In Laravel, there are different ways of using sections:
#yield('section1') // Filled in by child view
#section('section2')
// Default content, can be overwritten by child
// Different ways of closing the section
#endsection|stop|show|append
Who can tell me what the exact difference is between all of these?
Accoding to this, #stop and #endsection might be the same. (with one having been deprecated, but not anymore)
#endsection and #stop are the same and indicate the end of a section.
The section is not actually rendered on the page until you do #yield('sectionname')
In contrast, #show is equivalent to
#stop
#yield('sectionname')
i.e. it stops and immediately renders the section at that part of the page.
#append is basically equivalent to:
//FileA.blade.php
#section('sectionname')
... content
#stop
//FileB.blade.php
#extends('fileA')
#section('sectionname')
#parent
... more content after content
#stop
Here's some relevant source code:
protected function compileStop() {
return '<?php $__env->stopSection(); ?>';
}
protected function compileEndsection() {
return '<?php $__env->stopSection(); ?>'; //Same code
}
protected function compileShow() {
return '<?php echo $__env->yieldSection(); ?>';
}
Yield section just stops the current section and yields its contents.
I might be late in the party. But in Laravel 7.x series, there is no mention of "#stop" and "#append".
Q: Difference between #endsection and #show
#endsection directive just tells the blade engine where the section actually ends. And to show that section you need to use the #yield directive. If you don't yield that section blade won't show it after rendering the view.
For example in layout view:
<!-- layout -->
<body>
#section('content')
Some Content
#endsection
</body>
The above code has no meaning, of course we have defined a section. But it won't show up in the view to the client. So we need to yield it, to make it visible on the client. So lets yield it in the same layout.
<!--layout-->
<body>
#section('content')
Some content
#endsection
#yield('content')
</body>
Now the above code has some meaning to the client, because we have defined a section and told the Blade engine to yield it in the same layout.
But Laravel provides a shortcut to that, instead of explicitly yielding that section in the same layout, use the #section - #show directive pairs. Therefore the above code can be written as follows:
<!--layout-->
<body>
#section('content')
Some content
#show
</body>
So #show is just a compacted version of #endsection and #yield directives.
I hope I made everything clear. And one more thing, in laravel 7.x to append the content in the section, #parent directive is used.
Found it in quora
#show has similar functionality like #yield but you can use it for more things. When you declare #yield in your layout view you can set default value as well.
app.blade.php
#yield('title', 'Default Title')
and in your child view you can change the title
user.blade.php
#section('title', 'Custom Title')
However, you can set only string for default value in case of #yield. If you want to use some part of html content as a default part, you should use #show
app.blade.php
#section('some_div')
<h1>Default Heading1</h1>
<p>Default Paragraph
<span>Default Span</span>
</p>
#show
in your child view
#section('some_div')
<h1>Custom Heading1</h1>
<p>Custom Paragraph
<span>Custom Span</span>
</p>
#endsection
also you can use both default content and custom content together. just include #parent
#section('some_div')
#parent
<h1>Custom Heading1</h1>
<p>Custom Paragraph
<span>Custom Span</span>
</p>
#endsection
Related
Laravel Version: v8.41.0
PHP Version: 8.0.5
Sail Version: v1.5.1
Description:
I have an a.blade.php view that, in body, contains a #yield directive like this
#yield('post_body_scripts')
Then, the view is included in another one, b.blade.php that holds data for the post_body_scripts section
#extends('partials.layouts.app')
...
#include('c', ['foo' => 'bar'])
#section('post_body_scripts')
<script src="{{ asset('js/b.js') }}"></script>
#endsection
The included c view contains another part of the post_body_scripts section
#section('post_body_scripts')
#parent
<script src="https://cdn/ajsfile.js"></script>
#endsection
The #parent directive correctly works, but an hashtag starting placeholder is shown when the render of the view starts
<?php $__env->startSection('post_body_scripts'); ?>
##parent-placeholder-1a5ac98c3addb84257eb2d5b7ffee8f1cbf3b352##
<script src="https://cdn/ajsfile.js"></script>
<?php $__env->stopSection(); ?><?php /**PATH /var/www/html/resources/views/c.blade.php ENDPATH**/ ?>
Steps To Reproduce:
Create a base view that contains a #yield directive;
Create a view that extends the previous one and uses a #section directive for the previous yield;
Include, in the view created at point 2, another sub view;
In the view included at point 3, use a #section directive that starts with #parent for the declared yield.
