN $categories)");
while($row3 = mysql_fetch_array($query3)){
$query4 = mysql_query("SELECT shopimagePath FROM shopimages WHERE shopimageId = ".$row3['shopimageId']);
$row4 = mysql_fetch_array($query4);
echo $row3['messageContent']." - ".$row3['messageCode']." - ".$row4['shopimagePath']."<br />";
}

MySQL query within another query's while loop in PHP

I have the following code:
$query = mysql_query("SELECT * FROM activity ORDER BY activity_time DESC LIMIT 50");
while($result = mysql_fetch_array($query)) {
extract($result);
if ($activity_type == "discussion") {
$query = mysql_query("SELECT * FROM discussions WHERE discussion_uuid = '$activity_ref'");
while($result = mysql_fetch_array($query)) {
extract($result);
echo $discussion_user . " said:<br>" . $discussion_text . "<br>";
}
} elseif ($activity_type == "file") {
}
}
But it just returns the last row. My goal is to have a chronological list of "activities" each displayed slightly differently depending on their type.
Your using $query and $result twice so the second loop is overwriting the result of the first and stopping...
$query = mysql_query("SELECT * FROM activity ORDER BY activity_time DESC LIMIT 50");
and
$query = mysql_query("SELECT * FROM discussions WHERE discussion_uuid = '$activity_ref'");
same with $results var...
I would suggest you change to $query and $query2 but best to use something like
$activies = mysql_query("SELECT * FROM activity ORDER BY activity_time DESC LIMIT 50");
while($activity = mysql_fetch_array($activies)) {
and
$discussions = mysql_query("SELECT * FROM discussions WHERE discussion_uuid = '$activity_ref'");
while($discussion = mysql_fetch_array($discussions)) {
I would also avoid using extract - as you might be overwriting vars your not expecting to...
You have to create another connection to the database so that you can run them at the same time.
OR
You can load the results of the first one into an array, and then just loop through the array.

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