I have quiet interesting task at my university.
I have DB table:
----------------------------------------
| id | fee | status | created_at |
----------------------------------------
| 1 | 10 | COMPLAINABLE | 2018-05-01 |
| 2 | 15 | COMPLAINABLE | 2018-05-01 |
| 3 | 18 | COMPLAINABLE | 2018-05-02 |
| 4 | 1 | COMPLAINABLE | 2018-05-03 |
| 5 | 2 | COMPLAINABLE | 2018-05-03 |
----------------------------------------
I wrote SQL:
SELECT created_at AS ts, SUM(fee) AS value
FROM leads_ads
WHERE status NOT IN ('COMPLAINED', 'COMPLAIN_ACCEPTED')
GROUP BY DATE_FORMAT(created_at, '%Y-%m')
ORDER BY created_at ASC;
And at first result was fine:
-------------------------
| ts | value |
-------------------------
| 2018-05-01 | 25 |
| 2018-05-02 | 18 |
| 2018-05-03 | 3 |
-------------------------
But now i have to rewrite sql to get result like this:
---------------------------------------------------------------
| ts0 |value0| ts1 | value1 | ...... | tsn | valuen |
---------------------------------------------------------------
|2018-05-01| 25 |2018-05-02| 18 | ...... | tsn | valuen |
---------------------------------------------------------------
I tried many ways to do it but can't fine a right result(tried TRANSPOSE pivot table). So I decided to ask here. maybe someone will push me to the right way.
Thanks
Look at this article (this shows how you can resolve this with dynamic SQL): http://onlybluefeet.com/2015/01/18/how-to-rotate-rows-into-columns-in-mysql/
Related
I am using Laravel and eloquent If I have the following two tables
Sales
----
|id|
|--|
|1 |
|2 |
|3 |
|4 |
----
Sales_data
----
|sale_id|Product_id|
|------------|
| 1 | 30 |
| 1 | 24 |
| 1 | 18 |
| 2 | 18 |
| 2 | 30 |
| 3 | 24 |
| 4 | 18 |
| 4 | 24 |
--------------
I would like to retrieve the following info:
| Product_id | bought_with | times_bought_together |
|--------------|-------------|-----------------------|
| 30 | 18 | 2 |
| 30 | 24 | 1 |
| 24 | 18 | 1 |
------------------------------------------------------
This is the relation in Sales model, to the sale_data
public function data()
{
return $this->hasMany(\App\Models\SaleData::class, 'sale_id');
}
Thank you verry much
You can use DB::select() so you can put RAW SQL statements in it.
In this case its easyer to just use RAW SQL
DB::select("SELECT c.product_id, c.bought_with, count(*) as times_bought_together
FROM (
SELECT a.product_id as product_id, b.product_id as bought_with
FROM sales_data a
INNER join sales_data b
ON a.sale_id = b.sale_id AND a.product_id != b.product_id) c
GROUP BY c.product_id, c.bought_with
ORDER BY times_bought_together DESC LIMIT 50")
GoodLuck if you have the same problem!
I am trying to count how many require position there are for each jobseeker.
I have two tables: jobseeker and jobposition.
jobseeker:
+----+---------+-----------+----------------+
| id | fb_name | fullname | desireposition |
+----+---------+-----------+----------------+
| 1 | John | John Cena | 3 |
| 2 | Christ | Christ | 4 |
| 3 | Thomas | Cfitcher | 2 |
+----+---------+-----------+----------------+
and jobposition:
+----+--------+------------------+
| id | job_id | require_position |
+----+--------+------------------+
| 1 | 12 | 3 |
| 2 | 13 | 3 |
| 3 | 14 | 4 |
| 4 | 15 | 5 |
| 5 | 16 | 4 |
| 6 | 17 | 3 |
+----+--------+------------------+
My expected result is:
+----+---------+-----------+----------------+-----------------------+
| id | fb_name | fullname | desireposition | total_requireposition |
+----+---------+-----------+----------------+-----------------------+
| 1 | John | John Cena | 3 | 3 |
| 2 | Christ | Christ | 4 | 2 |
| 3 | Thomas | Cfitcher | 2 | 0 |
+----+---------+-----------+----------------+-----------------------+
I want to count how many require position there for each jobseeker.