Update
As notified to me in comments I tried using #stack directive but problem is still here.
a.blade.php
#stack('post_body_scripts')
b.blade.php
#push('post_body_scripts')
....
#endpush
c.blade.php
#push('post_body_scripts')
#parent
....
#endpush
remove #parent
#parent not use with #stack or #push
I'am new to Laravel I just want to know the difference between #extends and #include
#extends('tempalate')
can I use #include to add template file in my laravel project.
#include('tempalate')
To simply put it:
Using #include('') function you are including or adding an existing file.
Using #extends('') your are sending a portion of your file to the extended file.
Which is usually wrapped inside a #section('') function.
As per Laravel Documentation:
Blade's #include directive allows you to include a Blade view from
within another view. All variables that are available to the parent
view will be made available to the included view:
<div>
#include('shared.errors')
<form>
<!-- Form Contents -->
</form>
</div>
When defining a child view, use the Blade #extends directive to
specify which layout the child view should "inherit". Views which
extend a Blade layout may inject content into the layout's sections
using #section directives. Remember, as seen in the example above, the
contents of these sections will be displayed in the layout using
#yield:
<!-- Stored in resources/views/child.blade.php -->
#extends('layouts.app')
#section('title', 'Page Title')
#section('sidebar')
#parent
<p>This is appended to the master sidebar.</p>
#endsection
#section('content')
<p>This is my body content.</p>
#endsection
Laravel -> Blade Templates -> Including Subviews
I have a sample view:
File: hello.blade.php
//includes the basic html enclosed tags
<p>Hello world<p>
#yield('content')
File: tester.blade.php
#extends('hello')
#section('content')
<p>this is a test<p>
#yield('contents')
#endsection
File: content.blade.php
#extends('tester.blade.php')
#section('contents')
<p>any code will do<p>
#endsection
now my problem is whenever it only renders
Hello world
this is a test
is there any workaround this? or blade engine does not support nested yields? anyhelp will be greatly appreciated
I have not tested but you could try change content.blade.php to
#extends('tester')
and make sure you use
return view('content');
However #include inside #section works. or using #parent in content.blade.php
#extends('tester')
#section('content')
#parent
<p>any code will do</p>
#endsection
#parent will cause Blade to append parent view content with current view rather than overwrite whole section.
I've tested it but doesn't do what we expect.
But there is one solution that I still use when I'm facing to such situation. I use #parent blade directive like this
File: hello.blade.php
{{-- includes the basic html enclosed tags --}}
<p>Hello world<p>
#yield('content')
File: tester.blade.php
#extends('hello')
#section('content')
<p>this is a test<p>
#yield('contents')
#endsection
File: content.blade.php
#extends('tester.blade.php')
#section('contents')
#parent
<p>any code will do<p>
#endsection
If I have a layout called RightSideBar.blade.php in Laravel blade, one area yield('content') and the other yield('sidebar').
Is there a built in way to display a default partial if the view that is extending RightSideBar does not have a section('sidebar')?
I know you can pass a value by default, just wondering if there is a way to make default a partial.
Yes you can pass a default
Looking at the documentation
#yield('sidebar', 'Default Content');
Which basically puts a default output when the child template does not have #section('sidebar')
Most of the time we want multiple line default content, we can use this syntax:
#section('section')
Default content
#show
For example I have this in the template file:
#section('customlayout')
<article class="content">
#yield('content')
</article>
#show
You can see the difference between #show and #stop/#endsection: the above code is equivalent to the one below:
#section('customlayout')
<article class="content">
#yield('content')
</article>
#stop
#yield('customlayout')
In the other view files I can either set the content only:
#section('content')
<p>Welcome</p>
#stop
Or I can also set a different layout:
#section('content')
<p>Welcome</p>
#stop
#section('defaultlayout')
<div>
#yield('content')
</div>
#stop
The #stop is equivalent as the #endsection.
Although the docs specifies a default only as a string you can in fact pass a view
#yield('sidebar', \View::make('defaultSidebar'))
Laravel 5.2 added a #hasSection directive that checks if a section is defined in a view.
