how to get Multiple values in views page - php

Actually, cities are stored multiple values(with ids)
Example
(3,5)chennai,bangalore in one table.
How to get city names with the separated comma in views page.
controller code
$data['jobCityName'] =explode(',',$viewData['jobCity']);
for($i= 0; $i < sizeof($data['jobCityName']); $i++) {
$jobMultipleCity= $data['jobCityName'][$i];
$data['jobCityNames']=$this->hrm_model->getCitybyId($jobMultipleCity);
$data['jobCity']=$data['jobCityNames']['cityName'];
views Page Code
<?php echo $jobcity; ?>
present printed only one city name.
how to display cities in views page like(hyderabad,chennai,bangalore)

You can use foreach for iteration. Also you are overwriting previous value at $data['jobCity']=$data['jobCityNames']['cityName'];
like
$data['jobCityName'] =explode(',',$viewData['jobCity']);
foreach($data['jobCityName'] as $cityid) {
$data['jobCityNames']=$this->hrm_model->getCitybyId($cityid);
$data['jobCity'].=$data['jobCityNames']['cityName'];
}
Also it's recommended to use count instead of sizeof

Related

Can you put multiple elements in an html <a> tag?

Is there any way to create a new a href that remembers all the submitted data earlier. I don't know how to say it properly so I will describe in the code:
The first button
Click me
After the user clicks it, he is redirected to the same page but with the new button :
Click me
And so on :
Click me
How do i create the n variable to be added and increased after the button is pressed ?
( I have a table displayed from a database by using the while command with mysqli_fetch_array($database); )
The table is created like (trivial ) :
$retrieve_items = mysql_query("SELECT * FROM items WHERE id > 0");
$col = 0;
echo '<table width=100% border= 1><tr>';
while($row = mysql_fetch_array( $retrieve_items )) {
$col ++;
echo '<td>'.$row['name_item'].'</td>';
if ($col % 5 == 0 )
{
echo '</tr><tr>';
}
}
echo '</tr></table>';
I recommend not to try managing numbered variable names. If there is no important reason to do so, it will make your logic unnecessarily complicated.
PHP understands array parameters in e.g. $_GET. They are passed from HTML with empty braces appended to the parameter name.
This is a little demo to illustrate this alternative approach:
<?php
// get the passed array or generate a new one
$n = isset($_GET['n']) ? (array) $_GET['n'] : [];
//ppend 2 random numbers
$n[] = rand(1,100);
$n[] = rand(1,100);
//output the link with GET parameters in query
?>
the link
<!-- or let PHP's built-in generate a propper query --><br>
the link
Be aware, that the second link generated by http_build_query contains indexes of the array, which are commonly based on 0.
in php, to access the current query String, you can use
$_SERVER['QUERY_STRING']
so you could so something like
Click me
or you could replace your previous value in the query string

Should I create another table column or is there another way I can go about doing this?

I'm having an issue trying to figure out how to solve this problem.
I have a database with a Table that holds job information. There's a column called "Payments" and the values % per payment term are split up here like so: http://i.imgur.com/Y2Lb48e.png
So at the bottom the values will read 40%, 40%, 20%.
In the form, these values are displayed exactly the same as in the database, 40/40/20.
I was tasked with creating 4 option boxes instead with values in each ranging from 10% to 100%. Here's what the code looks like.
<label for='payment'>Payment Terms</label>
<?php
// Create 4 % boxes that add up to %100 for Payment Terms
// Must validate and add up to %100
$selects = 4;
if (isset($data2['payment'])) {
$percentages = explode("/", $data2['payment']);
// Make sure that the array is long enough by adding zeroes to the end
while (count($percentages) < $selects) $percentages[] = 0;
}
else {
$percentages = array_fill(0, $selects, 0);
}
$options = range(10, 100, 10);
for ($i = 0; $i < $selects; ++$i) { ?>
<ul style="list-style-type: none;"><li><select id="paymentSelect">
<option></option>
<?php foreach ($options as $o) { ?>
<option value="<?php echo $i; ?>"
<?php if ($o == $percentages[$i]) echo ' selected="selected"'; ?>>
<?php echo $o; ?>
</option>
<?php } ?>
</select></li></ul>
<?php } ?>
This is what the form looks like now: http://i.imgur.com/2OvDtsn.png
The blue date boxes is what I want to create. Will I have to make a new column in my table? How will I link each percentage to each date since the percentages are already in the table?
You could make a new table in your data base "Payments" and have a foreign key to tie it back to the original table, your payment column and your date column. Then you can have as many payment percents and Dates you would ever want.
I might be tempted to future proof this for 10 options or 20 options or whatever to save always changing the columns in the table. How about you have 4 rows to show your payment terms - pairs for each date and %. If you have multiple possibilities - i.e. several clients with different payment terms then your table should have a client_id. This way you can have some clients with 2 payments, others with 50 - simply by adding rows with fields (client_id, %, date).
Validation is the same and the table much simpler. To retrieve the payment data you are fetching multiple rows that make table building from PHP fairly straightforward too.
Best
Nick