Here is what I tried using crossJoin, but am unsure which join I actually need to be using.
$jobseekers = Jobseeker::crossJoin('jobpositions')
>select('fullname','fb_name','desire_position', DB::raw('count(require_position) as total_requireposition'))
->groupBy('fullname')->paginate(10);
Can anyone help guide me? Any help would be highly appreciated.
The regular MySQL query you want is:
SELECT s.id, fullname, fb_name, desireposition, IFNULL(COUNT(require_position), 0) AS require_position
FROM jobseeker AS s
LEFT JOIN jobposition AS p ON s.desireposition = p.require_position
GROUP BY s.id
I don't use Laravel, but I think the translation would be:
$Jobseeker->select('fullname','fb_name','desire_position', DB::raw('IFNULL(COUNT(require_position), 0) as total_requireposition'))
->leftjoin('jobposition', 'desireposition', '=', 'require_position')
->groupBy('jobseeker.id')
->paginate(10)
invoice
+----+-----+---------+-------+
| Sr | BRN | Name | Amnt |
+----+-----+---------+-------+
| 1 | 1 | John | 10 |
| 2 | 1 | John | 4 |
| 3 | 2 | Belly | 4 |
| 4 | 3 | John | 14 |
| 5 | 4 | John | 5 |
| 6 | 4 | John | 14 |
+----+-----+---------+-------+
I want to select all rows except the duplicate BRN. (If there are two/more ge in BRN then it should only select one)
I tried:
SELECT *(DISTINCT BRN) FROM invoice
Expected result:
+-----+---------+-------+
| BRN | Name | Amnt |
+-----+---------+-------+
| 1 | John | 10 |
| 2 | Belly | 4 |
| 3 | John | 14 |
| 4 | John | 5 |
+-----+---------+-------+
Given the following table:
+----+-----+---------+-------+
| Sr | BRN | Name | Amnt |
+----+-----+---------+-------+
| 1 | 1 | John | 10 |
| 2 | 1 | John | 4 |
| 3 | 2 | Belly | 4 |
| 4 | 3 | John | 14 |
| 5 | 4 | John | 5 |
| 6 | 4 | John | 14 |
+----+-----+---------+-------+
with the expected results:
+-----+---------+-------+
| BRN | Name | Amnt |
+-----+---------+-------+
| 1 | John | 10 |
| 2 | Belly | 4 |
| 3 | John | 14 |
| 4 | John | 5 |
+-----+---------+-------+
The difficult part is getting the amount, because it is arbitrary, not to mention that the values in Amnt are pretty much worthless in this result.
If you want distinct BRN, the query would be SELECT DISTINCT BRN FROM invoice
You might even get away with SELECT DISTINCT BRN, Name FROM invoice
An intermediate step would be SELECT BRN,Name FROM invoice GROUP BY BRN, Name
But if you try to include Amnt in the equation, then the query will fail because there's no way for the database to determine which Amnt to show.
So, you could try this kludge:
SELECT a.BRN, a.Name, b.Amnt FROM invoice AS a LEFT JOIN invoice AS b ON a.BRN=b.BRN
No guarantees on which Amnt it will pick up, though.
Hope that helps.
SELECT * FROM invoice WHERE Date >= :fdate GROUP BY BRN
See Here Use GROUP BY in Query with your Conditions
I have the following 3 tables: unit, stage, stats.