It's not mentioned in 5.3 or 5.4 docs for some reason.
#hasSection('sidebar')
#yield('sidebar')
#else
#yield('default-sidebar')
#endif
Tested in Laravel 8:
#yield can have default content as a second parameter. It can either be a string or a view file
// user-layout.blade.php
#yield('header', View::make('layouts.header'))
You can now override this "header" with section
#section('header')
<div>New Header</div>
#endsection
//// OR - you can also pass a view file as a second parameter //////
#section('header', View::make('layouts.new-header'))
Is there a way to load js into the <head> section of the page whena subview is loaded. I would like to only load specific JS files based on the view that is being called. I am using the blade template engine.
There is a much easier way to do this using sections and template inheritance.
Firstly, create a master layout file, something like this:
http://paste.laravel.com/UY9 It's one I use that includes
Initializr/Bootstrap. I store this in views/layouts/frontend/ as
master.blade.php for the frontend and views/layouts/admin/ as
master.blade.php for the admin and amend as necessary.
You'll notice various #section declarations ending with #show. Using
#show at the end instead of #stop, allows you to override them in
your other views, you'll notice I've added a #section('scripts')
declaration. So, you can create a view like so:
#extends('layouts.frontend.master')
#section('scripts')
Your Scripts
#stop
#section('content')
Your content
#stop
It's that simple. This is very powerful stuff, as it gives you the ability to set a default but also override it if necessary, keeping your views very clean and minimal.
A better way to do this though would be to do:
#extends('layouts.frontend.master')
#section('head')
#parent
Your Scripts
#stop
#section('content')
Your content
#stop
Then you can remove the #section('scripts') declaration from your master layout. Using the #parent helper will allow you to append content to a section, thus keeping it's default while adding the extra content you have specified in your view.
You can also provide default content for #yield declarations, like so #yield('content', 'Default content').
Check out http://codebright.daylerees.com/blade
First make a common header layout.
app/views/layouts/header.blade.php - header layout
<!DOCTYPE html>
<html>
<head>
<title>{{ $page->title }}</title> {{-- Getting title from $page object, which is passed from route --}}
{{ HTML::style('css/common.css') }}
{{ HTML::script('js/jquery.js') }}
{{ HTML::script('js/common.js') }}
Then page specific script layout.
app/views/layouts/script-about.blade.php - about-page script layout
{{ HTML::script('js/about.js') }}
Then view for specific page.
app/views/about.blade.php - about page
#extends('layouts.master')
#section('content')
<p>About-Us page content goes here</p>
#stop
Then common footer.
app/views/layouts/footer.blade.php - footer layout
</body>
</html>
Then the main layout to render.
app/views/layouts/master.blade.php - main layout
#include('layouts.header')
#include('layouts.script-'.$page->slug) {{-- Getting page name from $page object --}}
</head>
<body>
#yield('content')
#include('layouts.footer')
And from the route, you can pass the $page variable. You may like this route,
Route::get('{slug}', function($slug) {
$page = Page::where('slug', '=', $slug)->first();
// getting the datas from Page model with pages table where slug = last uri in your address-bar
if ( is_null($page) ) { // if no page in db, call 404
App::abort(404);
}
// render the view with page details
return View::make($page->slug)->with(array('page' => $page));
});
In laravel 5.4 as stated in the document
You can simply use stacks(#stack and #push) to be able to load CSS and JS from subviews(child views).
Add #stack to your layout where you want JS files or CSS files to be added from child views to layout.
Here I will define two stacks in the layout file one for CSS files and one for JS files. I give the first and the second stacks arbitrary name for instance styles and scripts
we want our CSS files to be loaded in the part of layout file
<head>
#stack('styles')
</head>
and let's say we want our scripts to be added right be for the closing body tag
in layout file
#stack('scripts')
</body>
now in the child view i can easily add CSS and JS files like this
#push('styles')
<style rel="stylesheet" href="{{asset('dropzone/dist/min/dropzone.min.css') }}" ></style>
#endpush
#push('scripts')
<script src="{{ asset('dropzone/dist/min/dropzone.min.js') }}"></script>
#endpush