How can I query the data where id_konsul = 4, and how can I get the latest staflow from created_at if it is the same?
example
id id_konsul staflow created_at
1 4 1 21/05/2018 11.03
2 4 2 22/05/2018 11.03
3 4 3 23/05/2018 11.03
4 4 4 24/05/2018 11.03
5 4 5 25/05/2018 11.03
6 4 6 26/05/2018 11.03
7 4 7 27/05/2018 11.03
8 4 6 28/05/2018 11.03
9 4 7 29/05/2018 11.03
10 4 7 30/05/2018 11.03
11 4 8 31/05/2018 11.03
than i get this
id id_konsul staflow created_at
1 4 1 21/05/2018 11.03
2 4 2 22/05/2018 11.03
3 4 3 23/05/2018 11.03
4 4 4 24/05/2018 11.03
5 4 5 25/05/2018 11.03
8 4 6 28/05/2018 11.03
10 4 7 30/05/2018 11.03
11 4 8 31/05/2018 11.03
try this query
SELECT * FROM test1 n
WHERE created_at=(SELECT MAX(created_at)FROM test1
WHERE staflow=n.staflow)
order by id
To get latest row per staflow attribute you can use a self join
select a.*
from demo a
join (
select id_konsul,staflow, max(created_at) created_at
from demo
where id_konsul = 4
group by id_konsul, staflow
) b on a.staflow = b.staflow
and a.id_konsul = b.id_konsul
and a.created_at = b.created_at;
Or using a left join
select a.*
from demo a
left join demo b on a.id_konsul = b.id_konsul
and a.staflow = b.staflow
and a.created_at < b.created_at
where a.id_konsul = 4
and b.id_konsul is null
Demo
To write above queries using laravel's query builder you can use following references
Laravel Eloquent select all rows with max created_at
Laravel - Get the last entry of each UID type
Laravel Eloquent group by most recent record
Please try this query.
SELECT * FROM table_name WHERE id_konsul = 4 ORDER BY created_at DESC LIMIT 1;
You can user INNER JOIN.
Example:
SELECT t0.* from {TABLE_NAME} AS t0 INNER JOIN {TABLE_NAME} t1 ON t0.staflow = t1.staflow WHERE t0.created_at > t1.created_at and t0.id_konsul = 4
Related
I`ve got the following table in mysql
id|top_id|amount
1 NULL 2
2 NULL 8
3 NULL 4
4 3 7
5 2 8
6 2 4
7 5 5
8 7 1
9 6 6
10 8 6
For the first 3 ids i need to sum up all amounts of its successors to get the following:
id | amount
1 8
2 32
3 11
I guess there should be joins but unfortunately I can`t get the working mysql request. Can somebody help me?
UPD: In php I have the following query:
$tops = $mysqli->query('SELECT * FROM table WHERE top_id IS NULL')
which obviously returns me just 3 top ids and their plain amounts (2, 8 and 4 respectively). Instead of 2, 8 and 4 I need to get 12, 28 and 11 and that`s the problem((
This is the crudest solution... No doubt someone will provide some hints for a more scalable solution shortly (perhaps employing PHP)...
SELECT a.id
, COALESCE(a.amount,0)
+ COALESCE(b.amount,0)
+ COALESCE(c.amount,0)
+ COALESCE(d.amount,0)
+ COALESCE(e.amount,0)
+ COALESCE(f.amount,0) total
FROM my_table a
LEFT
JOIN my_table b
ON b.top_id = a.id
LEFT
JOIN my_table c
ON c.top_id = b.id
LEFT
JOIN my_table d
ON d.top_id = c.id
LEFT
JOIN my_table e
ON e.top_id = d.id
LEFT
JOIN my_table f
ON f.top_id = e.id
WHERE a.top_id IS NULL;
I'm trying to get a set of values from a pivot table where column A is equal to an array of values, so for example ID 12 has attribute_value_id equal to 3 and 9. Can this be done? I've got this far...
ID | post_id | attribute_id | attribute_value_id
8 12 1 3
9 12 2 13
10 13 1 3
11 13 2 9
12 16 1 3
13 16 2 9
88 11 1 1
89 11 2 8
90 11 3 18
91 11 4 22
The query...
select *
from `searching_for_posts`
where (
select count(*)
from `attributes`
inner join `searching_for_attributes`
on `attributes`.`id` = `searching_for_attributes`.`attribute_id`
where `searching_for_attributes`.`searching_for_post_id` = `searching_for_posts`.`id`
and (`attribute_value_id` = 3 and `attribute_value_id` = 9)
) >= 1
If I use the and then I get no values. If I use the or then I get 3 values but it should return 2. I have limited SQL experience.
You can do this using group by and having. Your logic is hard to follow, but it is something like this:
select post_id
from table t
where attribute_value_id in (3, 9)
group by post_id
having count(distinct attribute_id) = 2;
I would think you would want to check on attribute_id as well, but that doesn't seem to be part of the question.