unit stage
+----+--------+ +----+-------+---------------------+
| id | status | | id |unit_id| date |
+----+--------+ +----+-------+---------------------+
| 1 | 2 | | 1 | 2 | 2013-11-22 00:00:00 |
| 2 | 3 | | 2 | 2 | 2013-11-26 12:00:00 |
| 3 | 3 | | 3 | 3 | 2013-10-11 00:00:00 |
| 4 | 0 | | 4 | 1 | 2013-12-29 00:00:00 |
+----+--------+ +----+-------+---------------------+
stats
+----+----------+---------------------+-------+
| id | stage_id | date | clicks|
+----+----------+---------------------+-------+
| 1 | 1 | 2013-11-22 00:00:00 | 10 |
| 2 | 1 | 2013-11-23 00:00:00 | 20 |
| 3 | 1 | 2013-11-24 00:00:00 | 25 |
| 4 | 2 | 2013-11-26 00:00:00 | 15 |
| 5 | 2 | 2013-11-27 12:00:00 | 21 |
| 6 | 3 | 2013-12-29 00:00:00 | 8 |
+----+----------+---------------------+-------+
I need a request, that will produce the following response:
+---------+---------------------+-----------------------+
| unit.id | stage.min.date | sum(stats.max.clicks) |
+---------+---------------------+-----------------------+
| 2 | 2013-11-22 00:00:00 | 46 |
| 3 | 2013-12-29 00:00:00 | 8 |
+---------+---------------------+-----------------------+
by the following rules:
1) unit.id - show only units with unit.status=3
2) stage.min.date - minimal stage.date for corresponding unit_id
3) sum(stats.max.clicks) - sum of stats.clicks with max dvalues for each stage_id associated with corresponding unit_id. In my example 46 = 25(stage_id=1) + 21(stage_id=2)
The problem is in min.date and sum of clicks - I have no idea how to get it in one query. Definitely it`s not a problem to do it using php code and several requests.
Schema in SQL Fiddle
Thanks in advance.
I just ask myself, why I do this? Your example resonse has an error, and does not match your fiddle... but:
SELECT
cc.unit_id, MIN(cc.date) as stage_min_date , SUM(dd.clicks) as stats_max_clicks
FROM
stage cc
LEFT JOIN (
SELECT
bb.stage_id, bb.clicks
FROM
stats bb LEFT JOIN (
SELECT id, stage_id, MAX(date) AS max_date
FROM stats
GROUP BY stage_id
) aa
ON
aa.max_date = bb.date
WHERE
aa.max_date IS NOT NULL
) dd
ON cc.id = dd.stage_id
LEFT JOIN unit ee
ON ee.id = cc.unit_id
WHERE ee.status = 3
GROUP BY cc.unit_id
...
I have 2 tables - users and users_audit, need to display results from 2 separate queries into 2 columns with relation to each other. I already figured out both queries.
query for users: SELECT rowid,data FROM users WHERE columnid = 1 GROUP BY rowid;
+-------+------------+
| rowid | data |
+-------+------------+
| 1 | John |
| 2 | Abi |
| 3 | Tony |
| 4 | Gregg |
| 5 | Jon |
| 6 | Victor |
| 7 | Daniel |
query for users_audit: SELECT date_created FROM users_audit WHERE rowid = 6 ORDER BY date_created DESC, date_created DESC LIMIT 1;
Purpose of the query is to display latest date_created for particular rowid.
+---------------------+
| date_created |
+---------------------+
| 2012-07-04 09:20:12 |
+---------------------+
Table users_audit looks like this:
SELECT * FROM users_audit;
+-------+---------+--------------+-------------+---------------------+
| id | rowid | before_value | after_value | date_created |
+-------+---------+--------------+-------------+---------------------+
| 1 | 6 | 3 | 5 | 2012-06-29 15:48:11 |
| 2 | 5 | Out (0) | 2 | 2012-07-04 09:20:10 |
| 3 | 6 | 5 | 4 | 2012-07-04 09:20:12 |
| 4 | 7 | 3 | 6 | 2012-07-04 09:20:14 |
| 5 | 3 | 2 | 3 | 2012-07-04 09:20:16 |
| 6 | 15 | 6 | 5 | 2012-07-04 09:20:22 |
I need to display 2 columns - data from users and date_created from users_audit for each rowid. It means query for users_audit must be run for each rowid (in the loop?).
Expected result displayed in php is:
+------------+----------------------+
| data | date_created |
+------------+----------------------+
| John | (latest date) |
| Abi | (latest date) |
| Tony | (latest date) |
| Gregg | (latest date) |
| Jon | (latest date) |
| Victor | 2012-07-04 09:20:12 |
| Daniel | (latest date) |
How can this be achieved this in php?
Why cant you just create a view and use a join to create the table you want?
SELECT users.data, users_audit.date_created FROM users
INNER JOIN users_audit ON users.rowid = users_audit.rowid
Or am I missing something here?
EDIT
SELECT users.data, users_audit.date_created FROM users
INNER JOIN users_audit ON users.rowid = users_audit.rowid
WHERE users_audit.date_created = (SELECT MAX(date_created) from users_audit
GROUP BY rowid)
I believe this should work..? Let me know.