Using For loop to get values of multiple elements in PHP

The title is so general mainly because I don't know what should be the appropriate title for it. Let me just explain the situation:
Say that I have two textboxes named LastName0 and FirstName0 and a button called addMore. When I click addMore, another two textboxes will be created through JavaScript. These textboxes will be named LastName1 and FirstName1. When I click the addMore button again, another two textboxes button will be created and named LastName2 and FirstName2 respectively. This will go on as long as the addMore button is clicked. Also, a button named deleteThis will be created alongside the textboxes. This simply deletes the created textboxes when clicked.
I also initialized a variable called counter. Every time the addMore button is clicked, the counter goes up by 1, and whenever the deleteThis button is clicked, the counter decreases by 1. The value of the counter is stored in a hidden input type.
When the user submits the form, I get the value of the counter and create a For loop to get all the values of the textboxes in the form. Here is the sample code:
//Suppose that the user decides to add 2 more textboxes. Now we have the following:
// LastName0 FirstName0
// LastName1 FirstName1
// LastName2 FirstName2
$ctr = $_POST['counter']; //the counter == 3
for ($x = 0; $x < $ctr; $ctr++)
{
$lastname = $_POST["LastName$x"];
$firstname = $_POST["FirstName$x"];
//This will get the values of LastName0,1,2 and FirstName0,1,2
//code to save to database…
}
On the code above, if the value of counter is equal to 3, then the values of textboxes LastName0,1,2 and FirstName0,1,2 will be saved. Now here is the problem: If the user decided to delete LastName1 and FirstName1, the For loop will not be able to iterate properly:
$ctr = $_POST['counter']; //the counter == 2
for ($x = 0; $x < $ctr; $ctr++)
{
//Only LastName0 and FirstName0 will be saved.
$lastname = $_POST["LastName$x"];
$firstname = $_POST["FirstName$x"];
//code to save to database…
}
Someone told me to use the "push and pop" concept to solve this problem, but I am not really sure on how to apply it here. So if anyone can tell me how to apply it, it'll be grand.
Add your input text boxes with name as array ie, <input type="text" name="FirstName[]" />
In php you can fetch them as a array. ie,
foreach($_POST["FirstName"] as $k=>$val){
echo $val; // give you first name
echo $_POST["LastName"][$k]; // will give you last ame
}
In this case even if one set of field is removed in HTML will not affect the php code.
One solution would be to use the isset function like this:
$ctr = $_POST['counter'];
for ($x = 0; $x < $ctr; $ctr++)
{
isset($_POST["LastName$x"])?$lastname = $_POST["LastName$x"]:;
isset($_POST["FirstName$x"])?$firstname = $_POST["FirstName$x"]:;
}
If it is possible, instead of using LastNameN and FirstNameN names try using LastName[N] and FirstName[N], this way the result is an array and you can iterate through it with a foreach, meaning you will not need the counter and the index of the value will not be important:
foreach ($_POST["LastName"] as $i=>$lastname) {
if (!isset($_POST["FirstName"][$i])) {
// This should only happen if someone messes with the client side before posting
throw new Exception("Last name input does not have a related First name input");
}
$firstname = $_POST["FirstName"][$i];
}
If not, then you may have to use your $counter in a different way
$current = 0;
while ($counter) { // Stop only when i found all
if (isset($_POST["LastName$current"]) {
$counter--; // Found one
$lastname = $_POST["LastName$current"];
$firstname = $_POST["FirstName$current"];
}
$current++;
}
A better way to solve this would be to use arrays for Firstname and Lastname. Instead of calling them Lastname0 and Firstname0, then Lastname1 and Firstname1, call them all Lastname[] and Firstname[]. Give them ID's of Lastname0 and Firstname0 and so on for the delete function, but keep the names as arrays.
When the form is submitted use the following:
foreach($_POST['Lastname'] as $i => $lastname) {
$firstname = $_POST['Firstname'][$i]
//... code to save into the database here
}
Be warned though that in IE if you have an empty field it will not be submitted, so if Lastname0 has a value, but Firstname0 does not, then $_POST['Firstname'][0] will in fact contain the value of Firstname1 (assuming it has a value in it). To get around this you can use javascript to check if a field is empty when submitting the form, and if so put the word EMPTY in it.
Do not use counter if not required
A much easier way is to add array name when admore clicked.
Give a name like first_name[] in textbox
if you create form like that you can use foreach through $_POST['first_name']
try var_dump($_POST) in you php code to see how things goes on.
Inside your for loop, maybe you could try...
if ((isset($_POST["LastName$x"])) && (isset($_POST["FirstName$x"]))){
$lastname = $_POST["LastName$x"];
$firstname = $_POST["FirstName$x"];
//code to save to database…
}
This will check if the variables exists before you try to do anything with them.