EDIT:
If these are stored in another table:
select a.post_id
from attributes a join
searching_for_attributes sfa
on a.attribute_id = sfa.attribute_id and
a.attribute_value_id = sfa.attribute_value_id
group by a.post_id
having count(*) = (select count(*) from searching_for_attributes);
In response to #GordonLinoff answer, I've managed to use GROUP BY and HAVING COUNT to get the desired data. Here's what I came up with and hope this helps someone else...
select *
from `searching_for_posts`
where (
select count(*)
from `attributes`
inner join `searching_for_attributes` on `attributes`.`id` = `searching_for_attributes`.`attribute_id`
where `searching_for_attributes`.`searching_for_post_id` = `searching_for_posts`.`id`
and `attribute_value_id` in (3, 9)
having count(distinct `attributes`.`id`) = 2
) >= 1
group by `id`
Assuming I have 2 tables:
leave_type
id name
1 maternity leave
2 Medical leave
3 Casual Leave
4 Sick Leave
5 honeymoon Leave
employee_leave_blance
id employee_id year leave_type_id val
1 4 2015 1 9
2 4 2015 2 5
3 8 2015 1 10
4 4 2015 3 4
Here employee_leave_blance.leave_type_id = leave_type.id
Now I want to get all Leave Type values for employee_id=4
In employee_leave_blance table for employee_id=4 there are only 3 leave_type entries but in leave_type table there are 5 of them.
I want to get 5 entries for a employee. If no entry is found in employee_leave_blance it should return 0.
Let me give an example: I want to get output for employee_id = 4
employee_id name val
4 maternity leave 9
4 Medical leave 5
4 Casual Leave 4
4 Sick Leave 0
4 honeymoon Leave 0
For this I've tried following query:
select
el.employee_id, lt.name, el.val from leave_type as lt
left join employee_leave_blance as el on el.leave_type_id = lt.id
where
el.year = YEAR(CURDATE()) and el.employee_id = 4
It however returns following results:
employee_id name val
4 maternity leave 9
4 Medical leave 5
4 Casual Leave 4
Now how can I get values for all leave_type for an employee?
Not sure if this is what you need, please try :
select ifnull(el.employee_id,4) as employee_id,
lt.name,ifnull(el.val,0) as val
from leave_type as lt
left join (select year,employee_id,val,leave_type_id
from employee_leave_balance) as el
on el.leave_type_id = lt.id
and el.year = year(curdate())
and el.employee_id = 4
Actually, your query would works with some modification. just remove where clause to and because you already joined tables and use ifnull function to return 0 for null values. This is your query with some improvement :
select
ifnull(el.employee_id,4) as employee_id, lt.name, ifnull(el.val,0) as val
from leave_type as lt
left join employee_leave_balance as el on el.leave_type_id = lt.id
and
el.year = YEAR(CURDATE()) and el.employee_id = 4
I have a table similar the following
id user_id father_id
1 1 1
2 2 1
3 3 2
4 4 2
5 5 2
6 6 3
7 7 4
I search for a sql query (prefer Fluent or Eloquent for Laravel 4) to give me the following result:
id user_id father_id family_members
3 3 2 3
4 4 2 3
5 5 2 3
1 1 1 2
2 2 1 2
6 6 3 1
7 7 4 1
As it can be observed family_members is the count of users who have the same father_id
select id, user_id, father_id, count(*) as family_members from users group by father_id
The query above, just keeps the top row of each group, but I want to keep all the other records and not only the first one; then sorting them first according to the family_members and then according to father_id
How can I achieve it?
I don´t know Fluent, nor Eloquent, nor Laravel 4, but the sql query would be like this.
SELECT yourTable.*, auxTable.family_members
FROM yourTable
LEFT JOIN
(
SELECT father_id, COUNT(id) as family_members
FROM yourTable
GROUP BY father_id
)auxTable ON yourTable.father_id = auxTable.father_id
ORDER BY family_members DESC, yourTable.father_id ASC
I solved the problem by the following Fluent query based on the answer from segio0983
$users = DB::table('users')
->leftjoin(DB::raw('(SELECT father_id, COUNT(id) as family_members
FROM users
GROUP BY father_id) auxTable '),function($join)
{
$join->on('users.father_id', '=', 'auxTable.father_id');
})
->orderBy('auxTable.family_members','desc')
->orderBy('users.father_id','asc')
->select('users.id','users.father_id','auxTable.family_members');
I have 2 tables and I need join these tables to show the latest articles from my site
Table Posts
ID ID_CAT ID_USER
10876 5 3489
10877 6 3453
10878 1 2356
10879 4 6789
10880 8 2348
10881 9 8327
Table Posts2
ID ID_CAT ID_USER
10882 7 3989
10883 2 3473
10884 7 2246
The result should be
ID ID_CAT ID_USER
10876 5 3489
10877 6 3453
10878 1 2356
10879 4 6789
10880 8 2348
10881 9 8327
10882 7 3989
10883 2 3473
10884 7 2246
I have this query from this similar article but not works.
:https://dba.stackexchange.com/questions/11367/how-to-join-two-table-and-show-one-query-result-in-mysql
SELECT name FROM
(
SELECT name FROM table1
UNION
SELECT name FROM table2
) A;
You didn't substitute in your own columns for this, try this query:
SELECT * FROM ( SELECT * FROM Posts UNION SELECT * FROM Posts2) AllPosts;