checkbox's stay checked after pagination in php

Hello i want any checkbox i am gonna check, to stay checked after pagination.
here is the code:
foreach($test as $string){
$queryForArray = "SELECT p_fname,p_id FROM personnel WHERE p_id = " .$string["p_id"]. " ;" ;
$resultForArray = mysql_query($queryForArray, $con);
$rowfForArray = mysql_fetch_array($resultForArray);
?>
<td id="<?php echo $rowfForArray["p_id"]?>" onclick="setStyles(this.id)" ><?php echo $rowfForArray["p_fname"]?></td>
<td><input id="<?php echo $rowfForArray["p_id"]?>" class="remember_cb" type="checkbox" name="how_hear[]" value="<?php echo $rowfForArray["p_fname"]?>"
<?php foreach($_POST['how_hear'] as $_SESSION){echo (( $rowfForArray["p_fname"] == $_SESSION) ? ('checked="checked"') : ('')); } ?>/></td>
</tr>
<tr>
I am geting the data from a search result i have in the same page , and then i have each result with a checkbox , so that i can check the "persons" i need for $_Session use.
The only think i want is the checkbox's to stay checked after pagination and before i submit the form!(if needed i can post the pagination code, but he is 100% correct)
In the checkbox tag use the ternary operation, without that foreach inside him:
<input [...] value="<?php echo $rowfForArray["p_fname"]?>" <?php $rowfForArray["valueToCompareIfTrue"] ? "checked='checked'" : ''; ?> />
because the input already is inside of 'for' loop, then each time of the loop will create a new checkbox wich will verify if need to being check or not.
I hope I have helped you.
A few ways to tackle this:
(Straight up PHP): Each page needs to be a seperate form then, and your "next" button/link needs to submit the form everytime they click next. The submit data should then get pushed to your $_SESSION var. The data can then be extracted and used to repopulate the form if they navigate backwards as well. Just takes some clever usage of setting the URL with the proper $_GET variables for the form.
(HTML5): This will rely more on JavaScript, but basically you get rid of pagination and then just break the entire data set into div chunks which you can hide/reveal with JavaScript+CSS or use a library like JQuery.
(AJAX): Add event listeners to the checkboxes so that when a button is checked an asynchronous call is made back to a PHP script and the $_SESSION variable is updated accordingly. Again, this one depends on how comfortable you are with JavaScript.
Just keep in mind that PHP = ServerSide & JavaScript = ClientSide. While you can hack some PHP together to handle "clientside" stuff, its usually ugly and convoluted...
I did it without touching the database...
The checkbox fields are a php collection "cbgroup[]".
I then made a hidden text box with all the values which equal the primary keys of the selectable items mirroring the checkboxes. This way, I can iterate through the fake checkboxes on the current page and uncheck the checkboxes by ID that exist on the current page only. If the user does a search of items and the table changes, the selectable items remain! (until they destroy the session)
I POST the pagination instead of GET.
After the user selects their items, the page is POSTED and I read in the hidden text field for all the checkbox IDs that exist on that current page. Because PhP only tells you which ones are checked from the actual checkboxes, I clear only the ones from the session array that exist on the POSTED page from this text box value. So, if the user selected items ID 2, 4, 5 previously, but the current page has IDs 7,19, and 22, only 7, 19, and 22 are cleared from the SESSION array.
I then repopulate the array with any previously checked items 7, 19, or 22 (if checked) and append it to the SESSION array along with 2, 4, and 5 (if checked)
After they page through all the items and made their final selection, I then post their final selections to the database. This way, they can venture off to other pages, perhaps even adding an item to the dB, return to the item selection page and all their selections are still intact! Without writing to the database in some temp table every page iteration!
First, go through all the checkboxes and clear the array of these values
This will only clear the checkboxes from the current page, not any previously checked items from any other page.
if (array_key_exists('currentids', $_POST)) {
$currentids = $_POST['currentids'];
if (isset($_SESSION['materials']) ) {
if ($_SESSION['materials'] != "") {
$text = $_SESSION['materials'];
$delimiter=',';
$itemList = explode($delimiter, $text);
$removeItems = explode($delimiter, $currentids);
foreach ($removeItems as $key => $del_val) {
//echo "<br>del_val: ".$del_val." - key: ".$key."<br>";
// Rip through all possibilities of Item IDs from the current page
if(($key = array_search($del_val, $itemList)) !== false) {
unset($itemList[$key]);
//echo "<br>removed ".$del_val;
}
// If you know you only have one line to remove, you can decomment the next line, to stop looping
//break;
}
// Leaves the previous paged screen's selections intact
$newSessionItems = implode(",", $itemList);
$_SESSION['materials'] = $newSessionItems;
}
}
}
Now that we have the previous screens' checked values and have cleared the current checkboxes from the SESSION array, let's now write in what the user selected, because they could have UNselected something, or all.
Check which checkboxes were checked
if (array_key_exists('cbgroup', $_POST)) {
if(sizeof($_POST['cbgroup'])) {
$materials = $_POST['cbgroup'];
$N = count($materials);
for($i=0; $i < $N; $i++)
{
$sessionval = ",".$materials[$i];
$_SESSION['materials'] = $_SESSION['materials'].$sessionval;
}
} //end size of
} // key exists
Now we have all the items that could possibly be checked, but there may be duplicates because the user may have paged back and forth
This reads the entire collection of IDs and removes duplicates, if there are any.
if (isset($_SESSION['materials']) ) {
if ($_SESSION['materials'] != "") {
$text = $_SESSION['materials'];
$delimiter=',';
$itemList = explode($delimiter, $text);
$filtered = array();
foreach ($itemList as $key => $value){
if(in_array($value, $filtered)){
continue;
}
array_push($filtered, $value);
}
$uniqueitemschecked = count($filtered);
$_SESSION['materials'] = null;
for($i=0; $i < $uniqueitemschecked; $i++) {
$_SESSION['materials'] = $_SESSION['materials'].",".$filtered[$i];
}
}
}
$_SESSION['materials'] is a collection of all the checkboxes that the user selected (on every paged screen) and contains the primary_key values from the database table. Now all you need to do is rip through the SESSION collection and read\write to the materials table (or whatever) and select/update by primary_key
Typical form...
<form name="materials_form" method="post" action="thispage.php">
Need this somewhere: tracks the current page, and so when you post, it goes to the right page back or forth
<input id="_page" name="page" value="<?php echo $page ?> ">
if ($page < $counter - 1)
$pagination.= " next »";
else
$pagination.= "<span class=\"disabled\"> next »</span>";
$pagination.= "</div>\n";
Read from your database and populate your table
When you build the form, use something like this to apply the "checked" value of it equals one in the SESSION array
echo "<input type='checkbox' name='cbgroup[]' value='$row[0]'";
if (isset($filtered)) {
$uniqueitemschecked = count($filtered);
for($i=0; $i < $uniqueitemschecked; $i++) {
if ($row[0] == $filtered[$i]) {
echo " checked ";
}
}
}
While you're building the HTML table in the WHILE loop... use this. It will append all the select IDs to a comma separated text value after the loop
...
$allcheckboxids = "";
while ($row = $result->fetch_row()) {
$allcheckboxids = $allcheckboxids.$row[0].",";
...
}
After the loop, write out the hidden text field
echo "<input type='hidden' name='currentids' value='$allcheckboxids'>";

Friends List Pagination

I have got a feature on my website called 'View friends' that displays a hidden div containing a users friends. The only problem so far is I would like it so that it would show 7 members on each row for 3 rows so a total of 21 members on each page. I know I will have to round up NumOfMembers/21 giving me the pages needed. I just need some advice in how I should set up the pagination from when thee SQL query gets the total amount of friends. Any ideas?
The SQL-query should use the limit and offset parameters for pagination, depending on the page n you are on, like this:
SELECT .... LIMIT 21 OFFSET n*21
When handling the results, simply use the modulo operator for determining the lines and rows your current result has to be put in:
// where $i is the result number
$row = $i % 7;
$line = $i % 3;
You have 2 options:
First you can load everything from the php in one query and put all users in an array(content), and just display in pages!
content = [];
max = 21;
function handlePaginationClick(page, pagination_container) {
$('#MyContentArea').empty();
for(var i=0;i<max;i++) {
if(null!=content[(page*max)+i]) $('#MyContentArea').append(content[(page*max)+i]);
}
return false;
}
$("#News-Pagination").pagination(content.length, {
items_per_page:max,
callback:handlePaginationClick
});
you can use Jquery Pagination: https://github.com/gbirke/jquery_pagination#readme
for that.
Another approach is still using jquery pagination, but not load everything at once! then you must have same ajax call in the method 'handlePaginationClick' to pull all page information.

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